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# Simplification Questions for SBI PO 2020 PDF

Download SBI PO Simplification Questions & Answers PDF for SBI PO Prelims and Mains exam. Very Important SBI PO Simplification Questions with solutions.

InstructionsInstructions: What will come in place of question mark (?) in the following questions?

Question 1: 3463 × 295 – 18611 = ? + 5883

a) 997091

b) 997071

c) 997090

d) 999070

e) None of these

Question 2: (23.1)2 + (48.6)2 – (39.8)2 = ? + 1147.69

a) (13.6)2

b) $\sqrt{12.8}$

c) 163.84

d) 12.8

e) None of these

Question 3: [(3$\sqrt{8}$+ $\sqrt{8}$ ) (8$\sqrt{8}$ + 7$\sqrt{8}$ )] – 98 = ?

a) 2$\sqrt{8}$

b) 8$\sqrt{8}$

c) $382$

d) $386$

e) None of these

Question 4: $\sqrt{11449}$x$\sqrt{6241}$ – (54)2 = $\sqrt{?}$ + (74)2

a) 3844

b) 3721

c) 3481

d) 3638

e) None of these

InstructionsInstructions: What approximate value should come in place of question mark (?) in the following questions? (Note: You are not expected to calculate the exact value.)

Question 5: 39.897% of 4331 + 58.779% of 5003 =?

a) 4300

b) 4500

c) 4700

d) 4900

e) 5100

Question 6: 43931.03 ÷ 2111.02 × 401.04 =?

a) 8800

b) 7600

c) 7400

d) 9000

e) 8300

Question 7: $\sqrt{6354}$ x 34.999 = ?

a) 3000

b) 2800

c) 2500

d) 3300

e) 2600

Question 8: $\sqrt[3]{4663}$ + 349 = ? ÷ 21.003

a) 7600

b) 7650

c) 7860

d) 7560

e) 7680

Question 9: 59.88 ÷ 12.21 × 6.35 =?

a) 10

b) 50

c) 30

d) 70

e) 90

InstructionsInstructions: What will come in place of the question mark (?) in the following questions?

Question 10: 4003×77 – 21015 = ?×116

a) 2477

b) 2478

c) 2467

d) 2476

e) None of these

Question 11: [(5$\sqrt{7}$ + $\sqrt{7}$ ) × (4$\sqrt{7}$ + 8$\sqrt{7}$ )] – (19)2 = ?

a) 143

b) 72$\sqrt{7}$

c) 134

d) 70$\sqrt{7}$

e) None of these

Question 12: (4444÷40) + (645÷25) + (3991÷26) = ?

a) 280.4

b) 290.4

c) 295.4

d) 285.4

e) None of these

Question 13: $\sqrt{33124}$×$\sqrt{2601}$ – (83)2 = (?)2 + (37)2

a) 37

b) 33

c) 34

d) 28

e) None of these

Question 14: 5$\frac{17}{37}$ × 4$\frac{51}{52}$ × 11$\frac{1}{7}$ + 2$\frac{3}{4}$ = ?

a) 303.75

b) 305.75

c) 303$\frac{3}{4}$

d) 305$\frac{1}{4}$

e) None of these

InstructionsInstructions: What approximate value should come in place of the question mark (?) in the following questions. (Note: You are not expected to calculate the exact value)

Question 15: 8787 ÷ 343 × $\sqrt{50}$ = ?

a) 250

b) 140

c) 180

d) 100

e) 280

Question 16: $\sqrt[3]{54821}$×(303÷8) = (?)2

a) 48

b) 38

c) 28

d) 18

e) 58

Question 17: $\frac{5}{8}$ of 4011.33 + $\frac{7}{10}$ of 3411.22 = ?

a) 4810

b) 4980

c) 4890

d) 4930

e) 4850

Question 18: 23% of 6783 + 57% of 8431 = ?

a) 6460

b) 6420

c) 6320

d) 6630

e) 6365.7

Question 19: 335.01×244.99 ÷ 55 = ?

a) 1490

b) 1550

c) 1420

d) 1590

e) 1400

Question 20: When X is subtracted from the numbers 9, 15 and 27 the remainders are in continued proportion. What is the value of X?

a) 8

b) 6

c) 4

d) 5

e) None of these

3463 × 295 = 1021585
1021585 – 18611 = 1002974
1002974 – 5883 = 997091

(23.1)2 = 533.61
(48.6 )2 = 2361.96
(39.8)2 = 1584.04
533.61 + 2361.96 – 1584.04 = 1311.53
1311.53 – 1147.69 = 163.84

[ $\sqrt{8}$ (3 +1) x $\sqrt{8}$(8 + 7)] – 98
= [4$\sqrt{8}$ x 15 x $\sqrt{8}$ ] – 98
= [60 x $\sqrt{8}$] – 98
= 480 – 98 = 382

$\sqrt{11449}$ x $\sqrt{6241}$ – (54)2 – (74)2 = $\sqrt{?}$
$\sqrt{?}$ = [107 x 79] – 2916 – 5476
= 8453 – 2916 – 5476 = 61
$\sqrt{?}$= (61)2 = 3721

40 x $\frac{4330}{100}$ + 59 + $\frac{5000}{100}$
= 1732 + 2950
= 4682

$\frac{43931}{2111}$ x 401 = 8345.01 ≈ 8300

After taking approximation equation will be

$\sqrt{6354}$ x 34.993 = 80 x 35 = 2800

$\sqrt[3]{4663}$ ≈ 17
17 + 349 = ? ÷ 21
366 x 21 = ?
? = 7686 ≈ 7680

After taking approximation equation will be 60 ÷ 12 x 6 = 30

4003 x 77 = 308231
308231 – 21015 = 287216
$\frac{287216}{116}$ = 2476

[(5$\sqrt{7}$ + $\sqrt{7}$ ) × (4$\sqrt{7}$ + 8$\sqrt{7}$ )] – (19)2
= [6$\sqrt{7}$ x 12$\sqrt{7}$] – 192
= [72 x 7] – 192
= 143

$\frac{4444}{40}$ = 111.1

$\frac{645}{25}$ = 25.8

$\frac{3991}{26}$ = 153.5

Total = 111.1 + 25.8 + 153.5 = 290.4

$\sqrt{33124}$×$\sqrt{2601}$ – (83)2
= 2393
2393 – 372
= 1024
$\sqrt{1024}$ = 32

5$\frac{17}{37}$ = $\frac{202}{37}$

4$\frac{51}{52}$ = $\frac{259}{52}$

11$\frac{1}{7}$ = $\frac{78}{7}$

2$\frac{3}{4}$ = $\frac{11}{4}$

$\frac{202}{37}$ x $\frac{259}{52}$ x $\frac{78}{7}$ = 303

303 + $\frac{11}{4}$ = 305.75

8787 ÷ 343 = 25.61
$\sqrt{50}$ = 7.07
25.61 x 7.07 = 181.06 ≈ 180

303 ÷ 8 =37.875 ≈ 38
$\sqrt[3]{54821}$ = 37.98 ≈ 38
382

$\frac{5}{8}$ x 4011.33 = 2507.08
$\frac{7}{10}$ of 3411.22 = 2387.854
2507.08 + 2387.854 = 4894.934 ≈ 4890

23% of 6783 can be calculated as (20+3)% of 6783 = 1560.09

57% of 8453 can be calculated as (50+7)% of 8431 = 4805.67

Sum will be = 1560.09 + 4805.67 = 6365.7

244.99 ≈ 245
245 ÷ 55 = 4.45
335.01 ≈ 335
335 x 4.45 = 1492 ≈ 1490

$\frac{9-x}{15-x}$ = $\frac{15-x}{27-x}$
x = 3

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