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# Simplification Questions for SBI Clerk PDF

Download SBI Clerk Simplification Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Simplification Questions with solutions.

## Instructions: What will come in place of the question mark (?) in the following questions?

Question 1: (4444÷40) + (645÷25) + (3991÷26) = ?

a) 280.4

b) 290.4

c) 295.4

d) 285.4

e) None of these

Question 2: 5$\frac{17}{37}$ × 4$\frac{51}{52}$ × 11$\frac{1}{7}$ + 2$\frac{3}{4}$ = ?

a) 303.75

b) 305.75

c) 303$\frac{3}{4}$

d) 305$\frac{1}{4}$

e) None of these

Question 3: $125^{4} \div 25^{4} * 5 ^{5} = 5 ^{?}$

a) 7

b) 9

c) 11

d) 13

e) none of the above

Question 4: $\frac{1}{7}$ of $2\frac{5}{8} \div \frac{3}{4} + \frac{1}{3} + \frac{1}{6}$

a) 1

b) 0

c) $\frac{1}{7}$

d) 2

e) None of the above

Question 5: 33.33% of 150 + 66.66% of 180 = ?% of 1700

a) 30

b) 25

c) 20

d) 10

e) 15

Question 6: What is the value of (x) in the following equation ?
$\frac { x ^ {1.2}}{98} = \frac {28}{x^{1.8}}$

a) 18

b) 12

c) 16

d) 14

e) None of these

Instructions

What should come in place of question mark (?) in the following questions ?

Question 7: $(96)^{2}+(63)^{2}=(?)^{2}-(111)^{2}-8350$

a) 33856

b) 30276

c) 174

d) 184

e) None of these

Instructions

What approximate value should come in place of question mark (?) in the following question ? (you are not expected to calculate the exact value )

Question 8: $(9795+7621+938)\div(541+831+496)= ?$

a) 9

b) 13

c) 17

d) 23

e) 29

Instructions

What will come in place of question mark (?) in the following questions:

Question 9: $25\cdot05\times123\cdot95+388\cdot999\times15\cdot001=?$

a) 900

b) 8950

c) 8935

d) 8975

e) 8995

Instructions

What will come in the place of question mark(?) in the given questions?

Question 10: $4\frac{1}{2}+(1\div2\frac{8}{9})-3\frac{1}{13}=?$

a) $1\frac{9}{26}$

b) $2\frac{7}{13}$

c) $1\frac{11}{26}$

d) $2\frac{4}{13}$

e) $1\frac{10}{13}$

Question 11: ${(441)^{1/2}\times207\times(343)^{1/3}}\div((14)^{2}\times(529)^{1/2})$ = ?

a) 5.75

b) 6.75

c) 7.75

d) 6.25

e) 6.50

Question 12: $(3\frac{3}{8}\times6\frac{5}{12})-(2\frac{3}{16}\times3\frac{1}{2})=?$

a) 21

b) 18

c) 14

d) 15

e) 16

Instructions

What should come in place of the question mark (?) in the following questions?

Question 13: $(4\times4\times4\times4\times4\times4)^{5}\times(4\times4\times4)^{8}\div(4)^{3}=(64)^?$

a) 17

b) 10

c) 16

d) 11

e) None of these

Question 14: What will come in the place of both question marks (?) in the following question?
$\frac{(?)^{1.8}}{32}=\frac{16}{(?)^{1.2}}$

a) 16

b) 64

c) 2

d) 4

e) 8

Instructions

What will come in place of question mark (?) in the given questions?

Question 15: $\frac{\sqrt{\frac{81}{25}} – \sqrt{\frac{144}{121}}}{\sqrt{\frac{1681}{484}}}$

a) 1/25

b) 3/11

c) 78/205

d) 2/5

e) 81/205

$\frac{4444}{40}$ = 111.1

$\frac{645}{25}$ = 25.8

$\frac{3991}{26}$ = 153.5

Total = 111.1 + 25.8 + 153.5 = 290.4

5$\frac{17}{37}$ = $\frac{202}{37}$

4$\frac{51}{52}$ = $\frac{259}{52}$

11$\frac{1}{7}$ = $\frac{78}{7}$

2$\frac{3}{4}$ = $\frac{11}{4}$

$\frac{202}{37}$ x $\frac{259}{52}$ x $\frac{78}{7}$ = 303

303 + $\frac{11}{4}$ = 305.75

$125^{4} is equal to 5^{12} and 25^{4} is equal to 5^{8}$

$\frac{1}{7}$ of $2\frac{5}{8} \div \frac{3}{4}$ = 0.5

As we can see that 33.33% of 150 will be $\frac{1}{3}$ of 150 i.e. 50 and 66.66% of 180 will be $\frac{2}{3}$ of 180 i.e. 120
Hence, sum will be = 170 which will be 10% of 1700.

The question can be reframed as,

$x^{1.2}\times x^{1.8}$ = 98*28 = 14*7*7*4= 7*7*7*8

x^3=7*7*7*8

Hence, x = 7*2 = 14

Let the number in the question mark be X.

So, $X^2 = 96^2 + 63^2 + 111^2 + 8350$

So, $X^2 = 9216 + 3969 + 12321 + 8350 = 33856 = 184^2$

So, $X = 184$

The numerator in the given fraction equals 9795+7621+938 = 18354

The denominator in the given fraction equals 541+831+496 = 1868

So, the given ratio becomes 18354/1868 = 9.82 ~ 9

Here we are approximating 25.05~25, 123.95~124, 388.99~389, 15.001~15.

The question can be rewritten as,

25*123+388*15=8935
Hence the correct option is 8935.

Given equation can be written as the following:

$\frac{9}{2} + \frac{9}{26} – \frac{40}{13} = \frac{46}{26}$

= $\frac{23}{13}$

Given equation can be written as follows:

$(21 \times 207 \times 7) \div (196 \times 23)$ = $\frac{189}{28}$ = 6.75

Given equation can be written as following:

$(\frac{27}{8} \times \frac{77}{12}) – (\frac{35}{16} \times \frac{7}{2})$

$\frac{693-245}{32} = 14$

The simplified expression equals $(4\times4\times4\times4\times4\times4)^{5}\times(4\times4\times4)^{8}\div(4)^{3}= (4^6)^5 \times (4^3)^8 \div 4^3 = 4^{30} \times 4^{24} \div 4^3 = 4^{30+24-3} = 4^{51}$

$64 = 4^3$

So, $4^{51} = 4^{3 \times 17} = (4^3)^{17} = 64^{17}$

Hence the correct answer is 17

Let the number in the question mark be ‘$x$’

So, $\frac{x^{1.8}}{32}=\frac{16}{x^{1.2}}$

So, $x^{1.8+1.2}=32*16=8^3$

So, $x^3 = 8^3$

Hence, $x=8$

$\frac{\sqrt{\frac{81}{25}} – \sqrt{\frac{144}{121}}}{\sqrt{\frac{1681}{484}}}$ = $\frac{{\frac{9}{5}} – \frac{12}{11}}{\frac{41}{22}}$