SBI Clerk Previous Year Simplification Questions
Download SBI Clerk Simplification Previous Year Questions & Answers PDF for SBI Clerk Prelims and Mains exam. Very Important SBI Clerk Simplification Previous Year questions on with solutions.
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Instructions
What should come in place of the question mark (?) in the following question ?
Question 1: ?% of 5600¬28% of 3500=1988
a) 58
b) 55
c) 51
d) 53
e) None of these
Question 2: $\frac{5}{8}+\frac{1}{4}+\frac{7}{12}=?$
a) $1\frac{11}{24}$
b) $1\frac{13}{24}$
c) $1\frac{9}{26}$
d) $1\frac{7}{24}$
e) None of these
Question 3: Simplify: $\sqrt{19+4\sqrt{21}}$
a) $2+\sqrt{26} $
b) $3-\sqrt{15} $
c) $\sqrt{5}+\sqrt{26} $
d) $\sqrt{12}+\sqrt{7}$
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Instructions
What should come in place of the question mark (?) in the following question ?
Question 4: $\frac{57}{67}\times\frac{32}{171}\times\frac{45}{128}=?$
a) $\frac{15}{262}$
b) $\frac{15}{268}$
c) $\frac{15}{266}$
d) $\frac{17}{268}$
e) None of these
Question 5: What will come in the place of question mark (?) in the following equation ?
$16^{7.5}\div8^{3.5}\div2^{7.5}$=?
a) $8^{4}$
b) $16^{4}$
c) $2^{15}$
d) $2^{27}$
e) None of these
Question 6: Simplify: $\frac{0.0347 \times 0.0347 \times 0.0347 + (0.9653)^3}{(0.0347)^2 – (0.347)(0.9653) + (0.9653)^2}$
a) 0.9306
b) 1.0009
c) 1.0050
d) 1
Question 7: Simplify the surd $ \frac{7 \sqrt{7} – 3 \sqrt{3}}{\sqrt{7} – \sqrt{3}}$
a) $ 10 + \sqrt{21}$
b) $ 10 – \sqrt{21}$
c) $ \sqrt{21} – 10 $
d) $ 7\sqrt{3} + 3\sqrt{7}$
Banking Study Material – 18000 Questions
Instructions
Instructions: What approximate value will come in place of question mark (?) in the following questions? (You are not expected to calculate the exact value.)
Question 8: $4\frac{1}{5} + 5\frac{5}{6} \times \frac{24}{7} \times 2\frac{4}{5}$ = ?
a) 60
b) $60\frac{1}{5}$
c) 44.8
d) 72.6
e) None of these
Instructions
In the following questions, what will come in the place of the question mark (?)
Question 9: $ \dfrac{ \sqrt{4225} * \sqrt{?} }{ \sqrt{6400} }$ = 13
a) 225
b) 250
c) 256
d) 275
e) Can’t be determined
Instructions
Find the approximate value of the number which should replace (?) in the following questions.
Question 10: $18.02*21.98 +\sqrt[3]{4923}*2.969 = ?$
a) 487
b) 397
c) 429
d) 447
e) 477
Question 11: What is the value of $1.75^3 – 1.25^3$?
a) 3
b) 3.2
c) 3.4
d) 3.6
Question 12: Simplify the equation: $\frac{31^3 + 22^3}{31^2 + 22^2 – 682}$
a) 9
b) 53
c) 69
d) 93
Instructions
What will come in place of question mark ‘?’ in the following questions?
Question 13: $\frac{4}{9} * \frac{18}{7} * (\frac{14}{3} * 1.5)$ = ?
a) 8
b) 9
c) 12
d) 16
e) 21
Question 14: $6\times 13+6+11-36\div 12$ =?
a) 29
b) 36
c) 64
d) 78
e) 92
Instructions
What value should come in place of the question mark (?) in the following questions?
Question 15: 102-(91-(83-(76-17-61))) is equal to?
a) 69
b) 76
c) 83
d) 96
e) 104
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Answers & Solutions:
1) Answer (D)
Reframing the question to simplify,
1988+28% of 3500 = 1988+(28*35)
Which reduces to,
1988+980=2968
2968=(x/100)*5600
x=2968/56
x=53
2) Answer (A)
$\frac{5}{8}+\frac{1}{4}+\frac{7}{12}=?$
Simplifying,
$\frac{7}{8}+\frac{7}{12}=?$
The equation reduces to,
7*{(1/8)+(1/12)}=(35/24)
Now converting $\frac{35}{24}$ to mixed fration, we get
$1\frac{11}{24}$
3) Answer (D)
Let $\sqrt{19+4\sqrt{21}} = \sqrt{a}+\sqrt{b}$
$\rightarrow a+b+2\sqrt{ab} = 19+4\sqrt{21}$.
Hence, a+b=19 and ab=84. Hence a=12, b=7.
4) Answer (B)
The expression, on reframing gives, $\frac{57}{171}\times\frac{32}{128}\times\frac{45}{67}$
which on simplifying gives,
(1/4)*(1/3)*(45/67) = (15/268)
5) Answer (A)
As $16,8,2$ are all exponents of $2$, let us simplify the expression to the powers of 2.
$16^{7.5} = (2^4)^{7.5} = 2^{30}$
$8^{3.5} = (2^3)^{3.5} = 2^{10.5}$
Hence, the given expression looks like this $2^{30} \div 2^{10.5} \div 2^{7.5} = 2^{30-10.5-7.5} = 2^{12} = 8^4$
Hence, the correct answer is option (a)
6) Answer (D)
Numerator is of the form of $a^{3} + b^{3}$ and denominator is of the form of $a^{2} + b^{2} – ab$
where a = .0347 and b= .9653
it will get reduce to a+b = 1
7) Answer (A)
Let $X = \frac{7 \sqrt{7} – 3 \sqrt{3}}{\sqrt{7} – \sqrt{3}}$
Multiplying numerator and denominator by $(\sqrt{7} + \sqrt{3})$,
$ X = (49 – 3 \sqrt{21} + 7 \sqrt{21} – 9)/4 = 10 + \sqrt{21}$
8) Answer (B)
We use BEDMAS rule to simplify the expression. We perform multiplication first.
Hence, expression = $4\frac{1}{5} + 5\frac{5}{6} \times \frac{24}{7} \times 2\frac{4}{5}$ = $4\frac{1}{5} + \frac{35*24*14}{6*7*5}$ = $4\frac{1}{5} + 4*14$ = $4\frac{1}{5} + 56$ = $60\frac{1}{5}$ .
9) Answer (C)
Sqrt of 4225 = 65 and sqrt of 6400 = 80. Simplifying, ? = 256
10) Answer (D)
We can approximate $18.02 \approx 18$ and $21.98 \approx 22$
Similarly, note that $17^3 = 4913$. Hence, $\sqrt[3]{4923}\approx 17$
And, $2.969 \approx 3$
Using the above approximations, we can simplify the expression to the below value.
$18*22 + 17*3 = 396 + 51= 447$
11) Answer (C)
To simplify the expression , we use the formula:
$a^3 – b^3$ = $(a-b)(a^2+b^2+ab)$
So, $1.75^3 – 1.25^3$ = (1.75-1.25) * (1.75 ^ 2 + 1.25 ^2 + 1.75 * 1.25) = 0.5 * (3.06 + 1.56 + 2.19) = 3.4
12) Answer (B)
We can solve the equation using the formula $a^3 + b^3$ = (a+b) * ($a^2+b^2$-ab)
So, the answer is 31 + 22 = 53
13) Answer (A)
We have to simplify: $\frac{4}{9} * \frac{18}{7} * \frac{14}{3} * 1.5$
So, we start with dividing 1.5 by 3 getting 0.5
So, the simplified value is $\frac{4}{9} * \frac{18}{7}$ * 14 * 0.5 = $\frac{4}{9} * \frac{18}{7}$ * 7
Cancelling out the 7, we get $\frac{4}{9}$ * 18
So, the simplified value is 4 * 2 = 8
14) Answer (E)
$6\times 13+6+11-36\div 12$ =?
By B.O.D.M.A.S rule, we have to follow Brackets first, followed by “Of”, followed by division, followed by multiplication, followed by multiplication, followed by addition and finally subtraction.
So, $6\times 13+6+11-36\div 12$ becomes $6\times 13+6+11-3$(We simplify division first as there are no brackets or “of”)
$6\times 13+6+11-3$ then becomes 78 + 6 + 11 – 3 after we simplify multiplication
Then we simplify addition to get 95 – 3 = 92
15) Answer (D)
When we solve questions involving multiple brackets, we solve the inside brackets first and gradually simplify the outer brackets.
(76-17-61) = 59 – 61 = -2
So,102-(91-(83-(76-17-61))) = 102-(91-(83-(-2)))
Minus of a negative number = positive value of the same number.
So, -(-2) = +2
Hence, 102-(91-(83-(-2))) = 102-(91-(85)) = 102 – 6 = 96
We hope this Simplification Question & Answers PDF of SBI Clerk is very Useful for preparation of SBI Clerk Exams.
