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# RRB Group-D Previous Year Maths Questions PDF

Download Top 15 RRB Group-D Previous year Maths Questions and Answers PDF. RRB Group-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.

Question 1: Pipe A can fill a tank in 2 hrs, Pipe B can fill the same tank in 3 hrs, In how many hours both pipes together can fill the tank ?

a) $1\frac{2}{5}$

b) $1\frac{1}{5}$

c) $1\frac{3}{5}$

d) $1\frac{4}{5}$

Question 2: It is known that 0 < θ < 90 and it is given that cot θ = 5/12. Find the value of cosecθ

a) 5/13

b) 13/12

c) 12/5

d) 12/13

Question 3: $\frac{sinA+sinB}{cosA-cosB}$ = ?

a) -cot($\frac{A-B}{2}$)

b) -tan($\frac{A-B}{2}$)

c) cot($\frac{A+B}{2}$)

d) tan($\frac{A+B}{2}$)

Question 4: If $a^3+b^3+c^3=3abc$, then find $a^2+b^2+c^2+ab+bc+ca = ?$

a) 0

b) $-ab-bc-ca$

c) $bc-ca-ab$

d) 2

Question 5: If $x+\frac{1}{x} = 2$ then find $x^8+\frac{1}{x^8}$?

a) 8

b) 4

c) 2

d) 16

Question 6: The average of four consecutive odd numbers is 28. Find the smallest number.

a) 25

b) 29

c) 33

d) 37

Question 7: What is the fourth proportional of 12,36 and 108 ?

a) 144

b) 162

c) 324

d) 216

Question 8: An airplane has A class tickets and B class tickets,number of people in A class to B class is 1:3 and the fares for A to B class ticket is 6:5. If the total amount collected is 4200. What is the amount collected from B class tickets ?

a) 3000

b) 2500

c) 2000

d) 1500

Question 9: $\frac{6}{8}\times \frac{16}{18} \times \frac{3}{4} \times X = \frac{4}{7}$, find $1/X$ ?

a) 4/7

b) 8/7

c) 7/8

d) 7/4

Question 10: $5\frac{3}{4}+4\frac{1}{2}-3\frac{3}{8} = ?$

a) $6\frac{7}{8}$

b) $7\frac{6}{8}$

c) $5\frac{6}{8}$

d) $5\frac{7}{8}$

Question 11: A fruit seller had some mangoes. He sold 30% of mangoes and still has 560 mangoes. How many mangoes he had originally?

a) 300

b) 800

c) 600

d) 450

Question 12: X,Y and Z contested in elections. X got 144 votes and Y got 30% votes of total votes then What is percent of votes received by Z if total number of voters is 300 ?

a) 20%

b) 21%

c) 22%

d) 19%

Question 13: Nithya wants to purchase 12 chocolates, 15 pencils, 13 pens. Cost of 1 pencil is 3/-, cost of 2 pens is 10/- and cost of chocolate is 2/-. Then find the total cost ?

a) 124

b) 134

c) 144

d) 154

Question 14: A number when divided by 11 leaves a remainder of 10 and when divided by 10 leaves a remainder of 8. Which of the following is a possible value of the number?

a) 123

b) 194

c) 62

d) 98

Question 15: Find the slope of the line passing through the points (2, -5) and (6, -7) ?

a) -1/2

b) 1/2

c) -2/3

d) 2/3

Let the capacity of tank = LCM of 2&3 = 6 units

Efficiency of pipe A = 6/2 = 3

Efficiency of pipe B = 6/3 = 2

Both together can fill the tank in $\frac{6}{2+3} hrs = \frac{6}{5} hrs = 1\frac{1}{5}hrs$

So the answer is option B.

$\text{cot} \theta = \frac{5}{12}$

$\text{cosec}^2 \theta$ = $1+\text{cot}^2 \theta = 1+{(\frac{5}{12})}^2 = \frac{169}{144}$

$\text{cosec}\theta = \frac{13}{12}$

So the answer is option B.

$\frac{sinA+sinB}{cosA-cosB}$

=$\frac{2sin(\frac{A+B}{2})cos(\frac{A-B}{2})}{-2sin(\frac{A+B}{2})sin(\frac{A-B}{2})}$

=-cot($\frac{A-B}{2}$)

So the answer is option A.

If $a^3+b^3+c^3=3abc$, then $a+b+c = 0$

$(a+b+c)^2 = 0$

$a^2+b^2+c^2+2ab+2bc+2ca = 0$

$a^2+b^2+c^2+ab+bc+ca = -ab-bc-ca$

So the answer is option B.

$x+\frac{1}{x} = 2$

Squaring on both sides

$(x+\frac{1}{x})^2 = 4$

$x^2+\frac{1}{x^2}+2 = 4$

$x^2+\frac{1}{x^2} = 2$

Squaring on both sides

$(x^2+\frac{1}{x^2})^2 = 4$

$x^4+\frac{1}{x^4}+2 = 4$

$x^4+\frac{1}{x^4} = 2$

Squaring on both sides

$(x^4+\frac{1}{x^4})^2 = 4$

$x^8+\frac{1}{x^8}+2 = 4$

$x^8+\frac{1}{x^8} = 2$

So the answer is option C.

Let the smallest odd number be x.
Given, $\dfrac{x+x+2+x+4+x+6}{4} = 28$
⇒ 4x+12 = 112
⇒ 4x = 100
⇒ x = 25
Hence, The smallest odd number = x = 25.

For fourth proportional we have 12:36::108:x
Therefore 12x=36*108
x=324

Let the people in A class and B class be 1x and 3x respectively
and the cost of ticket for A class and B class be 6y and 5y respectively
Total amount from A class is 1x*6y=6xy
Total amount from B class is 3x*5y=15xy
Total amount is 21xy=4200
xy=200
Amount from B class is 15*200=Rs 3000

$\frac{6}{8}\times \frac{16}{18} \times \frac{3}{4} \times X = \frac{4}{7}$

$\frac{3}{4}\times \frac{8}{9} \times \frac{3}{4} \times X = \frac{4}{7}$

$\frac{1}{2} \times X = \frac{4}{7}$

$X = 8/7$

$1/X = 7/8$

So the answer is option B.

$5\frac{3}{4}+4\frac{1}{2}-3\frac{3}{8} = (5+4-3)+(\frac{3}{4}+\frac{1}{2}-\frac{3}{8}) = 6+\frac{7}{8} = 6\frac{7}{8}$

So the answer is option A.

Given that he has sold 30% of mangoes.
Then he now has 70% of mangoes.
70% → 560
100% → ?

$= \dfrac{100\times560}{70} = 800$

=22%

Cost of 1 pencil is 3/-, cost of 2 pens is 10/- and cost of chocolate is 2/-

Cost of 1 pencil is 3/-, cost of 1 pens is 5/- and cost of chocolate is 2/-

Cost of 12 chocolates, 15 pencils, 13 pens = 12(2)+15(3)+13(5) = 24+45+65 = 134/-

So the answer is option B.

$Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{-7+5}{6-2} = \frac{-2}{4} = \frac{-1}{2}$