RRB Group-D Maths Questions PDF
Download Top 15 RRB Group-D Maths Questions and Answers PDF. RRB Group-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.
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Question 1: Find the LCM of 7/2, 9/4 and 5/3 ?
a) 252
b) 21
c) 126
d) 315
Question 2: 4591.15 – 528.116 = x + 456.123. Find x ?
a) 3660.911
b) 3666.911
c) 3006.911
d) 3606.911
Question 3: Sum of two numbers is 99 and difference is 63, then find the smaller number ?
a) 18
b) 36
c) 81
d) 54
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Question 4: What is the value closest to $\sqrt{2028}$ – $\sqrt{1152}$?
a) 8
b) 9
c) 10
d) 11
Question 5: What is the value of $21^3 – 19^3$
a) 2602
b) 2202
c) 2204
d) 2402
Question 6: The simplest form of $\frac{391}{667}$ is
a) $\frac{23}{31}$
b) $\frac{19}{23}$
c) $\frac{15}{19}$
d) $\frac{17}{29}$
RRB Group D previous year papers
Question 7: What is the average of 56, 45, 47, 61, 49, 54 and 52
a) 52
b) 54
c) 49.12
d) 63
Question 8: If the number 254a8b is divisible by 10 as well as 9, find the value of a.
a) 8
b) 9
c) 6
d) 7
Question 9: Find the smallest positive integer that should be multiplied to 2352 to make it a perfect square.
a) 2
b) 3
c) 7
d) 11
Question 10: Find the greatest common divisor of the numbers 75, 155 and 195.
a) 5
b) 15
c) 25
d) None of the above
RRB Group-D Important Questions (download PDF)
Question 11: The least number n, where n>4, which when divided by 9, 11 and 12 leaves a remainder 4 is
a) 396
b) 400
c) 796
d) None of the above
Question 12: 1818.12 + 1818.24 + 1919.19 = ?
a) 5545.45
b) 5333.44
c) 5555.55
d) 5444.44
Question 13: 75% of a number from which 10 has been deducted is 180. The number is
a) 200
b) 240
c) 330
d) 250
Question 14: If a speed of 24 kmph is converted into m/s, what would be the value obtained?
a) 6.67
b) 12.33
c) 13.33
d) 9.67
Question 15: 29% of 9000 + 35% of 5000 = ?
a) 4400
b) 4260
c) 4210
d) 4360
General Science Notes for RRB Exams (PDF)
Answers & Solutions:
1) Answer (D)
LCM of fractions = LCM of numerators/HCF of denominators
LCM of 7/2, 9/4 and 5/3 = (LCM of 7,9,5)/(HCF of 2,4,3) = 315/1 = 315
So the answer is option A.
2) Answer (D)
4591.15 – 528.116 = x + 456.123
4063.034 = x + 456.123
4063.034 – 456.123 = x
3606.911 = x
So the answer is option D.
3) Answer (A)
x+y = 99 —-(1)
x-y = 63 —–(2)
(1)-(2) ==> x+y-x+y = 99-63 ==> 2y = 36 ==> y = 18
So the answer is option A.
4) Answer (D)
The value of $\sqrt{2025}$ = 45
The value of $\sqrt{1152}$ = 34
So, the value closest to $\sqrt{2028}$ – $\sqrt{1152}$ = 11
5) Answer (D)
We know that $a^3 – b^3 = (a-b) \times (a^2 + ab + b^2) = (a-b) \times ((a+b)^2 – ab)$
In this case, $21^3 – 19^3 = (21 – 19) \times (21^2 + 21 \times 19 + 19^2)$
Which equals $2 \times ((21+19)^2 – 21\times 19)$
This equals $2 \times (40^2 – 399) = 2 \times (1600-399) = 2 \times 1201 = 2402$
6) Answer (D)
$\frac{391}{667}$ = $\frac{17 \times 23}{29 \times 23}$ = $\frac{17}{29}$
7) Answer (A)
We see that the numbers are distributed around 50.
So we find the differences around 50
Estimated mean= 50
Sum = +6-5-3+11-1+4+2 =14
n=7
Actual mean = 50 + 14/7 = 52.
8) Answer (A)
Since the number is divisible by 10, b = 0. Since the number is divisible by 9, the sum of the digits is also divisible by 9.
19+a+b should be divisible by 9. Since b = 0, only a = 8, satisfy this criteria.
9) Answer (B)
Let’s factorize 2352 into its prime factors.
2352 = 16 * 3 * 49 = $2^4 * 3 * 7^2 $.
To be a perfect square, the number should have prime factors with even indices. Hence, for 3 to have an even index, the number should be multiplied with 3.
10) Answer (A)
The numbers are $3*5^2$, $5*31$ and $5*39$.
So, the HCF of the three numbers is 5.
11) Answer (B)
$9 = 3^2$
$12 = 3 * 2^2$
So, the LCM of 9, 11 and 12 is $3^2 * 2^2 * 11$ = 9 * 4 * 11 = 396
So, the required number should be of the form 396k + 4
For k = 1, the number becomes 396 + 4 = 400
12) Answer (C)
The summation of first two terms will be = 3636.36 and the whole summation will be 5555.55
13) Answer (D)
Let the number be x. Hence, 75%*(x-10)=180. Hence, x=250.
14) Answer (A)
To convert the value of a speed from m/s to kmph, multiply the speed by 18/5. To convert the value of a speed from kmph to m/s, multiply the speed by 5/18.
So, value in m/s = 24 * 5/18 = 120/18 = 20/3 = 6.67 m/s
15) Answer (D)
29% of 9000 can be calculated as (20+9)% of 9000 i.e. 1800+810 = 2610
and 35% of 5000 will be = 1750
Hence, summation will be = 1750+2610 = 4360
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