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# RRB Group-D Expected Questions PDF

Download Top 15 RRB Group-D Expected Questions and Answers PDF. RRB Group-D Expected questions based on asked questions in previous exam papers very important for the Railway Group-D exam.

Question 1: Which of the following words cannot be formed using the letters of the word ‘INITIATIVE’.

a) VITIATE

b) NATIVE

c) VANITY

d) INVITE

Question 2: How many meaning ful 3 letter words can be made from the letter:B, R, O

a) 0

b) 1

c) 2

d) 3

Question 3: Which of the following Venn diagrams represents the relationship between fathers, sisters, mothers, sons and brothers?

a)

b)

c)

d)

Question 4: A and B can do a piece of work individually in 14 hours and 21 hours respectively. A started the work and will be assisted by B on every alternate hour. Then find the time in which the total work will be completed?

a) 10 hours 40 minutes

b) 12 hours 20 minutes

c) 11 hours 24 minutes

d) 14 hours 40 minutes

Question 5: The ratio of speed of boat upstream, speed of boat in still water and speed of boat downstream is 1:2:3. If speed of current is 18 km/hr, then find the speed of boat in still water.

a) 24 km/hr

b) 36 km/hr

c) 54 km/hr

d) 48 km/hr

Question 6: If ‘+’ means ‘$\times$’, ‘-’ means ‘$\div$’, ‘$\times$’ means ‘-’, ‘$\div$’ means ‘+’, then find the value of $310\div31+7\times2100-4$

a) 1

b) 2

c) 3

d) 4

Question 7: Which of the following set of mathematical signs from the given options must replace “@” in the following equation?
36@3@48@2000@40=110

a) $\times,-,+,\div$

b) $+,\times,\div,-$

c) $\times,-,+,\div,$

d) $-,+,\times,\div$

Question 8: If M means miltiplication, A means addition, S means subtraction and D means division, find the value of 11A91D13M8S5?

a) 62

b) 32

c) 139

d) 121

Question 9: Given is a statement followed by two arguments numbered I and II. Consider the statement and the arguments and decide which of the arguments is strong.
Statement:
We should not drink coffee every day.
Arguments:
I: Coffee changes the sleep cycle.
II: Coffee contains caffeine.

a) Only argument I is strong.

b) Only argument II is strong.

c) Neither of the arguments is strong.

d) Both the arguments are strong.

Question 10: If 4 and -2 are the roots of the equation $ax^2 + 16x + c = 0$, find a+c.

a) -72

b) -80

c) 56

d) Can’t be determined

Instructions

Study the following information carefully and answer the questions given below:
Four friends A, B, C and D, come from different places out of P, Q, R and S not necessary in the same order. All the four friends also own different cars out of L, M, N and O and each car is of a different colour out from W, X, Y and Z not necessary in the given order. Further following info is also known –
1) D has a car with Y colour.
2) A is from R and colour of his car is Z.
3) The colour of car N is W.
4) B is from S and owns L.
5) The friend with car M is from P.

Question 11: The friend who comes from place Q has a car of which colour?

a) Z

b) X

c) W

d) Y

Question 12: Who owns car O?

a) C

b) A

c) D

d) B

Question 13: Bag ‘A’ contains 4 red balls and 3 black balls and Bag ‘B’ contains 3 red and 2 black balls. If Ravi takes 1 ball each from both the bags, what is the probability that both the balls are of the same colour ?

a) $\frac{18}{35}$

b) $\frac{12}{35}$

c) $\frac{06}{35}$

d) $\frac{21}{35}$

Question 14: In how many ways can the letters of the word ‘COMPUTER’ be arranged such that the letter ‘C’ is always at the start?

a) 5040

b) 120

c) 40320

d) 40230

Question 15: Select the missing number ‘?’ from the given options

a) 10

b) 13

c) 9

d) 14

Letter ‘Y’ is not present in the word ‘INITIATIVE’. Thus, ‘VANITY’ cannot be formed.
Hence, option C is the right answer.

Only two words ROB and ORB can be formed using these letters.

All fathers and brothers are definitely sons. Some fathers are brothers and some brothers are fathers. Therefore, these 3 must be represented as 2 intersecting circles inside a large circle.

Some mothers are sisters and some sisters are mothers. These must be represented by 2 intersecting circles. Only option B satisfies these conditions and hence, option B is the right answer.

Let the total work be 42 units (LCM of 14 and 21)
Efficiency of A = 42/14 = 3 units/hour
Efficiency of B = 42/21 = 2 units/hour
A is assisted by B on every alternate hour
A can complete 3 units of work in first hour
A and B can complete 5 units of work in second hour.
Hence, 8 units of work will be completed in 2 hours.
Then, 40 units of work will be completed in 10 hours.
Remaining work = 2 units.
A can do 2 units of work in 2/3rd of an hour = $\dfrac{2}{3}\times60 = 40$ minutes
Therefore, Total work will be completed in 10 hours 40 minutes.

Let the speed of boat upstream be ‘x’ km/hr
Speed of boat in still water = 2x km/hr
Speed of boat downstream = 3x km/hr
Then, Speed of current = 3x-2x = x km/hr
Given, Speed of current = 18 km/hr
x → 18 km/hr
Speed of boat in still water = 2x = 36 km/hr

After decoding we have $310+31\times7-2100\div4$
=527-525
=2

By checking the options for option 3 applying BODMAS rule we have
36$\times$3-48+2000$\div$40=108-48+50
=110

$11+91\div13*8-5 = 11+7*8-5 = 11+56-5 = 62$

Argument 1 is incorrect because we do not know whether the person wants to change their sleep cycle or not. (For e.g. staying awake to study/work etc.) Argument 2 is incorrect because it is not mentioned whether caffeine is a harmful substance or not. So, Option C is correct.

We know that,
sum of the roots = -16/a = 4-2 = 2
a = -8
Product of the roots = c/a = 4*-2 = -8
c= -8 * a = -8 * -8 = 64

Hence, a+c = -8+64 = 56

Let us start by filling the given information.

D has a car with Y colour. B is from S and owns L. A is from R and the colour of his car is Z.

The colour of car N is W. The friend with car M is from P. Therefore, N-W form a pair and M-P form a pair.
From the table, we can see that C must have car N and D must have car M.

C must be from Q, A must own O and B must own a car of colour X. Therefore, the final arrangement is as follows.

The person from Q has a car of colour W.

Hence, option C is the right answer.

Let us start by filling the given information.

D has a car with Y colour. B is from S and owns L. A is from R and the colour of his car is Z.

The colour of car N is W. The friend with car M is from P. Therefore, N-W form a pair and M-P form a pair.
From the table, we can see that C must have car N and D must have car M.

C must be from Q, A must own O and B must own a car of colour X. Therefore, the final arrangement is as follows.

As we can see, A owns car O. Therefore, option B is the right answer.

First let us assume that red ball is picked from both the bags and so
Probability of selecting red ball from bag ‘A’ is $4c1/7c1$
Probability of selecting red ball from bag ‘B’ is $3c1/5c1$
And so probability of selecting red ball from both the bags is (4/7)*(3/5)=12/35
Now let us assume that black ball is picked from both the bags and so
Probability of selecting black ball from bag ‘A’ is $3c1/7c1$
Probability of selecting black ball from bag ‘B’ is $2c1/5c1$
And so probability of selecting black ball from both the bags is(3/7)(2/5)=6/35
Therefore probability of selecting same colour ball =(12/35)+(6/35)
=18/35

$4^2 – 6^2 + 11^2 = 101$
$7^2 – 9^2 + 12^2 = 112$
$?^2 = -8^2 + 5^2 + 139 = 100 = 10^2$