# Ration and Proportion Questions for MAH – CET PDF

Here you can download CMAT 2022 – important MAH – CET Ratio and Proportion Questions PDF by Cracku. Very Important MAH – CET 2022 and These questions will help your MAH – CET preparation. So kindly download the PDF for reference and do more practice.

Download Ratio and Proportion Questions for MAH – CET

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**Instructions**

Directions: Study the information carefully to answer these questions.

In a team, there are 240 members (males and females). Two-thirds of them are males. Fifteen per cent of males are graduates. The remaining males are non-graduates. Three-fourths of the females are graduates. The remaining females are non-graduates.

**Question 1:Â **What is the absolute difference between the number of females who are non-graduates and the number of males who are graduates?

a)Â 2

b)Â 24

c)Â 4

d)Â 116

e)Â 36

**Question 2:Â **What is the sum of the number of females who are graduates and the number of males who are non-graduates?

a)Â 184

b)Â 96

c)Â 156

d)Â 84

e)Â 196

**Question 3:Â **What is the ratio of the total number of males to the number of females who are non-graduates?

a)Â 6 : 1

b)Â 8 : 1

c)Â 8 : 3

d)Â 5 : 2

e)Â 7 : 2

**Question 4:Â **The ratio of the present age of Manisha and Deepali is 5 : X. Manisha is 9 years younger than Parineeta. Parineetaâ€™s age after 9 years will be 33 years. The difference between Deepaliâ€™s and Manishaâ€™s age is the same as the present age of Parineeta. What should come in place of X?

a)Â 23

b)Â 39

c)Â 15

d)Â Cannot be determined

e)Â None of these

**Question 5:Â **The average marks in English of a class of 24 students is 56. If the marks of three students were misread as 44, 45 and 61 in lieu of the actual marks 48, 59 and 67 respectively, then what would be the correct average?

a)Â 56.5

b)Â 59

c)Â 57.5

d)Â 58

e)Â None of these

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**Question 6:Â **In an enterance examination, Ritu scored 56 percent marks, Smita scored 92 percent marks and Rina scored 634 marks. The maximum marks of the examination is 875. What is the average marks scored by all the three girls together?

a)Â 1929

b)Â 815

c)Â 690

d)Â 643

e)Â None of these

**Question 7:Â **A certain amount was to be distributed among A, B and C in the ratio 2 : 3 : 4 respectively, but was erroneously distributed in the ratio 7 : 2 : 5 respectively. As a result of this, B got Rs.40 Less. What is the amount?

a)Â Rs.210

b)Â Rs.270

c)Â Rs.230

d)Â Rs.280

e)Â None of these

**Question 8:Â **Rs.73,689 are divided between A and B in the ratio of 4 : 7. What is the difference between thrice the share of A and twice of the share of B?

a)Â Rs.36,699

b)Â Rs.46,893

c)Â Rs.20,097

d)Â Rs.26,796

e)Â Rs.13,398

**Question 9:Â **A mixture of 150 L of wine and water contains 20% water. How many litres of water must be added so that water may be 25% of the mixture?

a)Â 12 L

b)Â 8 L

c)Â 10 L

d)Â 6 L

e)Â None of these

**Question 10:Â **Present age of a father is 3 times the present age of his son. 4 years later fatherâ€™s age is 13 more than 2 times of his sonâ€™s age. What is present age of father?

a)Â 54

b)Â 53

c)Â 51

d)Â 63

e)Â 52

**Question 11:Â **52% students from a college participated in a survey. What is the respective ratio between the numbers of students who did not participate in the

survey to the numbers of students who participated ?

a)Â 11:13

b)Â 12:13

c)Â 12:17

d)Â Cannot be determind

e)Â None of these

**Instructions**

Study the following table and answer the questions that follow:

**Question 12:Â **What is the average number of females specializing in HRM from all the colleges together ?

a)Â 30

b)Â 45

c)Â 50

d)Â 55

e)Â None of these

**Question 13:Â **The total number of males in college L are approximately what percent of total females from the same college ?

a)Â 10

b)Â 30

c)Â 50

d)Â 110

e)Â 70

**Question 14:Â **What is the respective ratio between the total numbers of students specializing in Economics from college P and the total number of students

specializing in Psychology from the same college ?

a)Â 29:31

b)Â 25:34

c)Â 28:39

d)Â 25:39

e)Â None of these

**Question 15:Â **The total number of females specializing in Political Science from college K,N and P together are approximately what percent of the males

specializing in the same field from the same colleges ?

a)Â 210

b)Â 90

c)Â 190

d)Â 150

e)Â 110

**Question 16:Â **How many students are there in college M from all the specializations together ?

a)Â 574

b)Â 576

c)Â 572

d)Â 568

e)Â None of these

**Question 17:Â **28% members of a certain group are married. What is the respective ratio between the number of married members to the number of unmarried members ?

a)Â 7:17

b)Â 5:18

c)Â 7:18

d)Â Cannot be determined

e)Â None of these

**Question 18:Â **If the numerator of a certain fraction increased by 200% and the denominator is increased by 150% the new fraction thus formed is $\frac{9}{10}$. What is the original fraction ?

a)Â $\frac{3}{4}$

b)Â $\frac{1}{4}$

c)Â $\frac{3}{5}$

d)Â $\frac{2}{5}$

e)Â None of these

**Question 19:Â **Yesterday Priti typed an essay of 5000 words at speed of 60 words per minute. Today she typed the same essay faster and her speed was 15% more than yesterday. What is the approximate difference in the time she took to type yesterday and the time she took to type today?

a)Â 20 minutes

b)Â 30 minutes

c)Â 10 minutes

d)Â 40 minutes

e)Â 1 hour

**Question 20:Â **The age of the father is 30 years more than the sonâ€™s age.Ten years hence the fatherâ€™s age will become three times the sonâ€™s age that time.What is the sonâ€™s present age in years?

a)Â Eight

b)Â Seven

c)Â Five

d)Â Cannot be determined

e)Â None of these

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**Answers & Solutions:**

**1)Â AnswerÂ (C)**

Total members = 240

Total males = 160

Total Females = 80

15% of males are graduates => 24 male graduates

75% of females are graduates => 60 female graduates

Absolute Difference between number of females who are non-graduates and number of males who are graduates = 24 – 20 = 4

**2)Â AnswerÂ (E)**

Total members = 240

Total males = 160

Total Females = 80

15% of males are graduates => 24 male graduates => 136 male non-graduates

75% of females are graduates => 60 female graduates => 20 female non-graduates

=>Â sum of the number of females who are graduates and the number of males who are non-graduates = 136 + 60 = 196

**3)Â AnswerÂ (B)**

Total members = 240

Total males = 160

Total Females = 80

15% of males are graduates => 24 male graduates => 136 male non-graduates

75% of females are graduates => 60 female graduates => 20 female non-graduates

Ratio of total number of males to number of female non-graduates = 160 : 20 = 8 : 1

**4)Â AnswerÂ (E)**

Parineetaâ€™s present age = 33 – 9 = 24 yrs.

Manishaâ€™s present age = 24 – 9 = 15yrs

Difference between Manisha and Deepali’s prresent ages = Parineeta’s present age

Deepaliâ€™s present age = Parineeta’s present age + Manisha’s present age = 24 + 15 = 39 yrs.

Ratio of the present age of Manisha and Deepali = 15 : 39 = 5 : 13

x = 13

**5)Â AnswerÂ (E)**

Total marks = 24 x 56 = 1344

Sum of actual marks = 1344 – (44 + 45 + 61) + (48 + 59 + 67) = 1368

Actual Average = $\frac{1368}{24}$ = 57

**6)Â AnswerÂ (D)**

Ritu’s marks = 56% of 875 = $\frac{56}{100}$ = 490

Smita’s marks = 92% of 875 = $\frac{92}{100}$ = 805

Rina’s marks = 634

Total marks = 1929

Average = $\frac{490 + 805 + 634}{3}$ = $\frac{1929}{3}$ = 643

**7)Â AnswerÂ (A)**

Let the amount be x

If the amount is divided into 9 parts , each part =Â $\frac{x}{9}$

B’s supposed amount = 3 xÂ $\frac{x}{9}$ =Â $\frac{x}{3}$

But B’s actual amount = 2 xÂ $\frac{x}{14}$ =Â $\frac{x}{7}$

$\frac{x}{3}$ –Â $\frac{x}{7}$ = 40

x = 210

**8)Â AnswerÂ (E)**

Share of A =Â $\frac{4}{11}$ x 73689 = 26796

Thrice share of A = 80388

Share of B =Â $\frac{7}{11}$ x 73689 = 46893

Twice the share of B = 93786

Difference = 13398

**9)Â AnswerÂ (C)**

The mixture contains 20% water and 80% of wine.

By the rule of allegation, Ratio of wine : water = 75 : 5 = 15 : 1

For 15 L wine, 1 L water is to be added.

âˆ´ For 150 L wine,$\frac{(150*1)}{15}=10$ L to be added.

**10)Â AnswerÂ (C)**

letâ€™s say present age of son is x, hence fatherâ€™s age will be 3x

4 years later, (x+4)*2 +13 = 3x+4 ; x=17 and 3x=51

**11)Â AnswerÂ (B)**

Let x be the total number of students.

52% of the students participated i.e .52x students participated.

48% of the students did not participate i.e .48x students did not participate.

Hence the ratio of students who did not participate to the students who participated is $\frac{.48x}{.52x}$ = $\frac{12}{13}$

**12)Â AnswerÂ (C)**

The average of all the females studying HRM in different colleges = [36+58+85+54+47+20]/6 = $\frac{300}{6}$ =50

**13)Â AnswerÂ (E)**

Total number of males in college L = 62+34+15+18+56+58= 243

Total number of females in college L = 65+14+58+56+65+86=344

Now, for percent of male of total females = 243/344 * 100 = 70%

**14)Â AnswerÂ (E)**

Total number of students specializing in economics in college P = 87

Total number of students specializing in physchology in college P = 117

Ratio = 87/117

**15)Â AnswerÂ (E)**

The required percentÂ = (Number of females/Number of males)*10 = (57+79+24)/(56+86+35)*100=(177/166)*100=110

**16)Â AnswerÂ (C)**

Total number of student is addition of all the students doing all the specialization = 18+28+67+25+26+85+25+35+64+85= 572

**17)Â AnswerÂ (C)**

Let total number of members be T.

The number of married number if percent is 28% = .28T

Hence, percent of unmarried members = (100-28)%=72%

And the number = .72T

The ratio of married to unmarried= .28/.72 = $\frac{7}{18}$

**18)Â AnswerÂ (A)**

Let numerator be x and denominator be y.

If numerator is increased by 200% it becomes 3x and if numerator is increased by 150% it becomes 2.5y

Now the new fraction is 9/10.

Hence, (3x/2.5y)=(9/10) which gives $\frac{x}{y}$=$\frac{3}{4}$

**19)Â AnswerÂ (C)**

The time taken by her to type 5000 words essay at a speed of 60words/min = 5000/60=83.33

Now when the speef is increased by 15%, the new speed = 69 words/min|

Time taken by her to type 5000 words essay with this speed = 5000/69 = 72.46

Time difference ~ 10 minutes

**20)Â AnswerÂ (C)**

Let the son age be x and fathers age be y.

The solution is obtained by solving two simultaneous equations as per given conditions,

x=y+10 and x+10=3(y+10)

Hence, y = 5