**Percentage Questions for SSC CGL PDF:**

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**Question 1:Â **If 30% of A is added to 40% of B, the answer is 80% of B. What percentage of A is B?

a) 30%

b) 40%

c) 70%

d) 75%

**Question 2:Â **A man spends 59% of his income and saves the rest. What percentage of his expenditure does he save?

a) 72.57 percent

b) 83.19 percent

c) 89.09 percent

d) 69.49 percent

**Question 3:Â **A grain dealer cheats to the extent of 10% while buying as well as selling by using false weights. His total profit percentage is :

a) 20%

b) 22.22%

c) 23.23%

d) 25%

**Question 4:Â **The costs of daily ticket of local train is Rs 130 and Monthly Pass costs Rs 3091.40. If I buy the Monthly Pass and travel for 29 days in a month than I save (in percentage)?

a) 16 percent

b) 18 percent

c) 15 percent

d) 14 percent

**Question 5:Â **The ratio of the number of boys and girls in a school is 2 : 3. If 25% of the boys and 30% of the girls are scholarship holders, the percentage of the school students who are not scholarship holders is

a) 72

b) 36

c) 54

d) 60

**Question 6:Â **The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is equal to

a) 32%

b) 34%

c) 42%

d) 44%

**Question 7:Â **A man spends 75% of his income. His income increases by 20% and his expenditure also increases by 10%. The percentage of increase in his savings is

a) 40%

b) 30%

c) 50%

d) 25%

**Question 8:Â **The marked price of a shirt is Rs 1280. If the shirt is being sold for Rs 900, then what is the discount percentage?

a) 31.31

b) 25.57

c) 29.68

d) 34.36

**Question 9:Â **The weights of two iron balls are 3.5 kg and 7.5 kg. What is the percentage weight of the 1st ball with respect to 2nd ball.

a) $46\frac{2}{3}4632â€‹%$

b) 35%

c) $46\frac{1}{3}4631â€‹%$

d) 45%

**Question 10:Â **A student multiplied a number by 5/6 instead of 6/5. What is the percentage error in the calculation?

a) 44 percent

b) 30.56 percent

c) 15.28 percent

d) 22 percent

**Answers & Solutions forÂ Percentage Questions for SSC CGL PDF:**

**1) Answer (D)**

it is given that

0.3 A + 0.4 B = 0.8 B

0.3 A = 0.4 B

A = 4/3 B

B = 3/4 A

hence B is 75 % of A

**2) Answer (D)**

Let total income of man =Â Rs. 100x

Amount spent = $\frac{59}{100} \times 100x = Rs. 59x$

=> Money saved = $100x – 59x = 41x$

âˆ´Â Percentage of his expenditure that he saves = $\frac{41x}{59x} \times 100$

= 69.49 %

**3) Answer (B)**

let the retailer buys 110 gram in Rs 100 because of 10 % cheating

so cost price = 1 gram = Rs 100/110 = Rs 0.909

and retailer sells 90 gram in Rs 100

and hence selling price = Rs 100 / 90 = Rs 1.111

Profit % = $\frac{1.111- 0.909}{0.909}Â = 22.22%$

**4)Â Answer (B)**

Train ticket cost for 1 day = Rs. 130

=> Cost for 29 days = $29Â \timesÃ—Â 130 = Rs. 3770$

Cost of monthly pass = Rs. 3091.40

=> Money saved = 3770 – 3091.40 = Rs 678.6

âˆ´Â Required % = $\frac{678.6}{3770} \times 100 = 18%$

=> Ans – (B)

**5) Answer (A)**

Let the number of boys be 2y and number of girls be 3y

25 % of boys = 0.25 x 2y = 0.5y

30% of girls = 0.3 x 3y = 0.9y

total scholarship holder = 0.5y + 0.9y = 1.4y

% of no scholarship holder = $\frac{3.6y}{5y}Â \times 100 = 72%$

**6) Answer (D)**

let the length of rectangle be L units and breadth be B units.

So area of rectangle = L x B

As both length and breadth has been increased by 20%

So new length = 1.2L

New breadth = 1.2B

New area = 1.2L x 1.2B = 1.44LB

Percentage increase in area = $\frac{1.44LB – LB}{LB}Â â€‹\times 100 = 44%$

**7) Answer (C)**

let the income of person be Rs y

So his expenditure be 75% of income which is = 0.75y

Saving = y- 0.75y = 0.25y

Now after increment of 20 % in income the new income becomes = 1.2y

Given that bew expenditure is 10% more than previous one.So , new expenditure is = 1.1 Ã— 0.75y = 0.825y

New savings = 1.2y – 0.825y = 0.375y

Percentage increase in savings = $\frac {0.375y-0.25y}{0.25y} \timesÂ 100 = 50%

**8) Answer (C)**

Marked price = Rs. 1280

Selling price = Rs. 900

=> Discount % = $\frac{1280-900}{1280}\times 100$

= $\frac{380}{12.8}=29.68%$

**9) Answer (A)**

Weight of 1st ball = 3.5 kg and weight of second ball = 7.5 kg

=> Percentage weight of the 1st ball with respect to 2nd ball

= $\frac{3.5}{7.5} \times 100$

= $\frac{35}{3} \times 4$ = $\frac{140}{3}$

= $46\frac{2}{3}%$

**10) Answer (B)**

Let the number be 30

When the student multiplied it by 5/6, => original result = $\frac{5}{6} \times 30 = 25$

When the student multiply it by 6/5, => New result = $\frac{6}{5} \times 30 = 36$

=> Percentage error in calculation = $\frac{(36 – 25)}{36} \times 100$

= $\frac{1100}{36} = 30.56%$

=> Ans – (B)

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