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# Number Series Questions For IBPS PO PDF:-

Download Number Series Questions For IBPS PO PDF. Practice IBPS PO Number series questions with solutions for Banking exams based on asked questions in previous papers.

Instructions: Instructions: In the following number series only one number is wrong. Find out the wrong number.

Question 1: 7, 12, 40, 222, 1742, 17390, 208608

a) 7
b) 12
c) 40
d) 1742
e) 208608

Question 2: 6, 91, 584, 2935, 11756, 35277, 70558

a) 91
b) 70558
c) 584
d) 2935
e) 35277

Question 3: 9050, 5675, 3478, 2147, 1418, 1077, 950

a) 3478
b) 1418
c) 5673
d) 2147
e) 1077

Question 4: 1, 4, 25, 256, 3125, 46656, 823543

a) 3125
b) 823543
c) 46656
d) 25
e) 256

Question 5: 8424, 4212, 2106, 1051, 526.5, 263.25, 131.625

a) 131.625
b) 1051
c) 4212
d) 8424
e) 263.25

Instructions: In each of these questions a number series is given. In each series only one number is wrong. Find out the wrong number.

Question 6: 5531    5506    5425    5304    5135    4910    4621

a) 5531
b) 5425
c) 4621
d) 5135
e) 5506

Question 7: 6 7 9 13 26 37 68

a) 7
b) 26
c) 69
d) 37
e) 9

Question 8: 1    3    10    36    152    760    4632

a) 3
b) 36
c) 4632
d) 760
e) 152

Question 9: 4    3    9    34    96    219    435

a) 4
b) 9
c) 34
d) 435
e) 219

Question 10: 157.5 45 15 6 3 2 1

a) 1
b) 2
c) 6
d) 157.5
e) 45

(7-1) x 2 = 12
(12 – 2) x 4 = 40
(40 – 3) x 6 = 222
(222 – 4) x 8 = 1744 ≠ 1742
(1744 – 5) x 10 = 17390
(17390 – 6) x 12 = 208608

$6 x 7 + 7^2 = 91 , 91 x 6 + 6^2 = 582 ≠ 584 , 582 x 5 + 5^2 = 2935,…$

$9070 – 15^3 = 5675 , 5675 – 13^3 = 3478 , 3478 – 11^3 = 2147 , 2147 – 9^3 = 1418 ,\\ 1418 – 7^3 = 1075 ≠ 1077 , 1075 – 5^3 = 950$

$1^1 = 1 , 2^2 = 4 , 3^3 = 27 ≠ 25 , 4^4 = 256 , 5^5 = 3125 , 6^6 = 46656 , 7^7 = 823543$

$\frac{8424}{2}$ = 4212

$\frac{4212}{2}$ = 2106

$\frac{2106}{2}$ = 1053 ≠ 1051

$\frac{1051}{2}$ = 526.5

$\frac{525.5}{2}$ = 263.25

$\frac{263.25}{2}$ = 131.625

5531 – $5^2$ = 5506
5506 – $9^2$ = 5425
5425 – $11^2$ = 5304
5134 – $13^2$ = 5135
5135 – $15^2$ = 4910
4910 – $17^2$ = 4621

Ever number after 5531 has a difference of a square.
Hence 5531 is the wrong number.

6 + 1 = 7
7 + 2 = 9
9 + 4 = 13
13 + 13 = 26
26 + 11 = 37
37 + 22 = 69
The number to be added is increasing everytime except for 37 where 11 is added after 13.

(1 x 1) + 2 = 3
(3 x 2) + 4 = 10
(10 x 3) + 6 = 36
(36 x 4) + 8 = 152
(152 x 5) + 10 = 770 ≠760
(770 x 6) + 12 = 4632

$0^2$ + 4 = 4
$1^2$ + 2 = 3
$3^2$ + 0 = 9
$6^2$ – 2 = 34
$10^2$ – 4 = 96
$15^2$ – 6 = 219
$21^2$ – 8 = 433 ≠ 435