**Missing Number Questions for SSC Stenographer PDF**

SSC Stenographer Missing Number Questions and Answers download PDF based on previous year question papers of SSC exam. 20 Very important Missing Number Questions for Stenographer.

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SSC Stenographer Previous Papers

**Question 1: **In the following question, select the missing number from the given series.

a) 81

b) 45

c) 99

d) 28

**Question 2: **Find the missing number as per given series in table ?

a) 10

b) 91

c) 17

d) 81

**Question 3: **Find the missing number as per given series ?

a) 2197

b) 729

c) 709

d) 1000

**Question 4: **In the following question, select the missing number from the given series.

a) 45

b) 23

c) 20

d) 51

**Question 5: **In the following question, select the missing number from the given series

a) R

b) K

c) L

d) O

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**Question 6: **In the following question, select the missing number from the given series.

a) 8

b) 12

c) 7

d) 9

**Question 7: **In the following question, select the missing number form the given series

a) 124

b) 132

c) 120

d) 125

**Question 8: **In the following question, select the missing number from the given series.

a) 17

b) 18

c) 10

d) 9

**Question 9: **In the following question, select the missing number from the given series

a) 119

b) 120

c) 170

d) 190

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**Question 10: **In the following question, select the missing number from the given series.

a) 47

b) 49

c) 50

d) 57

**Question 11: **__In the following questions select the missing number from the given series.__

a) 81

b) 361

c) 289

d) 225

**Question 12: **In the following question select the missing number of the given series

a) 9

b) 8

c) 6

d) 7

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**Answers & Solutions:**

**1) Answer (C)**

In each column, the number at the end is reverse of the product of other two.

Eg :- $7\times7=49\equiv94$

$6\times8=48\equiv84$

Similarly, $9\times11=99\equiv99$

=> Ans – (C)

**2) Answer (A)**

In each column, the number at the end is obtained by adding the squares of other two numbers.

Eg :- $(12)^2+(16)^2=144+256=400$

$(13)^2+(17)^2=169+289=458$

Similarly, $(11)^2+(x)^2=221$

=> $x^2=221-121=100$

=> $x=\sqrt{100}=10$

=> Ans – (A)

**3) Answer (A)**

The number at the end in each column is the cube of the sum of other two numbers.

Eg :- $(5+2)^3=(7)^3=343$

$(3+5)^3=(8)^3=512$

Similarly, $(6+7)^3=(13)^3=2197$

=> Ans – (A)

**4) Answer (B)**

The sum of each column is same.

Eg :- $64+32+9=105$

and $56+20+29=105$

Similarly, $46+36+x=105$

=> $x=105-82=23$

=> Ans – (B)

**5) Answer (B)**

The pattern followed is that the alphabets are numbered alphabetically, A=1, B=2, C=3 and so on and then the first alphabet in each column is obtained by :

F=6 and J=10, => $6+10=16\equiv P$

C=3 and J=10, => $3+10=13\equiv M$

Similarly, Q=17 and F=6, => $17-6=11\equiv K$

=> Ans – (B)

**6) Answer (A)**

The number at the end in each column is obtained by multiplying the other two.

Eg :- $7\times5=35$ and $17\times3=51$

Similarly, $13\times x=104$

=> $x=\frac{104}{13}=8$

=> Ans – (A)

**7) Answer (B)**

In each column, the first number is the square of the number which is obtained, by dividing the other two.

Eg :- $(\frac{96}{6})^2=(16)^2=256$

and $(\frac{85}{5})^2=(17)^2=289$

Similarly, $(\frac{x}{6})^2=484=(22)^2$

=> $x=22\times6=132$

=> Ans – (B)

**8) Answer (C)**

The pattern followed is that the alphabets are numbered alphabetically, A=1, B=2, C=3 and so on and then the first number in each column is obtained by :

D=4 and W=23, => $23-4=19$

E=5 and J=10, => $10-5=5$

Similarly, P=16 and Z=26, => $26-16=10$

=> Ans – (C)

**9) Answer (A)**

The pattern followed is that in each row the number at the end is the square root of the product of first two.

Eg :- $\sqrt{25\times144}=\sqrt{5\times5\times12\times12}=5\times12=60$

$\sqrt{81\times225}=\sqrt{9\times9\times15\times15}=9\times15=225$

Similarly, $\sqrt{49\times289}=\sqrt{7\times7\times17\times17}=7\times17=119$

=> Ans – (A)

**10) Answer (B)**

The pattern followed is that the numbers at the corresponding edges are squares of consecutive natural numbers.

Eg :- Top left : $(1)^2=1,(2)^2=4,(3)^2=9$

Top right : $(2)^2=4,(3)^2=9,(4)^2=16$

Similarly, $(5)^2=25,(6)^2=36,(7)^2=49$

Thus, missing term = **49**

=> Ans – (B)

**11) Answer (D)**

In each row, the number in the middle is the square of the first number.

Eg :- $13^2=169$ and $12^2=144$

Similarly, $15^2=225$

=> Ans – (D)

**12) Answer (C)**

The sum of each column is same.

Eg :- $6+7+3=16$

and $10+2+4=16$

Similarly, $9+1+x=16$

=> $x=16-10=6$

=> Ans – (C)

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