Maths Questions for SSC CHSL Set-2 PDF
Download SSC CHSL Maths Questions with answers Set-2 PDF based on previous papers very useful for SSC CHSL Exams. Top-10 Very Important Questions for SSC Exam
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Question 1: What is the mean of the range, median and mode of the data:
$2, 3, 1, 1, 3, 4, 2, 1, 1, 4, 5, 2, 4, 2, 2, 1, 3, 3, 2, 5$
a) $3\frac{1}{3}$
b) $4\frac{1}{2}$
c) $2\frac{2}{3}$
d) $4$
Question 2: The value of $\left(\frac{7}{8}\div5\frac{1}{4}\times7\frac{1}{5}-\frac{3}{20}of\frac{2}{3}\right)\div\frac{1}{2}+\left(\frac{3}{5}\times7\frac{1}{2}+\frac{2}{3}\div\frac{8}{15}\right)$ is equal to 7 + k, where k =
a) $\frac{3}{5}$
b) $\frac{1}{5}$
c) $\frac{1}{20}$
d) $\frac{19}{20}$
Question 3: The value of $2 \times 3 \div 2 of 3 \times 2 \div (4 + 4 \times 4 \div 4 of 4 – 4 \div 4 \times 4)$ is:
a) 8
b) 1
c) 4
d) 2
Question 4: The value of
$\frac{9}{15} of \left(\frac{2}{3} \div \frac{2}{3} of \frac{3}{2}\right) \div \left(\frac{3}{4} \times \frac{3}{4} \div \frac{3}{4} of \frac{4} {3}\right) of \left(\frac{5}{4} \div \frac{5}{2} \times \frac{2}{5} of \frac{4}{5}\right)$ is:
a) $\frac{20}{9}$
b) $\frac{4}{25}$
c) $\frac{18}{125}$
d) $\frac{40}{9}$
Question 5: The value of $\frac{8}{9} of \left(5\frac{1}{4} \div 2\frac{1}{3} of 4\right) \div \left(8 \div \frac{2}{3} of \frac{4}{5}\right) of \left(8 \times \frac{2}{3} \div \frac{4}{5}\right)$ is:
a) $\frac{1}{200}$
b) $1\frac{1}{8}$
c) $\frac{4}{15}$
d) $\frac{1}{100}$
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Question 6: The simplified value of $\frac{\left(3\frac{1}{5} + \frac{3}{5}\right) \div \frac{8}{5}}{1\frac{1}{7} \div \left\{\frac{5}{7} + \left(\frac{1}{7} \div \frac{1}{3}\right)\right\}}$ is:
a) $\frac{19}{7}$
b) $\frac{19}{16}$
c) $\frac{19}{8}$
d) $\frac{19}{64}$
Question 7: The value of $\frac{3 \div \left\{5 – 5 \div (6 – 7) \times 8 + 9\right\}}{4 + 4 \times 4 \div 4 of 4}$ is:
a) $\frac{1}{3}$
b) $\frac{1}{45}$
c) $\frac{1}{90}$
d) $\frac{1}{18}$
Question 8: The value of $\frac{18.43 \times 18.43 – 6.57 \times 6.57}{11.86}$ is:
a) 23.62
b) 25
c) 26
d) 24.12
Question 9: The value of $ \frac{(0.67 \times 0.67 \times0.67) \times (0.33 \times 0.33 \times 0.33)}{(0.67 \times 0.67) \div (0.67 \times 0.33) \div (0.33 \times 0.33)} $
a) 11
b) 0.34
c) 1.1
d) 3.4
Question 10: If $\left(1 + \frac{1}{2}\right)\left(1 + \frac{1}{4}\right)\left(1 + \frac{1}{6}\right)\left(1 + \frac{1}{8}\right)\left(1 – \frac{1}{3}\right)\left(1 – \frac{1}{5}\right)\left(1 – \frac{1}{7}\right) = 1 + \frac{1}{x}$, then what is the value of x?
a) 6
b) 8
c) 5
d) 7
Answers & Solutions:
1) Answer (C)
Arranging them in the ascending order we have
1,1,1,1,1,2,2,2,2,2,2,3,3,3,3,4,4,4,5,5
Median=middle value i.e average of 2 and 2 i. e 2
Mode=highest frequency number i.e 2
Range=highest-least value=5-1=4
Average=(2+2+4)/3
=$2\frac{2}{3}$
2) Answer (D)
Given : $\left(\frac{7}{8}\div5\frac{1}{4}\times7\frac{1}{5}-\frac{3}{20}of\frac{2}{3}\right)\div\frac{1}{2}+\left(\frac{3}{5}\times7\frac{1}{2}+\frac{2}{3}\div\frac{8}{15}\right)=7+k$
L.H.S. = $\left(\frac{7}{8}\div5\frac{1}{4}\times7\frac{1}{5}-\frac{3}{20}of\frac{2}{3}\right)\div\frac{1}{2}+\left(\frac{3}{5}\times7\frac{1}{2}+\frac{2}{3}\div\frac{8}{15}\right)$
= $\left(\frac{7}{8}\div\frac{21}{4}\times\frac{36}{5}-\frac{1}{10}\right)\div\frac{1}{2}+\left(\frac{3}{5}\times\frac{15}{2}+\frac{2}{3}\div\frac{8}{15}\right)$
= $\left(\frac{7}{8}\times\frac{4}{21}\times\frac{36}{5}-\frac{1}{10}\right)\div\frac{1}{2}+\left(\frac{3}{5}\times\frac{15}{2}+\frac{2}{3}\times\frac{15}{8}\right)$
= $[(\frac{6}{5}-\frac{1}{10})\times2]+\frac{9}{2}+\frac{5}{4}$
= $\frac{11}{5}+\frac{9}{2}+\frac{5}{4}$
= $\frac{44+90+25}{20}=\frac{159}{20}=7+\frac{19}{20}$
Comparing both sides, we get : $k=\frac{19}{20}$
=> Ans – (D)
3) Answer (D)
Following BODMAS ,
$2 \times 3 \div 2 of 3 \times 2 \div (4 + 4 \times 4 \div 4 of 4 – 4 \div 4 \times 4) $
= $2 \times 3 \div 6 \times 2 \div (4 + 4 \times 4 \div 16 – 4 \div 4 \times 4) $
= $2 \times \frac{1}{2} \times 2 \div (4 + 4 \times \frac{1}{4} – 4 \div 4 \times 4) $
= $2 \div (4 + 1 – 1 \times 4) $
= $2 \div (5 – 4) $
=2
So , the answer would be option d) 2.
4) Answer (D)
$\frac{9}{15} of \left(\frac{2}{3} \div \frac{2}{3} of \frac{3}{2}\right) \div \left(\frac{3}{4} \times \frac{3}{4} \div \frac{3}{4} of \frac{4} {3}\right) of \left(\frac{5}{4} \div \frac{5}{2} \times \frac{2}{5} of \frac{4}{5}\right)$
We know that “of” can be replace by multiply,
$\Rightarrow \frac{9}{15} of \left(\frac{2}{3} \div 1 \right) \div \left(\frac{3}{4} \times \frac{3}{4} \div 1 \right) of \left(\frac{5}{4} \div \frac{5}{2} \times \frac{8}{25} \right)$
Now, solving small brakets,
$\Rightarrow \frac{9}{15} of \left(\frac{2}{3} \right) \div \left(\frac{9}{16} \right) of \left(\frac{10}{20} \times \frac{8}{25} \right)$
$\Rightarrow \frac{9}{15} of \left(\frac{2}{3} \right) \div \left(\frac{9}{16} \right) of \left(\frac{4}{25} \right)$
$\Rightarrow \dfrac{\frac{18}{45}}{ \left(\frac{9}{100} \right) }$
$\Rightarrow \frac{18\times 100}{45\times 9}$
$\Rightarrow \frac{2\times 20}{9}$
$\Rightarrow \frac{40}{9}$
5) Answer (A)
6) Answer (C)
7) Answer (C)
Apply BODMAS rule to this type of problems
According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.
BODMAS full form
B=brackets
O=orders
D=division
M=multiplication
A=Addition
S=Subtraction
8) Answer (B)
$\frac{18.43 \times 18.43 – 6.57 \times 6.57}{11.86}$
$\frac{18.43^{2}-6.57^{2}}{11.86^{2}}$
$\frac{(18.43+6.57)(18.43 – 6.57)}{11.86}$
$\frac{25\times11.86}{11.86}=25$
9) Answer (B)
Mathematical Operators provided in the question seems to be incorrect. Please review the question again and provide correct data.
10) Answer (B)
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