IBPS PO Ages Questions with Answers Set-2 PDF

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IBPS PO Ages Questions with Answers Set-2 PDF
IBPS PO Ages Questions with Answers Set-2 PDF

IBPS PO Ages Questions with Answers Set-2 PDF:

Download IBPS PO Ages Questions with Answers Set-2 PDF. Practice Ages Questions with Solutions for Banking exams based on asked questions in previous papers.

 

Download IBPS PO Ages Questions with Answers Set-2 PDF

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Question 1: The respective ratio of the present ages of a mother and daughter is 7 : 1. Four years ago the respective ratio of their ages was 19:1. What will be the mother’s age four years from now ?

a) 42 years
b) 38 years
c) 46 years
d) 36 years
e) None of these

Question 2: The ages of Aarzoo and Arnav are in the ratio of 11:13 respectively.After 7 years the ratio of their ages will be 20:23. What is the difference in years between their ages ?

a) 4 years
b) 7 years
c) 6 years
d) 5 years
e) None of these

Question 3: 12 yr ago the ratio between the ages of A and B was 3:4 respectively. The present age of A is $3\frac{3}{4}$ times of C’s present age. If C’s present age is 10 yr, then what is B’s present age?

a) 48
b) 46
c) 60
d) 54
e) 36

Question 4: The ratio of the present ages of a mother and daughter is 7:1 Four years ago the ratio of their ages was 19:1 what will be the mother’s age four years from now ?

a) 42 years
b) 38 years
c) 46 years
d) 36 years
e) None of these

Question 5: 10 years ago, the ages of A and B were in the ratio of 13: 17. 17 years from now the ratio of their ages will be 10: 11. What is the age of B at present ?

a) 37 years
b) 40 years
c) 27 years
d) 44 years
e) None of these

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Answers & Solutions:

1) Answer (C)

Let the present ages of mother and daughter be x and y respectively.

$\frac{y}{x} = \frac{1}{7}$ => x = 7y

$\frac{y-4}{x-4} = \frac{1}{19}$ => 19y – 76 = x – 4 => x = 19y – 72

=> 7y = 19y – 72 => y = 6 and x = 42

Age of mother 4 years from now = 42 + 4 = 46

2) Answer (C)

Let the ages of Aarzoo and Arnav be X and Y respectively.

Hence, $\frac{X}{Y}=\frac{11}{13}$

Similarly, $\frac{X+7}{Y+7}=\frac{20}{23}$

Solving both the equations, we get $X=33$ and $Y=39$

So, the difference in ages equals 6

3) Answer (B)

$\frac{a-12}{b-12} = \frac{3}{4}$

$\frac{a}{c}$ = $\frac{15}{4}$

c = 10 => a = 37.5

=> b = 46 years

4) Answer (C)

Let the present ages of daughter and mother be d and m respectively.
7d = m
19(d-4) = m-4
=> 19d – 76 = 7d – 4
=> 12d = 72
=> d = 6 and m = 42
Mother’s age four years from now will be 42 + 4 = 46

5) Answer (C)

Let the present ages of A and B be x and y.
10 years ago, the ages of A and B were in the ratio of 13: 17 i.e $\frac{x-10}{y-10}$ = $\frac{13}{17}$
i.e 17x – 13y = 40

17 years from now the ratio of their ages will be 10: 11. i.e $\frac{x+17}{y+17}$ = $\frac{10}{11}$
i.e 10y-11x = 17
Simultaneously solving the two equation we get, x=23 and y=27 years.
Option C is correct answer.

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