Number series questions are very important for IBPS exams like IBPS Clerk and PO. A series of numbers will be given and you will asked to find out the next or missing or wrong number. Each series is formed from a particular progression/logic. Here comes a list of questions in which one number is wrong and rest of the terms follow the series.

**IBPS Clerk Number Series Questions PDF:**

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**Instructions:**

In each of these question a number series is given.In each series only one number is wrong.Find out the wrong numbers

**Question 1:**

1, 4, 15, 64 325, 1955

**A.** 15

**B.** 64

**C.** 325

**D.** 1955

**E.** None of these

**Question 2:**

6, 12, 21, 33, 49, 66

**A.** 21

**B.** 33

**C.** 49

**D.** 66

**E.** None of these

**Question 3:**

6, 11.5, 19, 28.5, 41

**A.** 6

**B.** 11.5

**C.** 41

**D.** 28.5

**E.** None of these

**Question 4:**

5, 26, 82, 214, 401, 702

**A.** 26

**B.** 82

**C.** 214

**D.** 401

**E.** None of these

**Question 5:**

5,20,73,274,1049

**A.** 20

**B.** 73

**C.** 274

**D.** 1049

**E.** None of these

**Question 6:**

3601, 3602, 1803, 604, 154, 36, 12

**A.** 3602

**B.** 1803

**C.** 604

**D.** 154

**E.** 36

**Question 7:**

4, 12, 42, 196, 1005, 6066, 42511

**A.** 12

**B.** 42

**C.** 1005

**D.** 196

**E.** 6066

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**Question 8:**

2, 8, 12, 20, 30, 42, 56

**A.** 8

**B.** 42

**C.** 30

**D.** 20

**E.** 12

**Question 9:**

32, 16, 24, 65, 210, 945, 5197.5

**A.** 945

**B.** 16

**C.** 24

**D.** 210

**E.** 65

**Question 10:**

7, 13, 25, 49, 97, 194, 385

**A.** 13

**B.** 49

**C.** 97

**D.** 194

**E.** 25

**Solutions to Number Series Questions for IBPS Clerk:**

**Â 1) **Answer (D)

4 = 1*2+2 ; 15 = 4*3+3 ; 64 = 15*4+4 ; 325 = 64*5+5 ; 1956 = 325*6+6

The nth term is of the form,

$T_n=(T_{n-1}\times n)+n$

The last term does not follow the pattern and is thus the wrong number in the sequence.

**2)** Answer (C)

2*2+2 = 6 ; 3*3+3 = 12 ; 4*4 + 5= 21 ; 5*5 +8 = 33 ; 6*6 + 12 = 48

**3)** Answer (C)

1.5*2 + 3 = 6

2.5*3 + 4 = 11.5

3.5*4 + 5 = 19

4.5*5 + 6 = 28.5

5.5*6 + 7 = 40

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**4)** Answer (C)

1*2+3=5 ; 4*5+6 = 26 ; 8*9+10 = 82 ; 13*14+15 = 212 ; 19*20 + 21 =401 ; 26*27 +28 = 702

**5)** Answer (C)

1^2 + 4= 5 ; 2^2 + 16 = 20 ; 3^2 + 64 = 73 ; 4^2 + 256 = 272 ; 5^2 + 1024 = 1049

**6)** Answer (D)

In the given series, nth term is obtained by – (Previous term/(n-1) ) +(n-1).

Hence the 5th term should be (604/4)+4 = 155.

However 5th term is given as 154.

Hence, 154 is wrong term in the given series.

**7)** Answer (B)

In this question, the nth term is obtained by (previous term*n + n^2).

Hence, after 12, the number would be (12*3+9)= 45

Therefore, the correct option is 45.

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**8)** Answer (A)

Here the consecutive difference between the terms is incremented by 2 for the series.

Hence, after 2, the number should be 6.

**9)** Answer (E)

Here the sucessive numbers are multiplied by .5,1.5.2.5….

Hence, in place of 65 the number should be 24*2.5=60.

Therefore, the incorrect number for series is 65.

**10)** Answer (D)

Here, in this series, the nth term is (previous term + $6*2^{n-2}$)

Hence, in place of 194 the term should be $(97+6*2^{4}) = 193$

Hope this questions had helped you get good understanding of Number Series questions asked in IBPS Clerk exams.