Bodmas questions for RRB Group D Set-2 PDF
Download Top-15 RRB Group-D Bodmas questions Set-2 PDF. RRB Group – D Bodmas questions based on asked questions in previous exam papers very important for the Railway Group-D exam.
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Question 1: $ 4 + \frac{1}{6} \times $ [ { $ – 12 \times ( 24 – 13 – 3) $ } $ \div ( 20 – 4) $ ] = ?
a) 4
b) 6
c) 5
d) 3
Question 2: The value of 16 – [ 5 – 2 { 14 of 2 – $( 8 \div 4 \times 2 – 1 + 3$ } ] is :
a) 35
b) 45
c) 55
d) 65
Question 3: The value of $ 14 \div $ { ( 5 of 2 – 3 ) } $ \times 4 ( 7 – 2 ) $ is :
a) 44
b) 40
c) $ \frac{1}{10} $
d) $ \frac{14}{19} $
Question 4: 0.296 + 2.96 + 29.6 + 296 = ?
a) 327.856
b) 328.756
c) 328.856
d) 327.756
Question 5: $45-[38-(80\div4-(8-12\div3)\div4)]=?$
a) 25
b) 27
c) 26
d) 28
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Question 6: $(8-(28-53))\div(-4\times5-(-9))=?$
a) 11
b) -3
c) 3
d) -11
Question 7: $ \frac{8.73 \times 8.73 \times 8.73 + 4.27 \times 4.27 \times 4.27}{8.73 \times 8.73 -8.73 \times 4.27 + 4.27 \times 4.27} $ is equal to —-
a) 11
b) 13
c) $ \frac {11}{7} $
d) None of these
Question 8: $100 \times 10 – 100 + 2000 \div 100 = ?$
a) 29
b) 920
c) 980
d) 1000
RRB Group D previous year papers
Question 9: $ (1-\frac{1}{2}) (1-\frac{1}{3}) (1-\frac{1}{4}) …..(1-\frac{1}{40}) = ?$
a) $ \frac{1}{40} $
b) $ \frac{1}{20} $
c) Countless
d) Zero
Question 10: $ 5^{5} \div (5^{3} \times 2^{2}) $ is
a) 125
b) 31.25
c) 6.25
d) 12.5
Question 11: $ 2^{4} \times 3^{4} \times 8^{4} \div (2 \times 3 \times 8)^{3} $ is
a) 576
b) 48
c) 96
d) 192
Instructions
What approximate value should come in place of question-mark (?) in the following questions ? (You are expected to calculate the exact value)
Question 12: $(9321+5406+1001)\div(498+929+660)$ = ?
a) 13.5
b) 4.5
c) 16.5
d) 7.5
Question 13: $561204\times58 = ? \times 55555$
a) 606
b) 646
c) 586
d) 716
Question 14: $(7857 + 3596 + 4123)\div96$=?
a) 155.06
b) 162.25
c) 151.83
d) 165.70
Question 15: Evaluate :- $(-216 \times 1728)^{\frac{1}{3}}$
a) -72
b) 27
c) 72
d) -27
RRB Group D previous year papers
Answers & Solutions:
1) Answer (D)
$ 4 + \frac{1}{6} \times $ [ { $ – 12 \times ( 24 – 13 – 3) $ } $ \div ( 20 – 4) $ ]
=$ 4 + \frac{1}{6} \times $ [ { $ – 12 \times 8 $ } $ \div 16 $ ]
=$ 4 + \frac{1}{6} \times -6$
=4-1
=3
2) Answer (C)
16 – [ 5 – 2 { 14 of 2 – $( 8 \div 4 \times 2 – 1 + 3$ } ]
=16 – [ 5 – 2 { 28 – $( 2 \times 2 – 1 + 3$ } ]
=16 – [ 5 – 2 { 28 – $( 3 + 3$ } ]
=16-[5-44]
=11+44
=55
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3) Answer (B)
$ 14 \div $ { ( 5 of 2 – 3 ) } $ \times 4 ( 7 – 2 ) $
=$ 14 \div $ 7 $ \times 4 ( 5) $
=2$ \times 4 ( 5) $
=2$ \times 20 $
=40
4) Answer (C)
0.296 + 2.96 + 29.6 + 296 = 328.856
5) Answer (C)
$45-[38-(80\div4-(8-12\div3)\div4)] = 45 – (38 – (20 – \dfrac{8-4}{4}))$
$= 45 – (38 -(20-\dfrac{4}{4})) = 45-(38-(20-1))$
$= 45-(38-19) = 45-19 = 26$
6) Answer (B)
$(8-(28-53)) = 8-28+53 = 33$
$(-4\times5-(-9)) = -20+9 = -11$
Therefore, $(8-(28-53))\div(-4\times5-(-9))=\dfrac{33}{-11} = -3$
7) Answer (B)
($ a ^ {3} + b ^ {3}$) / ($ a ^ {2} – ab + b ^ {2} $) = a + b
Substituting 8.73 for a and 4.27 for b, we get the answer
8) Answer (B)
By BODMAS, Division and Multiplication will be done before addition and subtraction.
Hence, 100 x 10 – 100 + 2000 / 100 = 1000 – 100 + 20 = 920
9) Answer (A)
1 – 1/2 = 1/2
1 – 1/3 = 2/3
1 – 1/4 = 3/4
The denominator of the first term gets cancelled by the numerator of the second term and so on…
So, the final value = 1/40
10) Answer (C)
$ 5^{5} \div (5^{3} \times 2^{2}) $=$5^{2}/2^{2}$
=25/4=6.25
11) Answer (B)
$ 2^{4} \times 3^{4} \times 8^{4} \div (2 \times 3 \times 8)^{3} $
=$\frac{2^{16} \times 3^{4}}{2^{12} \times 3^{3}}=2^{4} \times 3=48$
12) Answer (D)
9321+5406+1001= 15728
498+929+660= 2087
15728$\div$2087= 7.536
So option D is the right answer.
13) Answer (C)
$561204\times58 = ? \times 55555$
implies ? = $561204\times58 \div 55555$ = 586
14) Answer (B)
7857 + 3596 + 4123 = 15576
15576 / 96 = 162.25
15) Answer (A)
$(-216 \times 1728)^{\frac{1}{3}}$
=$(-6^{3} \times 12^{3})^{\frac{1}{3}}$
=-72
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We hope this Bodmas questions PDF for RRB Group-D Exam will be highly useful for your preparation.
