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# Average Questions for SSC CGL PDF:

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Question 1: The incomes of A and B are in the ratio 3 : 2 and their expenditures are in the ratio 5:3. If each saves Rs. 1000, then Aâ€™s income is

a) Rs. 6000
b) Rs. 4000
c) Rs. 2000
d) Rs. 5000

Question 2: The difference between successive discounts of 40% followed by 30% and 45% followed by 20% on the marked price of an article is Rs. 12. The marked price of the article is :

a) 800
b) 400
c) 200
d) 600

Question 3: Which of the following represents a correct proportion ?

a) 12: 9 = 16 : 12
b) 13 : 11 = 5 : 4
c) 30 : 45 = 13 : 24
d) 6 :10 = 4: 10

Question 4: In a Mathematics examination the numbers scored by 5 candidates are 5 successive odd integers. If their total marks is 185, the highest score is

a) 39
b) 43
c) 41
d) 37

Question 5: Three numbers are in the ratio 1 : 2 : 3 and their HCF is 12. The numbers are

a) 12,24, 36
b) 5, 10, 15
c) 4, 8, 12
d) 10, 20, 30

Question 6: The ratio of two numbers is 3 : 4 and their LCM is 180. The second number is

a) 30
b) 60
c) 45
d) 90

Question 7: A person distributes his pens among four friends A, B. C, D in the ratio 1/3 : 1/4 : 1/5 : 1/6 .What is the minimum number of pens that the person should have?

a) 60
b) 65
c) 75
d) 45

Question 8: The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25%, a mean score of 31. The mean score of remaining 55% is :

a) 50%
b) 51.4% approx.
c) 54.6% approx.
d) 45%

Question 9: Out of 10 teachers of a school, one teacher retires and in his place, a new teacher of age 25 years joins. As a result, average age of teachers is reduced by 3 years. The age (in years) of the retired teacher is:

a) 58
b) 60
c) 55
d) 50

Question 10: Three numbers are in the ratio 1 : 2 : 3. By adding 5 to each of them, the new numbers are in the ratio 2 : 3 : 4. The numbers are:

a) 10, 20, 30
b) 15, 30, 45
c) 1, 2, 3
d) 5, 10, 15

Answers & Solutions forÂ Average Questions for SSC CGL PDF:

As incomes of A and B are in the ratio 3 : 2. So , assume incomes of A and B be 3z and 2z
respectively
As the expenditure are in the ratio 5:3. So assume expenditure of A and B be 5y and 3y
respectively
Now it is given that every one saves Rs 1000
3z – 5y = 1000 ……….(1)
2z – 3y = 1000……….(2)
Solving equations 1 and 2
y = Rs 1000
z = Rs 2000
hence income of A = 3z = 3 x 2000 = Rs 6000

let the marked price of the article be Rs y
Ist case :
Two succesive discounts 40% followed by 30%
So after these two successive discounts the value of article becomes = 0.6 Ã— 0.7 Ã— y = 0.42 y
2nd case:
Two successive discounts are 45% followed by 20%
So after these two discounts the price if article becomes = 0.55 Ã— 0.8 Ã— y = 0.44y
It is given that :
0.44y – 0.42y = 12
0.02y = 12
y = Rs 600

Checking option 1 )
12: 9 = 4:3, 16 : 12 = 4:3
Checking option 2)
13 : 11 = 13:11 , 5 : 4= 5:4
checking option 3)
30 : 45 = 2:3, 26 : 24 = 13:12
Checking option 4)
6 :10 = 3:5, 4: 10 = 2:5
So option A is correct

let the numbers of 5 candidates be a-3,a-1,a+1,a+3,a+5
It is given that
a-3+a-1+a+1+a+3+a+5 =185
5a + 5 = 185
5a = 180
a= 36
The highest score = a + 5 = 36 + 5 = 41

As the numbers are in the ratio of 1:2:3 so let the numbers be y,2y,3y
The numbers taken are co prime, => the highest common factor = y
and y = 12
=> Numbers are 12,24,36

As the numbers are in the ratio 3:4
so assume the numbers are 3z and 4z
LCM of 3z and 4z = 12z
it is given that LCM of the above two numbers are = 180
So, 12z = 180
z = 15
and hence 2nd number = 4z = 4 x 15 = 60

It is given that A person distributes his pens among four friends A, B. C, D in the ratio 1/3 : 1/4 : 1/5 : 1/6
So when he is distributing pens , then the number of pens distributed to everyone should be a natural number and hence the number of total pens should be a multiple of 3,4,5,6
and the smallest natural number divisible by 3,4,5,6 is its LCM which is = 60
and hence minimum 60 pens should be there with the man before distribution.

Let the total number of people be 100 and total marks be 100.
Average = 52 => Total = 5200
Average of brightest 20 = 80=>Total marks scored by brightest 20 = 80*20 = 1600
Average of dullest 25 =31. => Total marks scored by dullest 25 = 25*31= 775
Marks scored by remaining 55 = 5200 -1600 – 775 = 2825
Average = 2825/55 = 51.4 % (Approx.)
Option B is the right answer.

Number of teachers = 10 years
Let the initial average age be A years
total age before retirement = 10A
Now new average age =( A-3) years
So new total age after new person joined= 10x(A-3) = 10A – 30 ………….(1)
let the age of retired teacher be z years, So
new total age can be calculated also as= 10A – z +25 ……..(2)
equations 1 and 2 are equal
so, 10A – 30 = 10A – z +25
z = 55 years.