Arithmetic Questions for IBPS Clerk Prelims
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Question 1: 11.11% of 90 + 8.33% of 120 =?
a) 20
b) 30
c) 40
d) 50
e) 60
Question 2: What is the value of (x) in the following equation ?
$ \frac { x ^ {1.2}}{98} = \frac {28}{x^{1.8}}$
a) 18
b) 12
c) 16
d) 14
e) None of these
Instructions
What should come in place of the question mark (?) in the following question ?
Question 3: $(7921\div178)-5.5=\sqrt{?}$
a) 1512
b) 1521
c) 1251
d) 1531
e) None of these
Instructions
What will come in the place of question mark(?) in the given questions?
Question 4: $(3\frac{6}{17}\div2\frac{7}{34}-1\frac{9}{25})=(?)^2$
a) $ \frac{2}{5}$
b) $\frac{1}{3}$
c) $\frac{4}{5}$
d) $\frac{1}{5}$
e) $\frac{3}{5}$
Instructions
What value should come in the place of question mark (?) in the following questions?
Question 5: $\frac{17}{24}\div\frac{68}{24}\div\frac{380}{95}=(?)^{2}$
a) 4
b) 8
c) 6
d) 9
e) None of these
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Instructions
What ‘’approximate’’ value should come in the place of question mark (?) in the following questions? (You are not expected to calculate the exact value )
Question 6: $\sqrt[3]{80000}$=?
a) 50
b) 49
c) 42
d) 38
e) 40
Instructions
In each of these questions two equations numbered I & II are given. You have to solve both the equations and give answer.
Question 7: I. $4a^{2}-20a+21=0$
II. $2b^{2}-5b+3=0$
a) if $a < b$
b) if $a > b$
c) if relationship between $a$ & $b$ cannot be established
d) if $a\geq b$
e) if $a\leq b$
Instructions
What will come in place of question mark (?) in the following questions ?
Question 8: $784\div 16 \div7=?$
a) 49
b) 14
c) 21
d) 7
e) None of these
Question 9: What will come in place of both question mark (?) in the following equation ?
$\frac {76\times 32 \div ? + 16}{6^{2} \div 9 \times 4 – ?} = 40$
a) 16
b) 4
c) 8
d) 12
e) 6
Question 10: $\frac{14}{19}\times\frac{57}{70}\times\frac{20}{21}=?$
a) $\frac{2}{7}$
b) $\frac{4}{7}$
c) $\frac{2}{9}$
d) $\frac{3}{7}$
e) None of these
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Instructions
What will come in place of the question mark (?) in the following questions?
Question 11: 56835 – 12683 + 38934 = ?
a) 83085
b) 83083
c) 83088
d) 83086
e) None of these
Question 12: What will come in place of both the question marks (?) in the following question ? $\frac{(?)^{1.3}}{45}=\frac{75}{(?)^{1.7}}$
a) 25
b) -15
c) -25
d) 17
e) None of these
Question 13: $8080 \div 80 \div 8 = ?$
a) 880
b) 12.625
c) 808
d) 16.225
e) None of these
Question 14: (14 $\times $ 24) + (27 $\times $12) = ?
a) 650
b) 665
c) 660
d) 655
e) None of these
Question 15: The product of two consecutive even numbers is 7568. What is 150% of the sum of the two numbers?
a) 204
b) 261
c) 304
d) 198
e) None of these
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Answers & Solutions:
1) Answer (A)
10+10 = 20 (11.11% = 1/9 and 8.33% = 1/12)
2) Answer (D)
The question can be reframed as,
$x^{1.2}\times x^{1.8}$ = 98*28 = 14*7*7*4= 7*7*7*8
x^3=7*7*7*8
Hence, x = 7*2 = 14
3) Answer (B)
Let unknown be x,
$(7921\div178)-5.5=\sqrt{x}$
Hence, x=[(7921/178)-5.5]^2=39^2=1521
4) Answer (A)
Given equation can be solved as follows:
$\frac{57}{17} \times \frac{34}{75} – \frac{34}{25}$ = $\frac{4}{25}$
Hence, answer will be A
5) Answer (E)
As we can see that equation can be written as $(\frac{17}{24}\times \frac{24}{68})\times\frac{95}{380}$
Hence, answer will be $\frac{1}{4}$
6) Answer (C)
We need to find the approximate value of $\sqrt[3]{80000}$
We know that $2^3 = 8$ and $10^3 = 1000$
Let the value of $\sqrt[3]{80000} = X$
So, $X = 2 \times 10 \times \sqrt[3]{10}$
The $\sqrt[3]{10}$ is approximately equal to 2.1
Hence, the approximate value equals $20*2.1 = 42$
The closest option is option (c)
7) Answer (D)
$4a^2-20a+21 = 0$
$(2a-3)(2a-7) = 0$
$a = \frac{3}{2}, \frac{7}{2}$
$2b^2-5b+3 = 0$
$(2b-3)(b-1) = 0$
$b = 1, \frac{3}{2}$
$\therefore a\geq b$
8) Answer (D)
784 = 7 x 7 x 16
Let x be the unknown quantity, then
x = $\frac{784}{16\times7} = 7$
9) Answer (C)
Let the value of the number which replaces the question mark be equal to $X$
$\frac {76\times 32 \div X + 16}{6^{2} \div 9 \times 4 – X} = 40$
So, $ 76 \times 32 \div X +16 = 40 \times (16 – X)$
Or, $ 2432 \div X + 16 = 640 – 40 \times X$
Dividing by 8, we get $304 \div X + 5 \times X = 78$
Or, $ 5X^2 – 78 \times X + 304 = 0$
Hence, $X=8$ and the correct answer is option (c)
10) Answer (B)
$\frac{14}{19}\times\frac{57}{70}\times\frac{20}{21}$
$\frac{2}{1}\times\frac{1}{7}\times\frac{2}{1}$
$\frac{4}{7}$
11) Answer (D)
This question is trying to check the BODMAS rule
56835 – 12683 + 38934 = (56835 + 38934) – 12683 = 83086
12) Answer (E)
Let ? = x
According to given equation
$\frac{(x)^{1.3}}{45}=\frac{75}{(x)^{1.7}}$
$ x^{3} $ = 45 $ \times$ 75
$ x^{3} $ = 15 $ \times$ 15 $ \times$ 15
x = 15
13) Answer (B)
$\frac{8080}{80}$ =101
101÷8 need not be calculated.
We know that 8×12=96 and 8×13=104. Hence the answer must lie between 12 and 13.
Hence the correct answer is Option B.
14) Answer (C)
(14$\times$24) + (27$\times$12)
= 336 + 324
= 660
15) Answer (B)
Let even numbers be ‘2n’ and ‘2n+2’.
According to question,
$2n\times(2n+2)=7568$.
$4n(n+1)=7568$.
$n(n+1)=1892$.
$n=43$.
Hence, numbers are 86 and 88 respectively.
Sum of numbers=86+88.
=174.
150% of sum of numbers=$1.5\times174$.
$=261$.
Hence, Option B is correct.
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