# Approximation Questions For IBPS RRB PO Set-2 PDF

Download Top-20 IBPS RRB PO Approximation Questions PDF. Approximation questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam.

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**Question 1:Â **What approximate value should come in place of the question mark (?) in the following questions?

$21 + 68 \div 17 = ? $

a)Â 25

b)Â 35

c)Â 40

d)Â 10

**Question 2:Â **What value should come in place of the question mark (?) in the following questions?

$31 \div 3 \times 15 = ?$

a)Â 180

b)Â 140

c)Â 165

d)Â 155

**Question 3:Â **What approximate value should comein place of the question mark (?) in the following equation?

($\frac{1}{9}\div\frac{1}{9}$ of $\frac{1}{3}$) of $\frac{1}{6}=?$

a)Â $\frac{1}{6}$

b)Â $\frac{1}{2}$

c)Â $\frac{1}{9}$

d)Â $\frac{1}{3}$

**Question 4:Â **What value should come in place of question mark(?) in the following equation?

$360\sqrt?$ + 4500 = 19700 – 9800

a)Â 395

b)Â 295

c)Â 225

d)Â 215

**Question 5:Â **What approximate value should come in place of the question mark (?) in the following question ?

$45.709 \div 11.342 \times 6.667 = ?$

a)Â 88

b)Â 46

c)Â 112

d)Â 56

e)Â 27

**Question 6:Â **What approximate value should come in place of the question mark (?) in the following question?

$54.786 \div 10.121 \times 4.454 = ?$

a)Â 84

b)Â 48

c)Â 118

d)Â 58

e)Â 24

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**Question 7:Â **What approximate value should come in place of the question mark (?) in the following questions?

$59.786 \div 14.444 \times 8.321 = ?$

a)Â 49

b)Â 58

c)Â 22

d)Â 66

e)Â 34

**Question 8:Â **What approximate value should come in place of the question mark (?) in the following question?

$4275 \div 496 \times (21)^{2} = ?$

a)Â 3795

b)Â 3800

c)Â 3810

d)Â 3875

e)Â 3995

**Question 9:Â **What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

$9980 \div 49 \times (4.9)^{2} – 1130 = ?$

a)Â 3800

b)Â 4500

c)Â 2600

d)Â 3000

e)Â 4080

**Question 10:Â **What approximate value should come in place of the question mark (?) in the following equation ?

$695.95\div 29.07 \times ? + 40.25 = 399.99$

a)Â 14

b)Â 17

c)Â 12

d)Â 16

e)Â 15

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**Question 11:Â **What approximate value should come in place of the question mark (?) in the following equation ?

$29.38 \times 37.05 \div ? + 7.45 = 100.5$

a)Â 10

b)Â 13

c)Â 14.5

d)Â 1.35

e)Â 12

**Question 12:Â **What approximate value should come in place of question mark(?) in the following equation ?

$9876\div 24.96+215.005-?=309.99$

a)Â 395

b)Â 295

c)Â 300

d)Â 315

e)Â 310

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**Answers & Solutions:**

**1)Â AnswerÂ (A)**

By applying BODMAS we have

=$21+(68\div17)$

=21+4

=25

**2)Â AnswerÂ (D)**

By applying BODMAS we have

$(31/3)\times 15$

=$31\times 5$

=155

**3)Â AnswerÂ (B)**

($\dfrac{1}{9}\div\dfrac{1}{9}$Â ofÂ $\dfrac{1}{3}$) of $\dfrac{1}{6} = (\dfrac{1}{9} \div \dfrac{1}{27}$)Â ofÂ $\dfrac{1}{6}$

$= \dfrac{1}{9} \times 27$Â ofÂ $\dfrac{1}{6}$

$= 3 \times \dfrac{1}{6} = \dfrac{1}{2}$

**4)Â AnswerÂ (C)**

$360\sqrt?$ + 4500 = 19700 – 9800

$\RightarrowÂ 360\sqrt? + 4500 = 9900$

$\RightarrowÂ 360\sqrt? = 5400$

$\RightarrowÂ \sqrt? = 15$

$\Rightarrow ? = 15^2$

$\Rightarrow ? = 225$

**5)Â AnswerÂ (E)**

ExpressionÂ :Â $45.709 \div 11.342 \times 6.667 = ?$

= $\frac{44}{11} \times 7$

= $4 \times 7 = 28$

$\approx$ 27

**6)Â AnswerÂ (E)**

ExpressionÂ : $54.786 \div 10.121 \times 4.454 = ?$

= $\frac{55}{10} \times 4.5$

= $24.75 \approx 24$

**7)Â AnswerÂ (E)**

ExpressionÂ :Â $59.786 \div 14.444 \times 8.321 = ?$

= $\frac{60}{15} \times 8$

= $4 \times 8$

= $32 \approx 34$

**8)Â AnswerÂ (C)**

ExpressionÂ :Â $4275 \div 496 \times (21)^{2} = ?$

= $\frac{4275 \times 441}{495}$

= 3808.63 $\approx$ 3810

**9)Â AnswerÂ (A)**

Since an approximate answer is sufficient, you can rewrite the question as $10000 \div 50 \times 5^{2} – 1130$

Following BDMAS rule the result is 3870.

The nearest value is 3800.

Hence Option A is the correct answer.

**10)Â AnswerÂ (E)**

Let the number to replace the question mark be equal to $X$

Hence, $695.95\div 29.07 \times X + 40.25 = 399.99$

$399.99 \approx 400$ and $695.95 \approx 696$ and $29.07 \approx 29$

So, the expression looks like $696 \div 29 \times X + 40 = 400$

Hence, $24 \times X = 360$ or $X = 15$

**11)Â AnswerÂ (E)**

Let the number to come in place of the question mark be equal to $X$

So, $29.38 \times 37.05 \div X + 7.45 = 100.5$

Or, $29.38 \times 37.05 \div X = 93.05$

So, $X = \frac{29.38 \times 37.05}{93.05} = 11.69 \approx 12$

**12)Â AnswerÂ (C)**

Let x be the value of the unknown number.

x= $\frac{9876}{24.96}$ + 215.005 – 309.99

= 395.67 – 94.985 $ = \approx$ 300