Approximation Questions For IBPS RRB PO Set-2 PDF

Download Top-20 IBPS RRB PO Approximation Questions PDF. Approximation questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam.

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Question 1: What approximate value should come in place of the question mark (?) in the following questions?
$21+68÷17=?$

a) 25

b) 35

c) 40

d) 10

Question 2: What value should come in place of the question mark (?) in the following questions?
$31÷3\times 15=?$

a) 180

b) 140

c) 165

d) 155

Question 3: What approximate value should comein place of the question mark (?) in the following equation?
($\frac{1}{9}÷\frac{1}{9}$ of $\frac{1}{3}$) of $\frac{1}{6}=?$

a) $\frac{1}{6}$

b) $\frac{1}{2}$

c) $\frac{1}{9}$

d) $\frac{1}{3}$

Question 4: What value should come in place of question mark(?) in the following equation?
$360\sqrt{?}$ + 4500 = 19700 – 9800

a) 395

b) 295

c) 225

d) 215

Question 5: What approximate value should come in place of the question mark (?) in the following question ?
$45.709÷11.342\times 6.667=?$

a) 88

b) 46

c) 112

d) 56

e) 27

Question 6: What approximate value should come in place of the question mark (?) in the following question?
$54.786÷10.121\times 4.454=?$

a) 84

b) 48

c) 118

d) 58

e) 24

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Question 7: What approximate value should come in place of the question mark (?) in the following questions?
$59.786÷14.444\times 8.321=?$

a) 49

b) 58

c) 22

d) 66

e) 34

Question 8: What approximate value should come in place of the question mark (?) in the following question?
$4275÷496\times (21{)}^2=?$

a) 3795

b) 3800

c) 3810

d) 3875

e) 3995

Question 9: What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)
$9980÷49\times (4.9{)}^2–1130=?$

a) 3800

b) 4500

c) 2600

d) 3000

e) 4080

Question 10: What approximate value should come in place of the question mark (?) in the following equation ?
$695.95÷29.07\times ?+40.25=399.99$

a) 14

b) 17

c) 12

d) 16

e) 15

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Question 11: What approximate value should come in place of the question mark (?) in the following equation ?
$29.38\times 37.05÷?+7.45=100.5$

a) 10

b) 13

c) 14.5

d) 1.35

e) 12

Question 12: What approximate value should come in place of question mark(?) in the following equation ?
$9876÷24.96+215.005-?=309.99$

a) 395

b) 295

c) 300

d) 315

e) 310

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Answers & Solutions:

1) Answer (A)

By applying BODMAS we have
=$21+(68÷17)$
=21+4
=25

2) Answer (D)

By applying BODMAS we have
$(31/3)\times 15$
=$31\times 5$
=155

3) Answer (B)

(${\displaystyle \frac{1}{9}}÷{\displaystyle \frac{1}{9}}$  of  ${\displaystyle \frac{1}{3}}$) of ${\displaystyle \frac{1}{6}}=({\displaystyle \frac{1}{9}}÷{\displaystyle \frac{1}{27}}$)  of  ${\displaystyle \frac{1}{6}}$

$={\displaystyle \frac{1}{9}}\times 27$  of  ${\displaystyle \frac{1}{6}}$

$=3\times {\displaystyle \frac{1}{6}}={\displaystyle \frac{1}{2}}$

4) Answer (C)

$360\sqrt{?}$ + 4500 = 19700 – 9800

$\Rightarrow 360\sqrt{?}+4500=9900$

$\Rightarrow 360\sqrt{?}=5400$

$\Rightarrow \sqrt{?}=15$

$\Rightarrow ?={15}^2$

$\Rightarrow ?=225$

5) Answer (E)

Expression : $45.709÷11.342\times 6.667=?$

= $\frac{44}{11}\times 7$

= $4\times 7=28$

$\approx$ 27

6) Answer (E)

Expression : $54.786÷10.121\times 4.454=?$

= $\frac{55}{10}\times 4.5$

= $24.75\approx 24$

7) Answer (E)

Expression : $59.786÷14.444\times 8.321=?$

= $\frac{60}{15}\times 8$

= $4\times 8$

= $32\approx 34$

8) Answer (C)

Expression : $4275÷496\times (21{)}^2=?$

= $\frac{4275\times 441}{495}$

= 3808.63 $\approx$ 3810

9) Answer (A)

Since an approximate answer is sufficient, you can rewrite the question as $10000÷50\times 5^2–1130$

Following BDMAS rule the result is 3870.

The nearest value is 3800.

Hence Option A is the correct answer.

10) Answer (E)

Let the number to replace the question mark be equal to $X$

Hence, $695.95÷29.07\times X+40.25=399.99$

$399.99\approx 400$ and $695.95\approx 696$ and $29.07\approx 29$

So, the expression looks like $696÷29\times X+40=400$
Hence, $24\times X=360$ or $X=15$

11) Answer (E)

Let the number to come in place of the question mark be equal to $X$

So, $29.38\times 37.05÷X+7.45=100.5$
Or, $29.38\times 37.05÷X=93.05$
So, $X=\frac{29.38\times 37.05}{93.05}=11.69\approx 12$

12) Answer (C)

Let x be the value of the unknown number.

x= $\frac{9876}{24.96}$ + 215.005 – 309.99

= 395.67 – 94.985 $=\approx$ 300

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