Approximation Questions For IBPS RRB PO PDF
Download Top-20 IBPS RRB PO Approximation Questions PDF. Approximation questions based on asked questions in previous year exam papers very important for the IBPS RRB PO (Officer Scale-I, II & III) exam.
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Question 2:Â What approximate value should come in place of the question mark (?) in the following questions?
$59.786 \div 14.444 \times 8.321 = ?$
a)Â 49
b)Â 58
c)Â 22
d)Â 66
e)Â 34
Question 3:Â What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)
$9980 \div 49 \times (4.9)^{2} – 1130 = ?$
a)Â 3800
b)Â 4500
c)Â 2600
d)Â 3000
e)Â 4080
Question 4:Â What approximate value should come in place of the question mark (?) in the following equation ?
$695.95\div 29.07 \times ? + 40.25 = 399.99$
a)Â 14
b)Â 17
c)Â 12
d)Â 16
e)Â 15
Question 5:Â What approximate value should come in place of the question mark (?) in the following equation ?
$29.38 \times 37.05 \div ? + 7.45 = 100.5$
a)Â 10
b)Â 13
c)Â 14.5
d)Â 1.35
e)Â 12
Question 6:Â What approximate value should come in place of question mark(?) in the following equation ?
$9876\div 24.96+215.005-?=309.99$
a)Â 395
b)Â 295
c)Â 300
d)Â 315
e)Â 310
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Question 7:Â What approximate value should come in place of the question mark(?) in the following question? (Note: You are not expected to find the exact value).
30.003 * 49.991 * 6.984 = ?
a)Â 7500
b)Â 10500
c)Â 9000
d)Â 13500
e)Â 12000
Question 8:Â What approximate value should come in place of the question mark(?) in the following question? (Note: You are not expected to find the exact value).
$\sqrt{7394} = ? $
a)Â 71
b)Â 76
c)Â 81
d)Â 86
e)Â 91
Question 9: What approximate value should come in place of the question mark (?) in the following question’?$ 754 \div \sqrt{4076} \times 24 $ = ?
a)Â 294
b)Â 256
c)Â 265
d)Â 300
e)Â 288
Question 10:Â What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value)
3001.45 + 34.990 * 29.923 = ?
a)Â 3750
b)Â 3900
c)Â 4000
d)Â 3950
e)Â 4050
Question 11:Â What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value)
$\frac{3330}{23}$ = ?
a)Â 145
b)Â 140
c)Â 135
d)Â 130
e)Â 125
Question 12:Â What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value)
49.99 * 74.910 * 0.33 = ?
a)Â 1400
b)Â 1000
c)Â 1250
d)Â 1500
e)Â None of the above
Question 13:Â What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value)
$\sqrt{11023}$ = ?
a)Â 90
b)Â 95
c)Â 110
d)Â 105
e)Â 115
Question 14:Â What approximate value should come in the place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value)
7.997 * 16.005 * 40.055 = ?
a)Â 5400
b)Â 5120
c)Â 5200
d)Â 5000
e)Â None of the above
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Answers & Solutions:
2) Answer (E)
Expression : $59.786 \div 14.444 \times 8.321 = ?$
= $\frac{60}{15} \times 8$
= $4 \times 8$
= $32 \approx 34$
3) Answer (A)
Since an approximate answer is sufficient, you can rewrite the question as $10000 \div 50 \times 5^{2} – 1130$
Following BDMAS rule the result is 3870.
The nearest value is 3800.
Hence Option A is the correct answer.
4) Answer (E)
Let the number to replace the question mark be equal to $X$
Hence, $695.95\div 29.07 \times X + 40.25 = 399.99$
$399.99 \approx 400$ and $695.95 \approx 696$ and $29.07 \approx 29$
So, the expression looks like $696 \div 29 \times X + 40 = 400$
Hence, $24 \times X = 360$ or $X = 15$
5) Answer (E)
Let the number to come in place of the question mark be equal to $X$
So, $29.38 \times 37.05 \div X + 7.45 = 100.5$
Or, $29.38 \times 37.05 \div X = 93.05$
So, $X = \frac{29.38 \times 37.05}{93.05} = 11.69 \approx 12$
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6) Answer (C)
Let x be the value of the unknown number.
x= $\frac{9876}{24.96}$ + 215.005 – 309.99
= 395.67 – 94.985 $ = \approx$ 300
7) Answer (B)
The question can be modified to 30*50*7 to get the approximate answer.
30 * 50 * 7
= 1500 * 7
= 10500
8) Answer (D)
We know that $80^2$ is equal to 6400 and $90^2$ = 8100.
Since 7394 is between 6400 and 8100, its square root must lie between 80 and 90.
So, it is either 81 or 86.
Lets find the square of 81 => 81*81 = 6561
=> $\sqrt{7394}$ = 86 approximately
9) Answer (E)
In order to find the approximate value of $ 754 \div \sqrt{4076} \times 24 $, we need to find the approximate value of $\sqrt{4076}$
We know that $64^2 = 4096$ and $63^2 = 3969$
So, a rough approximation of $\sqrt{4076} = 63.8$
So, a rough approximation of the expression needed becomes $754 \div 63.8 \times 24 $
We note that 63.8 * 12 = 765
So, $754 \div 63.8 \approx 12$
Hence, the required approximation is $24 \times 12 = 288$
Hence, the correct answer is option (e)
10) Answer (E)
The approximate calculation is as follows:
3000 + 35 * 30
35*30 = 1050
3000 + 1050 = 4050
11) Answer (A)
23 * 145 = 3335
From the options, we can see that 145 is the number that is closest to the answer.
12) Answer (C)
0.33 = 1/3
The approximate calculation is as follows:
50 * 75 * (1/3) = 50 * 25 = 1250
13) Answer (D)
$105^2$ = 11025
From the options, the closest number to the square root of 11023 is 105.
14) Answer (B)
The approximate calculation is as follows:
8*16*40 = 8*8*2*8*5 = $8^3$ * 10 = 5120