Approximation Questions For IBPS PO PDF

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Instructions

What should come in place of the question mark (?) in the following questions ?

Question 1: ${2^{0.2}} \times 64 \times {8^{1.3}} \times {4^{0.2}} = {8^?}$

a) 2.7

b) 2.5

c) 3.7

d) 3.2

e) None of these

Question 2: 83% of 6242 x 12% of 225 = ?

a) 146286.42

b) 134263.18

c) 139883.22

d) 1562218.23

e) None of these

Question 3: $1{1 \over 8} + 1{6 \over 7} + 3{3 \over 5}$ = ?

a) $8{{121} \over {140}}$

b) $6{{163} \over {280}}$

c) $9{{197} \over {280}}$

d) $7{{117} \over {140}}$

e) None of these

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Question 4: ? ÷ 25 ÷ 12 = 248.76

a) 74628

b) 497.52

c) 62452

d) 870.66

e) None of these

Question 5: ${(73)^3}$ = ?

a) 365127

b) 298627

c) 305867

d) 389017

e) None of these

Instructions

What should come in place of the question mark (?) in the following questions?

Question 6: $\sqrt[3]{1331}$ =

a) 27

b) 21

c) 17

d) 9

e) None of these

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Question 7: 188.21 – 27.54 – 11.93 = ?

a) 139.74

b) 126.64

c) 148.74

d) 184.64

e) None of these

Question 8: 1268 ÷ 8 ÷ 2 = ?

a) 71.75

b) 317

c) 268

d) 79.25

e) None of these

Question 9: ${8^{1.1}} \times {4^2}^{.7} \times {2^{3.3}} = {2^?}$

a) 7.1

b) 14

c) 0.5

d) 9

e) None of these

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Instructions

What approximate value will come in place of question mark (?) in the given questions? (You are not expected to calculate the exact value).

Question 10: 344 ÷ 4.99 + 144.08 ÷ 8.89 =?

a) 119

b) 85

c) 43

d) 54

e) 132

Question 11: 43.99 x 20.001 – 1439 ÷ 6 = ?

a) 500

b) 640

c) 540

d) 600

e) 680

Question 12: 459.85 + 519.82 = ?% of 1399.92

a) 90

b) 70

c) 75

d) 50

e) 80

Question 13: 40 % of 309 ÷ 4 + ? = 6.9992

a) 24

b) 18

c) 42

d) 56

e) 34

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Answers & Solutions:

1) Answer (E)

Expression : ${2^{0.2}} \times 64 \times {8^{1.3}} \times {4^{0.2}} = {8^?}$

=> $(2)^{0.2} \times (2)^6 \times (2)^{3 \times 1.3} \times (2)^{2 \times 0.2} = (2)^{3 \times x}$

=> $(2)^{0.2 + 6 + 3.9 + 0.4} = (2)^{3 x}$

=> $(2)^{10.5} = (2)^{3 x}$

Comparing powers of 2, we get :

=> $3x = 10.5$

=> $x = \frac{10.5}{3} = 3.5$

2) Answer (C)

Expression : 83% of 6242 x 12% of 225 = ?

= $(\frac{83}{100} \times 6242) \times (\frac{12}{100} \times 225)$

= $5180.86 \times 27$

= $139883.22$

3) Answer (B)

Expression : $1{1 \over 8} + 1{6 \over 7} + 3{3 \over 5}$ = ?

= $(1 + 1 + 3) + (\frac{1}{8} + \frac{6}{7} + \frac{3}{5})$

= $5 + (\frac{35 + 240 + 168}{280})$

= $5 + \frac{443}{280} = 5 + \frac{280 + 163}{280}$

= $5 + (1 + \frac{163}{280}) = 6{{163} \over {280}}$

4) Answer (A)

Expression : ? ÷ 25 ÷ 12 = 248.76

=> $\frac{x}{25} \times \frac{1}{12} = 248.76$

=> $x = 248.76 \times 300$

=> $x = 74628$

5) Answer (D)

Expression : ${(73)^3}$

= $73 \times 73 \times 73$

= $5329 \times 73 = 389017$

---

Shortcut Method : We can find the last two digits of $73^3$, which is ’17’

Thus, ans – (D)

6) Answer (E)

Expression : $\sqrt[3]{1331}$

= $\sqrt[3]{11 \times 11 \times 11}$

= $11$

7) Answer (C)

Expression : 188.21 – 27.54 – 11.93 = ?

= 188.21 – 39.47

= 148.74

8) Answer (D)

Expression : 1268 ÷ 8 ÷ 2 = ?

= $\frac{1268}{8} \div 2$

= $\frac{158.5}{2} = 79.25$

9) Answer (E)

Expression : ${8^{1.1}} \times {4^2}^{.7} \times {2^{3.3}} = {2^?}$

=> $(2)^{3 \times 1.1} \times (2)^{2 \times 0.7} \times (2)^{3.3} = (2)^x$

=> $(2)^{3.3} \times (2)^{1.4} \times (2)^{3.3} = (2)^x$

=> $(2)^{3.3 + 1.4 + 3.3} = (2)^x$

Comparing both sides, we get :

=> $x = 3.3 + 1.4 + 3.3 = 8$

10) Answer (B)

Expression : 344 ÷ 4.99 + 144.08 ÷ 8.89 =?

= $(\frac{345}{5}) + (\frac{144}{9})$

= $69 + 16 = 85$

11) Answer (B)

Expression : 43.99 x 20.001 – 1439 ÷ 6 = ?

= $(44 \times 20) – (\frac{1440}{6})$

= $880 – 240 = 640$

12) Answer (B)

Expression : 459.85 + 519.82 = ?% of 1399.92

=> $460 + 520 = \frac{x}{100} \times 1400$

=> $980 = 14x$

=> $x = \frac{980}{14} = 70$

13) Answer (B)

40 % of 249 ÷ 4 + ? = 6.9992

0.40*249/4 – 6.9992 = ?

? = 18

 

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