Algebra Questions for IBPS Clerk set-2 PDF
Download important Algebra Questions set-2 PDF based on previously asked questions in IBPS Clerk and other Banking Exams. Practice Scheduling Questions and Answers for IBPS Clerk Exam.
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Question 1: The value of x for which the expressions 19 - 5x and 19x + 5 become equal is …………..
a) 7/12
b) -7/12
c) -12/7
d) 12/7
Question 2: If 7 + 4x > 3 + 3x and 3x – 2 < 5 – x; then x can take which of the following values?
a) 2
b) 3
c) 1
d) -5
Question 3: If $3x^{2} = 10^{2} – 5^{2}$, find the value of x?
a) 7
b) 5
c) 9
d) 11
Question 4: If (7x – 13) – (12x + 3) = 14, then the value of x is ______ .
a) -6
b) 6
c) 2/5
d) -2/5
Question 5: If 2 + 2x < 5 – x/2 and 5x + 3 > 5 – 5x; then x can take which of the following values?
a) 2
b) 0
c) -2
d) 1
Question 6: If (x + y):(x – y) = 5:2, find value of (4x + 5y) / (x – 4y)
a) 43/5
b) -5/43
c) -43/5
d) 5/43
Question 7: The value of x for which the expressions 11x + 7 and 17x – 1 become equal is ______.
a) -4/3
b) 3/4
c) 4/3
d) -3/4
Question 8: If 2x + 3y = 0 and 3x - 4y = 34, then x - y =
a) 10
b) -10
c) 2
d) -2
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Question 9: If 5 - 3x < 4 - x and 5(2 - x) > 2 - 2x, then x can take which of the following values?
a) 0
b) -1
c) 1
d) 3
Question 10: If a:b = 3:8, find the value of (5a – 3b)/(2a + b).
a) 9/14
b) 14/9
c) -9/14
d) -14/9
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Answers & Solutions:
1) Answer (A)
Expressions : 19 - 5x and 19x + 5
=> $19 – 5x = 19x + 5$
=> $19x + 5x = 19 – 5$
=> $24x = 14$
=> $x = \frac{14}{24} = \frac{7}{12}$
=> Ans – (A)
2) Answer (C)
Expression 1 : 7 + 4x > 3 + 3x
=> $4x – 3x$ > $3 – 7$
=> $x$ > $-4$ ————–(i)
Expression 2 : 3x – 2 < 5 – x
=> $3x + x$ < $5 + 2$
=> $4x$ < $7$
=> $x$ < $\frac{7}{4}$ —————–(ii)
Combining inequalities (i) and (ii), we get : $-4$ < $x$ < $\frac{7}{4}$
Thus, $x$ can take values = -3 , -2 , -1 , 0 , 1
=> Ans – (C)
3) Answer (B)
Expression : $3x^{2} = 10^{2} – 5^{2}$
=> $3x^2 = 100 – 25$
=> $3x^2 = 75$
=> $x^2 = \frac{75}{3} = 25$
=> $x = \sqrt{25} = 5$
=> Ans – (B)
4) Answer (A)
Expression : $(7x – 13) – (12x + 3) = 14$
=> $7x – 13 – 12x – 3 = 14$
=> $-5x – 16 = 14$
=> $-5x = 16 + 14 = 30$
=> $x = \frac{30}{-5} = -6$
=> Ans – (A)
5) Answer (D)
Expression 1 : 2 + 2x < 5 – x/2
=> $2x + \frac{x}{2}$ < $5 – 2$
=> $\frac{5x}{2}$ < $3$
=> $x$ < $\frac{6}{5}$ ———-(i)
Expression 2 : 5x + 3 > 5 – 5x
=> $5x + 5x$ > $5 – 3$
=> $10x$ > $2$
=> $x$ > $\frac{1}{5}$ ———-(ii)
Combining inequalities (i) and (ii), we get : $\frac{1}{5}$ < $x$ < $\frac{6}{5}$
Thus, the only value that $x$ can take = 1
=> Ans – (D)
6) Answer (C)
Given : $\frac{x + y}{x – y} = \frac{5}{2}$
=> $2x + 2y = 5x – 5y$
=> $2y + 5y = 5x – 2x$ => $7y = 3x$
=> $y = \frac{3x}{7}$
To find : $\frac{4x + 5y}{x – 4y}$
= $[4x + 5(\frac{3x}{7})] \div [x – 4(\frac{3x}{7})]$
= $(4x + \frac{15x}{7}) \div (x – \frac{12x}{7})$
= $(\frac{43x}{7}) \div (\frac{-5x}{7})$
= $\frac{43x}{7} \times \frac{-7}{5x} = \frac{-43}{5}$
=> Ans – (C)
7) Answer (C)
Expressions : 11x + 7 and 17x – 1
=> $11x + 7 = 17x – 1$
=> $17x – 11x = 7 + 1$
=> $6x = 8$
=> $x = \frac{8}{6} = \frac{4}{3}$
=> Ans – (C)
8) Answer (A)
Equation 1 : 2x + 3y = 0
Multiplying by 3 on both sides, we get : $6x + 9y = 0$ ———–(iii)
Equation 2 : 3x - 4y = 34
Multiplying by 2 on both sides, => $6x – 8y = 68$ ———–(iv)
Subtracting equation(iv) from (iii),
=> $(6x – 6x) + (9y + 8y) = (0 – 68)$
=> $17y = -68$
=> $y = \frac{-68}{17} = -4$
Substituting it in equation (i), we get : $2x + 3(-4) = 0$
=> $2x = 12$
=> $x = \frac{12}{2} = 6$
$\therefore (x – y) = 6 – (-4) = 6 + 4 = 10$
=> Ans – (A)
9) Answer (C)
Expression 1 : 5 - 3x < 4 - x
=> $3x-x$ > $5-4$
=> $2x$ > $1$
=> $x$ > $\frac{1}{2}$ ————(i)
Expression 2 : 5(2 - x) > 2 - 2x
=> $10-5x$ > $2-2x$
=> $5x-2x$ < $10-2$
=> $3x$ < $8$
=> $x$ < $\frac{8}{3}$ ————–(ii)
Combining inequalities (i) and (ii), we get : $\frac{1}{2}$ < $x$ < $\frac{8}{3}$
The only value that $x$ can take among the given options = 1
=> Ans – (C)
10) Answer (C)
It is given that $a$ : $b$ = 3 : 8
Let $a = 3$ and $b = 8$
To find : $\frac{5a – 3b}{2a + b}$
= $\frac{(5 \times 3) – (3 \times 8)}{(2 \times 3) + (8)}$
= $\frac{(15 – 24)}{(6 + 8)} = \frac{-9}{14}$
=> Ans – (C)
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