Expected Reasoning Questions for SSC CGL 2020 PDF:
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Question 1: If A=1,
CAT=60,
then MAN=?
a) 27
b) 90
c) 180
d) 182
Question 2: Find the missing number from the given responses:
a) 12
b) 51
c) 56
d) 120
Question 3: If Jhansi is 12 ahead in rank of Prabha, who ranks 15th from last, then how many students are there in the class if Jhansi ranks 4th in order of merit ?
a) 23
b) 27
c) 30
d) 31
Question 4: The distance between two cities is 30 Km. A man goes at a speed of 30 Km per hour and returns at 20 Km per hour. What is his average speed
a) 25 Km/hr
b) 24 Km/hr
c) 10 Km/hr
d) 26 Km/hr
Question 5: Find the missing term in the following question:
a) 3
b) 9
c) 1
d) 7
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Question 6: 14 notebooks of a class were corrected with ink pen while 22 notebooks were corrected with colour pencil. If 4 notebooks were corrected with both, what is the strength of class?
a) 30
b) 32
c) 28
d) 25
Question 7: In a row of 15 children, when Raju was shifted three places towards right, he became 8th from the right end. What was his earlier position from the left end of the row?
a) 14
b) 12
c) 6
d) 5
Question 8: In a row of students, if John , who is 16th from the left, and Johnson, who is 8th from the right, interchange their positions, John becomes 33rd from left. How many students are there in a row?
a) 38
b) 39
c) 40
d) 41
Question 9: Some equations are solved on the basis of certain system. Find out the correct answer for the unsolved equation on that basis.
If 3*2*8*4 = 632 , 2*4*4*4 = 816 then 3*3*5*1 = ?
a) 95
b) 45
c) 315
d) 184
Question 10: How many squares are there in the given figure ?
a) 4
b) 5
c) 8
d) 9
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Answers & Solutions:
1) Answer (D)
If the letters are represented by respective numbers, A = 1 , B = 2 , C = 3 ,……….., Z = 26
A = 1
CAT = 3 $\times$ 1 $\times$ 20 = 60
MAN = 13 $\times$ 1 $\times$ 14 = 182
=> Ans – (D)
2) Answer (D)
In the first column, the number at the end is obtained by multiplying the first two numbers and adding the result with the third number.
Eg : $(6\times8)+3=48+3=51$
and $(15\times4)+5=60+5=65$
Similarly, $(20\times5)+20=100+20=120$
=> Ans – (D)
3) Answer (C)
Prabha’s rank from last = 15th
=> Jhansi’s rank from last = 15 + 12 = 27th
Also, Jhansi’s rank from top = 4th
$\therefore$ Total number of students = (27+4) – 1 = 31 – 1 = 30
=> Ans – (C)
4) Answer (B)
Total distance between cities = 30 km
Using, time = distance/speed
Time taken when speed is 30 kmph = $\frac{30}{30}=1$ hour
Similarly, time taken in the return journey = $\frac{30}{20}=1.5$ hours
$\therefore$ Average speed = total distance/total time
= $\frac{30+30}{1+1.5}=\frac{60}{2.5}$
= $24$ km/hr
=> Ans – (B)
5) Answer (C)
The numbers written are cubes of natural numbers.
$1^3$ = 1
$2^3$ = 8
$3^3$ = 27
$4^3$ = 64
=> Ans – (C)
6) Answer (B)
Notebooks corrected with ink pen = 14
Notebooks corrected with colour pencil = 22
Notebooks corrected with both = 4
Thus, strength of class = $(22+14)-4=36-4=32$
=> Ans – (B)
7) Answer (D)
Total children in the row = 15
Raju’s final position from right end = 8th
=> Raju’s initial position from right end = 8+3 = 11th
$\therefore$ His earlier position from left end = (15-11)+1 = 5th
=> Ans – (D)
8) Answer (C)
Johnson’s initial position from right end = 8th
John’s final position from left end = 33rd
Both of them are on the same seat.
=> Total students in the row = (33+8) – 1 = 40
=> Ans – (C)
9) Answer (A)
The product of the first two and the last two numbers is concatenated.
Eg : 3*2*8*4 = 6 and 32 = 632
and 2*4*4*4 = 8 and 16 = 816
Similarly, 3*3*5*1 = 9 and 5 = 95
=> Ans – (A)
10) Answer (B)
Small squares = AEIG, EBHI, GCFI, IHDF
Big square = ABCD
Thus, total squares = 5
=> Ans – (B)
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