Arithmetic Questions for RRB Group-D PDF
Download Top 15 RRB Group-D Arithmetic Questions and Answers PDF. RRB Group-D Arithmetic questions based on asked questions in previous exam papers very important for the Railway Group-D exam.
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Question 1: What is the value closest to $\sqrt{2028}$ – $\sqrt{1152}$?
a) 8
b) 9
c) 10
d) 11
Question 2: What is the square root of 156.25
a) 13.5
b) 15.25
c) 10.5
d) 12.5
Question 3: If $Y – \sqrt{Y} = 30$, what is the value of $Y$?
a) 25
b) 36
c) Any of the above two options
d) Can’t be determined
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Question 4: What is the value of $21^3 – 19^3$
a) 2602
b) 2202
c) 2204
d) 2402
Question 5: $\sqrt{0.01+\sqrt{0.0967+0.0258}}$ = ?
a) 0.6
b) 0.5
c) 0.4
d) 0.3
Question 6: When polynomial $x^{4}-3x^{2}+2x+5$ is divided by (x-1), the remainder is
a) 2
b) 3
c) 4
d) 5
RRB Group D previous year papers
Question 7: Evaluate :- $(-216 \times 1728)^{\frac{1}{3}}$
a) -72
b) 27
c) 72
d) -27
Question 8: What is the average of 56, 45, 47, 61, 49, 54 and 52
a) 52
b) 54
c) 49.12
d) 63
Question 9: 45/13 * (19 + 7) + 5 = ?
a) 95
b) 105
c) 100
d) 87.5
Question 10: If the function $x^3-3x^2+2x-a$ is divisible by (x-2), then find the value of “a”.
a) 0
b) 1
c) 2
d) -1
RRB Group-D Important Questions (download PDF)
Question 11: If the number 2a3 is divisible by 11, then find the value of “a”?
a) 3
b) 4
c) 5
d) 6
Question 12: 4.23232323… = ?
a) 422/99
b) 440/9
c) 419/99
d) 415/99
Question 13: IF 5=10,6=18,7=35,8=56,10=?
a) 100
b) 130
c) 120
d) 110
Question 14: By interchanging which two signs the equation will be correct?
19 + 36 x 12 ÷ 4 – 26 = 5
a) + and –
b) x and ÷
c) ÷ and –
d) + and x
Question 15: The following equation is incorrect. Which two signs should be interchanged to correct the equation?
$15 \times 12 + 40 \div 40 – 6 = 21$
a) + and x
b) + and ÷
c) – and +
d) ÷ and x
General Science Notes for RRB Exams (PDF)
Answers & Solutions:
1) Answer (D)
The value of $\sqrt{2025}$ = 45
The value of $\sqrt{1152}$ = 34
So, the value closest to $\sqrt{2028}$ – $\sqrt{1152}$ = 11
2) Answer (D)
$15625 = 5*3125 = 25*625 = 25^3 = 5^6$
Hence, $\sqrt{15625} = 5^3 = 125$
Therefore, $\sqrt{156.25} = 12.5$
3) Answer (B)
Let the value of $\sqrt{Y} = p$. Note that $p$ is positive.
Therefore, $p^2 – p = 30$
Or, $p^2 – p – 30 = 0$
Therefore, $p^2 – 6p + 5p – 30 = 0$
Therfore, $(p-6)(p+5)=0$
Hence, $p=6$ or $p=-5$
But as $p$ is positive, it implies that $p=6$ and $Y=p^2=36$
4) Answer (D)
We know that $a^3 – b^3 = (a-b) \times (a^2 + ab + b^2) = (a-b) \times ((a+b)^2 – ab)$
In this case, $21^3 – 19^3 = (21 – 19) \times (21^2 + 21 \times 19 + 19^2)$
Which equals $2 \times ((21+19)^2 – 21\times 19)$
This equals $2 \times (40^2 – 399) = 2 \times (1600-399) = 2 \times 1201 = 2402$
5) Answer (A)
$\sqrt{0.01+\sqrt{0.0967+0.0258}}$ = $\sqrt{0.01+\sqrt{0.1225}}$ = $\sqrt{0.01+0.35}$ = $\sqrt{0.36}$ = $0.6$
So the answer is option A.
6) Answer (D)
$f(x)=x^{4}-3x^{3}+2x +5$
to find the remainder put x=1 in $f(x)$
$f(1)$=1-3+2+5=5
∴5 is the remainder
7) Answer (A)
$(-216 \times 1728)^{\frac{1}{3}}$
=$(-6^{3} \times 12^{3})^{\frac{1}{3}}$
=-72
8) Answer (A)
We see that the numbers are distributed around 50.
So we find the differences around 50
Estimated mean= 50
Sum = +6-5-3+11-1+4+2 =14
n=7
Actual mean = 50 + 14/7 = 52.
9) Answer (A)
As per BODMAS rule, we would add the contents of the brackets first.
=> 45/13 *26 + 5
26 = 13 * 2
=> 45 * 2 + 5
=> 90 + 5
=> 95
10) Answer (A)
f(x) = $x^3-3x^2+2x-a$. f(2) = 0
$2^3-(3*2*2)+(2*2)-a = 0$
$8-12+4-a = 0$
a = 0
11) Answer (C)
Since 2a3 is divisible by 11, therefore (2+3-a) should be divisible by 11.
5-a = 0 or divisible by 11
a = 5.
12) Answer (C)
x = 4.232323….
100x = 423.23232323….
100x-x = 423.2323…-4.2323… = 419
x = 419/99
13) Answer (B)
In this sequence each number is multiplied by a prime number 5*2=10,6*3=18,7*5=35,8*7=56,9*11=99,10*13=130.
14) Answer (B)
Expression : 19 + 36 x 12 ÷ 4 – 26 = 5
(A) : + and –
$\equiv19-36\times12\div4+26=5$
L.H.S. = $19-(36\times3)+26=19-108+26=-63\neq$ R.H.S.
(B) : x and ÷
$\equiv19+36\div12\times4-26=5$
L.H.S. = $19+(3\times4)-26=19+12-26=5=$ R.H.S.
=> Ans – (B)
15) Answer (A)
Expression : $15 \times 12 + 40 \div 40 – 6 = 21$
(A) : + and x
$\equiv15+ 12 \times 40 \div 40 – 6 = 21$
L.H.S. = $15+(12\times\frac{40}{40})-6$
= $15+12-6=21=$ R.H.S.
=> Ans – (A)
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