Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 59
If each edge of a cube is increased by 50%, the percentage increase in its surface area is
Solution
Let edge of cube, $$a = 10$$ cm
Surface Area, $$S = 6 a^2 = 6 (10)^2 = 600 cm^2$$
When edge is increased by 50%
=> New edge of cube, $$a' = 10 + \frac{50}{100} \times 10 = 15$$ cm
New surface area, $$S' = 6 (a')^2 = 6 (15)^2 = 1350 cm^2$$
$$\therefore$$ % increase in surface area = $$\frac{1350 - 600}{600} \times 100$$
= $$\frac{750}{6} = 125 \%$$
Create a FREE account and get:
- Download Maths Shortcuts PDF
- 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
