**Time and Distance Questions for SSC CGL PDF Set-2:**

Time and Distance Questions for SSC CGL PDF

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**Question 1:** Raj and Prem walk in opposite directions at the rate of 3 km and 2 km per hour respectively. How far will they be from each other after 2 hours ?

a) 10 km

b) 8 km

c) 6 km

d) 2 km

**Question 2:** A train runs at an average speed of 75 km/hr. If the distance to be covered is 1050 kms, how long will the train take to cover it ?

a) 13 hrs

b) 12 hrs

c) 15 hrs

d) 14 hrs

**Question 3:** A and B are 20 km apart. A can walk at an average speed of 4 km/hour and B at 6 km/ hr. If they start walking towards each other at 7 a.m., when they will meet ?

a) 8.00 a.m.

b) 8.30 a.m.

c) 9.00 a.m.

d) 10.00 a.m.

**Question 4:** A policeman starts to chase a thief. When the thief goes 10 steps the policeman moves 8 steps. 5 steps of the policeman is equal to 7 steps of the thief. The ratio of the speeds of the policeman and the thief is

a) 25 : 28

b) 25 : 26

c) 28 : 25

d) 56 : 25

**Question 5:** A tap drips at a rate of one drop/sec. 600 drops make 100m1. The number of litres wasted in 300 days is

a) 4320000

b) 432000

c) 43200

d) 4320

**Question 6:** A gun is fired at a distance of 1.34 km from Geeta. She hears the sound after 4 seconds. The speed at which sound travels is

a) 325 m/sec

b) 335 m/sec

c) 330 m/sec

d) 300 m/sec

**Question 7:** A and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days and B for 7 days, C finishes it in 13 days. In how many days B could finish the work ?

a) 48 days

b) 24 days

c) 16 days

d) 12 days

**Question 8:** A policeman goes after a thief who has 100 metres start, if the policeman runs a kilometre in 8 min, and the thief a km in 10 min, the distance covered by thief before he is overpowered is

a) 350 m

b) 400 m

c) 320 m

d) 420 m

**Question 9:** A swimmer swims from a point A against a current for 5 minutes and then swims backwards in favour of the current for next 5 minutes and comes to the point B. If AB = 100 metres, the speed of the swimmer (in km per hour) is :

a) 0.4

b) 0.2

c) 1

d) 0.6

**Question 10:** Santa and Julie start walking from the same place in the opposite directions. If Julie walks at a speed of 2.5 km/hr and Santa at a speed of 2 km/hr, in how much time will they be 18 km apart ?

a) 4.0 hrs

b) 4.5 hrs

c) 5.0 hrs

d) 4.8 hrs

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**Answers & Solutions for Time and Distance Questions for SSC CGL PDF:**

**1) Answer (A)**

Since Raj and Prem walks in opposite directions, their relative speed will be sum of their

individual speeds i.e.

Speed, ss = 3+2 = 5 kmph

Now, distance covered in 2 hours = time * speed

= 5*2 = 10 km

**2) Answer (D)**

Speed of train = 75 km/h

Distance to be covered = 1050 km

=> Time taken = distance / Speed

= 1050 / 75 => 14 hours.

**3) Answer (C)**

Distance between A & B = 20 km

Since they are walking towards each other, their relative speed will be the sum of their individual speeds

=> relative speed = 6+4 = 10 km/h

=> Time taken to meet each other = 20 / 10 = 2 hours

=> They will meet at (7+2) = 9.00 a.m.

**4) Answer (C)**

5 steps of Policeman = 7 steps of a thief

=> 1 step of Policeman = 7/5 steps of thief

=> 8 Steps of Policeman = 8 x 7/5 steps of thief = 56/5 steps of thief

The ratio of speeds of policeman and thief = ratio of distance covered by policeman and thief in a same time

=> In same time policeman moves 8 steps and thief moves 10 steps

=> 56/5 : 10 (because as we calculated earlier 8 steps of policeman = 56/5 steps of thief)

=> 56 : 50 = 28 : 25

**5) Answer (D)**

Rate at which tap drips = 1 drop/sec

Now, no. of seconds in 1 day = 24*60*60 = 86400 sec

=> In 1 day the tap drips 86400 drops

=> 86400 / 600 ∗100 = 14400 ml = 14.4 litres

Thus, in 300 days, water wasted = 14.4*300 = 4320 litres

**6) Answer (B)**

speed = distance/time = 1.34km/4sec = 1340m/4sec = 335m/s.

so the answer is option B.

**7) Answer (A)**

Let us assume the total work to be done as 48 units.

Let the capacities of A be a, B be b and C be c.

12(a+b) = 48 => a+b = 4 ———-(1)

16 (b+c) = 48 => b+c = 3.———–(2)

5a+7b+13c = 48 (Given in the question). ————(3)

(1) x 5 + (2) x 13 => 5a + 5b + 13b + 13c =20+39

5a+18b+13c = 59 —————————-(4)

(4) – (3) => 11b = 11

b = 1

Therefore, b can complete the work in 48 days. Option A is the right answer.

**8) Answer (B)**

given that thief is already 100 m far from police and speed of police is 125 m/min

Speed of thief = 100 m /min

Relative speed of police= 125-100=25 m/min

Using distance = speed x time

100 = 25 × T

T= 4min

In 4 minutes ,thief can cover = 100 × 4 = 400 m

**9) Answer (D)**

Let the speed of the swimmer be S and current be X.

5(S-X)+ 5 (S+X)= 100

=> 10S = 100

S = 10 m/min = 600 m/hour = 0.6 kmph.

Option D is the right answer.

**10) Answer (A)**

here it is given that speed of Santa and Julie are 2.5km/hr and 2km/hr respectively

As it is mentioned that both are going in opposite direction then relative speed = 2.5+2 = 4.5 km/hr

Using Distance = Speed × Time

Distance = 18km

18 = 4.5 × T

T = 4 hours