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# Time and Work Questions for SSC MTS

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Question 1:Â Ten men or twelve women can finish the same workin 10 days. If 5 men and 2 women undertake the work together, how many days will they take to complete the work?

a)Â 15

b)Â 40

c)Â 20

d)Â 60

Solution:

Total work = time $\times$ (men + women)

Ten men or twelve women can finish the same workin 10 days so,

$10m \times 10 = 12w \times 10$

5m = 6w

LetÂ time taken to complete same work by 5 men and 2 women be d days.

Total work done byÂ 5 men and 2 women = (5m + 2w) $\times$ d

12w $\times 10$ =Â (6w + 2w) $\times$ d

d = 120/8 = 15 days

$\therefore$ They will completed the same work in 15 days.

Question 2:Â Two cars A and B leave Delhi at 8:30 a.m. and at 9 a.m. for Shimla, respectively. They travel at the speeds of 40km/h and 50 km/h respectively. How many kilometres away from Delhi will the two cars be together?

a)Â 45 km

b)Â 100 km

c)Â 200 km

d)Â 5 km

Solution:

Cars A and B leave Delhi at 8:30 a.m. and at 9 a.m. for Shimla, respectively so,

Distance traveled by car A in 30 min = speed $\times times = 40 \times 1/2 = 20 km (30 min = 30/60 hr = 1/2 hr) Relative speed of car B = 50 – 40 = 10 km/hr Time taken by car B to cover 20 kmÂ = 20/10 = 2 hr (Time = distance/speed) Distance covered in 2 hr = 50 \times 2 = 100 km$\therefore$100Â kilometers away from Delhi will the two cars be together. Question 3:Â A and B, working together, can complete a work in d days. Working alone, A takes (8 + d) days and B takes (18 + d) days to complete the same work. A works for 4 days. The remaining work will be completed by B alone, in: a)Â 24 days b)Â 16 days c)Â 18 days d)Â 20 days 3)Â AnswerÂ (A) Solution: To find the time whenÂ A and B, working together =$\sqrt{more days taken by A \times more days taken by B}$d =$\sqr{8 \times 18}$= 12 Time taken by A to complete the work = (8 + d) = 8 + 12 = 20 Time taken by B to complete the work = (18 + d) = 18 + 12 = 30 Let the total work be 60. (LCM of 20 and 30 is 60.) Efficiency of A = 60/20 = 3 Efficiency of B = 60/30 = 2 Work done by A in 4 days = efficiency$\times time = 3 \times 4 = 12$Remaining work = 60 – 12 = 48 Time taken by B to complete the remaining work = 48/2 = 24 days$\therefore$Â The remaining work will be completed by B alone, in 24 days. Question 4:Â The time taken by a boat to travel 13 km downstream is the same as time taken by it to travel 7 km upstream. If the speed of the stream is 3 km/h, then how much time (in hours) will it take to travel a distance of 44.8 km in still water? a)Â$4\frac{12}{25}$b)Â$5\frac{3}{5}$c)Â$5\frac{2}{5}$d)Â$4\frac{13}{25}$4)Â AnswerÂ (A) Solution: Speed of the stream = 3 km/h Let the speed of the boat be v. Speed in downstream = 3 + v Speed in upstream = v – 3 Time = distance/speed According to the question, The time taken by a boat to travel 13 km downstream = time taken by boat to travel 7 km upstream 13/(3 + v) = 7/(v – 3) 13v – 39 = 21 + 7v 6v = 60 v = 10 km/h Speed of boat = 10 km/h The time taken by a boat to travelÂ a distance of 44.8 km in still water = 44.8/10 = 112/25 =$ 4 \frac{12}{25}$hr Question 5:Â Eight persons can finish a work in 20 days. After 5 days they were requested to complete the work in the next 8 days. How many more persons should join the group to fulfil the requirement? a)Â 23 b)Â 15 c)Â 7 d)Â 12 5)Â AnswerÂ (C) Solution: Total work = number of persons$\times time = 8 \times 20 = 160$Work done in 5 days = 8$times 5 = 40$Remaining Work = 160 – 40 = 120 According to question, Number of man$\times$Â time = 120 Number of man$\times$8 = 120 Number of man = 120/8 = 15 Number ofÂ persons should join the group = 15 – 8 = 7 Question 6:Â A can finish a work in 20 days and B can finish the same work in 25 days. They begin together, but B left the work after 5 days. How many more days will A take to finish the remaining work? a)Â 11 b)Â 8 c)Â 16 d)Â 21 6)Â AnswerÂ (A) Solution: Let the total work be 100 units. ($\because LCM of 20 and 25 is 100.$) Efficiency of A = work/time = 100/20 = 5 unit/day Efficiency of B = 100/25 = 4 unit/day Work done by A and B in 5 days = efficiency$\times times =Â (4 +Â  5) \times$5 = 45 units Remaining work = 100 – 45 = 55 units Time taken by AÂ to complete 55 units work = 55/5 = 11 days Question 7:Â A can do a piece of work in 6 days. B can do it in 9 days. With the assistance of C they completed the work in 3 days. In how many days can C alone do the work ? a)Â 18 b)Â 8 c)Â 12 d)Â 16 7)Â AnswerÂ (A) Solution: Let the total work be 18 units. ($\because$LCM of 6, 9 and 3 is 18.) Efficiency of A = work/time = 18/6 = 3 units/day Efficiency of B = 18/9 = 2Â units/day Efficiency of (A + B + C)Â = 18/3 = 6Â units/day Efficiency of C =Â Efficiency of (A + B + C) –Â Efficiency of A –Â Efficiency of B = 6 – 3 – 2 = 1 unit/day Time taken by C to complete work alone = 18/1 = 18 days Question 8:Â A train crosses a platform 180 m long in 60 sec at a speed of 72 km/h. The time taken by the train to cross an electric pole is: a)Â 51 sec b)Â 0.51 min c)Â 5.1 sec d)Â 5.1 min 8)Â AnswerÂ (A) Solution: Length of platform = 180 m Time = 60 sec Speed = 72 km/hrÂ = 72$\times$5/18 = 20 m/sec Total length =Â length of platform +Â length of train = 180 +Â length of train Speed = length/time 180 + length of train = 20$\times$60 Length of train =1200 – 180 = 1020 m The time taken by the train to cross an electric pole = 1020/20 = 51 sec Question 9:Â The two trains leave Varanasi for Lucknow at 11:00 a.m. and at 11:30 a.m., respectively and travel at a speed of 110 km/h and 140 km/h, respectively. How many kilometers from Varanasi will both trains meet? a)Â$255\frac{1}{3}$km b)Â$238\frac{2}{3}$km c)Â$246\frac{1}{3}$km d)Â$256\frac{2}{3}$km 9)Â AnswerÂ (D) Solution: Let the train which leaves Varanasi at 11:00 be A and another train be B. Speed of train A = 110 km/hr Speed of train B = 140 km/hr Distance covered by train A in 30 min(30/60 = 1/2 hr)Â = speed$\times time = 110 \times 1/2 = 55 km$At 11:30, distance between both trains will be 55 km. Relative speed of train B = 140 – 110 = 30 km/hr Time taken by train BÂ to meet = 55/30 = 11/6 hr Distance covered by train B in 11/6 hr = 140$\times 11/6 = 256 \frac{2}{3}\therefore 256 \frac{2}{3}$Â kilometers from Varanasi will both trains meet. Question 10:Â A contract is to be completed in 75 days and 187 men are to work 15 hours per day. After 65 days,$\frac{3}{5}$of the work is completed. How many additional men may be employed, so that the work may be completed in time, each man now working 17 hours per day? a)Â 532 b)Â 495 c)Â 308 d)Â 514 10)Â AnswerÂ (C) Solution:$10\times\ \ \ $From the formula, Total work =Â$\frac{mdh}{w1}$here, m = man/woman d =days h = hour w = work Total work =$75 \timesÂ 187 \times 15$Â =Â 210375 Work done in 65 days =Â 210375$\times \frac{3}{5}$= 126255 Remaining work =Â 210375 –Â 126255 = 84150$(187 + m) \timesÂ 10 \times 17$= 84150 (187 + m) = 495 m = 495 -187 = 308$\therefore$308Â additional men may be employed, so that the work may be completed in time. Question 11:Â Two cyclists X and Y start at the same time from place A and go towards place B at a speed of 6 km/h and 8 km/h,respectively. Despite stopping for 15 minutes during the journey, Y reaches 10 minutes earlier than X. The distance between the places A and B is: a)Â 6 km b)Â 16.5 km c)Â 8 km d)Â 10km 11)Â AnswerÂ (D) Solution: Time = distance/speed Time taken by x to reach destination =Â Time taken by y to reach destination + 10 min Let the Distance be d.$\frac{d}{6} = \frac{d}{8}+ \frac{15}{60}+Â \frac{10}{60}\frac{d}{6} = \frac{d}{8}+ \frac{1}{4}+ \frac{1}{6}\frac{d}{6} = \frac{3d + 6 + 4}{24}$d=$\frac{3d + 10}{4}$4d = 3d +Â 10 d = 10 km$\therefore$Â The distance between the places A and B is 10 km. Question 12:Â Amit and Sunil together can complete a work in 9 days, Sunil and Dinesh together can complete the same work in 12 days, and Amit and Dinesh together can complete the same work in 18 days. In how many days will they complete the work if Amit, Sunil and Dinesh work together? a)Â 12 days b)Â 8 days c)Â 14 days d)Â 16 days 12)Â AnswerÂ (B) Solution: Let the total work be 36 units. ($\because$LCM of 9, 12 and 18 is 36.) Efficiency ofÂ Amit and Sunil = work/time = 36/9 = 4 units/day Efficiency ofÂ Sunil and Dinesh = 36/12 = 3 units/day Efficiency ofÂ Amit and Dinesh = 36/18 = 2Â units/day Efficiency of Amit,Â Sunil andÂ Dinesh =$\frac{4 + 3 + 2}{2}$= 9/2 Time taken by Amit, Sunil and Dinesh to complete the work =$\frac{36}{9/2}$= 8 days Question 13:Â A, B and C can individually complete a task in 24 days,16 days and 32 days respectively. If A and C start the work and worked for 6 days and left, then the number of days required by B to complete the remaining task, is: a)Â$9$b)Â$17\frac{1}{2}$c)Â$7\frac{1}{2}$d)Â$12\frac{1}{2}$13)Â AnswerÂ (A) Solution: Let the total work be 96 units. ($\because$LCM of 24, 16 and 32 is 96.) Efficiency of A = work/time = 96/24 = 4 Efficiency of B = 96/16 = 6 Efficiency of C = 96/32 = 3 Efficiency of A and C = 4 + 3 = 7 Work done by A and C in 6 days = 7$\times$6 = 42 units Remaining work = 96 – 42 = 54 units Time taken by B to complete 54 units work = 54/6 = 9 days Question 14:Â Sixteen men can finish a work in 8 days. Eight men and nine women working together can finish the same work in 10 days. In how many days will twenty women finish the same work? a)Â 9 b)Â 12 c)Â 11 d)Â 13 14)Â AnswerÂ (B) Solution: Total work = man/woman$\times$time Work is same so, 16m$\times 8 = (8m + 9w) \times 10

$\Rightarrow$ 128m = 80m + 90w

$\Rightarrow$ 48m = 90w

$\Rightarrow$ 8m = 15w

Let the 20 women complete work in days so,

Total work = 20w $\times$ d

$\Rightarrow$ (8m + 9w) \times 10Â = 20w $\times$ d

$\Rightarrow$ (15w + 9w) \times 10 = 20w $\times$ d

$\Rightarrow$ 24w \times 10 = 20w $\times$ d

$\Rightarrow$ d = 12 days

$\therefore$Â Twenty women finish the same work in 12 days.

Question 15:Â Pipes A and B can fill a tank in 10 hours and 40 hours, respectively. C is an outlet pipe attached to the tank. If all the three pipes are opened simultaneously, it takes 80 minutes more time than what A and B together take to fill the tank. A and B are kept opened for 7 hours and then closed and C was opened. C will now empty the tank in:

a)Â 49 hours

b)Â 38.5 hours

c)Â 42 hours

d)Â 45.5 hours

Solution:

Let the total work be 40 units.

$(\because$ L.C.M. of 10 and 40 is 40.)

Efficiency of A = work/time = 40/10 = 4 units/hour

Efficiency of B = 40/40 = 1Â unit/hour

Time time taken by pipe A and B = $\frac{40}{4 +Â 1}$ = 8 hours

Time time taken by pipe A, B andÂ C together = 8 hours + 80/60 hours = 28/3 hours

Efficiency ofÂ  A, B andÂ C together = $\frac{40}{28/3}$ = 30/7Â units/hour
Efficiency of C alone = 30/7 – 5 = -5/7 (- as pipe C is an outlet pipe and does negative work)

Work done by pipe A and B in 7 hours = (1 + 4)$\times$7 = 35 units

Time taken by pipe C to empty the tank = $\frac{35}{5/7}Â =Â Â 49$