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# SBI PO Expected Quant Questions 2019

Download SBI PO Expected Quant Questions & Answers PDF for SBI PO Prelims and Mains exam. Very Important SBI PO Expected Quant questions with solutions.

Question 1: In 8 years, Ramesh will be twice as old as Farheen was 8 years ago. If Ramesh is now 16 years older than Farheen, the present age of Farheen is :

a) 32

b) 40

c) 36

d) 44

e) 24

Question 2: A was thrice as old as B when C was 2 years old. A will be twice as old as B when C is 10 years old. How old will B be when the difference between the ages of A and B will be equal to the age of C?

a) 16 years

b) 22 years

c) 18 years

d) 24 years

e) 32 years

Question 3: The ratio of P’s age 3 years ago and Q’s age after 5 years is 6 : 13. If at present, the ratio of their ages is 11 : 20, then what is the ratio of P’s age 2 years hence and Q’s age 5 years ago?

a) $\frac{9}{11}$

b) $\frac{7}{9}$

c) $\frac{5}{13}$

d) $\frac{7}{11}$

e) $\frac{8}{13}$

Question 4: The sum of the ages of a P and Q is 53 years. Four years ago, the product of their ages was two times the square of Q’s age. The present age of P is?

a) 34 years

b) 38 years

c) 32 years

d) 42 years

e) 36 years

Question 5: The present age of Sanjay is 40 percent of his mother’s present age. 8 years from now, he will be half as old as his mother. What is the sum of present ages of Sanjay and his mother?

a) 42 years

b) 70 years

c) 56 years

d) 84 years

e) 50 years

Question 6: The average marks of a class increased by $\large\frac{1}{3}$ when a student’s marks were wrongly entered as 64 instead of 46. The number of students in the class are

a) 54

b) 58

c) 63

d) 57

e) None of these

Question 7: The average age of students in a class is 12. If the average age of boys is 18 and the average age of girls is 14 and If the number of boys are 22, then find the total number of students in the class

a) 52

b) 55

c) 60

d) 58

e) None of these

Question 8: In the first 20 overs of a cricket game, the run rate was 4.5, What should be the run rate in the next 30 overs of the game to chase the target of 210?

a) 6

b) 4

c) 8

d) 6.5

e) None of these

Question 9: In a society, 60% of residents own a car and 40% own a bike. Nobody owns car and bike both. Also, 25% of the residents work in the banking sector. If 20% of those who work in the banking sector own a bike, then the residents who own a car and work in non-banking sector form what percentage of the total people?

a) 25%

b) 40%

c) 37.5%

d) 60%

e) 42.5%

Question 10: Amit scored 10% less marks than Sumit and 20% more marks than Rakesh. If Tina scored 35 marks more than Amit and Sumit scored 20 marks less than Tina, what is the absolute difference between the marks of Tina and Rakesh?

a) 75

b) 82.5

c) 37.5

d) 57.5

e) 40

Instructions

The following table shows the breakup of the marks scored by students of Class X of Sharda Mandir in Maths for 5 years from 2001-2005.

Note: A student can score a maximum of 100 marks.

Question 11: The students scoring below 40 are said to have failed the exam whereas the students scoring in between are 60-90 said to have passed the exam with distinction.
What is the ratio of the number of students that failed and the number of students that got distinction during the given period?

a) 420:313

b) 417:305

c) 323:251

d) 4:3

e) 5:4

Question 12: The students scoring between 80 and 90 marks is said to have passed the exam with A grade. How many students got A grade during the given period?

a) 925

b) 775

c) 825

d) 875

e) 900

Question 13: What is the ratio of the number of students scoring marks in between 20 and 40 and the number of students scoring marks in between 80 and 90 in 2004?

a) 1:2

b) 3:4

c) 2:1

d) 4:3

e) 5:3

Question 14: What is the number of students scoring in between 40 and 60 in 2005?

a) 450

b) 470

c) 460

d) 480

e) 440

Question 15: How many students scored less than 40 in the year 2003?

a) 550

b) 475

c) 450

d) 425

e) 600

Question 16: To meet the demand during summer, a milkman mixed water with pure milk in 2:5. Then he sold the same mixture at 20% more than normal price. By what percent his revenue will increase during summers? (Water is available without any cost)

a) 60 percent

b) 50 percent

c) 40 percent

d) 68 percent

e) 63 percent

Question 17: A retailer bought 5 dozen notebooks. He got these notebooks at 30% less than printed price. To clear his stock soon he offered 1 notebook free on buying 4 notebooks. If the retailer sold all notebooks on printed price, what’s is retailer’s profit percentage in this transaction?

a) 28.57%

b) 21.35%

c) 12.48%

d) 42.89%

e) 14.28%

Question 18: Krishna purchased a new laptop. After 2 years, he sold it to Pradeep at a discount of 30% when compared to the actual cost price. Pradeep spent 680 for repairing the laptop after purchase. After using it for 2 years, he sold it to Ravi at a discount of 30% when compared to the total amount he invested in the laptop. If Ravi paid exactly half the amount which Krishna paid, find the amount that Krishna paid when he purchased the laptop?

a) 47600

b) 36600

c) 68000

d) 72000

e) None of the above.

Question 19: Gugan sold a computer to Raj by marking the price up by 20%. Raj then sold the computer to Hari at a profit of 30%. Hari sold the computer to Balu at a profit of 50%. If Balu bought the computer by paying Rs. 1560 more than the price at which Hari bought the computer, what is the actual cost price of the computer?

a) Rs.1000

b) Rs.2000

c) Rs.3000

d) Rs.4000

e) Rs.5200

Question 20: A shopkeeper marks up the price of an article by x%. Then, he offers a discount of (x/2)%.If he ends up with a loss of 48%, then the value of x is

a) 120

b) 80

c) 140

d) 160

e) 60

Let us assume the present age of Farheen = x years
So present age of Ramesh will be = x + 16 years

Ramesh’s age after 8 years will be = x+16+8 = x+24 years
Farheen’s age 8 years ago = x – 8 years

$\Rightarrow$ x+24 = 2*(x-8)
$\Rightarrow$ x= 40 years

So the present age of Farheen will be 40 years.

Let the age of A and B initially be ‘a’ and ‘b’ respectively.

When C = 2, a/b = 3
=> a = 3b
When C = 10, 8 years have passed.
=> (a+8)/(b+8) = 2
a+8 = 2b + 16
a = 2b+8
=> b = 8 years and a = 24 years.

When C is as old as the difference between the ages of A and B, i.e, when C is 24-8 = 16 years old, age of B will be 8+14 = 22 years. Therefore, option B is the right answer.

We have,
$\frac{P – 3}{Q + 5} = \frac{6}{13}$
So, 13P – 39 = 6Q + 30
13P – 6Q = 69
$\frac{P}{Q} = \frac{11}{20}$
20P – 11Q = 0
Solving both the equations we have,
P = 33 years and Q = 60 years
So, $\frac{P + 2}{Q – 5} = \frac{35}{55} = \frac{7}{11}$

Hence, option D is the right answer.

Let the age of P and Q be p and q respectively.
We have, p+q = 53
$(p-4)(q-4) = 2 * (q-4)^2$
p-4 = 2q – 8
p = 2q – 4
Substituing the value of p in first equation,
3q – 4 = 53
q = 19
p = 53 – 19 = 34
Hence, option A is right choice.

Let the present age of Sanjay’s mother be ‘x’. So Sanjay’s present age will be .4x
We have been given that
(.4x + 8)*2 = x + 8
=> .8x + 16 = x + 8
=> .2x = 8
=> x = 40
Hence, the present age of the mother is 40 years. Thus, required sum = 56.

Let the number of students be ‘x’

Given that the average is increased by $\Large\frac{1}{3}$ due to the increase of $18$ marks ( $64$ $-$ $46$ $=$ $18$ marks )

Actual increase in marks $=$ $\Large\frac{1}{3}$ $\times$ x

$\Rightarrow$ $\Large\frac{1}{3}$ $\times$ x $=$ $18$

$\therefore$ Number of students(x) $=$ $54$

Let the total age of boys be ‘B’

Average age of boys = 18

$\Large\frac{B}{22}$ $=$ $18$

$\Rightarrow$ B $=$ $396$

Let the total age of Girls be ‘G’

Let the number of girls be ‘x’

Average age of girls $=$ $14$

$\Large\frac{G}{x}$ $=$ $14$

$\Rightarrow$ G $=$ $14$x

Total average of students $=$ $12$

Total age of students $=$ Total age of boys $+$ Total age of girls $=$ $396$ $+$ $14$x

Total number of students $=$ Number of boys $+$ Number of girls $=$ $22$ $+$ x

Average age of class $=$ $12$

$\Rightarrow$ $\Large\frac{396 + 14x}{22 + x}$ $=$ $12$

$\Rightarrow$ $396$ $+$ $14$x $=$ $462$ $+$ $12$x

$\Rightarrow$ $2$x $=$ $66$

$\Rightarrow$ x $=$ $33$

$\therefore$ Number of girls $=$ $33$

Total number of students $=$ $22$ $+$ $33$ $=$ $55$

Run-rate = 4.5 runs per over

$1$ over $\rightarrow$ $4.5$ runs
$20$ overs $\rightarrow$ $20\times4.5$ $=$ $90$ runs

Total target $=$ $210$ runs

Remaining score $=$ $210$ $-$ $90$ $=$ $120$ runs

Remaining overs $=$ $30$ overs

$\therefore$ Required run-rate $=$ $\Large\frac{120}{30}$ $=$ $4$ runs per over

Let the total number of residents be 100x
People who own car = 60k
People who own a bike = 40k
People who work in the banking sector = 25k
People in the banking sector who own a bike = 20% of 25k = 5k
Rest of the people who work in the banking sector must be owning a car
Number of people owning a car and working in banking sector = 25k – 5k = 20k
Number of people owning a car and working in non-banking sector = 60k – 20k = 40k
Required % = 40k/100k * 100 = 40%
Hence, option B is the correct answer.

Let Sumit scored 100x marks
Then, Amit scored 90x marks
Amit’s score is 20% more than that of Rakesh.
So, Rakesh’s score = 75x
Tina’s score = Amit’s score + 35 = 90x + 35…..(i)
Tina’s score = Sumit’s score + 20 = 100x + 20…(ii)
On comparing (i) and (ii),
90x + 35 = 100x + 20
On solving, we get x = 1.5
So, Rakesh’s score = 75x = 75* 1.5 = 112.5
And Tina’s score = 90x + 35 = 170
Difference = (170 – 112.5) = 57.5
Hence, option D is the correct answer.

Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20
Number of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
Number of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
Number of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
Number of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
Number of students scoring in between 90-100 = Number of students scoring above 90

Thus, the required ratio = 2085:1525 = 417:305
Hence, option B is the correct answer.

Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20
Number of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
Number of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
Number of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
Number of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
Number of students scoring in between 90-100 = Number of students scoring above 90

Thus, 875 students got A grade during the given period.
Hence, option D is the correct answer.

Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20
Number of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
Number of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
Number of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
Number of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
Number of students scoring in between 90-100 = Number of students scoring above 90

Thus, the required ratio = 125:250 = 1:2
Hence, option A is the correct answer.

Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20
Number of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
Number of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
Number of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
Number of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
Number of students scoring in between 90-100 = Number of students scoring above 90

Thus, 440 students scored in between 40 and 60 in 2005.
Hence, option E is the correct answer.

Number of students scoring in between 0-20 = Total students appeared – Number of students scoring above 20
Number of students scoring in between 20-40 = Number of students scoring above 20 – Number of students scoring above 40
Number of students scoring in between 40-60 = Number of students scoring above 40 – Number of students scoring above 60
Number of students scoring in between 60-80 = Number of students scoring above 60 – Number of students scoring above 80
Number of students scoring in between 80-90 = Number of students scoring above 80 – Number of students scoring above 90
Number of students scoring in between 90-100 = Number of students scoring above 90

Thus, 425 students scored less than 40 in the year 2003.
Hence, option D is the correct answer.

Let us assume that on a normal day he sells milk at x rupee per litre and he sells y litre of milk
So revenue generated on normal day = x*y = xy

He mixed water with milk in ratio of 2:5 so net quantity = $\frac{2+5}{5} * y$ = 1.4y
New selling price during summer = 1.2x rupees per litre

So revenue generated in summers = 1.4y * 1.2x = 1.68xy
Hence we can say that revenue will go up by 68 percent.

Number of notebooks that retailer bought = 5 * 12 = 60

Let us assume that printed price on each notebook = 100

The retailer bought these notebooks at 30% less = 70 Rupees/notebook

Sum invested by the retailer = 60*70 = 4200

By selling 60 notebooks he will get money for = $\frac{4}{5}*60$ = 48 notebooks

Money collected by the retailer by selling these notebooks = 48*100 = 4800

Hence, retailer’s profit percentage = $\frac{4800-4200}{4200}*100$ = 14.28%

Let assume Krishna paid 100x when he purchased the laptop.
So Krishna sold it to Pradeep for = $\frac{100-30}{100}*100x$ = 70x
And Pradeep also spent 680 rupees for repairing
So total amount invested by Pradeep = 70x+680
So the amount Ravi paid to Pradeep = $\frac{100-30}{100}*(70x+680)$ = 49x+476
We also know that Ravi paid exactly half of what Krishna paid
i.e. 0.5*(100x) = 49x+476
$\Rightarrow$ x = 476
So the amount for which Krishna purchased the laptop = 100*476 = 47600

Let the worth of the computer to be Rs. x.
Let the price at which Raj bought the computer be 1.2x.
Price at which Hari bought = 1.3*1.2x = 1.56x
Price at which Balu bought = 1.5*1.56x = 2.34x
Difference between the prices at which Balu and Hari bought = 2.34x – 1.56x = 0.78x
It has been given that 0.78x = 1560
x = Rs. 2000.
Therefore, option B is the right answer.

Let the price of the article be $P$.
Let us consider $x$ in decimal form for the ease of calculation.
$(1+x)(1-x/2)P = 0.52P$
$(1+x)(2-x) = 1.04$
$2-x+2x -x^2 = 1.04$
$-x^2+x = -0.96$
$x^2-x-0.96 = 0$
$x = 1.6$ or $x = -0.6$
We can ignore the negative root since it has been given that the shopkeeper marks up the price of the product.

=> $x = 160$% and hence, option D is the right answer.

We hope this Expected Quant Question & Answers PDF of SBI PO is very Useful for preparation of SBI PO Exams.