**RRB JE Profit & Loss Questions Set-2 PDF**

Download Top 15 RRB JE Profit & Loss Questions Set-2 and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam.

Download RRB JE Profit & Loss Questions Set-2 PDF

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**Question 1: **If an article is sold at Rs. 304.5, the shopkeeper incurs a loss of 13%. What should be his selling price to gain a profit of 13%?

a) Rs. 395.5

b) Rs. 387.5

c) Rs. 399

d) Rs. 391.5

e) Rs. 401

**Question 2: **Ram buys toys at 8 pieces per 70 rupees. He sells toys in boxes containing 5 toys. At what price must he sell a box if he wants to realize a profit percentage of 60%?

a) Rs. 50

b) Rs. 60

c) Rs. 70

d) Rs. 80

e) Rs. 90

**Question 3: **A salesman makes a profit of 30% when he gives a discount of 35% on the marked price. What will be the profit if the discount given is 20%?

a) 45%

b) 50%

c) 63%

d) 55%

e) 60%

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**Question 4: **A dishonest shopkeeper marks up the price of the goods by 50 % and then offers a discount of 20 %. He uses a faulty weighing machine which shows 1000 g when the actual weight is 800 g. What is his profit percentage in the sales?

a) 25 %

b) 20 %

c) 50 %

d) 32 %

e) 40 %

**Question 5: **An article when sold for 960 fetches 20% profit.What would be the percent profit /loss if such 5 article are sold for Rs. 825/-each?

a) 3.125 % profit

b) 3.125 % loss

c) Neither profit nor loss

d) 16.5 % profit

e) None of these

**Question 6: **Mahesh bought 10 pencils for 80 rupees and he sold them at 9.2 rupees per each pencil. What is the profit /loss percentage?

a) 17%

b) 25%

c) 20%

d) 15%

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**Question 7: **The cost price of an article is Rs.1700. If it was sold at a price of Rs.2006, what was the percentage profit on the transaction?

a) 18

b) 12

c) 10

d) 15

e) 20

**Question 8: **Manoj incurred a loss of 40 percent on selling an article for 5,700. What was the cost price of the article ?

a) 7,725

b) 9,080

c) 8,250

d) 9,400

e) None of these

**Question 9: **A whole-seller sells apples to a fruit vendor at cost price. The vendor manages to trick the whole-seller into giving him an extra apple per four apples that he buys. But, the whole-seller on sensing some foul play decides to change the weighing machine, citing some fault in it, for measuring the remaining two-thirds of the lot. The new weighing machine is such that it shows the weight of 3 apples equivalent to 5 apples. How much does the whole-seller originally gain/lose in the entire transaction? (Assume all apples to be of uniform size and weight)

a) Loss of 18.33%

b) Gain of 18.33%

c) Loss of 37.78%

d) Gain of 37.78%

**Question 10: **A shopkeeper, after being insisted by a customer, gives a discount of 33.33%. He later realizes that he made a loss of Rs 10. He calculates that he should have a given a discount of only 20% to get the profit of Rs 10. By what % does the shopkeeper mark up the price of the item?

a) 36.36%

b) 25%

c) 30%

d) 33.33%

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**Question 11: **For an umbrella, the ratio of the marked price to the cost price is 9 : 8. What is the approx. profit/loss percentage if the ratio of the percentage discount offered and the profit or loss percentage were in the ratio 4 : 5?

a) 6.4% loss

b) 6.6% profit

c) 5.8% loss

d) 7.1% profit

**Question 12: **Arjun sells a cycle to Ben at a profit of 28%. Charan buys it from Ben at Arjun’s cost price. What is Ben’s percentage profit or loss in the transaction?

a) 33.33%

b) 14.58%

c) 21.88%

d) 36.67%

e) 36.58%

**Question 13: **A person marked up an item 16% above Cost Price and gave a discount of 25%. Then find effective loss percent.

a) 15%

b) 11%

c) 9%

d) 13%

**Question 14: **A person bought 50 oranges for Rs.450 and sold at the rate of Rs.108 per dozen. Then, find overall profit/loss percent.

a) 11.11% loss

b) No Profit No loss

c) 12.5% profit

d) 11.11% profit

**Question 15: **A shopkeeper purchased a TV for Rs.2,000 and a radio for Rs.750. He sells the TV at a profit of 20% and ther radio at a loss of 5%. The total loss or gain is

a) Gain Rs.353.50

b) Gain Rs.362.50

c) Loss Rs.332

d) Loss Rs.300

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**Answers & Solutions:**

**1) Answer (A)**

Let cost price be ‘cp’, and the two selling prices be ‘sp1’ and ‘sp2’ respectively.

Loss% = (cost price – selling price) *100/ (cost price)

0.13*cp = cp – sp1

sp1 = 0.87*cp

cp = 304.5 / 0.87 = 350

Profit% = ( – cost price + selling price) *100/ (cost price)

0.13 *350 = sp2 – 350

sp2 = Rs. 395.5

Hence, option A is the right choice.

**2) Answer (C)**

Let us assume that Ram buys 40 pieces. He will buy 40 pieces for 70*5 = Rs.350.

Ram will pack these 40 pieces into 40/5 = 8 boxes.

Ram wants to realize a profit percentage of 60%.

=> Selling price of the 8 boxes = 1.6*350 = Rs.560

=> Selling price of 1 box = Rs. 560/8 = Rs. 70

Therefore, option C is the right answer.

**3) Answer (E)**

Let ‘x’ be the marked price.

Discount of 35%, selling price will be = 0.65x

Since the profit is 30%,

cost price * 1.3 = 0.65x

cost price = 0.5x

When discount of 20%, selling price will be = 0.8x

Profit% = $\frac{0.8x – 0.5x}{0.5x}$*100 = 60%

Hence, option E is the right answer.

**4) Answer (C)**

Let he has 1000 g of goods and cost price of this entire lot is 1000. So selling price would be 1000*1.5*.8 = 1200. i.e 1.2 per gram.

Now, the machine measures 1000 gm for 800 gm. Hence, he can sell 1000 gm as 1250 gm. Thus, the amount earned by him will be 1250*1.2 = 1500.

Hence, the profit percentage is 50 %.

**5) Answer (A)**

Let cost price of an article = $Rs.$ $100x$

If Selling price = Rs 960

=> Profit % = $\frac{960-100x}{100x} \times 100=20$

=> $960-100x=20x$

=> $20x+100x=120x=960$

=> $x=\frac{960}{120}=8$

Thus, cost price of 1 article = $100 \times 8 = Rs.$ $800$

If selling price = Rs. 825

$\therefore$ **Profit %** = $\frac{825-800}{800} \times 100$

= $\frac{25}{8} = 3.125\%$

=> Ans – (A)

**6) Answer (D)**

Cost price of 10 pencils = Rs 80

Selling price of 10 pencils = 9.2*10=Rs 92

Profit percentage = ((92-80)/80)*100 = (12/80)*100 = 15%.

So the correct option to choose is D – 15%

**7) Answer (A)**

Profit = S.P. – C.P. = 2006 – 1700

= Rs. 306

=> Profit % = $\frac{306}{1700} * 100$

= 18%

**8) Answer (E)**

SP = 5700

Loss percentage = 40%

(CP-SP)/CP = 40/100

CP = $ (5/3) \times SP $

= 9500

**9) Answer (D)**

Given, fruit vendor buys at the cost price to the whole-seller.

Let, us assume the cost price of an apple = Re 1

Two cases arise:

Case 1: Before changing weighing machine

Since, the vendor is getting an apple extra per 4 apples bought

For whole-seller:

CP= Rs 5

SP= Rs 4

Loss % = $\left[\frac{5-4}{5}\right]*100$ = 20%

Case 2: After changing weighing machine

For whole-seller:

CP= Rs 3

SP= Rs 5

Profit % = $\left[\frac{5-3}{3}\right]*100$ = 66.67%

Since, the measurements in the two lots are in the ratio of 1:2

We can apply alligation to find out the net profit/loss %:

On solving for x

$\frac{66.67-x}{x+20}=\frac{1}{2}$

=> x $\approx$ 37.78%

**10) Answer (A)**

Let the MP of the item be $x$.

Thus, according to the given conditions we get

$\dfrac{x-SP}{x} = \dfrac{1}{3}$

=> $3x-3SP = x$

Thus, $SP = \dfrac{2x}{3}$

He made a loss of Rs 10 on selling the item at this SP.

Thus, $CP = 10+\dfrac{2x}{3}$

After giving a discount of 20% the SP would have been $0.8x$

He made a profit of Rs 10 on selling the item at this SP.

Thus, $CP = \dfrac{4x}{5} -10$

Thus, we get,

$10+\dfrac{2x}{3} = \dfrac{4x}{5} -10$

Thus, $\dfrac{x*(12-10)}{15} = 20$

Thus, $x = 150 = MP$

Thus, $CP = 0.8*150-10 = 110$

Thus, the shopkeeper marks up the price of the given item by $\dfrac{100*(150-110)}{110}\approx36.36$%

Hence, option A is the correct answer.

**11) Answer (B)**

$\frac{marked price}{cost price} = \frac{9}{8}$

Let the marked price = 9x and cost price = 8x

$\frac{percentage discount}{profit/loss percentage} = \frac{4}{5}$

Let the percentage discount = 4y% and profit/loss percentage = 5y%

Considering there is a profit,

Selling price = (1 – 4y%) * 9x = (1 + 5y%) * 8x

9x – 36xy/100 = 8x + 40xy/100

x = 76xy/100

y = 100/76

So percentage profit = 5 * 100/76 = 6.6% approx.

Hence, option B is the right answer.

**12) Answer (C)**

Let Arjun’s CP be x

Arjun’s SP will be 1.28x

Ben’s CP = 1.28x

Given, Charan’s CP = x. Hence, Ben’s SP = x.

Hence, Ben’s loss = 0.28x

Loss % = (0.28/1.28)*100 = 21.88%

**13) Answer (D)**

Let the Cost Price of the item be Rs.100

Then, Marked Price = 116% of Rs.100 = Rs.116

Selling Price after a discount of 25% = 75% of Rs.116 = Rs.87

Therefore, Effective loss percent = $\frac{100-87}{100}\times100 = 13$%

**14) Answer (B)**

Cost Price of 50 oranges = Rs.450

Cost Price of 1 orange = 450/50 = Rs.9

Selling Price of 12 oranges = Rs.108

Selling Price of 1 orange = Rs.108/12 = Rs.9

Therefore, Profit = Rs.9 – Rs.9 = 0

Hence, There is no profit and no loss in this transaction.

**15) Answer (B)**

Cost price of TV = Rs. 2000

Profit % = 20%

=> Selling price of TV = $2000+(\frac{20}{100}\times2000)$

= $2000+400=Rs.$ $2400$

Similarly, selling price of radio = $750-(\frac{5}{100}\times750)$

= $750-37.5=Rs.$ $712.5$

Thus, total cost price = $(2000+750)=Rs.$ $2750$

and total selling price = $(2400+712.5)=Rs.$ $3112.5$

$\therefore$ **Gain **= $3112.5-2750=Rs.$ $362.50$

=> Ans – (B)

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