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# RRB JE Profit & Loss Questions Set-2 PDF

Download Top 15 RRB JE Profit & Loss Questions Set-2 and Answers PDF. RRB JE Maths questions based on asked questions in previous exam papers very important for the Railway JE exam.

Question 1: If an article is sold at Rs. 304.5, the shopkeeper incurs a loss of 13%. What should be his selling price to gain a profit of 13%?

a) Rs. 395.5

b) Rs. 387.5

c) Rs. 399

d) Rs. 391.5

e) Rs. 401

Question 2: Ram buys toys at 8 pieces per 70 rupees. He sells toys in boxes containing 5 toys. At what price must he sell a box if he wants to realize a profit percentage of 60%?

a) Rs. 50

b) Rs. 60

c) Rs. 70

d) Rs. 80

e) Rs. 90

Question 3: A salesman makes a profit of 30% when he gives a discount of 35% on the marked price. What will be the profit if the discount given is 20%?

a) 45%

b) 50%

c) 63%

d) 55%

e) 60%

Question 4: A dishonest shopkeeper marks up the price of the goods by 50 % and then offers a discount of 20 %. He uses a faulty weighing machine which shows 1000 g when the actual weight is 800 g. What is his profit percentage in the sales?

a) 25 %

b) 20 %

c) 50 %

d) 32 %

e) 40 %

Question 5: An article when sold for 960 fetches 20% profit.What would be the percent profit /loss if such 5 article are sold for Rs. 825/-each?

a) 3.125 % profit

b) 3.125 % loss

c) Neither profit nor loss

d) 16.5 % profit

e) None of these

Question 6: Mahesh bought 10 pencils for 80 rupees and he sold them at 9.2 rupees per each pencil. What is the profit /loss percentage?

a) 17%

b) 25%

c) 20%

d) 15%

Question 7: The cost price of an article is Rs.1700. If it was sold at a price of Rs.2006, what was the percentage profit on the transaction?

a) 18

b) 12

c) 10

d) 15

e) 20

Question 8: Manoj incurred a loss of 40 percent on selling an article for 5,700. What was the cost price of the article ?

a) 7,725

b) 9,080

c) 8,250

d) 9,400

e) None of these

Question 9: A whole-seller sells apples to a fruit vendor at cost price. The vendor manages to trick the whole-seller into giving him an extra apple per four apples that he buys. But, the whole-seller on sensing some foul play decides to change the weighing machine, citing some fault in it, for measuring the remaining two-thirds of the lot. The new weighing machine is such that it shows the weight of 3 apples equivalent to 5 apples. How much does the whole-seller originally gain/lose in the entire transaction? (Assume all apples to be of uniform size and weight)

a) Loss of 18.33%

b) Gain of 18.33%

c) Loss of 37.78%

d) Gain of 37.78%

Question 10: A shopkeeper, after being insisted by a customer, gives a discount of 33.33%. He later realizes that he made a loss of Rs 10. He calculates that he should have a given a discount of only 20% to get the profit of Rs 10. By what % does the shopkeeper mark up the price of the item?

a) 36.36%

b) 25%

c) 30%

d) 33.33%

Question 11: For an umbrella, the ratio of the marked price to the cost price is 9 : 8. What is the approx. profit/loss percentage if the ratio of the percentage discount offered and the profit or loss percentage were in the ratio 4 : 5?

a) 6.4% loss

b) 6.6% profit

c) 5.8% loss

d) 7.1% profit

Question 12: Arjun sells a cycle to Ben at a profit of 28%. Charan buys it from Ben at Arjun’s cost price. What is Ben’s percentage profit or loss in the transaction?

a) 33.33%

b) 14.58%

c) 21.88%

d) 36.67%

e) 36.58%

Question 13: A person marked up an item 16% above Cost Price and gave a discount of 25%. Then find effective loss percent.

a) 15%

b) 11%

c) 9%

d) 13%

Question 14: A person bought 50 oranges for Rs.450 and sold at the rate of Rs.108 per dozen. Then, find overall profit/loss percent.

a) 11.11% loss

b) No Profit No loss

c) 12.5% profit

d) 11.11% profit

Question 15: A shopkeeper purchased a TV for Rs.2,000 and a radio for Rs.750. He sells the TV at a profit of 20% and ther radio at a loss of 5%. The total loss or gain is

a) Gain Rs.353.50

b) Gain Rs.362.50

c) Loss Rs.332

d) Loss Rs.300

Let cost price be ‘cp’, and the two selling prices be ‘sp1’ and ‘sp2’ respectively.
Loss% = (cost price – selling price) *100/ (cost price)
0.13*cp = cp – sp1
sp1 = 0.87*cp
cp = 304.5 / 0.87 = 350
Profit% = ( – cost price + selling price) *100/ (cost price)
0.13 *350 = sp2 – 350
sp2 = Rs. 395.5
Hence, option A is the right choice.

Let us assume that Ram buys 40 pieces. He will buy 40 pieces for 70*5 = Rs.350.
Ram will pack these 40 pieces into 40/5 = 8 boxes.
Ram wants to realize a profit percentage of 60%.
=> Selling price of the 8 boxes = 1.6*350 = Rs.560
=> Selling price of 1 box = Rs. 560/8 = Rs. 70
Therefore, option C is the right answer.

Let ‘x’ be the marked price.
Discount of 35%, selling price will be = 0.65x
Since the profit is 30%,
cost price * 1.3 = 0.65x
cost price = 0.5x
When discount of 20%, selling price will be = 0.8x
Profit% = $\frac{0.8x – 0.5x}{0.5x}$*100 = 60%
Hence, option E is the right answer.

Let he has 1000 g of goods and cost price of this entire lot is 1000. So selling price would be 1000*1.5*.8 = 1200. i.e 1.2 per gram.
Now, the machine measures 1000 gm for 800 gm. Hence, he can sell 1000 gm as 1250 gm. Thus, the amount earned by him will be 1250*1.2 = 1500.
Hence, the profit percentage is 50 %.

Let cost price of an article = $Rs.$ $100x$

If Selling price = Rs 960

=> Profit % = $\frac{960-100x}{100x} \times 100=20$

=> $960-100x=20x$

=> $20x+100x=120x=960$

=> $x=\frac{960}{120}=8$

Thus, cost price of 1 article = $100 \times 8 = Rs.$ $800$

If selling price = Rs. 825

$\therefore$ Profit % = $\frac{825-800}{800} \times 100$

= $\frac{25}{8} = 3.125\%$

=> Ans – (A)

Cost price of 10 pencils = Rs 80
Selling price of 10 pencils = 9.2*10=Rs 92
Profit percentage = ((92-80)/80)*100 = (12/80)*100 = 15%.
So the correct option to choose is D – 15%

Profit = S.P. – C.P. = 2006 – 1700

= Rs. 306

=> Profit % = $\frac{306}{1700} * 100$

= 18%

SP = 5700

Loss percentage = 40%

(CP-SP)/CP = 40/100

CP = $(5/3) \times SP$

= 9500

Given, fruit vendor buys at the cost price to the whole-seller.
Let, us assume the cost price of an apple = Re 1

Two cases arise:
Case 1: Before changing weighing machine
Since, the vendor is getting an apple extra per 4 apples bought
For whole-seller:
CP= Rs 5
SP= Rs 4
Loss % = $\left[\frac{5-4}{5}\right]*100$ = 20%

Case 2: After changing weighing machine
For whole-seller:
CP= Rs 3
SP= Rs 5
Profit % = $\left[\frac{5-3}{3}\right]*100$ = 66.67%

Since, the measurements in the two lots are in the ratio of 1:2
We can apply alligation to find out the net profit/loss %:

On solving for x

$\frac{66.67-x}{x+20}=\frac{1}{2}$

=> x $\approx$ 37.78%

Let the MP of the item be $x$.
Thus, according to the given conditions we get
$\dfrac{x-SP}{x} = \dfrac{1}{3}$
=> $3x-3SP = x$
Thus, $SP = \dfrac{2x}{3}$
He made a loss of Rs 10 on selling the item at this SP.
Thus, $CP = 10+\dfrac{2x}{3}$
After giving a discount of 20% the SP would have been $0.8x$
He made a profit of Rs 10 on selling the item at this SP.
Thus, $CP = \dfrac{4x}{5} -10$
Thus, we get,
$10+\dfrac{2x}{3} = \dfrac{4x}{5} -10$
Thus, $\dfrac{x*(12-10)}{15} = 20$
Thus, $x = 150 = MP$
Thus, $CP = 0.8*150-10 = 110$
Thus, the shopkeeper marks up the price of the given item by $\dfrac{100*(150-110)}{110}\approx36.36$%
Hence, option A is the correct answer.

$\frac{marked price}{cost price} = \frac{9}{8}$
Let the marked price = 9x and cost price = 8x
$\frac{percentage discount}{profit/loss percentage} = \frac{4}{5}$
Let the percentage discount = 4y% and profit/loss percentage = 5y%
Considering there is a profit,
Selling price = (1 – 4y%) * 9x = (1 + 5y%) * 8x
9x – 36xy/100 = 8x + 40xy/100
x = 76xy/100
y = 100/76
So percentage profit = 5 * 100/76 = 6.6% approx.
Hence, option B is the right answer.

Let Arjun’s CP be x
Arjun’s SP will be 1.28x
Ben’s CP = 1.28x

Given, Charan’s CP = x. Hence, Ben’s SP = x.

Hence, Ben’s loss = 0.28x

Loss % = (0.28/1.28)*100 = 21.88%

Let the Cost Price of the item be Rs.100
Then, Marked Price = 116% of Rs.100 = Rs.116
Selling Price after a discount of 25% = 75% of Rs.116 = Rs.87
Therefore, Effective loss percent = $\frac{100-87}{100}\times100 = 13$%

Cost Price of 50 oranges = Rs.450
Cost Price of 1 orange = 450/50 = Rs.9
Selling Price of 12 oranges = Rs.108
Selling Price of 1 orange = Rs.108/12 = Rs.9
Therefore, Profit = Rs.9 – Rs.9 = 0
Hence, There is no profit and no loss in this transaction.

Cost price of TV = Rs. 2000

Profit % = 20%

=> Selling price of TV = $2000+(\frac{20}{100}\times2000)$

= $2000+400=Rs.$ $2400$

Similarly, selling price of radio = $750-(\frac{5}{100}\times750)$

= $750-37.5=Rs.$ $712.5$

Thus, total cost price = $(2000+750)=Rs.$ $2750$

and total selling price = $(2400+712.5)=Rs.$ $3112.5$

$\therefore$ Gain = $3112.5-2750=Rs.$ $362.50$

=> Ans – (B)

We hope this Profit & Loss Questions Set-2 for RRB JE Exam will be highly useful for your preparation