Maths Questions for RRB Group-D Set-3 PDF
Download Top-15 RRB Group-D Maths Questions set-3 PDF. RRB GROUP-D Maths questions based on asked questions in previous exam papers very important for the Railway Group-D exam.
Download Maths Questions for RRB Group-D Set-3 PDF
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Question 1: Find the value of x if 5*(4x-3/2) + 2x = 4-3x/2
a) 23/47
b) 1/2
c) 2/3
d) 3/2
Question 2: Find a-b if a+b = 23, ab = 132 ?
a) 1
b) -1
c) 2
d) Either (a) or (b)
Question 3: Find 7+8+9+10+……+50 = ?
a) 1275
b) 1254
c) 1257
d) 1244
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Question 4: Find the value of $a^3+b^3$, if $a+b = 13, ab = 40$ ?
a) 627
b) 637
c) 647
d) 657
Question 5: It is known that 0 < θ < 90 and it is given that cot θ = 5/12. Find the value of cosecθ
a) 5/13
b) 13/12
c) 12/5
d) 12/13
Question 6: Find the value of $tan 48^\circ – tan 3^\circ – tan 48^\circ.tan 3^\circ$
a) 0
b) 1
c) -1
d) 2
Question 7: If 0.20 : 4 : : x : 120, then find the value of x.
a) 0.6
b) 60
c) 20
d) 6
RRB Group D previous year papers
Question 8: The average of 7 consecutive numbers is 4. Then find the smallest number.
a) 2
b) 1
c) 3
d) 5
Question 9: Three numbers A,B and C are such that A is 50% more than C and B is 50% of C. If sum of three numbers is 168, then what is the smallest number?
a) 26
b) 22
c) 18
d) 28
Question 10: Prathap distributes his money to his sons A,B,C and D in the ratio of 5:6:4:3 and B gets 6000 more than D. What is the total money distributed ?
a) 30000
b) 32000
c) 36000
d) 34000
Question 11: Find the value of the given expression.
$ 6 – 36 \times 3 \div 6 + 5 = ? $
a) 7
b) $ \frac{-42}{11} $
c) -7
d) $ \frac{42}{11} $
RRB Group-D Important Questions (download PDF)
Question 12: A boy raises a box with a weight of 120 N through a height of 2 m. The work done by him is:
a) 60 J
b) 120 J
c) 240 J
d) 180 J
Instructions
Question 13: Value of is $12+16\div 3.7-2.80\times 2$
a) 9.8
b) 10.72
c) 12.56
d) 11.34
Question 14: Which of the fractions given below is not equal to $\frac{4}{11}$ ?
a) $\frac{32}{88}$
b) $\frac{84}{209}$
c) $\frac{64}{176}$
d) $\frac{20}{55}$
Question 15: What is the value of (361.223-34.567$\times$2+123.345)
a) 413.137
b) 412.267
c) 415.434
d) 414.367
General Science Notes for RRB Exams (PDF)
Answers & Solutions:
1) Answer (A)
5(4x-3/2) + 2x = 4-3x/2
20x – 15/2 + 2x = 4-3x/2
22x + 3x/2 = 4 + 15/2
47x/2 = 23/2
x = 23/47
So the answer is option A.
2) Answer (D)
$(a-b)^2 = (a+b)^2 – 4ab$
$(a-b)^2 = (23)^2 – 4(132)$
$(a-b)^2 = 529 – 528$
$(a-b)^2 = 1$
$a-b = +1 or -1$
So the answer is option D.
3) Answer (B)
WKT, sum of 1st n natural numbers = $\frac{n(n+1)}{2}$
$7+8+9+10+……+50 = (1+2+3+…..+50)-(1+2+3+….+6)$
This equals $\frac{(50)(51)}{2} – \frac{(6)(7)}{2} = 1275 – 21 = 1254$
So the answer is option B.
4) Answer (B)
$a^3+b^3 = (a+b)^3-3ab(a+b) = 13^3-3(40)(13) = 2197 – 1560 = 637$
So the answer is option B.
5) Answer (B)
$\text{cot} \theta = \frac{5}{12}$
$\text{cosec}^2 \theta$ = $1+\text{cot}^2 \theta = 1+{(\frac{5}{12})}^2 = \frac{169}{144}$
$\text{cosec}\theta = \frac{13}{12}$
So the answer is option B.
6) Answer (B)
$48-3 = 45$
Applying tan on both sides
$tan (48-3)^\circ = tan 45^\circ$ → (1)
We know that $tan (A-B)^\circ = \dfrac{tan A^\circ – tan B^\circ}{1+tan A^\circ.tan B^\circ}$
Then, (1) becomes
$\dfrac{tan 48^\circ – tan 3^\circ}{1+tan 48^\circ.tan 3^\circ} = 1$ (Since, $tan 45^\circ = 1$)
$tan 48^\circ – tan 3^\circ = 1+tan 48^\circ.tan 3^\circ$
⇒ $tan 48^\circ – tan 3^\circ – tan 48^\circ.tan 3^\circ = 1$
7) Answer (D)
$4\times x = 0.20\times120$
⇒ $x = \dfrac{0.20\times120}{4} = 6
8) Answer (B)
Let the smallest number be x.
Given, $\dfrac{x+x+1+x+2+x+3+x+4+x+5+x+6}{7} = 4$
⇒ 7x+21 = 28
⇒ 7x = 7
⇒ x = 1
Hence, The smallest number = 1.
9) Answer (D)
Let C be 2x.
Then B = 50% of 2x = x
A = 150% of 2x = 3x.
Given, 3x+x+2x = 168
⇒ 6x = 168 ⇒ x = 28
Therefore, Smallest number = 28
10) Answer (C)
Amount received by A,B,C and D be 5x,6x,4x and 3x respectively
B-D=6000 i.e 6x-3x=6000
x=2000
Total sum is 5x+6x+4x+3x=18x=36000
11) Answer (C)
Using BODMAS rule,
= 6 – 36 x (3/6) + 5
= 6 – 18 + 5 = -7
Hence, option C is the correct answer.
12) Answer (C)
We know, Work done = Force x time
According to the question,
Work done = 120 x 2 Joules
Work done = 240 Joules
13) Answer (B)
By simplification we get
=12+4.32-5.6
=10.72
14) Answer (B)
After simplify all the fractions given in options, we can get the odd one.
$\frac{32}{88}$ = $\frac{4}{11}$
$\frac{84}{209}$ (This is not equal to $\frac{4}{11}$.)
$\frac{64}{176}$ = $\frac{4}{11}$
$\frac{20}{55}$ = $\frac{4}{11}$
15) Answer (C)
By simplifying we get
(292.089+123.345)=415.434
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