# Linear Equations Questions for TISSNET 2022 – Download PDF

Download TISSNET 2022 Linear Equation [PDF] by Cracku. Very Important Linear Equation Questions for TISSNET 2022 based on asked questions in previous exam papers. These questions will help your TISSNET exam preparation. So kindly download the PDF for reference and do more practice.

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**Question 1:Â **In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 10%

a)Â 1 kg

b)Â 200gm

c)Â 800 gm

d)Â 1.8 kg

e)Â None of these

**Question 2:Â **P. Q and R have a certain amount of money with themselves. Q has 25% more than what P has, and R has ${1 \over 5}$th of what Q has. If P. Q and R together have Rs. 150, then how much money does P alone have? (in Rs.)

a)Â 40

b)Â 70

c)Â 80

d)Â 60

e)Â 50

**Question 3:Â **Among five people – A, B, C, D and E â€” each scoring different marks, only one person scored less marks than B. D scored more marks than B but less than A. A did not score the highest marks. Who scored the second highest marks?

a)Â E

b)Â Cannot be determined

c)Â A

d)Â C

e)Â D

**Question 4:Â **A, B and C have a certain amount of money with themselves. C has ${3 \over 4}$ of what A has and B has Rs. 50 less than C. If A, B and C together have Rs. 250, then how much does A alone have? (in Rs.)

a)Â 75

b)Â 160

c)Â 80

d)Â 120

e)Â 140

**Question 5:Â **If an amount of Rs. 97836 is distributed equally amongst 31 children, how much amount would each child get ?

a)Â Rs. 3756

b)Â Rs. 3556

c)Â Rs. 3356

d)Â Rs. 3156

e)Â None of these

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**Question 6:Â **In a class of 30 students and 2 teachers, â€˜each student got sweets that are 20% of the total number of students and each teacher got sweets that are 30% of the total number of students. How many sweets were there ?

a)Â 188

b)Â 180

c)Â 208

d)Â 178

e)Â None of these

**Question 7:Â **The cost of 20 folders and 15 pens is Rs. 995. What is the cost of 12 folders and 9 pens ?

a)Â Rs. 652

b)Â Rs. 597

c)Â Rs. 447

d)Â Cannot be determined

e)Â None of these

**Question 8:Â **The cost of 12 note-books and 16 pens is Rs. 852. What is the cost of 9 note-books and 12 pen?

a)Â Rs. 743

b)Â Rs. 639

c)Â Rs. 567

d)Â Cannot be determined

e)Â None of these

**Question 9:Â **The cost of 10 Chairs and 15 Tables is Rs. 15,525/-. What is the cost of 8 Chairs and 12 Tables?

a)Â Rs. 13,560/-

b)Â Rs. 12,420/-

c)Â Rs. 14,840/-

d)Â Cannot be determined

e)Â None of these

**Question 10:Â **A trader sells 150 metres of cloth for Rs. 6,600 and he sells 300 metres of cloth for Rs. 12,750. How much concession does the trader give per metre of cloth, when he sells 300 metres of cloth?

a)Â Rs. 3

b)Â Rs.2.5

c)Â Rs. 1.5

d)Â Rs. 2

e)Â None of these

**Question 11:Â **Cost of 20 pens and 17 pencils is Rs. 418. What is the cost of 60 pens and 51 pencils ?

a)Â Rs. 1.251

b)Â Rs. 1.257

c)Â Rs. 1,227

d)Â Rs. 1,221

e)Â None of these

**Question 12:Â **Cost of 36 pens and 42 pencils is Rs.460/-. What is the cost of 18 pens and 21 pencils?

a)Â Rs.230/-

b)Â Rs.203/-

c)Â Rs.302/-

d)Â Rs.320/-

e)Â None of these

**Question 13:Â **Ram was asked to find 7/8 of a fraction but he mistakenly divided the fraction by 7/8 . As a result the difference between the answers was 75/784 . What should be the Ramâ€™s correct answer ?

a)Â $\frac{5}{14}$

b)Â $\frac{7}{16}$

c)Â $\frac{5}{16}$

d)Â $\frac{7}{14}$

e)Â None of these

**Question 14:Â **Some capsules were bought for Rs. 176. If the price of each capsule had been Rs. 3 less, 6 more capsules would have been bought for the same amount. What was the number of capsules bought ?

a)Â 13

b)Â 16

c)Â 17

d)Â 8

e)Â 11

**Question 15:Â **An employer gives Rs. 26 per day to an employee on duty and deducts Rs. 7 per day for his absence from the duty. If after 56 days, the employee receives 829, for how many days was the employee absent ?

a)Â 21

b)Â 15

c)Â 19

d)Â 13

e)Â 17

**Question 16:Â **35 per cent of a number is two times 75 per cent of another number. What is the ratio between the first and the second numbers respectively ?

a)Â 35 : 6

b)Â 31 : 7

c)Â 23 : 7

d)Â 32 : 9

e)Â None of these

**Question 17:Â **A car manufacturing plant manufactures 96 dozen-cars in eight days. How many dozen cars will the plant manufacture in 17 days

a)Â 210

b)Â 224

c)Â 204

d)Â 209

e)Â None of these

**Question 18:Â **The cost of 8 fans and 14 ovens is Rs. 36,520. What is the cost of 12 fans and 21 ovens ?

a)Â Rs.56,800

b)Â Rs.54,780

c)Â Rs.57,950

d)Â Cannot be determined

e)Â None of these

**Question 19:Â **In order to pass in an examination, a student is required to get 280 marks out of the aggregate marks. Hema got 264 marks and was declared fail by 2 percent. What is the minimum passing percentage of the examination ?

a)Â 33

b)Â 35

c)Â 40

d)Â 44

e)Â None of these

**Question 20:Â **The cost price of 8 chairs is same as that of 5 tables. The total cost of 6 chairs and 2 tables is Rs. 3680. Find the cost of 6 tables.

a)Â Rs. 3840

b)Â Rs. 3850

c)Â Rs. 3860

d)Â Rs. 3845

e)Â None of these

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**Answers & Solutions:**

**1)Â AnswerÂ (A)**

Total mixture of sand and iron = 1 kg

Quantity of iron = $\frac{20}{100} \times 1 = 0.2$ kg

Let $x$ kg of sand should be added, thus total iron in the mixture

=> $0.2=\frac{10}{100} \times (x+1)$

=> $2=x+1$

=> $x=2-1=1$ kg

=> Ans – (A)

**2)Â AnswerÂ (D)**

Let P has = $Rs. 100x$

=> Amount with Q = $100x + \frac{25}{100} \times 100x = Rs. 125x$

=> Amount with R = $\frac{1}{5} \times 125x = Rs. 25x$

Total amount together = $100x + 125x + 25x = 150$

=> $x = \frac{150}{250} = \frac{3}{5}$

=> $x = 0.6$

$\therefore$ Amount with P alone = $100 \times 0.6 = Rs. 60$

**3)Â AnswerÂ (C)**

Let us rank the person according to the marks scored by them, where 1 -> highest marks and 5 -> lowest marks.

Only one person scored less marks than B, => B = 4

Also, AÂ > DÂ >Â B and $A \neq 1$

=> A = 2 and D = 3

Thus, ranking from 1-5 = C/E , A , D , B , E/C

$\therefore$ A scored the second highest marks.

**4)Â AnswerÂ (D)**

Amount with A = $Rs. 4x$

=> Amount with C = $\frac{3}{4} \times 4x = Rs. 3x$

=> Amount withÂ B = $Rs. (3x – 50)$

Total amount with A,B & C = $4x + 3x + (3x – 50) = 250$

=> $10x = 250 + 50 = 300$

=> $x = \frac{300}{10} = 30$

$\therefore$ Amount with A = $4 \times 30 = Rs. 120$

**5)Â AnswerÂ (D)**

Total amount = 97836

No. of children = 31

Since amount is distributed equally

=> Amount each child will get = $\frac{97836}{31}$ = Rs. 3,156

**6)Â AnswerÂ (E)**

There are 30 students and 2 teachers.

Sweets received by each student = $\frac{20}{100} * 30$ = 6

=> Total sweets received by all the students = 30 * 6 = 180

Sweets received by each teacher = $\frac{30}{100} * 30$ = 9

=> Total sweets received by both teachers = 2 * 9 = 18

$\therefore$ Total sweets distributed in class = 180 + 18 = 198

**7)Â AnswerÂ (B)**

Let the cost of a folder = Rs. $x$

and cost of a pen = Rs. $y$

=> $20x + 15y = 995$

Multiplying the above equation by $(\frac{3}{5})$, we getÂ :

=> $\frac{3}{5} \times (20x + 15y = 995)$

=> $12x + 9y = 597$

$\therefore$ Cost of 12 folders and 9 pens is Rs. 597

**8)Â AnswerÂ (B)**

Let the cost of a note-book = Rs. $x$

and cost of a pen = Rs. $y$

=> $12x + 16y = 852$

Multiplying the above equation by $(\frac{3}{4})$, we getÂ :

=> $\frac{3}{4} \times (12x + 16y = 852)$

=> $9x + 12y = 639$

$\therefore$ Cost of 9 note-books and 12 pens is Rs. 639

**9)Â AnswerÂ (B)**

Let the cost of a chair = Rs. $x$

and cost of a table = Rs. $y$

=> $10x + 15y = 15525$

Multiplying the above equation by $(\frac{4}{5})$, we getÂ :

=> $\frac{4}{5} \times (10x + 15y = 15525)$

=> $8x + 12y = 12420$

$\therefore$ Cost of 8 chairs and 12 tables is Rs. 12,420

**10)Â AnswerÂ (C)**

Case I : Trader sells 150 metres of cloth for Rs. 6,600

=> S.P. per metre = Rs. $\frac{6600}{150}$

= Rs. 44

Case II : TraderÂ sells 300 metres of cloth for Rs. 12,750

=> S.P. per metre = Rs. $\frac{12750}{300}$

= Rs. 42.5

$\therefore$ Required discount = Rs. (44 – 42.5) = Rs. 1.5

**11)Â AnswerÂ (E)**

C.P. of 1 pen = Rs. $x$

C.P. of 1 pencil = Rs. $y$

=> $20x + 17y = 418$

Multiplying above equations by 3

$\therefore$ $60x + 51y = 1254$

**12)Â AnswerÂ (A)**

Cost of 36 pens and 42 pencils = 460

Dividing by 2, we getÂ :

=> cost of 18 pens and 21 pencils = $\frac{460}{2}$ = Rs. 230

**13)Â AnswerÂ (C)**

Let fraction be $x$

Ram’s correct answer should be = $\frac{7}{8}x$

Ram’s actual answer = $\frac{x}{\frac{7}{8}}=\frac{8}{7}x$

Difference = $\frac{8x}{7}-\frac{7x}{8}=\frac{75}{784}$

=> $\frac{(64x-49x)}{56}=\frac{75}{784}$

=> $15x=\frac{75}{784}\times56$

=> $x=\frac{75}{14}\times\frac{1}{15}$

=> $x=\frac{5}{14}$

$\therefore$ Ram’s correct answer should be = $\frac{7}{8}\times\frac{5}{14}=\frac{5}{16}$

=> Ans – (C)

**14)Â AnswerÂ (B)**

Let capsules bought = $x$

Acc. to ques,

=> $\frac{176}{x} – \frac{176}{x + 6} = 3$

=> $\frac{176 \times 6}{x (x + 6)} = 3$

=> $x (x + 6) = 352 = 22 \times 16$

=> $x (x + 6) = 16 (16 + 6)$

=> $x = 16$

**15)Â AnswerÂ (C)**

Let the number of days in which employee was absent = $x$

=> Days in which he was present = $(56 – x)$

Acc. to ques,

=> $(56 – x) \times 26 – 7x = 829$

=> $1456 – 26x – 7x = 829$

=> $33x = 1456 – 289 = 627$

=> $x = \frac{627}{33} = 19$

**16)Â AnswerÂ (E)**

Let the first and second numbers resp be $x$ and $y$

=> $\frac{35}{100} x = \frac{75}{100} y \times 2$

=> $35x = 150y$

=> $\frac{x}{y} = \frac{30}{7}$

**17)Â AnswerÂ (C)**

Cars manufactured in 8 days = 96 dozen

Cars manufactured in 17 days = $\frac{96}{8} \times 17$

= 204 dozen

**18)Â AnswerÂ (B)**

Let the cost of a fan = Rs. $x$

Cost of an oven = Rs. $y$

=> $8x + 14y = 36520$

Multiplying both sides by $(\frac{3}{2})$, we getÂ :

=> $\frac{3}{2} \times (8x + 14y = 36520)$

=> $12x + 21y = 54,780$

**19)Â AnswerÂ (B)**

Let the maximum marks in the examination = $100x$

Acc. to ques,

=> $\frac{2}{100} \times 100x = 280 – 264$

=> $2x = 16$

=> $x = \frac{16}{2} = 8$

=> Max marks = 8 * 100 = 800

$\therefore$ Passing percentage = $\frac{280}{800} \times 100$ = 35Â %

**20)Â AnswerÂ (A)**

Let CP of 1 chair = Rs. $x$

and CP of 1 table =Â Rs.Â $y$

Now, $8x = 5y$

and $6x + 2y = 3680$

Solving above equations, we get

$x = 400$ and $y = 640$

$\therefore$ Cost of 6 tables = 6*640 =Â Rs.Â 3840