Alphabet and Numeric Puzzles Questions for IBPS RRB and PO Prelims

Here you can download a free Alphabet and Numeric Puzzles questions PDF with answers for IBPS PO and IBPS RRB PO 2022 by Cracku. These are some tricky questions in the IBPS PO and IBPS RRB PO 2022 exam that you need to find the Alphabet and Numeric Puzzles for the given questions. These questions will help you to do practice and solve the Alphabet and Numeric Puzzles questions in the IBPS PO and IBPS RRB PO exams. Utilize this best PDF practice set which is included answers in detail. Click on the below link to download the Alphabet and Numeric Puzzles MCQ PDF for IBPS PO and IBPS RRB PO 2022 for free.

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Question 1: Complete the series; FAQ, AQF, ___, FAQ, AQF

a) QAF

b) QFA

c) FQA

d) AFQ

1) Answer (B)

Solution:

From the 2nd term onwards,

1st letter of every term is 2nd letter of the previous term

2nd letter of every term is 3rd letter of the previous term

3rd letter of every term is 1st letter of the previous term

2nd term is AQF so as per the above logic third term will be QFA.

Question 2: Complete the series; DIT, GMQ, KQM, PUH,____

a) VYB

b) UYB

c) VXC

d) TUJ

2) Answer (A)

Solution:

Considering the first letters of each term.

There are 2 alphabets in between D and G (E and F).

There are 3 alphabets between G and K (H, I and J).

There are 4 alphabets between K and P (L, M, N, and O)

Hence, there will be 5 alphabets between P and the required letter. Thus, the required letter will be V (Q, R, S, T and U)

Considering the second letter of each term.

There are three alphabets between each of the second terms, I and M (J, K, L), M and Q (N, O, P), and Q and U (R, S, T).

Hence, there will be three terms between the required term and U, i.e., V, W, X. Thus, the required second term is Y.

Hence, the answer is option A.

Question 3: The missing character in the series A D I _ Y is

a) Q

b) P

c) R

d) O

3) Answer (B)

Solution:

There are two alphabets between A and D.
There are four alphabets between D and I.
There must be six alphabets between I and next letter.
I, J, K, L, M, N, O, P
There are eight alphabets between P and Y
Therefore, missing character is ‘P’.

Answer is option B.

Question 4: The seventh term in the series 5, 13, 29, 61, ……. is ________________.

a) 97

b) 191

c) 253

d) 509

4) Answer (D)

Solution:

5 x 2 + 3 = 13

13 x 2 + 3 = 29

29 x 2 + 3 = 61

61 x 2 + 3 = 125

125 x 2 + 3 = 253

253 x 2 + 3 = 509

Answer is option D.

Question 5: Complete the following series of numbers: 6, 26, 126, 626, …….

a) 3126

b) 3125

c) 3216

d) 3215

5) Answer (A)

Solution:

6 x 5 – 4 = 26

26 x 5 – 4 = 126

126 x 5 – 4 = 626

626 x 5 – 4 = 3126

Answer is option A.

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Question 6: Select the combination of letters that when sequentially placed in the blanks of the given letter series will complete the series.
dabx_dab_ _d_b_xdab_x_

a) axdaxxd

b) xxxaxxd

c) xxcbxad

d) dxadadd

6) Answer (B)

Solution:

By Trial and Error method,

Option A

dabxa | dabxd | dabxx | dabxx | d

The above letters do not form a series. Hence option A is incorrect.

Option B

dabxx | dabxx |dabxx | dabxx | d

The above letters form a series.

Hence, the correct answer is Option B

Question 7: Select the combination of letters that when sequentially placed in the gaps of the given letter series will complete the series.
K _ _ MKXZ _ KX _ MK _ ZM

a) XZMZK

b) MZMZX

c) XXMKX

d) XZMZX

7) Answer (D)

Solution:

By Trial and Error method,

Option A

K X Z M | K X Z M | K X Z M | K K Z M

The above letters do not form a series. Hence option A is incorrect.

Option B

K M Z M | K X Z M | K X Z M | K X Z M

The above letters do not form a series. Hence option B is incorrect.

Option C

K X X M | K X Z M | K X K M | K X Z M

The above letters do not form a series. Hence option C is incorrect.

Option D

K X Z M | K X Z M | K X Z M | K X Z M

The above letters form a series.

Hence, the correct answer is Option D

Question 8: Select the letter-cluster that can replace the question mark (?) in the following series.
BDF, DHL, FLR, ?

a) HPX

b) IQY

c) HPY

d) HOX

8) Answer (A)

Solution:

The logic here is

B + 2 = D  $\longrightarrow$  D + 2 = F  $\longrightarrow$  F + 2 = H

D + 4 = H  $\longrightarrow$  H + 4 = L  $\longrightarrow$  L + 4 = P

F + 6 = L  $\longrightarrow$  L + 6 = R  $\longrightarrow$  R + 6 = X

Similarly, the next letter-cluster in the series is HPX

Hence, the correct answer is Option A

Question 9: Select the combination of letters that when sequentially placed in the gaps of the given letter series will complete the series.
U_D_UP_M_PDMU_DM

a) UMDUD

b) MPUDU

c) PMUPD

d) PMDUP

9) Answer (D)

Solution:

By Trial and Error method,

Option A 

UUDM | UPDM | UPDM | UDDM

The above letters do not form a series. Hence option A is incorrect.

Option B

UMDP | UPUM | PPDM | UUDM

The above letters do not form a series. Hence option B is incorrect.

Option C

UPDM | UPUM | PPDM | UDDM

The above letters do not form a series. Hence option C is incorrect.

Option D

UPDM | UPDM | UPDM | UPDM

The above letters form a series.

Hence, the correct answer is Option D

Question 10: Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
a b b _ b_ _ b a b _ _ b a b b b b_ _

a) b a b b a a b

b) a b b a a b b

c) a b b a b a b

d) a b b a a a b

10) Answer (C)

Solution:

By Trial and Error method,

Option A

a b b b b | a b b a b | b a b a b | b b b a b

The above letters do not form a series. Hence option A is incorrect.

Option B

a b b a b | b b b a b | a a b a b | b b b b b

The above letters do not form a series. Hence option B is incorrect.

Option C

a b b a b | b b b a b | a b b a b | b b b a b

The above letters form a series.

Hence, the correct answer is Option C

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