High Level Simplification Questions for SBI PO 2020 PDF

Download SBI PO High Level Simplification Questions & Answers PDF for SBI PO Prelims and Mains exam. Top-15 Very Important SBI PO Questions with solutions for Banking Exams.

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Question 1: 12.5% of 64 + 11.11% of 90 = ?

a) 18

b) 19

c) 20

d) 22

e) 24

Question 2: 7.69% of 130 + 6.66% of 150 = ?

a) 20

b) 21

c) 22

d) 23

e) 24

Question 3: 33.33% of 150 + 66.66% of 180 = ?% of 1700

a) 30

b) 25

c) 20

d) 10

e) 15

Question 4: 3.44% of 290 + 20% of 580 = ?% of 630

a) 60

b) 50

c) 40

d) 30

e) 20

Instructions

What should come in place of the question mark (?) in the following question ?

Question 5: 6389-1212-2828= ?

a) 2349

b) 2493

c) 2934

d) 2393

e) None of these

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Question 6: $\frac{31}{43}\times\frac{86}{95}\times\frac{41}{93}=?$

a) $\frac{82}{267}$

b) $\frac{82}{283}$

c) $\frac{83}{265}$

d) $\frac{82}{285}$

e) None of these

Question 7: $526\times12+188=50\times ?$

a) 120

b) 160

c) 140

d) 110

e) None of these

Question 8: $62^{2}-32^{2}+(?^{2})=3144$

a) 17

b) 16

c) 19

d) 15

e) None of these

Question 9: $\sqrt[3]{21952}+33=?$

a) 58

b) 61

c) 63

d) 53

e) None of these

Question 10: ?% of 5600¬28% of 3500=1988

a) 58

b) 55

c) 51

d) 53

e) None of these

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Question 11: $32000\times\frac{3}{4}\times?\times\frac{1}{2}=4800$

a) $\frac{2}{3}$

b) $\frac{3}{5}$

c) $\frac{2}{5}$

d) $\frac{1}{4}$

e) None of these

Question 12: $(8536¬\sqrt{2209})\times0\cdot3=?$

a) $2556\cdot7$

b) $2456\cdot7$

c) $2546\cdot7$

d) $2645\cdot7$

e) None of these

Question 13: $\frac{5}{8}+\frac{1}{4}+\frac{7}{12}=?$

a) $1\frac{11}{24}$

b) $1\frac{13}{24}$

c) $1\frac{9}{26}$

d) $1\frac{7}{24}$

e) None of these

Question 14: What is the value of (x) in the following equation ?
$ \frac { x ^ {1.2}}{98} = \frac {28}{x^{1.8}}$

a) 18

b) 12

c) 16

d) 14

e) None of these

Instructions

What approximate value should come in place of the question mark (?) in the following questions ? (Note: you are not expected to calculate the

exact value)

Question 15: $\sqrt[3]{1231=}?$

a) 10

b) 30

c) 50

d) 70

e) 100

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Answers & Solutions:

1) Answer (A)

8+10 = 18 (12.5% = 1/8 and 11.11% = 1/9)

2) Answer (A)

10+10 = 20 (7.69% = 1/13 and 6.66%=1/15)

3) Answer (D)

As we can see that 33.33% of 150 will be $\frac{1}{3}$ of 150 i.e. 50 and 66.66% of 180 will be $\frac{2}{3}$ of 180 i.e. 120
Hence, sum will be = 170 which will be 10% of 1700.
So answer will be d

4) Answer (E)

As we know that 3.44% of 290 will be equivalent to $\frac{1}{29}$ of 290 that will be 10 and 20% of 580 will be 116
Hence, their sum will be = 126 which will be 20% of 630
Hence, answer will be e

5) Answer (A)

Now, 1212 + 2828 = 4040

Therefore, 6389-4040 = 2349

6) Answer (D)

$\frac{31}{43}\times\frac{86}{95}\times\frac{41}{93}=?$

Can be rewritten as,

$\frac{31}{93}\times\frac{86}{43}\times\frac{41}{43}$

which solves out to be,

$\frac{1}{3}\times\frac{2}{1}\times\frac{41}{43}$

And hence, the answer is,

$\frac{82}{285}$

7) Answer (E)

$526 \times 12 = 6312$

$6312 + 188 = 6500$

Let the number in the question mark be X.

So, $X \times 50 = 6500$

$X = 130$

8) Answer (E)

The question can be reframed as,

$3144-62^{2}+32^{2}=(?^{2})$

$3144-3844+1024=324$

But,

$18^{2}=324$

And hence, none of the above is option.

9) Answer (B)

Here, 21952^(1/3)=28
Now, 28+33= 61

10) Answer (D)

Reframing the question to simplify,

1988+28% of 3500 = 1988+(28*35)

Which reduces to,

1988+980=2968

2968=(x/100)*5600

x=2968/56

x=53

11) Answer (C)

Assuming the unknown quantity to be x,

x * (32000) * (3/4) * (1/2) = 4800

Which reduces to,

x * (32000) *3/8 = 4800

x = 4800*(8/3)*(1/32000)

x = 2/5

12) Answer (C)

$(8536¬\sqrt{2209})\times0\cdot3=?$

$(8536¬47)\times0\cdot3=?$

$(8489)\times0\cdot3=?$

This reduces to,

8489*(.3) = 2546.7

13) Answer (A)

$\frac{5}{8}+\frac{1}{4}+\frac{7}{12}=?$

Simplifying,

$\frac{7}{8}+\frac{7}{12}=?$

The equation reduces to,

7*{(1/8)+(1/12)}=(35/24)

Now converting $\frac{35}{24}$ to mixed fration, we get

$1\frac{11}{24}$

14) Answer (D)

The question can be reframed as,

$x^{1.2}\times x^{1.8}$ = 98*28 = 14*7*7*4= 7*7*7*8

x^3=7*7*7*8

Hence, x = 7*2 = 14

15) Answer (A)

We know that 10³=1000,

11³= 1331

Now, 1000<1231<1331

Hence, 10³<1231<11³

10<1231^(1/3) <11

Now, the nearest option is 10.

Hence, cube root of 1231 can be considered to be approximately as 10.

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