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# Bodmas Questions For IBPS PO

Download Bodmas Questions For IBPS PO PDF. Practice Bodmas Questions with Solutions for Banking exams based on asked questions in previous papers.

Question 1: Select the option that can replace the question mark (?) in the following equation.
$2 + 5\div [5+8\div( 1+\frac{1}{3}) – 1]$ = ?

a) $\frac{1}{2}$

b) $\frac{5}{2}$

c) $\frac{3}{2}$

d) 2

Question 2: What should come in place of the question mark (?) in the following question?
$2 – [6 – \left\{3 + (-4 + 5 + 1) \times 8\right\} +12] =?$

a) 4

b) 2

c) 3

d) 1

Question 3: What should come in place of the question mark (?) in the following question?
$1 – [5 – \left\{2 + (-5 + 6 – 2)2\right\}] = ?$

a) 0

b) 2

c) -2

d) -4

Question 4: What approximate value should comein place of the question mark (?) in the following equation?
($\frac{1}{9}\div\frac{1}{9}$ of $\frac{1}{3}$) of $\frac{1}{6}=?$

a) $\frac{1}{6}$

b) $\frac{1}{2}$

c) $\frac{1}{9}$

d) $\frac{1}{3}$

Question 5: What should come in place of question mark (?) in the following questions?
$(140+80\times2-24)\div(80+20\times3-40)=?$

a) 276

b) -27.6

c) 2.76

d) 0.276

Question 6: What should come in place of question mark (?) in the following questions?
$1.5\times78\div0.5=?$

a) 243

b) 234

c) 238

d) 216

Question 7: What should come in place of question mark (?) in the following questions?
$383\div25\times2.5+12=?$

a) 68.30

b) 222.14

c) 50.30

d) 124.24

Question 8: What should come in place of the question mark (?) in the following question?
$6\div6\times9+6-9\times6-6+6\times9=?$

a) 7

b) 8

c) 10

d) 9

Question 9: What should come in place of the question mark (?) in the following question?
$[((16\div4)\times4)\div4]=?$

a) 2

b) 5

c) 4

d) 3

Question 10: What value should come in place of question mark(?) in the following equation?
$360\sqrt?$ + 4500 = 19700 – 9800

a) 395

b) 295

c) 225

d) 215

= $2 + 5\div [5+8\div( 1+\frac{1}{3}) – 1]$

= $2 + 5\div [5+8\div( \frac{4}{3}) – 1]$

= $2 + 5\div [5+8 \times \frac{3}{4} – 1]$

= $2 + 5\div 10$

= $\frac{5}{2}$

Hence, option B is the correct answer.

Expression : $2 – [6 – \left\{3 + (-4 + 5 + 1) \times 8\right\} +12]$

= $2 – [6 – \left\{3 + (2\times 8)\right\} +12]$

= $2-[6-19+12]$

= $2+1=3$

=> Ans – (C)

Expression : $1 – [5 – \left\{2 + (-5 + 6 – 2)2\right\}] = ?$

= $1 – [5 – \left\{2 + (-1\times2)\right\}]$

= $1 – [5 -(2-2)]$

= $1-(5-0)$

= $1-5=-4$

=> Ans – (D)

($\dfrac{1}{9}\div\dfrac{1}{9}$  of  $\dfrac{1}{3}$) of $\dfrac{1}{6} = (\dfrac{1}{9} \div \dfrac{1}{27}$)  of  $\dfrac{1}{6}$

$= \dfrac{1}{9} \times 27$  of  $\dfrac{1}{6}$

$= 3 \times \dfrac{1}{6} = \dfrac{1}{2}$

$(140+80\times2-24) = 140+160-24 = 276$
$(80+20\times3-40) = 80+60-40 = 100$
Therefore, $(140+80\times2-24)\div(80+20\times3-40) = \dfrac{276}{100} = 2.76$

$1.5\times78\div0.5= \dfrac{1.5\times78}{0.5}$

$=\dfrac{15\times78}{5} = 78\times3 = 234$

$360\sqrt?$ + 4500 = 19700 – 9800

$\Rightarrow 360\sqrt? + 4500 = 9900$

$\Rightarrow 360\sqrt? = 5400$

$\Rightarrow \sqrt? = 15$

$\Rightarrow ? = 15^2$

$\Rightarrow ? = 225$