Geometry Questions for Bank Exams – SBI Clerk

Geometry Questions for Bank Exams – SBI Clerk:

Geometry questions will be asked in quantitative aptitude or numerical ability section for banking exams of SBI clerk, IBPS PO, RBI and railway exams.

We are providing some important geometry practice questions and answers for SBI clerk exam.

Geometry Questions for Bank Exams – SBI Clerk

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Question 1:

The area of a triangle is half the area of a square. The perimeter of the square is 224cms What is the area of the triangle ?

a) 1856 cm^2
b) 1658 cm^2
c) 1558 cm^2
d) 1586 cm^2
e) None of these

Question 2:

In a right angled triangle, two sides are of the same length. Which of the options is one of the angles of that triangle?

a) 30
b) 45
c) 60
d) 75
e) None of the above

Question 3:

A rope makes 125 rounds of a cylinder with base radius 15 cm. How many times can it go round a cylinder with base radius 25 cm?

a) 100
b) 75
c) 80
d) 65
e) None of these

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The radius of a circular field is equal to the side of a square field whose perimeter is 784 feet. What is the area of the circular field ?

a) 107914 Sq.ft
b) 120736 Sq.ft.
c) 107362 Sq.ft.
d) 127306 Sq.ft.
e) None of these

Question 5:

The area of a square is 1444 square metres. The breadth of a rectangle is 1/4th the side of the square and the length of the rectangle is thrice the breadth. What is the difference between the area of the square and the area of the rectangle?

a) 1152.38 sq.mtr.
b) 1169.33 sq.mtr.
c) 1181.21 sq.mtr.
d) 1173.25 sq.mtr.
e)None of these.

Question 6:

The area of a rectangle is twice the area of a tringle. The perimeter of the rectangle is 58cm. What is the area of the triangle ?

a) 106 cm^2
b) 108 cm^2
c) 104 cm^2
d) Cannot be determined
e) None of these

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Solutions (1 to 6)

1) Answer (e)

Let’s assume that side of square is s.
Now, Perimeter 4s=224, hence, s=56.
Area of triangle = .5(area of square) = .5*(56^2) = 1568 which is not any of the option.

2) Answer (b)

If two sides of the right angled triangle are equal, it is a right angled isosceles triangle. So, the angles of the triangle are 45, 45 and 90.

3) Answer (b)

Let the required number of rounds be x.
More radius, less rounds (Inverse Proportion)
Radius in cm = Round
15 = 125
25 = x
⟹ x=(15 * 125)/25 = 75 rounds

4) Answer (b)

Perimeter = 784 => Side of square = 196
Radius of circle = 196
=> Area = 22/7 * 196 * 196$$ = 120736

5) Answer (d)

Side = $$\sqrt{1444}$$ = 38
Breadth of rectangle = 1/4
th of 38 = 9.5
Length = thrice of breadth = 28.5
Area of rectangle =  9.5 x 28.5 = 270.75
Difference = 1173.25 m^2

6) Answer (d)

The data provided in question is insufficient for calculation.
Hence, we cannot calculate the required area of triangle.

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