# Time and Work Questions for LIC AAO PDF Set-2

Download Important Time & Work questions for LIC AAO exam. Top 20 Time & Work questions set-2 with answers based on previous year asked questions.

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**Question 1: **A-B means A is the father of B. A+B means A is the daughter of B. $A\div B$ Means A is the son of B. $A\times B$ means A is the wife of B . Then, what is the relation of P with T in the expression P+S-T?

a) Son

b) Daughter

c) Sister

d) Wife

**Question 2: **12 year old Mahesh is three times as old as his brother Ramesh. How old will Mahesh be when he is twice as old as Ramesh ?

a) 14 years

b) 20 years

c) 18 years

d) 16 years

**Question 3: **9 children can complete a piece of work in 360 days, 18 men can complete the same piece of work in 72 days and 12 women can complete it in 162 days. In how many days can 4 men, 12 women and 10 children together complete the piece of work ?

a) 68 days

b) 81 days

c) 96 days

d) 124 days

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**Question 4: **10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work ?

a) 3

b) 5

c) 7

d) Cannot be determined

**Question 5: **8 men can finish a piece of work in 40 days. If 2 more men join with them, then the work will be completed in

a) 30 days

b) 32 days

c) 36 days

d) 25 days

**Question 6: **A man, a woman and a boy together complete a piece of work in 3 days. If a man alone can do it in 6 days and a boy alone in 18 days, how long will a woman take to complete the work ?

a) 9 days

b) 21 days

c) 24 days

d) 27 days

**Question 7: **A, B and C can do a piece of work in 20, 25 and 40 days. They started the work together but B left 4 days before completion. In how many days the work is completed?

a) 13$\large\frac{4}{23}$ days

b) 10$\large\frac{2}{23}$ days

c) 12$\large\frac{3}{17}$ days

d) 14$\large\frac{5}{17}$ days

e) None of these

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**Question 8: **5 men and 13 women can do a piece of work in 5 days while 2 men and 7 women can do the same work in 11 days. Then in how many days can 4 men and 6 women can complete the work?

a) 8$\large\frac{1}{2}$ days

b) 6$\large\frac{1}{3}$ days

c) 7$\large\frac{1}{2}$ days

d) 9 days

e) None of these

**Question 9: **A can do a piece of work in 24 days. B can do the same work in 36 days. With the help of C, the work has finished in 9 days. If total wage for doing the work is Rs.6400, then the amount received by C is

a) Rs. 2400

b) Rs.1800

c) Rs.1600

d) Rs.2000

e) None of these

**Question 10: **A and B can do a piece of work in 15 days and 20 days respectively. They work in alternate days starting with A. In how many days, total work will be completed?

a) $16\frac{1}{3}$ days

b) $17\frac{1}{4}$ days

c) 17 days

d) 15 days

e) None of these

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**Answers & Solutions:**

**1) Answer (C)**

P + S means P is the daughter of S and S – T means S is the father of T.Thus S is the father of both P and T.∴P is the sister of T.

**2) Answer (D)**

age of Mahesh=12

Given, Mahesh is 3 times as old as Ramesh.

So age of Ramesh is=4

From options, we can see that when we put Mahesh’s age to be 16, we get the age Ramesh to be 8.

∴ when Mahesh is 16 his age is twice that of Ramesh.

**3) Answer (B)**

Let the speed of child, man and woman to complete work W be x,y and z respectively.

Therefore, as per given conditions

x = W/3240

y= W/1296

and z = W/1944

Now, the combined speed of 4 men, 12 women and 10 children = 4y+12z+10x = W/81

Now, number of days = W/(W/81) = 81 days

The correct option is option B

**4) Answer (C)**

Let the speed of Women be x and that of children be y. Let piece of work be W.

10x=W/7, x=W/70

10y =W/14 y= W/140

Now, 5x + 10y = W/14 + W/14 = W/7

Number of day srequired to complete the work = W/(W/7) = 7 days.

Therefore, the correct option is option C.

**5) Answer (B)**

Let the work be W and speed of each man be x.

W/(8x) = 40

x = W/320

If two more men join, total speed will become = W/32

Now, the work can be done= W/(W/32) = 32 days

Therefore work will be done in 32 days.

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**6) Answer (A)**

Let the man’s, woman’s and boy’s speed be x, y and z.

Let the piece of work be W.

Now, x+y+z = W/3

Also, x = W/6

and z=W/18

Therefore, y = W/3 – W/6 – W/18

y = W/9

Number of days required by woman alone to complete the work = W/y = W/(W/9)

Hence, number of days = 9

Therefore, the correct option is option A.

**7) Answer (B)**

A can do the work in 20 days

B can do the work in 25 days

C can do the work in 40 days

Total work = LCM of 20,25,40 $=$ 200 units

Efficiency of A $=$ $\Large\frac{200}{20}$ $=$ 10 units/day

Efficiency of B $=$ $\Large\frac{200}{25}$ $=$ 8 units/day

Efficiency of C $=$ $\Large\frac{200}{40}$ $=$ 5 units/day

Let the number of days required to complete the work be ‘X’ days

Total work done by A in X days $=$ 10 $\times$ X $=$ 10X units

Total work done by C in X days $=$ 5 \times X $=$ 5X days

B left 4 days before completion

Total work done by B in (X – 4) days $=$ 8(X – 4) $=$ (8X – 32) units

$\therefore$ 10X + 5X + 8X – 32 $=$ 200

23X – 32 $=$ 200

$\therefore$ X $=$ $\Large\frac{232}{23}$ $=$ 10$\Large\frac{2}{23}$ days

**8) Answer (C)**

No. of men$_{1}$ $\times$ No. of days$_{1}$ $=$ No. of men$_{2}$ $\times$ No. of days$_{2}$

$\Rightarrow$ (5M+13W)5 $=$ (2M+7W)11

$\Rightarrow$ 25M + 65W $=$ 22M + 77W

$\Rightarrow$ 3M $=$ 12W

$\therefore$ 1M $=$ 4W

Let the number of days required for 4 men and 6 women to complete the work be ‘x’ days

(5M + 13W) $\times$ 5 $=$ (4M + 6W) $\times$ x

Substituting M $=$ 4W in above equation

$\Rightarrow$ (20M + 13W) $\times$ 5 $=$ (16M + 6W) $\times$ x

$\Rightarrow$ 33W $\times$ 5 $=$ 22W $\times$ x

$\Rightarrow$ x $=$ $\Large\frac{33 \times 5}{22}$ $=$ $\Large\frac{15}{2}$ $=$ 7$\Large\frac{1}{2}$ days

**9) Answer (A)**

A can do a piece of work in $24$ days

B can do the same work in $36$ days

A+B+C can do it together in $9$ days

Total work $=$ LCM of $24$,$36$,$9$ $=$ $72$ units

Efficiency of A $=$ $\Large\frac{72}{24}$ $=$ $3$ units/day

Efficiency of B $=$ $\Large\frac{72}{36}$ $=$ $2$ units/day

Efficiency of A $+$ B $+$ C $=$ $\Large\frac{72}{9}$ $=$ $8$ units/day

\Rightarrow Efficiency of C $=$ $8$ $-$ $5$ $=$ $3$ units/day

Total efficiency of A $+$ B $+$ C $=$ $8$ units

Total wages $=$ Rs.$6400$

$8$ units $\rightarrow$ Rs.$6400$

$1$ unit $ \rightarrow$ Rs.$800$

then C’s wage $=$ $3\times800$ $=$ Rs.$2400$

**10) Answer (C)**

A can do a piece of work in $15$ days

B can do the same in $20$ days

Total work $=$ LCM of $15$ and $20$ days $=$ $60$ units

Efficiency of A $=$ $\Large\frac{60}{15}$ $=$ $4$ units/day

Efficiency of B $=$ $\Large\frac{60}{20}$ $=$ $3$ units/day

They work in alternate days starting with A

So, A and B can do $7$ units in $2$ days

So, $56$ units can be completed in $16$ days

Remaining $4$ units can be completed by A in $1$ day

$\therefore$ total work can be completed in $17$ days