**Sequence and Series Questions for SSC CGL PDF:**

Sequences and series Questions and answers for SSC CGL Exam download PDF based on arithmetic progression (AP), geometric progression (GP). Number series related problems for SSC exam with solutions and explanations covering both tough and easy questions.

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**Question 1:** Which number is wrong in the given series?

12439, 23549, 34659, 45769

a) 34659

b) 23549

c) 45769

d) 12439

**Question 2:** Find the missing number :

2, 10, 20, 32, 46, ?

a) 62

b) 65

c) 64

d) 60

**Question 3:** What will come in place of the question mark (?) in the series?

3, 8, 27, 112, (?), 3396

a) 565

b) 452

c) 560

d) 678

**Question 4:** If 1 + 4=9, 2 + 8=18, 3+6 = 15 then 7 + 8 = ?

a) 41

b) 23

c) 30

d) 32

**Question 5:** Find the wrong number in the series from the given alternatives.

17, 36, 53, 68, 83, 92

a) 53

b) 68

c) 83

d) 92

**Question 6:** Find the wrong number in the series. 6, 9, 15, 22, 51, 99

a) 99

b) 51

c) 22

d) 15

**Question 7:** Find out the set of numbers amongst the four sets of numbers given in the

alternatives which is most like the set given in the question.

Given Set : (8, 56, 72)

a) (7, 56, 63)

b) (3, 15, 24)

c) (6. 42, 54)

d) (5, 30, 35)

**Question 8:** Which of the given letter groups follows the same principle on which the numbers are arranged in the given number group ?

(5, 8, 13, 20, 29)

a) ACGKR

b) ADIMS

c) ADIPY

d) ADGRO

**Question 9:** Find out the wrong number in the sequence

102, 101, 98, 93, 86, 74, 66, 53

a) 101

b) 66

c) 74

d) 93

**Question 10:** Based on the given data, estimate the number of â€˜Television buyersâ€™ for the year 1990.

1982 1984 1986 1988 1990

447 458 489 540 ?

a) 611

b) 591

c) 571

d) 601

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**Answers & Solutions forÂ Sequence and Series Questions for SSC CGL PDF:**

**Answers & Solutions:**

**1) Answer (A)**

here we need to find the wrong number in 12439, 23549, 34659, 45769

as we will add the digits of every number

12439 : 1+2+3+4+9 = 19

23549 : 2+3+5+4+9 = 23

34659 : 3+4+6+5+9 = 27

45769 : 4+5+7+6+9 = 31

As we can see that in very case the sum of digits of number is a prime number except in case of 34659 and hence 34659 is the odd one out

**2) Answer (A)**

let the missing number be y

10 – 2 = 8

20 – 10 = 10

32 – 20 = 12

46 – 32 = 14

as we can see that difference is getting increased by 2 and hence

y – 46 = 16

y = 62

**3) Answer (A)**

Let the missing term be y

here the sequence is 3, 8, 27, 112, y, 3396

here the pattern is :

8 = 3 x 2 + 2

27 = 8 x 3 + 3

112 = 27 x 4 + 4

so from the highlighted pattern , we can say that

y = 112 x 5 + 5 = 565

**4) Answer (B)**

Here we are given :

1 + 4=9

2 + 8=18

3+6 = 15

So if the number is , x + y then it is equal to [(x+y) + y]

here we need to calculate value of 7 + 8 = [(7 + 8) + 8] = 23

**5) Answer (C)**

The terms in the series are 17 + (17+19) + (17+19+17) + (17+19+17+15) + ( 17+19+15+15) + (17+19+15+13+11) .

Each term adds the odd number which precedes the one added to the previous term, except for the fifth term.

The correct sequence would be 17,36,53,68,81,92.

Hence Option C is the correct answer.

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**6) Answer (C)**

9 -6 =3

15 -9 =6

22 -15 =7

51 -22 =29

99 -51 =48

So Ignoring the difference between the terms where one of the terms is 22 all other differences are multiple of 3

So 22 is the wrong term and the correct series would have been

9 -6 = 3 x 1

15 -9 = 3 x 2

27 -15 = 3 x 4

51 -27 = 3 x 8

99 -51 = 3 x 16

So 22 is the wrong term

**7) Answer (C)**

(8, 56, 72)

follows the pattern

(8 , 8 x 7 , 8 x 9 )

So (6. 42, 54) is similar to (8, 56, 72)

as it follows the pattern

(6 , 6 x 7 , 6 x 9 )

**8) Answer (C)**

The Series follows the pattern

5

5+3 =8

8+5 =13

13 +7 =20

20+9 = 29

So the option representing the correct letter group must follow the same pattern

So the letter series is

A

A+3 = D

D +5 =I

I +7 = P

P + 9 =Y

So the letter series is ADIPY

**9) Answer (C)**

The Series follows pattern

102

102 -1 =101

101 -3 =98

98 -5 =93

93 -7 =86

Since 1,3,5 and 7 are subtracted in order to get the next term

So 7 +2 =9

should be subtracted in order to get next term

So next term should be

86 -9 =77

77 -11 =66

66-13 =53

So option C is correct.

**10) Answer (A)**

Number of television Buyers in 1982 = 447

Number of Television buyers in 1984 = 458 (447+11)

Number of Television buyers in 1986 = 489 (458+ 11 +20)

Number of Television buyers in 1988 = 540 (489 + 11 +20 +20 )

Number of Television buyers in 1990 = 611 (540 + 11 +20 +20 + 20 )

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