Ratio and proportion was important topic for all competitive exams. The concepts to learn are less and the practice can improve your speed a lot, Mostly the questions are easily to solve and will be combined with other applications of ages, mixtures and proportions topics.<\/p>\n
Ratio and Proportion for SSC CHSL:<\/strong><\/p>\n 20 SSC CHSL (latest pattern mocks) – Rs. 117<\/a><\/p>\n You can practice SSC CHSL English question papers\u00a0<\/a><\/p>\n Download All SSC CHSL Questions Topic wise PDF<\/a><\/p>\n Download Ratio and proportion formulas PDF<\/a><\/p>\n Take Free SSC CHSL Mock test 2018<\/a><\/p>\n Question 1: a) increased in the ratio 52:63 Question 2: a) 9:10 Question 3:<\/strong><\/p>\n In an army selection process, the ratio of selected to unselected was 3:1. If 60 less had applied and 30 less selected, the ratio of selected to unselected would have been 5:1. How many candidates had applied for the process?<\/p>\n a) 240 Question 4:<\/strong><\/p>\n The bus fare between two cities is increased in the ratio 11:18. What would be the increase in the fare, if the original fare is Rs 550?<\/p>\n a) Rs 350 Take SSC CHSL Free Mock Test<\/a><\/p>\n SSC CHSL 2018 Syllabus PDF<\/a><\/p>\n Question 5:<\/b><\/p>\n The third proportional of two numbers 4 and 28 is _______.<\/p>\n a) 52 Question 6:<\/strong><\/p>\n The third proportional of two numbers 9 and 15 is<\/p>\n a) 21 Question 7:<\/b><\/p>\n The bus fare between two cities is increased in the ratio 25:29. Find the increase in the fare, if the original fare is Rs. 625<\/p>\n a) Rs 725 SSC CHSL Daily practice set<\/a><\/p>\n Question 8: a) 48 Solutions (1 to 8)<\/strong><\/p>\n 1) Answer (c) 2) Answer (c) Let $$4x$$ candidates applied for the process. \u00a0<\/strong><\/p>\n 4) Answer (a)<\/strong><\/p>\n Let original fare = Rs. $$11x$$ 5) Answer (d) 6) Answer (c) 7) Answer (d)<\/strong><\/p>\n Let original fare = Rs. $$25x$$ 8) Answer (b)<\/strong><\/p>\n Three numbers a,b,c are in proportion iff $$b^2 = ac$$ We hope this ratio and proportion questions for SSC CHSL and CGL are useful to you.<\/p>\n
\n<\/b>
\nBy increasing the price of entry ticket to a fair in the ratio 9:13, the number of visitors to the fair has decreased in the ratio 7:4. In what ratio has the total collection increased or decreased?<\/p>\n
\nb) increased in the ratio 36:91
\nc) decreased in the ratio 63:52
\nd) decreased in the ratio 91:36<\/p>\n
\n<\/b>
\nIf Giridhar’s salary is 5\/3 times of Hariraj’s and Shaunak’s is 2\/3 times of Hariraj’s, what is the ratio of Giridhar’s salary to Shaunak’s.<\/p>\n
\nb) 10:9
\nc) 5:2
\nd) 2:5
\n<\/b><\/p>\n
\nb) 480
\nc) 120
\nd) 720<\/p>\n
\nb) Rs 900
\nc) Rs 180
\nd) Rs 360<\/p>\n
\nb) 56
\nc) 84
\nd) 196
\n<\/b><\/p>\n
\nb) 30
\nc) 25
\nd) 45<\/p>\n
\nb) Rs 145
\nc) Rs 290
\nd) Rs 100<\/p>\n
\n<\/b>
\nThe third proportional of two numbers 24 and 36 is ?<\/p>\n
\nb) 54
\nc) 72
\nd) 108<\/p>\n
\nLet cost of original ticket = Rs 9 and and number of visitors = 70
\n=> Original revenue = 9 $$\\times$$ 70 = Rs 630
\nAfter increase in cost of ticket
\nNew cost of ticket = Rs 13 and number of visitors = 40
\n=> New Revenue = 13 $$\\times$$ 40 = Rs 520
\nSince, new revenue is less than original revenue, thus total collection has decreased.
\n$$\\therefore$$ Decrease in total collection ratio = $$\\frac{630}{520}$$ = 63 : 52
\n=> Ans – (C)<\/p>\n
\n<\/strong>Let Hariraj’s salary = $$3x$$
\n=> Giridhar’s salary = $$\\frac{5}{3} \\times 3x = 5x$$
\n=> Shaunak’s salary = $$\\frac{2}{3} \\times 3x = 2x$$
\n$$\\therefore$$ Ratio\u00a0of Giridhar’s salary to Shaunak’s = $$\\frac{5x}{2x}$$
\n= 5\u00a0: 2
\n=> Ans – (C)<\/p>\n
\n3) Answer (a)<\/strong><\/p>\n
\nCandidates selected = $$3x$$ and candidates not selected = $$x$$
\nIf candidates applied = $$4x – 60$$
\nCandidates selected = $$3x – 30$$
\n=> Candidates not selected = $$(4x – 60) – (3x – 30) = x – 30$$
\nAccording to ques,
\n=> $$\\frac{3x – 30}{x – 30} = \\frac{5}{1}$$
\n=> $$3x – 30 = 5x – 150$$
\n=> $$2x = 150 – 30 = 120$$
\n=> $$x = \\frac{120}{2} = 60$$
\n$$\\therefore$$ Number of candidates who applied for the process = $$4 \\times 60 = 240$$
\n=> Ans – (A)<\/p>\n
\n=> New fare = Rs. $$18x$$
\nAlso, original fare = $$550 = 11x$$
\n=> $$x = \\frac{550}{11} = 50$$
\n$$\\therefore$$ Increase in fare = $$18x – 11x = 7x $$
\n= $$7 \\times 50 = Rs. 350$$<\/p>\n
\n<\/strong>
\nThree numbers a,b,c are in proportion iff $$b^2 = ac$$
\nHere, a = 4 and b = 28
\n=> $$(28)^2 = 4 \\times c$$
\n=> $$c = \\frac{28 \\times 28}{4} = 7 \\times 28$$
\n=> $$c = 196$$
\n=> Ans – (D)<\/p>\n
\n<\/strong>
\nThree numbers a,b,c are in proportion iff $$b^2 = ac$$ where $$b$$ is the mean proportion and $$c$$ is the third proportion
\nThe given numbers are 9 and 15
\n=> $$(15)^2 = 9 \\times c$$
\n=> $$c = \\frac{15 \\times 15}{9}$$
\n=> $$c = 5 \\times 5 = 25$$
\n=> Ans – (C)<\/p>\n
\n=> New fare = Rs. $$29x$$
\nAlso, original fare = $$625 = 25x$$
\n=> $$x = \\frac{625}{25} = 25$$
\n$$\\therefore$$ Increase in fare = $$29x – 25x = 4x $$
\n= $$4 \\times 25 = Rs. 100$$<\/p>\n
\nHere, a = 24 and b = 36
\n=> $$(36)^2 = 24 \\times c$$
\n=> $$c = \\frac{36 \\times 36}{24} = 3 \\times 18$$
\n=> $$c = 54$$
\n=> Ans – (B)<\/p>\n