SSC CHSL Reasoning section is very similar to the questions of ssc cgl and banking exam\u00a0 questions. But you can expect the difficulty may be little less as CHSL is based for SSC 10+2 aspirants (Intermediate level). In SSC CHSL exam, reasoning section is named as general intelligence section, but the questions are very same. This are some of the reasoning model questions useful for CHSL exam.<\/p>\n
20 SSC CHSL (latest pattern mocks) – Rs. 117<\/a><\/p>\n You can practice SSC CHSL Previous year solved papers<\/a><\/p>\n Download SSC CHSL General intelligence PDF<\/a><\/p>\n Take Free SSC CHSL Mock test 2018<\/a><\/p>\n Questions 1-5:<\/strong> Question 1: B. One<\/p>\n C. Two<\/p>\n D. Three<\/p>\n E. More than three<\/p>\n Question 2: A. One<\/p>\n B. Two<\/p>\n C. Three<\/p>\n D. Four<\/p>\n Question 3: A. None<\/p>\n B. One<\/p>\n C. Two<\/p>\n D. Three<\/p>\n Question 4: A. None<\/p>\n B. One<\/p>\n C. Two<\/p>\n D. Three<\/p>\n Question 5: B. BAR<\/p>\n C. URN<\/p>\n D. ELF<\/p>\n E. TOP<\/p>\n SSC CHSL History PDF<\/a><\/p>\n SSC CHSL Geography PDF<\/a><\/p>\n Question 6: a) STW<\/p>\n b) WUS<\/p>\n c) SWU<\/p>\n d) UWS<\/p>\n e)None of these<\/p>\n Question 7: B. One<\/p>\n 3. Two<\/p>\n 4. Three<\/p>\n SSC CHSL Expected Cutoff 2018<\/a><\/p>\n Question 8: In a certain code language \u2018how can you go\u2019 is written as \u2018ja da ka pa\u2019 \u2018can you come here\u2019 is written as \u2018na ka sa ja\u2019 and \u2018come and go\u2019 is written as \u2018ra pa sa\u2019. How is \u2018here\u2019 written i that code language ? B. na<\/p>\n C. pa<\/p>\n D. Data Inadequate<\/p>\n Question 9: a) %653<\/p>\n b) %63<\/p>\n c) %5@3<\/p>\n d) %@53<\/p>\n e)None of these<\/p>\n Question 10: How many meaningful English words can be formed with the letters LGEU using each letter only once in each word ?<\/p>\n a) None b) One c) Two d) Three e)More than three<\/p>\n Take a Free Mock test for SSC CHSL<\/a><\/p>\n SSC CHSL 2018 Syllabus PDF<\/a><\/p>\n Answers for SSC CHSL Reasoning questions<\/strong><\/p>\n Answer-1: New words = ITW , ABR , NRU , EFL , OPT Thus, there is only 1 word which does not start with vowel = NRU<\/p>\n => Ans – (B)<\/p>\n Answer-2:<\/p>\n Words : WIT , BAR , URN , ELF , TOP Second letter of the word which is second from the right = ELF Third letter of the word which is third from the left = URN There is only 1 word between L & N = M => Ans – (A)<\/p>\n Answer-3:<\/p>\n Words : WIT , BAR , URN , ELF , TOP If each of the consonants is changed to previous letter and each vowel is changed to next letter in the English alphabetical series, => New words : VJS , ABQ , VQM , FKE , SPO Thus, there are two words which have no vowels = VJS , VQM => Ans – (C)<\/p>\n Answer-4: Answer-5: Answer-6: The second alphabet is C –(+2)–> E therefore U –(+2) –> W<\/p>\n And the third alphabet is C –(-2)–> A therefore U –(-2) –> S Thus, UWS will be the next letter in the series.<\/p>\n Answer-7: Answer-8: Answer-9: Answer-10:<\/p>\n Only one. GLUE<\/p>\n Hope this SSC CHSL questions and answers are useful to you.\u00a0Try to solve from previous questions papers of SSC CHSL<\/a> to learn more on this topic.<\/p>\n Download GK and Current Affairs PDF for SSC CHSL<\/a><\/p>\n
\nFollowing questions are based on five words given below ; WIT BAR URN ELF TOP (The new words formed after performing the mentioned operations may or may not necessarily be meaningful English words)<\/p>\n
\nIf in each of the words, all the alphabets are arranged in English alphabetical order within the word, how many words will NOT begin with a vowel?
\nA. None<\/p>\n
\nHow many letters are there in the English alphabetical series between second letter of the word which is second from the right and the third letter of the word which is third from the left of the given words?<\/p>\n
\nIf in each of the given words, each of the consonants is changed to previous letter and each vowel is changed to next letter in the English alphabetical series, in how many words thus formed will no vowels appear?<\/p>\n
\nIf the last alphabet in each of the words is changed to the next alphabet in the English alphabetical order, how many words having two vowels (same or different vowels) will be formed?<\/p>\n
\nIt the given words are arranged in the order as they would appear in a dictionary from left to right, which of the following will be fourth from the left?
\nA. WIT<\/p>\n
\nWhat should come next in the following letter series based on English alphabet ? CEA IKG OQM ?<\/p>\n
\nThe positions of how many digits in the number 59164823 will remain unchanged after the digits are rearranged in descending order within the number ?
\nA. None<\/p>\n
\nA. ja<\/p>\n
\nIn a certain code DOWN is written as \u20185@9#\u2019 and NAME is written as \u2018#6%3\u2019. How is MODE written in that code ?<\/p>\n
\nWords : WIT , BAR , URN , ELF , TOP
\nIf all the alphabets are arranged in English alphabetical order, =><\/p>\n
\nSequence : WIT , BAR , URN , ELF , TOP If the last alphabet in each of the words is changed to the next alphabet in the English alphabetical order, => New words : WIU , BAS , URO , ELG , TOQ Thus, there are only two words with 2 or more vowels = WIU , URO => Ans – (C)<\/p>\n
\nWe just need to look at the first letter. B comes first followed by E, T, U and W. Hence the correct answer is option C.<\/p>\n
\nBased on the English alphabet, the above arrangement follows the following pattern : The first alphabet in each word is
\nC –(+6)–> I –(+6)–> O –(+6)–> U<\/p>\n
\nLets write the original and rearranged number one below the other 59164823 98654321
\nSo we can see that numbers whose place remains unchanged are 2 and 4, Thus the answer is 2<\/p>\n
\nFrom first and second condition, there are two common words i.e., can & you which are coded as ‘ja’ or ‘ka’
\nFrom second and third statement, only common word is come coded as ‘sa’
\nNow, in the second statement, only word left is here coded as ‘na’<\/p>\n
\nLooking at the above codes, we can conclude that : M – % O – @ D – 5 E – 3, therefore\u2234 MODE is coded as ‘%@53’<\/p>\n