This blog contains the CAT Aptitude Questions PDF: very useful for the CAT sample
\nprevious year questions and answers download PDF and solving these questions for CAT<\/p>\n
CAT Aptitude Questions PDF:<\/strong><\/span><\/p>\n Get 10 CAT Mocks for Rs. 499<\/a><\/p>\n Download data interpretation questions set-1 PDF<\/a> and all Quantitative aptitude questions PDF<\/a>.<\/p>\n Download CAT Problems on Trains PDF<\/a><\/p>\n Question 1:<\/strong><\/p>\n The integers 1, 2, \u2026, 40 are written on a blackboard. The following operation is then repeated 39 times: In each repetition, any two numbers, say a and b, currently on the blackboard are erased and a new number a + b – 1 is written. What will be the number left on the board at the end?<\/p>\n a) 820 Question 2:<\/strong><\/p>\n The number of common terms in the two sequences 17, 21, 25,\u2026, 417 and 16, 21, 26,\u2026, 466 is<\/p>\n a) 78 100 Free GK tests for IIFT (Download App)<\/a><\/p>\n Question 3:<\/strong><\/p>\n Rahim plans to drive from city A to station C, at the speed of 70 km per hour, to catch a train arriving there from B. He must reach C at least 15 minutes before the arrival of the train. The train leaves B, located 500 km south of A, at 8:00 am and travels at a speed of 50 km per hour. It is known that C is located between west and northwest of B, with BC at 60\u00b0 to AB. Also, C is located between south and southwest of A with AC at 30\u00b0 to AB. The latest time by which Rahim must leave A and still catch the train is closest to<\/p>\n a) 6: 15 am Question 4:<\/strong><\/p>\n A truck traveling at 70 kilometers per hour uses 30% more diesel to travel a certain distance than it does when it travels at the speed of 50 kilometers per hour. If the truck can travel 19.5 kilometers on a liter of diesel at 50 kilometers per hour, how far can the truck travel on 10 liters of diesel at a speed of 70 kilometers per hour?<\/p>\n a) 130 Question 5:<\/strong><\/p>\n Let T be the set of integers {3,11,19,27,\u2026451,459,467} and S be a subset of T such that the sum of no two elements of S is 470. The maximum possible number of elements in S is<\/p>\n a) 32 Take a free CAT mock test<\/a><\/p>\n Answers and Solutions for CAT Aptitude Questions PDF:<\/strong><\/p>\n Solutions:<\/strong><\/p>\n 1)<\/strong> Answer (C)<\/p>\n Let the first operation be (1+40-1) = 40, the second operation be (2+39-1) = 40 and so on 2)<\/strong> Answer (C)<\/p>\n The terms of the first sequence are of the form 4p + 13 Download Profit & Loss Questions PDF<\/a><\/p>\n Download Ratio & Proportion Questions PDF<\/a><\/p>\n 3)<\/strong> Answer (B)<\/p>\n According to given conditions angle between AC and AB is 30 degrees and between AB and BC is 60 degrees. So the triangle formed is a 30-60-90 triangle. 4)<\/strong> Answer (C)<\/p>\n If the truck is being driven at 70 kmph, it takes 1.3 liters of diesel to travel 19.5 km. 5)<\/strong> Answer (D)<\/p>\n No. of terms in series T , 3+(n-1)*8 = 467 i.e. n=59. We hope that this CAT Aptitude Questions PDF is very useful to you.<\/p>\n
\nb) 821
\nc) 781
\nd) 819
\ne) 780<\/p>\n
\nb) 19
\nc) 20
\nd) 77
\ne) 22<\/p>\n
\nb) 6: 30 am
\nc) 6:45 am
\nd) 7: 00 am
\ne) 7: 15 am<\/p>\n
\nb) 140
\nc) 150
\nd) 175<\/p>\n
\nb) 28
\nc) 29
\nd) 30<\/p>\n
\nSo, after 20 operations, all the numbers are 40. After 10 more operations, all the numbers are 79
\nProceeding this way, the last remaining number will be 781<\/p>\n
\nThe terms of the second sequence are of the form 5q + 11
\nIf a term is common to both the sequences, it is of the form 4p+13 and 5q+11
\nor 4p = 5q -2. LHS = 4p is always even, so, q is also even.
\nor 2p = 5r – 1 where q = 2r.
\nNotice that LHS is again even, hence r should be odd. Let r = 2m+1 for some m.
\nHence, p = 5m + 2.
\nSo, the number = 4p+13 = 20m + 21.
\nHence, all numbers of the form 20m + 21 will be the common terms. i.e 21,41,61,…,401 = 20.<\/p>\n
\nSo, total time taken by train is 5 hrs, hence the train reaches at 1 pm. Accordingly, Rahim has to reach C fifteen minutes before i.e. at 12:45 PM.
\nTime taken by Rahim to travel by car is around 6.2 hrs. So, the latest time by which Rahim must leave A and still be able to catch the train is 6:30 am.<\/p>\n
\nTherefore, with 10 liters of diesel, the truck can travel 10\/1.3 * 19.5 km = 150 km.<\/p>\n
\nNow S will have atleast have of 59 terms i.e 29 .
\nAlso the sum of 29th term and 30th term is less than 470.
\nHence, maximum possible elements in S is 30.<\/p>\n