In IBPS Clerk exam, most aspirants feel hard to clear cutoffs of numerical ability (quantitative aptitude-maths). But the trick is to only attempt the easy questions rather than spending time on difficult or lengthy questions.This section will have 35 questions of one mark each in the prelims exam. The questions will be basically on arithmetic and basic maths.<\/p>\n
IBPS Clerk Numerical Ability Questions With Answers PDF<\/strong><\/span>:<\/p>\n Download IBPS Clerk Numerical Ability Questions With Answers PDF:<\/a><\/p> 75 IBPS Clerk Mocks – just Rs.199<\/a><\/p> IBPS Clerk Free Mock Test-2018<\/a><\/p><\/p>\n Download all GK ebooks for Banking exams<\/a>\u00a0and all IBPS clerk questions and answers PDF<\/a>.<\/p>\n b) 26 min Question 2: a) 3478 Question 3: a) 15 kmph Question 4: a) 250 % Question 5: a) 16:15 100 Free GK tests for Banking Download App<\/a><\/p>\n IBPS CLERK FREE COMPUTER AWARENESS TESTS<\/a><\/p> a) Rs. 37,000 Question\u00a07:<\/strong><\/p>\n Find out the wrong number in the given number series a) 7 Question\u00a08:<\/strong><\/p>\n A bag of fruits was distributed among 4 students P, Q, R and S. P took 3\/8th of the fruits. Q took 1\/5th of the remaining fruits and the remaining fruits were equally distributed among R and S. What fraction of fruits did R get?<\/p>\n a) 1\/4 Take free IBPS Clerk mock test<\/a><\/p>\n Solutions for IBPS Clerk numerical ability questions:\u00a0(1\u00a0to\u00a08)<\/strong><\/p>\n 1)<\/strong>\u00a0Answer\u00a0(E)<\/p>\n Time\u00a0taken\u00a0by\u00a0Shweta\u00a0to\u00a0complete\u00a0300\u00a0units\u00a0of\u00a0work\u00a0at\u00a0a\u00a0speed\u00a0of\u00a015units\/min\u00a0=\u00a0300\/15\u00a0=\u00a020 2)<\/strong>\u00a0Answer\u00a0(E)<\/p>\n 9070\u00a0–\u00a015^3\u00a0=\u00a05675\u00a0,\u00a05675\u00a0–\u00a013^3\u00a0=\u00a03478\u00a0,\u00a03478\u00a0–\u00a011^3\u00a0=\u00a02147\u00a0,\u00a02147\u00a0–\u00a09^3\u00a0=\u00a01418\u00a0,\u00a01418\u00a0–\u00a07^3\u00a0=\u00a01075\u00a0\u2260\u00a01077\u00a0,\u00a01075\u00a0–\u00a05^3\u00a0=\u00a0950<\/p>\n 3)<\/strong>\u00a0Answer\u00a0(C)<\/p>\n With\u00a0the\u00a0current\u00a0=>\u00a0downstream 4)<\/strong>\u00a0Answer (B)<\/p>\n Let the marked price be Rs. 100. Also Download all our IBPS Clerk questions and answers<\/a>.<\/p>\n 5)<\/strong>\u00a0Answer (A)<\/p>\n Let the two numbers be p,q 6)<\/strong>\u00a0Answer (D)<\/p>\n Let the earnings of A and B be 8k and 9k respectively. 7)<\/strong>\u00a0Answer\u00a0(D)<\/p>\n (7-1)\u00a0x\u00a02\u00a0=\u00a012 8)<\/strong>\u00a0Answer\u00a0(A)<\/p>\n Let\u00a0P+Q+R+S\u00a0=\u00a0x\u00a0where\u00a0x\u00a0is\u00a0bag\u00a0of\u00a0fruits. Hope you find this numerical ability questions for IBPS clerk set useful, also download all IBPS questions and answers PDF<\/a><\/p>\n Download Complete General Knowledge for all Banking exams\u00a0<\/a><\/p>\n
\na) 16 minQuestion 1:
\n<\/b>Yesterday Shweta completed 300 units of work at the rate of 15 units per minute. Today she completed the same units of work but her speed was 40% faster than yesterday. What is the approximate difference in the time she took to complete the work yesterday and the time she took today ?<\/p>\n
\nc) 46 min
\nd) 36 min
\ne)6 min<\/p>\n
\n<\/b>
\nFind out the wrong number in the given series
\n9050, 5675, 3478, 2147, 1418, 1077, 950<\/p>\n
\nb) 1418
\nc) 5673
\nd) 2147
\ne)1077<\/p>\n
\n<\/b>
\nA boat\u2019s speed with the current is 15 kmph and the boat\u2019s speed against the current is 5 kmph. What is the speed of the current?<\/p>\n
\nb) 10 kmph
\nc) 5 kmph
\nd) 20 kmph
\ne)None of the above<\/p>\n
\n<\/b>
\nA person bought an article on 40% discount and sold it at 50% more than the marked price. What profit did he get?<\/p>\n
\nb) 150 %
\nc) 350 %
\nd) 200 %
\ne)None of these<\/p>\n
\n<\/b>
\n75% of a number is equal to four-fifth of another number.What is the ratio between the first number and the second number respectively ?<\/p>\n
\nb) 15:14
\nc) 5:6
\nd) 15:16
\ne)None of these<\/p>\n
\n
\nQuestion 6:
\n<\/b>
\nRatio of earnings of A and B is 8 : 9 respectively. If the earnings of A increased by 50% and the earnings of B decrease by 25%, the new ratio of their earnings becomes 16:9 respectively. What are \u2018A\u2019 earnings ?<\/p>\n
\nb) Rs. 28,500
\nc) Rs. 22,000
\nd) Cannot be determined
\ne)None of these<\/p>\n
\n7, 12, 40, 222, 1742, 17390, 208608<\/p>\n
\nb) 12
\nc) 40
\nd) 1742
\ne)208608<\/p>\n
\nb) 3\/8
\nc) 1\/8
\nd) 5\/16
\ne)Other than those as options<\/p>\n
\nNew\u00a0speed\u00a0=\u00a01.4*15\u00a0=\u00a021\u00a0units\/min
\nTime\u00a0taken\u00a0by\u00a0Shweta\u00a0to\u00a0complete\u00a0300\u00a0units\u00a0of\u00a0work\u00a0at\u00a0a\u00a0speed\u00a0of\u00a021units\/min\u00a0=\u00a0300\/21\u00a0~14
\nTime\u00a0difference\u00a0=\u00a06\u00a0minutes<\/p>\n
\nAgainst\u00a0the\u00a0current\u00a0=>\u00a0upstream
\nLet\u00a0the\u00a0speed\u00a0of\u00a0the\u00a0boat\u00a0be\u00a0\u2018s\u2019\u00a0and\u00a0the\u00a0speed\u00a0of\u00a0the\u00a0river\u00a0be\u00a0\u2018r\u2019.
\nSo,\u00a0s\u00a0\u2013\u00a0r\u00a0=\u00a05\u00a0and\u00a0s\u00a0+\u00a0r\u00a0=\u00a015
\n=>2s\u00a0=\u00a020\u00a0=>\u00a0s\u00a0=\u00a010\u00a0and\u00a0r\u00a0=\u00a05\u00a0kmph
\nSpeed\u00a0of\u00a0the\u00a0current\u00a0=\u00a05\u00a0kmph<\/p>\n
\nThen cost price = 100 \u2013 40 = Rs. 60
\nSelling price = 100+ 50 = Rs. 150
\nProfit = 150 \u2013 60 = 90
\nProfit%=90\/60\u00d7100=150%<\/p>\n
\n75% of p means 75\/100*p or
\n3\/4 of p, 4\/5 of other number means 4\/5q.Both are equal.
\nHence,3\/4p=4\/5q hence,p\/q=16\/15.
\nHence the ratio is 16:15,hence, A<\/p>\n
\nNew earnings of A = 150\/100 * 8k = 12k
\nNew earnings of B = 3\/4 * 9k = 6.75k
\nSo, 12k : 6.75k = 16 : 9
\nBut, from this equation, we cannot determine the value of k.
\nSo, option d) is the correct answer.<\/p>\n
\n(12\u00a0\u2013\u00a02)\u00a0x\u00a04\u00a0=\u00a040
\n(40\u00a0\u2013\u00a03)\u00a0x\u00a06\u00a0=\u00a0222
\n(222\u00a0\u2013\u00a04)\u00a0x\u00a08\u00a0=\u00a01744\u00a0\u2260\u00a01742
\n(1744\u00a0\u2013\u00a05)\u00a0x\u00a010\u00a0=\u00a017390
\n(17390\u00a0\u2013\u00a06)\u00a0x\u00a012\u00a0=\u00a0208608<\/p>\n
\nP\u00a0=\u00a0(3\/8)x
\nQ\u00a0=\u00a0(1\/5)*5x\/8\u00a0=\u00a0x\/8
\nLet\u00a0R\u00a0and\u00a0S\u00a0be\u00a0fraction\u00a0by\u00a0y.
\nFruits\u00a0with\u00a0R\u00a0and\u00a0S\u00a0=\u00a0x\u00a0-3x\/8\u00a0–\u00a0x\/8\u00a0=\u00a0x\/2
\nSO\u00a0fruits\u00a0with\u00a0R\u00a0=\u00a0x\/4<\/p>\n