Many aspirant feel it difficult to reach Quantitative Aptitude sectional cut off. But the trick is here to attempt only the easy and less time consuming questions. How much you are good at a particular topic, if the question is difficult, then better to leave it. You should allocate around 22 minutes to solve this section. The main important topics are simplification, Arithmetic topics (Number series, profit and loss, quadratic equations, percentages, simple and compound interest, averages, ratio and proportion). There will be data interpretation questions also in this section. Here we have provided solved questions on time, speed and distance for IBPS clerk.<\/p>\n
IBPS Clerk Quantitative Aptitude Questions with Answers PDF:<\/strong><\/span><\/p>\n You can download the IBPS clerk quant questions PDF, or you can go through the details below.<\/p>\n Download IBPS Clerk Quant Questions PDF<\/a><\/p> 75 IBPS Clerk Mocks – just Rs.199<\/a><\/p> IBPS Clerk Free Mock Test-2018<\/a><\/p><\/p>\n Also download all our IBPS Clerk solved questions PDF<\/a>.<\/p>\n Question1:<\/strong><\/p>\n Three friends J, K and Ljog around a circular stadium and complete one round in 12, 18 and 20 seconds respectively. In how many minutes will all the three meet again at the starting point<\/p>\n a) 5 Question 2:<\/strong><\/p>\n The speed of a boat when travelling downstream is 32 Kms. \/ Hr. , whereas when travelling upstream it is 28 kms\/hr. What is the speed of the boat in still water ?<\/p>\n a) 27 Kms\/Hr. Question 3:<\/strong><\/p>\n If I walk at 4 km\/h, I miss the bus by 10 min. If I walk at 5 km\/h, I reach 5 min before the arrival of the bus. How far I walk to reach the bus stand?<\/p>\n a) 5 km Question 4:<\/strong><\/p>\n The speed of a boat in still water is 15 km\/hr and the rate of current is 3 km\/hr. The distance travelled down steam in 12 minutes is:<\/p>\n a) 3.3 km 100 Free GK tests for Banking Download App<\/a><\/p>\n Question 5:<\/strong><\/p>\n An express train travelled at an average speed of 75 km\/h stopping for 5 min every 125 km. How long did it take to reach its destination 375 km from the starting point?<\/p>\n a) 6 h 30 min Question 6:<\/strong><\/p>\n A boat\u2019s speed with the current is 15 kmph and the boat\u2019s speed against the current is 5 kmph. What is the speed of the current?<\/p>\n a) 15 kmph Question 7:<\/strong><\/p>\n The average speed of a bus is 8 times the average speed of a bike. The bike covers a distance of 186 km in 3 hours. How much distance will the bus cover in 10 hours ?<\/p>\n a) 4069 km Question 8:<\/strong><\/p>\n A 210 m long train takes 6 s to cross a man running at 9 km\/h in a direction opposite to that of the train. What is the speed of the train? (in km\/h)<\/p>\n a) 127 IBPS CLERK FREE COMPUTER AWARENESS TESTS<\/a><\/p>\n Question 9:<\/strong><\/p>\n A truck covers a distance of 640 km in 10 h. A car covers the same distance in 8 h. What is the respective ratio between the speed of the truck and the car?<\/p>\n a) 3: 4 Question 10:<\/strong><\/p>\n Faisal walks 325 m every day .How many kilometers will he walk in four weeks?<\/p>\n a) 6.2 Solutions for IBPS Clerk Quantitative Aptitude Questions with Answers PDF:<\/strong><\/p>\n 1)<\/strong> Answer (D)<\/p>\n All the three friends will meet at the starting point again after X seconds, such that X is the LCM of the times taken by J, K and L to complete one round. 2)<\/strong> Answer (E)<\/p>\n Let the speed of boat in still water be v and the speed of water be x. Take free IBPS Clerk mock test<\/a><\/p>\n 3)<\/strong> Answer (A)<\/p>\n Suppose the required distance be d km\/h 4)<\/strong> Answer (D)<\/p>\n Speed downstream = (15 + 3) kmph = 18 kmph. 5)<\/strong> Answer (D)<\/p>\n Time taken to cover 375 km = (375\/75)h = 5h 6)<\/strong> Answer (C)<\/p>\n With the current => downstream IBPS Clerk Previous papers<\/a><\/p>\n 7)<\/strong> Answer (C)<\/p>\n Let x be the speed of bike and y be the speed of bus. 8) <\/b>Answer (C)<\/p>\n Speed of train = x 9) <\/b>Answer (E)<\/p>\n We know the formula of speed which is Speed = Distance\/Time 10)<\/b> Answer (B)<\/p>\n Number of days in 4 weeks = 4*7 = 28 We hope that IBPS Clerk Quantitative Aptitude Questions With Answers PDF is useful to you.<\/p>\n Also Download all our IBPS Clerk questions and answers<\/a>.<\/p>\n
\nb) 8
\nc) 12
\nd) 3
\ne) None of these<\/p>\n
\nb) 29 Kms\/Hr.
\nc) 31 Kms\/Hr.
\nd) Cannot be determined
\ne) None of these<\/p>\n
\nb) 5.5 km
\nc) 6 km
\nd) 7.5 km
\ne) None of these<\/p>\n
\nb) 2.9 km
\nc) 2.4 km
\nd) 3.6 km
\ne) None of these<\/p>\n
\nb) 4 h 45 min
\nc) 3 h 15 min
\nd) 5 h 10 min
\ne) None of these<\/p>\n
\nb) 10 kmph
\nc) 5 kmph
\nd) 20 kmph
\ne) None of the above<\/p>\n
\nb) 4096 km
\nc) 4960 km
\nd) 4690 km
\ne) None of these<\/p>\n
\nb) 121
\nc) 117
\nd) 108
\ne) 111<\/p>\n
\nb) 1: 2
\nc) 5: 6
\nd) 6: 7
\ne) None of these<\/p>\n
\nb) 9.1
\nc) 8.6
\nd) 7.8
\ne) None of these<\/p>\n
\n=> LCM of 12, 18 and 20 = 180 seconds = 3 minutes.
\nHence 3 minutes is the answer.<\/p>\n
\nBoat speed while going upstream = v-x = 28
\nBoat speed while going downstream = v+x = 32
\n=> 2v = 60 => v = 30
\nHence, none of these is the correct answer.<\/p>\n
\nThen, d\/4-d\/5=15min=1\/4 h \u21d2d 1\/20=1\/4\u21d2d=5km<\/p>\n
\nDistance traveled =(18\u00d712\/60)km = 3.6 km.<\/p>\n
\nNumber of stoppages = 375\/125-1 = 2
\nTotal time to stoppages = (5 \u00d7 2 ) min = 10 min
\nHence, total time taken = 5 h 10 min<\/p>\n
\nAgainst the current => upstream
\nLet the speed of the boat be \u2018s\u2019 and the speed of the river be \u2018r\u2019.
\nSo, s \u2013 r = 5 and s + r = 15
\n=>2s = 20 => s = 10 and r = 5 kmph
\nSpeed of the current = 5 kmph<\/p>\n
\ny=8x
\nAlso, bike covers 186 kilometers of distance in 3 hours
\nTherefore, x = 186\/3 = 62km\/hr
\nNow, y = 8x = 496km\/hr
\nDistance covered by bus in 10 hours with this speed = 4960 km\/hr<\/p>\n
\nRelative speed = x + 9(5\/18) = x + 2.5
\nSpeed = 210\/6 = 35m\/s
\nx + 2.5 = 35 => x = 32.5 m\/s = 32.5 * (18\/5) = 6.5 * 18 = 117 kmph<\/p>\n
\nSpeed of a truck = 640\/10 = 64
\nSpeed of a car = 640\/8 = 80
\nRatio of speed of truck and car = 64:80 = 4:5<\/p>\n
\nSince Faisal walks 325 m every day
\nDistance walked in 28 days = 325*28 = 9100m
\n9100m = 9.1km<\/p>\n