Number series questions are very important for IBPS exams like IBPS Clerk and PO. A series of numbers will be given and you will asked to find out the next or missing or wrong number. Each series is formed from a particular progression\/logic. Here comes a list of questions in which one number is wrong and rest of the terms follow the series.<\/p>\n
IBPS Clerk Number Series Questions PDF:<\/span><\/strong><\/span><\/p>\n You can download the Number Series questions PDF or you can go through the details below.<\/p>\n Download IBPS Clerk Number Series Questions PDF<\/a><\/p>\n Get 25 IBPS Clerk mocks for Rs. 149. Enroll here<\/a><\/p>\n Take Free IBPS Clerk Mock Test<\/a><\/p>\n Download IBPS Clerk Previous papers PDF<\/a><\/p>\n Go to Free Banking Study Material<\/a> (15,000 Solved Questions)<\/p>\n Instructions:<\/strong><\/p>\n In each of these question a number series is given.In each series only one number is wrong.Find out the wrong numbers<\/p>\n Question 1:<\/strong><\/p>\n 1, 4, 15, 64 325, 1955<\/p>\n A.<\/strong> 15 Question 2:<\/strong><\/p>\n 6, 12, 21, 33, 49, 66<\/p>\n A.<\/strong> 21 Question 3:<\/strong><\/p>\n 6, 11.5, 19, 28.5, 41<\/p>\n A.<\/strong> 6 Question 4:<\/strong><\/p>\n 5, 26, 82, 214, 401, 702<\/p>\n A.<\/strong> 26 Question 5:<\/strong><\/p>\n 5,20,73,274,1049<\/p>\n A.<\/strong> 20 IBPS Clerk Online Mock Test<\/a><\/p>\n Question 6:<\/strong><\/p>\n 3601, 3602, 1803, 604, 154, 36, 12<\/p>\n A.<\/strong> 3602 Question 7:<\/strong><\/p>\n 4, 12, 42, 196, 1005, 6066, 42511<\/p>\n A.<\/strong> 12 IBPS CLERK PRELIMS QUESTION PAPER 2016 PDF<\/a><\/p>\n Question 8:<\/strong><\/p>\n 2, 8, 12, 20, 30, 42, 56<\/p>\n A.<\/strong> 8 Question 9:<\/strong><\/p>\n 32, 16, 24, 65, 210, 945, 5197.5<\/p>\n A.<\/strong> 945 Question 10:<\/strong><\/p>\n 7, 13, 25, 49, 97, 194, 385<\/p>\n A.<\/strong> 13 Solutions to Number Series Questions for IBPS Clerk:<\/strong><\/p>\n \u00a01) <\/b>Answer (D)<\/p>\n 4 = 1*2+2 ; 15 = 4*3+3 ; 64 = 15*4+4 ; 325 = 64*5+5 ; 1956 = 325*6+6 2)<\/strong> Answer (C)<\/p>\n 2*2+2 = 6 ; 3*3+3 = 12 ; 4*4 + 5= 21 ; 5*5 +8 = 33 ; 6*6 + 12 = 48<\/p>\n 3)<\/strong> Answer (C)<\/p>\n 1.5*2 + 3 = 6 IBPS CLERK EXPECTED CUTOFF 2017<\/a><\/p>\n 4)<\/strong> Answer (C)<\/p>\n 1*2+3=5 ; 4*5+6 = 26 ; 8*9+10 = 82 ; 13*14+15 = 212 ; 19*20 + 21 =401 ; 26*27 +28 = 702<\/p>\n 5)<\/strong> Answer (C)<\/p>\n 1^2 + 4= 5 ; 2^2 + 16 = 20 ; 3^2 + 64 = 73 ; 4^2 + 256 = 272 ; 5^2 + 1024 = 1049<\/p>\n 6)<\/strong> Answer (D)<\/p>\n In the given series, nth term is obtained by – (Previous term\/(n-1) ) +(n-1). 7)<\/strong> Answer (B)<\/p>\n In this question, the nth term is obtained by (previous term*n + n^2). Download IBPS Clerk 2017 Syllabus PDF<\/a><\/p>\n 8)<\/strong> Answer (A)<\/p>\n Here the consecutive difference between the terms is incremented by 2 for the series. 9)<\/strong> Answer (E)<\/p>\n Here the sucessive numbers are multiplied by .5,1.5.2.5…. 10)<\/strong> Answer (D)<\/p>\n Here, in this series, the nth term is (previous term + $6*2^{n-2}$) Hope this questions had helped you get good understanding of Number Series questions asked in IBPS Clerk exams.<\/p>\n Highly Rated Free Preparation App for Banking Exams<\/a><\/p>\n
\nB.<\/strong> 64
\nC.<\/strong> 325
\nD.<\/strong> 1955
\nE.<\/strong> None of these<\/p>\n
\nB.<\/strong> 33
\nC.<\/strong> 49
\nD.<\/strong> 66
\nE.<\/strong> None of these<\/p>\n
\nB.<\/strong> 11.5
\nC.<\/strong> 41
\nD.<\/strong> 28.5
\nE.<\/strong> None of these<\/p>\n
\nB.<\/strong> 82
\nC.<\/strong> 214
\nD.<\/strong> 401
\nE.<\/strong> None of these<\/p>\n
\nB.<\/strong> 73
\nC.<\/strong> 274
\nD.<\/strong> 1049
\nE.<\/strong> None of these<\/p>\n
\nB.<\/strong> 1803
\nC.<\/strong> 604
\nD.<\/strong> 154
\nE.<\/strong> 36<\/p>\n
\nB.<\/strong> 42
\nC.<\/strong> 1005
\nD.<\/strong> 196
\nE.<\/strong> 6066<\/p>\n
\nB.<\/strong> 42
\nC.<\/strong> 30
\nD.<\/strong> 20
\nE.<\/strong> 12<\/p>\n
\nB.<\/strong> 16
\nC.<\/strong> 24
\nD.<\/strong> 210
\nE.<\/strong> 65<\/p>\n
\nB.<\/strong> 49
\nC.<\/strong> 97
\nD.<\/strong> 194
\nE.<\/strong> 25<\/p>\n
\nThe nth term is of the form,
\n$T_n=(T_{n-1}\\times n)+n$
\nThe last term does not follow the pattern and is thus the wrong number in the sequence.<\/p>\n
\n2.5*3 + 4 = 11.5
\n3.5*4 + 5 = 19
\n4.5*5 + 6 = 28.5
\n5.5*6 + 7 = 40<\/p>\n
\nHence the 5th term should be (604\/4)+4 = 155.
\nHowever 5th term is given as 154.
\nHence, 154 is wrong term in the given series.<\/p>\n
\nHence, after 12, the number would be (12*3+9)= 45
\nTherefore, the correct option is 45.<\/p>\n
\nHence, after 2, the number should be 6.<\/p>\n
\nHence, in place of 65 the number should be 24*2.5=60.
\nTherefore, the incorrect number for series is 65.<\/p>\n
\nHence, in place of 194 the term should be $(97+6*2^{4}) = 193$<\/p>\n