{"id":44585,"date":"2021-01-29T13:31:22","date_gmt":"2021-01-29T08:01:22","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=44585"},"modified":"2021-01-29T13:31:22","modified_gmt":"2021-01-29T08:01:22","slug":"important-questions-on-quadratic-equations-for-cmat-exam","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/important-questions-on-quadratic-equations-for-cmat-exam\/","title":{"rendered":"Important Questions On Quadratic Equations For CMAT Exam"},"content":{"rendered":"

Quadratic Equation Questions For CMAT Exam<\/strong><\/h1>\n

Download CMAT Quadratic Equations\u00a0 Questions and Answers PDF covering the important questions. Most expected Quadratic questions with explanations for CMAT 2021 exam.<\/p>\n

Download Important Questions On Quadratic Equations For CMAT Exam<\/a><\/p>\n

Get 5 CMAT Mocks – Just Rs. 299<\/a><\/p>\n

Take CMAT Free Mock Test<\/a><\/p>\n

Download CMAT Previous Papers PDF<\/a><\/p>\n

Instructions<\/b><\/p>\n

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
\nMark answer if
\na) a<\/b><\/b><b<\/p>\n

b) $a\\leq b$<\/p>\n

c) relationship between a & b cannot be established<\/p>\n

d) a>b<\/p>\n

e) $a\\geq b$<\/p>\n

Question 1:\u00a0<\/b>I.$2a^{2}+a-1=0$
\nII.$12b^{2}-17b+6=0$<\/p>\n

a)\u00a0$a<b$<\/p>\n

b)\u00a0$a\\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a\\geq b$<\/p>\n

Question 2:\u00a0<\/b>I.$a^{2}-5a+6=0$
\nII. $2b^{2}-13b+21=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a\\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a\\geq b$<\/p>\n

Question 3:\u00a0<\/b>I.$a^{2}+5a+6=0$
\nII.$b^{2}+7b+12=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a \\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a \\geq b$<\/p>\n

Question 4:\u00a0<\/b>I.$16a^{2}=1$
\nII.$3b^{2}+7b+2=0$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a\\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a\\geq b$<\/p>\n

Question 5:\u00a0<\/b>I.$a^{2}+2a+1=0$
\nII.$b^{2}=\\pm4$<\/p>\n

a)\u00a0$a<b$<\/b><\/p>\n

b)\u00a0$a \\leq b$<\/p>\n

c)\u00a0Relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0$a>b$<\/p>\n

e)\u00a0$a \\geq b$<\/p>\n

Get 5 TISSNET Mocks – Rs. 299<\/a><\/p>\n

Download CMAT Previous Papers PDF<\/a><\/p>\n

Instructions<\/b><\/p>\n

In each of the following question two equations are given you have to solve them and
\nGive answer (a)if p<q
\n<\/q
\nGive answer (b)if p>q
\nGive answer (c)if $p\\leq$q
\nGive answer(d)if $p\\geq$q
\nGive answer (e)if p=q<\/p>\n

Question 6:\u00a0<\/b>I.$p^{2}-7p=-12$
\nII.$q^{2}-3q+2=0$<\/p>\n

a)\u00a0if p<q<\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p\\leq$q<\/p>\n

d)\u00a0if $p\\geq$q<\/p>\n

e)\u00a0if p=q<\/p>\n

Question 7:\u00a0<\/b>I. $12p^{2}-7p=-1$
\nII. $6q^{2}-7q+2=0$<\/p>\n

a)\u00a0if $p < q$<\/q><\/p>\n

b)\u00a0if $p > q$<\/p>\n

c)\u00a0if $p\\leq q$<\/p>\n

d)\u00a0if $p\\geq q$<\/p>\n

e)\u00a0if $p = q$<\/p>\n

Question 8:\u00a0<\/b>I.$p^{2}+12p+35=0$
\nII.$2q^{2}+22q+56=0$<\/p>\n

a)\u00a0if p < q<\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p \\leq q$<\/p>\n

d)\u00a0if $p\\geq q$<\/p>\n

e)\u00a0if p=q or no relationship can be established<\/p>\n

Question 9:\u00a0<\/b>I.$p^{2}-8p+15=0$
\nII.$q^{2}-5q=-6$<\/p>\n

a)\u00a0if p < q<\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p\\leq q$<\/p>\n

d)\u00a0if $p\\geq q$<\/p>\n

e)\u00a0if p=q<\/p>\n

Question 10:\u00a0<\/b>I.$2p^{2}+20p+50=0$
\nII.$q^{2}=25$<\/p>\n

a)\u00a0if p<q <\/q><\/p>\n

b)\u00a0if p>q<\/p>\n

c)\u00a0if $p \\leq q$<\/p>\n

d)\u00a0if $p\\geq q $<\/p>\n

e)\u00a0if p = q<\/p>\n

Instructions<\/b><\/p>\n

For the two given equations I and II—-<\/p>\n

Take CMAT Free Mock Test With Solutions<\/a><\/p>\n

Enroll to MAH MBA CET Crash Course<\/a><\/p>\n

Question 11:\u00a0<\/b>I. $6p^{2}+5p+1=0$
\nII. $20q^{2}+9q=-1$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 12:\u00a0<\/b>I. $3p^{2}+2p-1=0$ II. $2q^{2}+7q+6=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 13:\u00a0<\/b>I. $p=\\frac{\\sqrt{4}}{\\sqrt{9}}$ II. $9q^{2}-12q+4=0$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Question 14:\u00a0<\/b>I. $p^{2}+13p+42=0$ II. $q^{2}=36$<\/p>\n

a)\u00a0Give answer (A) if p is greater than q.<\/p>\n

b)\u00a0Give answer (B) if p is smaller than q.<\/p>\n

c)\u00a0Give answer (C) if p is equal to q.<\/p>\n

d)\u00a0Give answer (D) if p is either equal to or greater than q.<\/p>\n

e)\u00a0Give answer (E) if p is either equal to or smaller than q.<\/p>\n

Instructions<\/b><\/p>\n

In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.<\/p>\n

Question 15:\u00a0<\/b>I. $2x^{2}+19x+45=0$
\nII. $2y^{2}+11y+12=0$<\/p>\n

a)\u00a0x = y<\/p>\n

b)\u00a0x> y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between xand y cannot be determined<\/p>\n

e)\u00a0x + y<\/p>\n

Download TISSNET Previous Papers PDF<\/a><\/p>\n

Take TISSNET Mock Test Here<\/a><\/p>\n

Question 16:\u00a0<\/b>I. $3x^{2}-13x+12=0$
\nII. $2y^{2}-15y+28=0$<\/p>\n

a)\u00a0x> y<\/p>\n

b)\u00a0x= y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between x and y cannot be determined<\/p>\n

e)\u00a0x\u2264 y<\/p>\n

Question 17:\u00a0<\/b>I. $x^{2}=16$
\nII. $2y^{2}-17y+36=0$<\/p>\n

a)\u00a0$x > y$<\/p>\n

b)\u00a0$x\\geq y$<\/p>\n

c)\u00a0$x < y$<\/p>\n

d)\u00a0relationship between x and y cannot be determined<\/p>\n

e)\u00a0$x \\leq y$<\/p>\n

Question 18:\u00a0<\/b>I. $6x^{2}+19x+15=0$
\nII. $3y^{2}+11y+10=0$<\/p>\n

a)\u00a0x = y<\/p>\n

b)\u00a0x > y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0$x \\geq y$<\/p>\n

e)\u00a0$x \\leq y$<\/p>\n

Question 19:\u00a0<\/b>I. $2x^{2}-11x+15=0$
\nII. $2y^{2}-11y+14=0$<\/p>\n

a)\u00a0x > y<\/p>\n

b)\u00a0x> y<\/p>\n

c)\u00a0x < y<\/p>\n

d)\u00a0relationship between x and y cannot be determined<\/p>\n

e)\u00a0x \u2264 y<\/p>\n

Instructions<\/b><\/p>\n

In the following questions two equations numbered I and
\nII are given. You have to solve both the equations and
\na: if x > y
\nb: if x \u2265 y
\nc: if x < y
\nd: if x \u2264 y
\ne: if x = y or the relationship cannot be established.<\/p>\n

Question 20:\u00a0<\/b>I. $x^{2}+x-12=0$
\nII. $y^{2}+2y-8=0$<\/p>\n

a)\u00a0if x > y<\/p>\n

b)\u00a0if x \u2265 y<\/p>\n

c)\u00a0if x < y<\/p>\n

d)\u00a0if x \u2264 y<\/p>\n

e)\u00a0if x = y or the relationship cannot be established.<\/p>\n

Free MBA Preparation YouTube Videos<\/a><\/p>\n

Join 7K MBA Aspirants Telegram Group<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$2a^{2}+a-1=0$
\nWe get the factor as:
\na=-1, a=0.5<\/p>\n

$12b^{2}-17b+6=0$
\nSolving, we get the factor as,
\na= .66, b= .75<\/p>\n

Hence, b>a
\nOption A is the correct option.<\/p>\n

2)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Soving the quadratic equations we get,
\n$a^{2}-5a+6=0$
\ni.e (a-2)(a-3)=0
\ni.e a=2, a=3<\/p>\n

$2b^{2}-13b+21=0$
\ni.e (b-3.5)(b-3)=0
\ni.e b= 3.5 and b=3<\/p>\n

Hence, we can deduce that $a\\leq b$
\nTherefore, option B is correct.<\/p>\n

3)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$a^{2}+5a+6=0$
\ni.e (a+2)(a+3)=0
\ni.e a=-2, a=-3<\/p>\n

.$b^{2}+7b+12=0$
\ni.e (b+4)(b+3)=0
\ni.e b=-4, b=-3<\/p>\n

Hence, we can deduce that $a \\geq b$.
\nTherefore, option E is correct.<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$16a^{2}=1$
\nSolving we get, a=-.25, a=+.25<\/p>\n

$3b^{2}+7b+2=0$
\nSolving we get, b= -2. b = -1\/3<\/p>\n

Hence, a>b. Option D is correct.<\/p>\n

5)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We can easily solve equation I to get a = -1
\nBut we cannot solve $b^{2}=\\pm4$. Square root of negative number is not a real number.
\nHence, we cannot find a value of b. Therefore, we cannot establish a relationship between a and b.<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$p^2-7p+12 = 0$
\n$(p-3)(p-4) = 0$
\n$p = 3, 4$<\/p>\n

$q^2-3q+2 = 0$
\n$(q-1)(q-2) = 0$
\n$q = 1, 2$<\/p>\n

$\\therefore p > q$<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$12p^2-7p+1 = 0$
\n$(4p-1)(3p-1) = 0$
\n$p = \\frac{1}{3}, \\frac{1}{4}$<\/p>\n

$6q^2-7q+2 = 0$
\n$(2q-1)(3q-2) = 0$
\n$q = \\frac{1}{2}, \\frac{2}{3}$<\/p>\n

$\\therefore p < q$<\/p>\n

8)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$p^2+12p+35 = 0$
\n$(p+5)(p+7) = 0$
\n$p = -5, -7$<\/p>\n

$2q^2+22q+56 = 0$
\n$q^2+11q+28 = 0$
\n$(q+4)(q+7) = 0$
\n$q = -4, -7$<\/p>\n

As we can see $p$ can be greater than, less than or equal to $q$. No relationship can be established between $p$ and $q$ and hence, option E is the right answer.<\/p>\n

9)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$p^2-8p+15 = 0$
\n$(p-3)(p-5) = 0$
\n$p = 3, 5$<\/p>\n

$q^2-5q+6 = 0$
\n$(q-2)(q-3) = 0$
\n$q = 2, 3$<\/p>\n

$p\\geq q$<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$2p^2+20p+50 = 0$
\n$p^2+10p+25 = 0$
\n$(p+5)^2 = 0$
\n$p = -5$<\/p>\n

$q^2 = 25$
\n$q = 5, -5$<\/p>\n

$p\\leq q$<\/p>\n

Get 5 CMAT Mocks for just Rs. 299<\/a><\/p>\n

Download CMAT Previous Papers Andriod App<\/a><\/p>\n

11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$6p^2+5p+1 = 0$
\n$(2p+1)(3p+1) = 0$
\n$p = -\\frac{1}{2}, -\\frac{1}{3}$<\/p>\n

$20q^2+9q+1 = 0$
\n$(4q+1)(5q+1) = 0$
\n$q = -\\frac{1}{4}, -\\frac{1}{5}$<\/p>\n

$p < q$<\/p>\n

12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$3p^2+2p-1 = 0$
\n$(3p-1)(p+1) = 0$
\n$p = -1, \\frac{1}{3}$<\/p>\n

$2q^2+7q+6 = 0$
\n$(2q+3)(q+2) = 0$
\n$q = -2, -\\frac{3}{2}$<\/p>\n

p > q<\/p>\n

13)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$p = \\frac{\\sqrt{4}}{\\sqrt{9}}$
\n$p = \\frac{2}{3}$<\/p>\n

$9q^2-12q+4 = 0$
\n${(3q-2)}^2 = 0$
\n$q = \\frac{2}{3}$<\/p>\n

p = q<\/p>\n

14)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$p^2+13p+42 = 0$
\n$(p+6)(p+7) = 0$
\n$p = -6, -7$<\/p>\n

$q^2 = 36$
\n$q = -6, 6$<\/p>\n

$p\\leq q$<\/p>\n

15)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$2x^2+19x+45 = 0$
\n$(2x+9)(x+5) = 0$
\n$x = -5, -\\frac{9}{2}$<\/p>\n

$2y^2+11y+12 = 0$
\n$(2y+3)(y+4) = 0$
\n$y = -4, -\\frac{3}{2}$<\/p>\n

x < y<\/p>\n

16)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

$3x^2-13x+12 = 0$
\n$(3x-4)(x-3) = 0$
\n$x = \\frac{4}{3}, 3$<\/p>\n

$2y^2-15y+28 = 0$
\n$(2y-7)(y-4) = 0$
\n$y = \\frac{7}{2}, 4$<\/p>\n

x < y<\/p>\n

17)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$x^2 = 16$
\n$x = 4, -4$<\/p>\n

$2y^2-17y+36 = 0$
\n$(2y-9)(y-4) = 0$
\n$y = \\frac{9}{2}, 4$<\/p>\n

$x \\leq y$<\/p>\n

18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$6x^2+19x+15 = 0$
\n$(3x+5)(2x+3) = 0$
\n$x = -\\frac{5}{3}, -\\frac{3}{2}$<\/p>\n

$3y^2+11y+10 = 0$
\n$(3y+5)(y+2) = 0$
\n$y = -\\frac{5}{3}, -2$<\/p>\n

$x\\geq y$<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$2x^2-11x+15 = 0$
\n$(2x-5)(x-3) = 0$
\n$x = 3, \\frac{5}{2}$<\/p>\n

$2y^2-11y+14 = 0$
\n$(2y-7)(y-2) = 0$
\n$y = 2, \\frac{7}{2}$<\/p>\n

relationship between x and y cannot be established<\/p>\n

20)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

$x^2+x-12 = 0$
\n$(x-3)(x+4) = 0$
\n$x = -4, 3$<\/p>\n

$y^2+2y-8 = 0$
\n$(y-2)(y+4) = 0$
\n$y = -4, 2$<\/p>\n

Comparing x and y,
\n-4 = -4
\n-4 < 2
\n3 > -4
\n3 > 2
\nHence, relationship can not be established between $x$ and $y$<\/p>\n

Get 5 CMAT Mocks for just Rs. 299<\/a><\/p>\n

Download CMAT Previous Papers Andriod App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

Quadratic Equation Questions For CMAT Exam Download CMAT Quadratic Equations\u00a0 Questions and Answers PDF covering the important questions. Most expected Quadratic questions with explanations for CMAT 2021 exam. Take CMAT Free Mock Test Download CMAT Previous Papers PDF Instructions In each of these question two equations I & II with variables a & b are […]<\/p>\n","protected":false},"author":53,"featured_media":44587,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3,3433],"tags":[1567,4147],"class_list":{"0":"post-44585","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-cat","8":"category-cmat","9":"tag-cmat","10":"tag-quadratic-equations"},"better_featured_image":{"id":44587,"alt_text":"Important Questions On Quadratic Equations For CMAT Exam","caption":"Important Questions On Quadratic Equations For CMAT Exam","description":"Important Questions On Quadratic Equations For CMAT Exam","media_type":"image","media_details":{"width":960,"height":504,"file":"2021\/01\/fig-29-01-2021_06-10-41.jpg","sizes":{"medium":{"file":"fig-29-01-2021_06-10-41-300x158.jpg","width":300,"height":158,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-300x158.jpg"},"thumbnail":{"file":"fig-29-01-2021_06-10-41-150x150.jpg","width":150,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-150x150.jpg"},"medium_large":{"file":"fig-29-01-2021_06-10-41-768x403.jpg","width":768,"height":403,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-768x403.jpg"},"tiny-lazy":{"file":"fig-29-01-2021_06-10-41-30x16.jpg","width":30,"height":16,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-30x16.jpg"},"td_218x150":{"file":"fig-29-01-2021_06-10-41-218x150.jpg","width":218,"height":150,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-218x150.jpg"},"td_324x400":{"file":"fig-29-01-2021_06-10-41-324x400.jpg","width":324,"height":400,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-324x400.jpg"},"td_696x0":{"file":"fig-29-01-2021_06-10-41-696x365.jpg","width":696,"height":365,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-696x365.jpg"},"td_0x420":{"file":"fig-29-01-2021_06-10-41-800x420.jpg","width":800,"height":420,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-800x420.jpg"},"td_80x60":{"file":"fig-29-01-2021_06-10-41-80x60.jpg","width":80,"height":60,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-80x60.jpg"},"td_100x70":{"file":"fig-29-01-2021_06-10-41-100x70.jpg","width":100,"height":70,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-100x70.jpg"},"td_265x198":{"file":"fig-29-01-2021_06-10-41-265x198.jpg","width":265,"height":198,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-265x198.jpg"},"td_324x160":{"file":"fig-29-01-2021_06-10-41-324x160.jpg","width":324,"height":160,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-324x160.jpg"},"td_324x235":{"file":"fig-29-01-2021_06-10-41-324x235.jpg","width":324,"height":235,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-324x235.jpg"},"td_356x220":{"file":"fig-29-01-2021_06-10-41-356x220.jpg","width":356,"height":220,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-356x220.jpg"},"td_356x364":{"file":"fig-29-01-2021_06-10-41-356x364.jpg","width":356,"height":364,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-356x364.jpg"},"td_533x261":{"file":"fig-29-01-2021_06-10-41-533x261.jpg","width":533,"height":261,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-533x261.jpg"},"td_534x462":{"file":"fig-29-01-2021_06-10-41-534x462.jpg","width":534,"height":462,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-534x462.jpg"},"td_696x385":{"file":"fig-29-01-2021_06-10-41-696x385.jpg","width":696,"height":385,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-696x385.jpg"},"td_741x486":{"file":"fig-29-01-2021_06-10-41-741x486.jpg","width":741,"height":486,"mime-type":"image\/jpeg","source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41-741x486.jpg"}},"image_meta":{"aperture":"0","credit":"","camera":"","caption":"","created_timestamp":"0","copyright":"","focal_length":"0","iso":"0","shutter_speed":"0","title":"","orientation":"0"}},"post":44585,"source_url":"https:\/\/cracku.in\/blog\/wp-content\/uploads\/2021\/01\/fig-29-01-2021_06-10-41.jpg"},"yoast_head":"\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\t\n\t\n\n\n\n