Download CMAT Time and Work Questions and Answers PDF covering the important questions. Most expected Time, Distance and Work questions with explanations for CMAT 2021 exam.<\/p>\n
Download Time And Work Questions For CMAT<\/a><\/p>\n Get 5 CMAT Mocks – Just Rs. 299<\/a><\/p>\n Take CMAT Free Mock Test<\/a><\/p>\n Download CMAT Previous Papers PDF<\/a><\/p>\n Question 1:\u00a0<\/b>If Hanuman Jayanthi in 2019 falls on Monday, then on which day will it fall in 2021(Consider Hanuman Jayanthi falls on the same date every year)<\/p>\n a)\u00a0Tuesday<\/p>\n b)\u00a0Wednesday<\/p>\n c)\u00a0Thursday<\/p>\n d)\u00a0Monday<\/p>\n e)\u00a0None of these<\/p>\n Question 2:\u00a0<\/b>If Hanuman Jayanthi in 2019 falls on Monday, then on which day will it fall in 2021(Consider Hanuman Jayanthi falls on the same date every year)<\/p>\n a)\u00a0Tuesday<\/p>\n b)\u00a0Wednesday<\/p>\n c)\u00a0Thursday<\/p>\n d)\u00a0Monday<\/p>\n e)\u00a0None of these<\/p>\n Question 3:\u00a0<\/b>If Hanuman Jayanthi in 2019 falls on Monday, then on which day will it fall in 2021(Consider Hanuman Jayanthi falls on the same date every year)<\/p>\n a)\u00a0Tuesday<\/p>\n b)\u00a0Wednesday<\/p>\n c)\u00a0Thursday<\/p>\n d)\u00a0Monday<\/p>\n e)\u00a0None of these<\/p>\n Question 4:\u00a0<\/b>Find the angle between the hands of a clock when the time is 4:45 pm.<\/p>\n a)\u00a0127.5<\/p>\n b)\u00a0144.5<\/p>\n c)\u00a0120<\/p>\n d)\u00a0140<\/p>\n e)\u00a0150<\/p>\n Question 5:\u00a0<\/b>Ram and Shyam run a race between points A and B 5km apart. Ram starts at 9 am a)\u00a010:20 am<\/p>\n b)\u00a010:30 am<\/p>\n c)\u00a010:40 am<\/p>\n d)\u00a010:50 am<\/p>\n Get 5 TISSNET Mocks – Rs. 299<\/a><\/p>\n Download CMAT Previous Papers PDF<\/a><\/p>\n Question 6:\u00a0<\/b>A car factory had a certain number of workers. These workers could produce certain number of cars per day. But due to the nationwide lockdown, some of the workers migrated back to their hometowns. During the subsequent unlock phases 1,2,3,4 which lasted for 10 days, the factory is allowed to operate with 20%,40%,60%,80% of the remaining workers respectively. If the average output per day of the factory during the unlock phases is 40% of the pre-lockdown output, what is the percentage of workers who migrated back to their home towns.<\/p>\n Question 7:\u00a0<\/b>A car factory had a certain number of workers. These workers could produce certain number of cars per day. But due to the nationwide lockdown, some of the workers migrated back to their hometowns. During the subsequent unlock phases 1,2,3,4 which lasted for 10 days, the factory is allowed to operate with 20%,40%,60%,80% of the remaining workers respectively. If the average output per day of the factory during the unlock phases is 40% of the pre-lockdown output, what is the percentage of workers who migrated back to their home towns.<\/p>\n Question 8:\u00a0<\/b>A car factory had a certain number of workers. These workers could produce certain number of cars per day. But due to the nationwide lockdown, some of the workers migrated back to their hometowns. During the subsequent unlock phases 1,2,3,4 which lasted for 10 days, the factory is allowed to operate with 20%,40%,60%,80% of the remaining workers respectively. If the average output per day of the factory during the unlock phases is 40% of the pre-lockdown output, what is the percentage of workers who migrated back to their home towns.<\/p>\n Question 9:\u00a0<\/b>A car factory had a certain number of workers. These workers could produce certain number of cars per day. But due to the nationwide lockdown, some of the workers migrated back to their hometowns. During the subsequent unlock phases 1,2,3,4 which lasted for 10 days, the factory is allowed to operate with 20%,40%,60%,80% of the remaining workers respectively. If the average output per day of the factory during the unlock phases is 40% of the pre-lockdown output, what is the percentage of workers who migrated back to their home towns.<\/p>\n Question 10:\u00a0<\/b>An escalator is moving upwards. A person takes 60 a)\u00a0480\/7<\/p>\n b)\u00a0450\/7<\/p>\n c)\u00a0440\/7<\/p>\n d)\u00a0490\/7<\/p>\n Take CMAT Free Mock Test With Solutions<\/a><\/p>\n <\/p>\n Enroll to MAH MBA CET Crash Course<\/a><\/p>\n Question 11:\u00a0<\/b>An escalator is moving upwards. A person takes 60 a)\u00a0480\/7<\/p>\n b)\u00a0450\/7<\/p>\n c)\u00a0440\/7<\/p>\n d)\u00a0490\/7<\/p>\n Question 12:\u00a0<\/b>A watch loses 5 seconds every minute and was set right at 10 a)\u00a010 pm Tuesday<\/p>\n b)\u00a010 pm Friday<\/p>\n c)\u00a010 pm Saturday<\/p>\n d)\u00a010 pm Sunday<\/p>\n Question 13:\u00a0<\/b>Two pipes A and B can fill a tank in 24\/7 hours when opened simultaneously. If B alone can take 2 hours less than A alone takes to fill the tank completely. How much does A alone take to fill the tank?(in hours)<\/p>\n a)\u00a08<\/p>\n b)\u00a012<\/p>\n c)\u00a04<\/p>\n d)\u00a06<\/p>\n Question 14:\u00a0<\/b>At what time does the hour hand and the minute hand overlap between 4 pm and 5 pm?<\/p>\n a)\u00a04 hours $21\\ \\frac{9}{11}\\min$<\/p>\n b)\u00a04 hours $22\\ \\frac{9}{11}\\min$<\/p>\n c)\u00a04 hours $36\\ \\frac{9}{11}\\min$<\/p>\n d)\u00a04 hours $39\\ \\frac{9}{11}\\min$<\/p>\n Question 15:\u00a0<\/b>At what time does the hour hand and the minute hand overlap between 4 pm and 5 pm?<\/p>\n a)\u00a04 hours $21\\ \\frac{9}{11}\\min$<\/p>\n b)\u00a04 hours $22\\ \\frac{9}{11}\\min$<\/p>\n c)\u00a04 hours $36\\ \\frac{9}{11}\\min$<\/p>\n d)\u00a04 hours $39\\ \\frac{9}{11}\\min$<\/p>\n Download TISSNET Previous Papers PDF<\/a><\/p>\n Take TISSNET Mock Test Here<\/a><\/p>\n Question 16:\u00a0<\/b>At what time does the hour hand and the minute hand overlap between 4 pm and 5 pm?<\/p>\n a)\u00a04 hours $21\\ \\frac{9}{11}\\min$<\/p>\n b)\u00a04 hours $22\\ \\frac{9}{11}\\min$<\/p>\n c)\u00a04 hours $36\\ \\frac{9}{11}\\min$<\/p>\n d)\u00a04 hours $39\\ \\frac{9}{11}\\min$<\/p>\n Question 17:\u00a0<\/b>Three racers A, B and C completed the marathon at 3:10 PM, 4:30 PM and 5:40 PM respectively\u00a0if they started the marathon at 10:10 AM, 9:30 AM and 7: 40 AM\u00a0 respectively\u00a0on the same day. What is the duration between the time at which A will overtake B and time at which overtake C?<\/p>\n a)\u00a01 hour<\/p>\n b)\u00a050 minutes<\/p>\n c)\u00a045 minutes<\/p>\n d)\u00a040 minutes<\/p>\n Question 18:\u00a0<\/b>Three racers A, B and C completed the marathon at 3:10 PM, 4:30 PM and 5:40 PM respectively\u00a0if they started the marathon at 10:10 AM, 9:30 AM and 7: 40 AM\u00a0 respectively\u00a0on the same day. What is the duration between the time at which A will overtake B and time at which overtake C?<\/p>\n a)\u00a01 hour<\/p>\n b)\u00a050 minutes<\/p>\n c)\u00a045 minutes<\/p>\n d)\u00a040 minutes<\/p>\n Question 19:\u00a0<\/b>Three racers A, B and C completed the marathon at 3:10 PM, 4:30 PM and 5:40 PM respectively\u00a0if they started the marathon at 10:10 AM, 9:30 AM and 7: 40 AM\u00a0 respectively\u00a0on the same day. What is the duration between the time at which A will overtake B and time at which overtake C?<\/p>\n a)\u00a01 hour<\/p>\n b)\u00a050 minutes<\/p>\n c)\u00a045 minutes<\/p>\n d)\u00a040 minutes<\/p>\n Question 20:\u00a0<\/b>Ananya travels equal distances at a speed of 5 kmph, 10 kmph and 15 kmph. She travels for a total of. What id the average speed of Ananya?<\/p>\n a)\u00a0a<\/p>\n b)\u00a0b<\/p>\n c)\u00a0c<\/p>\n d)\u00a0d<\/p>\n Free MBA Preparation YouTube Videos<\/a><\/p>\n Join 7K MBA Aspirants Telegram Group<\/a><\/p>\n Answers & Solutions:<\/strong><\/span><\/p>\n 1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Since 2020 is leap year there are 3 odd days between 2019 and 2021. 2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Since 2020 is leap year there are 3 odd days between 2019 and 2021. 3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n Since 2020 is leap year there are 3 odd days between 2019 and 2021. 4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Hour hand moves at a speed of 1\/2 degree\/min 5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Assuming time taken by Ram = t<\/p>\n Then the time taken by Shyam = t-45\/60 =t-0.75 (Since he started 45 minutes later)<\/p>\n Now, since the distance travelled by Ram and Shyam is same.<\/p>\n 5t=10(t-0.75)<\/p>\n t=2t-0.75*2<\/p>\n => t = 1.5 hours<\/p>\n 1.5 hours after 9 a.m. = 6)\u00a0Answer:\u00a020<\/b><\/p>\n Let the number of workers remaining during unlock phases be x. 7)\u00a0Answer:\u00a020<\/b><\/p>\n Let the number of workers remaining during unlock phases be x. 8)\u00a0Answer:\u00a020<\/b><\/p>\n Let the number of workers remaining during unlock phases be x. 9)\u00a0Answer:\u00a020<\/b><\/p>\n Let the number of workers remaining during unlock phases be x. 10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Assume the Then, (n+N) = (n-N) = d\/80<\/p>\n Adding both the 2n = d\/60 + d\/80<\/p>\n Hence, d\/n = Get 5 CMAT Mocks for just Rs. 299<\/a><\/p>\n Download CMAT Previous Papers Andriod App<\/a><\/p>\n 11)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Assume the Then, (n+N) = (n-N) = d\/80<\/p>\n Adding both the 2n = d\/60 + d\/80<\/p>\n Hence, d\/n = 12)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Since the watch loses 5 13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n Let the time taken by A be x hours => Time taken by B is x – 2 hours. 14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n At 4pm the angle between the minute and hour hand= 30×4 =120 degrees<\/p>\n Initial distance between min and hour hand = 120$^{\\circ\\ \\ }$<\/p>\n Relative velocity of minutes hand wrt to hour hand\u00a0= 11\/2\u00a0$^{\\circ\\ \\ }$ \/ min<\/p>\n Time taken for them to meet= 120\/(11\/2) = 240\/11 minutes<\/p>\n 15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n At 4pm the angle between the minute and hour hand= 30×4 =120 degrees<\/p>\n Initial distance between min and hour hand = 120$^{\\circ\\ \\ }$<\/p>\n Relative velocity of minutes hand wrt to hour hand\u00a0= 11\/2\u00a0$^{\\circ\\ \\ }$ \/ min<\/p>\n Time taken for them to meet= 120\/(11\/2) = 240\/11 minutes<\/p>\n 16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n At 4pm the angle between the minute and hour hand= 30×4 =120 degrees<\/p>\n Initial distance between min and hour hand = 120$^{\\circ\\ \\ }$<\/p>\n Relative velocity of minutes hand wrt to hour hand\u00a0= 11\/2\u00a0$^{\\circ\\ \\ }$ \/ min<\/p>\n Time taken for them to meet= 120\/(11\/2) = 240\/11 minutes<\/p>\n 17)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Time taken by A to complete the marathon: 5hrs<\/p>\n Time taken by B to complete the marathon: 7hrs<\/p>\n Time taken by C to complete the marathon: 10hrs<\/p>\n They started the marathon at 10:10 AM, 9:30 AM and 7: 40 AM respectively<\/p>\n Let’s say A meet B after he travelled x minutes, B would have travelled\u00a0x+40 minutes.<\/p>\n Now, x\/x+40=5\/7<\/p>\n 7x= 5x+200<\/p>\n x=100 minutes.<\/p>\n Similarly,<\/p>\n Let’s say A meet C after he travelled y minutes, C would have travelled y+150 minutes.<\/p>\n y\/(y+150)= 5\/10<\/p>\n y=150<\/p>\n y-x=50 minutes<\/p>\n Option B<\/p>\n 18)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Time taken by A to complete the marathon: 5hrs<\/p>\n Time taken by B to complete the marathon: 7hrs<\/p>\n Time taken by C to complete the marathon: 10hrs<\/p>\n They started the marathon at 10:10 AM, 9:30 AM and 7: 40 AM respectively<\/p>\n Let’s say A meet B after he travelled x minutes, B would have travelled\u00a0x+40 minutes.<\/p>\n Now, x\/x+40=5\/7<\/p>\n 7x= 5x+200<\/p>\n x=100 minutes.<\/p>\n Similarly,<\/p>\n Let’s say A meet C after he travelled y minutes, C would have travelled y+150 minutes.<\/p>\n y\/(y+150)= 5\/10<\/p>\n y=150<\/p>\n y-x=50 minutes<\/p>\n Option B<\/p>\n 19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n Time taken by A to complete the marathon: 5hrs<\/p>\n Time taken by B to complete the marathon: 7hrs<\/p>\n Time taken by C to complete the marathon: 10hrs<\/p>\n They started the marathon at 10:10 AM, 9:30 AM and 7: 40 AM respectively<\/p>\n Let’s say A meet B after he travelled x minutes, B would have travelled\u00a0x+40 minutes.<\/p>\n Now, x\/x+40=5\/7<\/p>\n 7x= 5x+200<\/p>\n x=100 minutes.<\/p>\n Similarly,<\/p>\n Let’s say A meet C after he travelled y minutes, C would have travelled y+150 minutes.<\/p>\n y\/(y+150)= 5\/10<\/p>\n y=150<\/p>\n y-x=50 minutes<\/p>\n Option B<\/p>\n 20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n A is the correct answer.<\/p>\n
\nfrom A at a speed of 5km\/hr, reaches B, and returns to A at the same speed. Shyam
\nstarts at 9:45 am from A at a speed of 10kmph, reaches B and comes back to A at the
\nsame speed. At what time does Shyam overtake Ram?<\/p>\n
\nseconds to climb up the escalator and 80 seconds to climb down
\nthe same escalator. Find out how much would it take to climb the
\nescalator if it is not moving. Assume the speed of the person is
\nmore than that of escalator.<\/p>\n
\nseconds to climb up the escalator and 80 seconds to climb down
\nthe same escalator. Find out how much would it take to climb the
\nescalator if it is not moving. Assume the speed of the person is
\nmore than that of escalator.<\/p>\n
\npm on Wednesday. At what time whould it show the correct time
\nagain?<\/p>\n
\nSo, in 2021 it will fall on Thursday.<\/p>\n
\nSo, in 2021 it will fall on Thursday.<\/p>\n
\nSo, in 2021 it will fall on Thursday.<\/p>\n
\nThe minute hand moves at a speed of 6 degrees\/min
\nAt 4:00, the hour hand is 120 degrees with the minute hand
\nin 45 min Minute hand covers 11\/2*45 = 247.5 degrees
\n.’. The angle between the minute hand and the hour hand is 247.5 -120= 127.5 degrees<\/p>\n
\n10:30 a.m.<\/p>\n
\nThe average number of workers working per day during the unlock phase = (0.2x + 0.4x + 0.6x + 0.8x)\/4 = 0.5x
\nLet the number of workers before lockdown be = y.
\nThe average number of workers per day before lockdown = y.
\nIt is given 0.5x = 40% of y
\n=> 0.5x = .4y
\n=> x = .8y
\nHence the number of workers who migrated = y – 0.8y = 0.2y
\nPercentage of workers who migrated = $\\frac{0.2y \\times 100}{y}$ = 20%<\/p>\n
\nThe average number of workers working per day during the unlock phase = (0.2x + 0.4x + 0.6x + 0.8x)\/4 = 0.5x
\nLet the number of workers before lockdown be = y.
\nThe average number of workers per day before lockdown = y.
\nIt is given 0.5x = 40% of y
\n=> 0.5x = .4y
\n=> x = .8y
\nHence the number of workers who migrated = y – 0.8y = 0.2y
\nPercentage of workers who migrated = $\\frac{0.2y \\times 100}{y}$ = 20%<\/p>\n
\nThe average number of workers working per day during the unlock phase = (0.2x + 0.4x + 0.6x + 0.8x)\/4 = 0.5x
\nLet the number of workers before lockdown be = y.
\nThe average number of workers per day before lockdown = y.
\nIt is given 0.5x = 40% of y
\n=> 0.5x = .4y
\n=> x = .8y
\nHence the number of workers who migrated = y – 0.8y = 0.2y
\nPercentage of workers who migrated = $\\frac{0.2y \\times 100}{y}$ = 20%<\/p>\n
\nThe average number of workers working per day during the unlock phase = (0.2x + 0.4x + 0.6x + 0.8x)\/4 = 0.5x
\nLet the number of workers before lockdown be = y.
\nThe average number of workers per day before lockdown = y.
\nIt is given 0.5x = 40% of y
\n=> 0.5x = .4y
\n=> x = .8y
\nHence the number of workers who migrated = y – 0.8y = 0.2y
\nPercentage of workers who migrated = $\\frac{0.2y \\times 100}{y}$ = 20%<\/p>\n
\nspeed of person
\nis n and that of
\nthe escalator is
\nN<\/p>\n
\nd\/60<\/p>\n
\nequation,<\/p>\n
\n480\/7 = 68.5
\nseconds<\/p>\n
\nspeed of person
\nis n and that of
\nthe escalator is
\nN<\/p>\n
\nd\/60<\/p>\n
\nequation,<\/p>\n
\n480\/7 = 68.5
\nseconds<\/p>\n
\nseconds every minute
\nIt loses 5 minutes every
\nhour.
\nThe correct time would be
\nwhen it loses 12 hours=
\n12*60 minutes
\nTime taken= (12*60)\/ 5=
\n144 hours= 6days.
\nThe clock would show
\ncorrect time at 10 pm
\nTuesday.<\/p>\n
\n1\/x +1\/x-2 = 7\/24
\n48x- 48= 7×2-14x
\n7×2- 62x+48=0
\nx=8 annd 6\/7
\nA takes 8 houre as A must be greater than 2.<\/p>\n