{"id":44199,"date":"2021-01-19T14:08:08","date_gmt":"2021-01-19T08:38:08","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=44199"},"modified":"2021-01-19T14:08:08","modified_gmt":"2021-01-19T08:38:08","slug":"ssc-chsl-arithmetic-practice-questions","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/ssc-chsl-arithmetic-practice-questions\/","title":{"rendered":"SSC CHSL Arithmetic Practice Questions"},"content":{"rendered":"

Arithmetic Questions for SSC CHSL Exam<\/strong><\/h1>\n

Download Arithmetic Questions for SSC CHSL exam 2020. Most important arithmetic practice questions based on asked questions in previous exam papers for SSC CHSL. Start practice and download the questions along with solutions. It will be helpful to crack the SSC CHSL exam 2020.<\/p>\n

Download SSC CHSL Arithmetic Questions <\/a><\/p>\n

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Question 1:\u00a0<\/b>Which two signs should be interchanged in the following equation to make it correct?
\n$5 \\times 15 \\div 7 – 20 + 4 = 77$<\/p>\n

a)\u00a0$(+\u00a0 and\u00a0 -)$<\/p>\n

b)\u00a0$(\\div\u00a0 and\u00a0 +)$<\/p>\n

c)\u00a0$(-\u00a0 and\u00a0 \\times)$<\/p>\n

d)\u00a0$(+\u00a0 and\u00a0 \\times)$<\/p>\n

Question 2:\u00a0<\/b>Which two signs should be interchanged in the following equation to make it correct?
\n$405 + 27 \\times 40 – 308 \\div 22 = 314$<\/p>\n

a)\u00a0$+\u00a0 and\u00a0 \\div$<\/p>\n

b)\u00a0$\\times\u00a0 and\u00a0 +$<\/p>\n

c)\u00a0$\\div\u00a0 and\u00a0 \\times$<\/p>\n

d)\u00a0$+\u00a0 and\u00a0 -$<\/p>\n

Question 3:\u00a0<\/b>Three persons A, B and C have different amounts of rupees with them. If C takes \u20b911 from A, C will have equal amount as B has. B and C together have total \u20b9111. How many rupees does C have?<\/p>\n

a)\u00a060<\/p>\n

b)\u00a065<\/p>\n

c)\u00a050<\/p>\n

d)\u00a070<\/p>\n

Question 4:\u00a0<\/b>Which two signs should be interchanged in the following equation to make it correct?
\n$211 \\times 14 + 627 \\div 33 – 17 = 520$<\/p>\n

a)\u00a0$+\u00a0 and\u00a0 -$<\/p>\n

b)\u00a0$+\u00a0 and\u00a0 \\div$<\/p>\n

c)\u00a0$\\div\u00a0 and\u00a0 \\times$<\/p>\n

d)\u00a0$\\times\u00a0 and\u00a0 -$<\/p>\n

Question 5:\u00a0<\/b>By interchanging the given two signs which of the following equation will be correct?
\n$+\u00a0 and\u00a0 -$<\/p>\n

a)\u00a0$13 – 14 \\times 3 + 7 = 48$<\/p>\n

b)\u00a0$9 + 16 – 11 \\times 2 = 3$<\/p>\n

c)\u00a0$11 \\times 3 + 5 – 2 = 36$<\/p>\n

d)\u00a0$16 \\times 4 + 11 – 10 = 65$<\/p>\n

Question 6:\u00a0<\/b>By interchanging which two signs the equation will be correct?
\n$11 + 9 – 4 \\times 12 \\div 6 = 32$<\/p>\n

a)\u00a0$\\div\u00a0 and\u00a0 -$<\/p>\n

b)\u00a0$-\u00a0 and\u00a0 +$<\/p>\n

c)\u00a0$\\times\u00a0 and\u00a0 +$<\/p>\n

d)\u00a0$\\times\u00a0 and\u00a0 \\div$<\/p>\n

Question 7:\u00a0<\/b>After interchanging the given two signs, what will be the value of $9 + 143 \\div 13 \\times 11 – 160 = ?$
\n$\\times\u00a0 and\u00a0 \\div$<\/p>\n

a)\u00a018<\/p>\n

b)\u00a0-32<\/p>\n

c)\u00a0-17<\/p>\n

d)\u00a028<\/p>\n

Question 8:\u00a0<\/b>If the given two numbers are interchanged, which of the following equations will become correct?
\n3 and 5<\/p>\n

a)\u00a0$6 + 5 \\times 2 – 3 = 7$<\/p>\n

b)\u00a0$3 + 4 – 1 \\times 5 = 2$<\/p>\n

c)\u00a0$3 + 5 – 4 \\times 2 = -1$<\/p>\n

d)\u00a0$1 + 9 \\div 3 + 5 = 9$<\/p>\n

Question 9:\u00a0<\/b>If the two signs, ‘$\\times$ and $\\div$’ are interchanged, which of the following equations will be correct?<\/p>\n

a)\u00a0$14 + 62 \\times 13 \\div 31 = 38$<\/p>\n

b)\u00a0$14 + 9 \\div 24 \\times 3 = 86$<\/p>\n

c)\u00a0$63 + 59 \\div 4 \\times 8 = 171$<\/p>\n

d)\u00a0$11 \\times 12 \\div 48 + 6 = 40$<\/p>\n

Question 10:\u00a0<\/b>After interchanging the given two signs, what will be the value of $11 \\div 9 – 63 + 7 \\times 2$ ?
\n$\\div\u00a0 and\u00a0 +$<\/p>\n

a)\u00a02<\/p>\n

b)\u00a05<\/p>\n

c)\u00a0-4<\/p>\n

d)\u00a0-2<\/p>\n

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Question 11:\u00a0<\/b>By interchanging the given two signs which of the following equation will be correct?
\n$\\times$ and $+$<\/p>\n

a)\u00a0$4 + 9 \\times 11 \\div 3 = 37$<\/p>\n

b)\u00a0$11 \\times 6 \\div 18 + 54 = 29$<\/p>\n

c)\u00a0$13 – 12 \\times 5 + 11 = 46$<\/p>\n

d)\u00a0$6 \\times 11 + 13 \\div 11 = 17$<\/p>\n

Question 12:\u00a0<\/b>After interchanging the given signs, what will be the value of $16 + 19 \\times 51 \\div 153 – 12 ?$
\n$\\times\u00a0 and\u00a0 \\div$<\/p>\n

a)\u00a063<\/p>\n

b)\u00a051<\/p>\n

c)\u00a061<\/p>\n

d)\u00a057<\/p>\n

Question 13:\u00a0<\/b>By interchanging which two numbers the equation will be correct?
\n$9 – 2 \\times 4 \\div 6 = -3$<\/p>\n

a)\u00a06 and 9<\/p>\n

b)\u00a06 and 2<\/p>\n

c)\u00a04 and 9<\/p>\n

d)\u00a02 and 4<\/p>\n

Question 14:\u00a0<\/b>By interchanging which two signs the equation will be correct?
\n$19 + 63 \\div 7 – 8 \\times 12 = 79$<\/p>\n

a)\u00a0$-\u00a0 and\u00a0 \\times$<\/p>\n

b)\u00a0$\\times\u00a0 and\u00a0 +$<\/p>\n

c)\u00a0$\\div\u00a0 and\u00a0 -$<\/p>\n

d)\u00a0$\\times\u00a0 and\u00a0 \\div$<\/p>\n

Question 15:\u00a0<\/b>By interchanging which two signs the equation will be correct?
\n$6 + 9 \\times 2 – 3 \\div 4 = 8$<\/p>\n

a)\u00a0$-\u00a0 and\u00a0 \\div$<\/p>\n

b)\u00a0$-\u00a0 and\u00a0 +$<\/p>\n

c)\u00a0$+\u00a0 and\u00a0 \\div$<\/p>\n

d)\u00a0$\\div\u00a0 and\u00a0 \\times$<\/p>\n

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Question 16:\u00a0<\/b>By interchanging which two numbers, the value obtained after solving the given equation will be \u201913\u2019?
\n$7 + 8 \\div 4 \\times 3$<\/p>\n

a)\u00a08 and 3<\/p>\n

b)\u00a08 and 4<\/p>\n

c)\u00a07 and 3<\/p>\n

d)\u00a03 and 4<\/p>\n

Question 17:\u00a0<\/b>By interchanging which two signs the equation will be correct?
\n$11 + 16 \\times 12 \\div 4 – 2 = 21$<\/p>\n

a)\u00a0$\\times\u00a0 and\u00a0 -$<\/p>\n

b)\u00a0$-\u00a0 and\u00a0 +$<\/p>\n

c)\u00a0$\\div\u00a0 and\u00a0 +$<\/p>\n

d)\u00a0$\\div\u00a0 and\u00a0 \\times$<\/p>\n

Question 18:\u00a0<\/b>By interchanging which two signs the equation will be correct?
\n$9 \\times 11 \\div 31 + 62 – 13 = 18$<\/p>\n

a)\u00a0$\\times\u00a0 and\u00a0 \\div$<\/p>\n

b)\u00a0$-\u00a0 and\u00a0 \\times$<\/p>\n

c)\u00a0$\\div\u00a0 and\u00a0 +$<\/p>\n

d)\u00a0$+\u00a0 and\u00a0 \\times$<\/p>\n

Question 19:\u00a0<\/b>After interchanging the given two numbers, what will be the value of $3 + 2 \\div 1 \\times 4 – 7$?
\n4 and 7<\/p>\n

a)\u00a010<\/p>\n

b)\u00a012<\/p>\n

c)\u00a013<\/p>\n

d)\u00a011<\/p>\n

Question 20:\u00a0<\/b>After interchanging which two numbers, the value of given equation will be \u20184\u2019?
\n6 + 3 $\\div$ 9 $\\times$ 7 – 5<\/p>\n

a)\u00a07 and 6<\/p>\n

b)\u00a03 and 5<\/p>\n

c)\u00a05 and 6<\/p>\n

d)\u00a09 and 5<\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Trial and error method.<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

if we interchange $+\u00a0 and\u00a0 -$\u00a0 answer would be 2952<\/p>\n

if we interchange $+\u00a0 and\u00a0 \\div$ answer would be 20.71<\/p>\n

if we interchange\u00a0 $\\div\u00a0 and\u00a0 \\times$ answer would be 20689.07<\/p>\n

if we interchange\u00a0\u00a0$\\times\u00a0 and\u00a0 -$ answer would be\u00a0 520<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

By interchanging ‘$+$’ and ‘$-$’<\/p>\n

(A) :\u00a0$13 – 14 \\times 3 + 7 = 48$<\/p>\n

L.H.S. $\\equiv13+14\\times3-7$<\/p>\n

=\u00a0$13+42-7=48=$ R.H.S.<\/p>\n

=> Ans – (A)<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

if we interchange 3 and 5 then-<\/p>\n

6 + 3 $\\times$ 2 – 5<\/p>\n

= 6+6-5<\/p>\n

=7<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

If we interchange\u00a0‘$\\times$ and $\\div$’ then-<\/p>\n

14 + 9 $ \\times $ 24 $ \\div $ 3<\/p>\n

= 14+72<\/p>\n

= 86<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$11 \\div 9 – 63 + 7 \\times 2$<\/p>\n

=\u00a0$11 + 9 – 63\u00a0\\div 7 \\times 2$<\/p>\n

=\u00a0 $11 + 9 – 9 \\times 2$<\/p>\n

= 11 – 9 =2<\/p>\n

So , the answer would be option a )2.<\/p>\n

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11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

On interchanging the two signs $ +$ and $\\times $<\/p>\n

we get the equation as<\/p>\n

$ 11+6 \\div 18\\times 54 $<\/p>\n

or $11+1\\div 3\\times 54 =29$<\/p>\n

$ 29=29 $ which is true<\/p>\n

12)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

On interchanging the signs $\\times and \\div$<\/p>\n

we get the equation as<\/p>\n

$ 16+19\\div 51 \\times 153 -12 $<\/p>\n

or $ 16+19 \\times 3-12$<\/p>\n

16+57-12=61<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$9 – 2 \\times 4 \\div 6 = -3$<\/p>\n

By option (2) 6 and 2, on interchanging we get,\u00a0$9 – 6 \\times 4 \\div 2 = -3$<\/p>\n

Using BODMAS rule, we get, $9 – 6 \\times 2 = -3$<\/p>\n

9 – 12 = -3<\/p>\n

-3 = -3<\/p>\n

Hence LHS = RHS.<\/p>\n

Hence our answer.<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

For this question we have to go by option, so when we replace $-\u00a0 and\u00a0 \\times$ as per option A,<\/p>\n

$19 + 63 \\div 7 \\times 8 – 12 = 79$<\/p>\n

$19 + {\\frac{63}{7}}\\times 8 – 12 = 79$<\/p>\n

$19 + {9\\times8} – 12 = 79$<\/p>\n

$19 + 72 – 12 = 79$<\/p>\n

$79 = 79$<\/p>\n

Therefore option A is the answer.<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$6 + 9 \\times 2 – 3 \\div 4 = 8$<\/p>\n

this results in a fraction so in order to get a whole number which is 8 it is important to place divide symbol such that a whole number is obtained<\/p>\n

now if\u00a0\u00a0$-\u00a0 and\u00a0 \\div$ is interchanged 9 gets divided by 3 thus resulting in a whole number<\/p>\n

$6 + 9 \\times 2\\div 3-\u00a0 4 $ (using BODMAS rule)<\/p>\n

$ 6 + \\frac{\u00a09 \\times 2}{ 3} – 4 $<\/p>\n

= 6+ 6 – 4 = 8<\/p>\n

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16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

going by the options<\/p>\n

A) 8 and 3<\/p>\n

$7 + 3 \\div 4 \\times 8$=\u00a0 $7 + \\frac{8}{4}\\times 3$ = 7 + 6 = 13 (Option A is correct )<\/p>\n

B) 8 and 4<\/p>\n

$7 + 4 \\div 8 \\times 3$ =\u00a0\u00a0$7 + \\frac{4}{8}\\times 3$\u00a0= 7 + $\\frac{3}{2}$= $\\frac{17}{2}$\u00a0 \u00a0(option B is incorrect)<\/p>\n

c) 7 and 3<\/p>\n

$3 + 8 \\div 4 \\times 7$ = 3+$\u00a0\\frac{8}{4}\\times 7$ = 3 +14 = 17\u00a0(option C is incorrect)<\/p>\n

d) 3 and 4<\/p>\n

$7 + 8 \\div 3 \\times 4$ = 7+\u00a0$\u00a0\\frac{8}{3}\\times 4$ = 7 +$\u00a0\\frac{32}{3}$ =\u00a0$\u00a0\\frac{53}{3}$\u00a0\u00a0(option D is incorrect)<\/p>\n

17)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given, 11+16 $\\times$ 12 $ $ $\\div$ 4 $ $ – 2 = 21<\/p>\n

These type of questions can be quickly solved by checking options.<\/p>\n

So,from the options we get option A would be correct.<\/p>\n

On solving,11+16-12 $\\div $ 4 $ $ $\\times$2 $ $<\/p>\n

$\\Rightarrow$\u00a0 27 – 6 = 21.<\/p>\n

18)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

19)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

given \u00a03 + 2 \u00f7 1 \u00d7 4 – 7<\/p>\n

on interchanging 4 and 7<\/p>\n

BODMAS rule{ brackets > of > division > multiplication > addition > subtraction }<\/p>\n

we get\u00a0\u00a03 + 2 \u00f7 1 \u00d7 7 – 4 ( using BODMAS rule)<\/p>\n

3+$\\frac{2}{1} \\times$ 7 -4 = 3 + 2 $\\times$ 7\u00a0 – 4 = 3 + 14 – 4 = 13<\/p>\n

20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

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 <\/p>\n

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Arithmetic Questions for SSC CHSL Exam Download Arithmetic Questions for SSC CHSL exam 2020. Most important arithmetic practice questions based on asked questions in previous exam papers for SSC CHSL. Start practice and download the questions along with solutions. It will be helpful to crack the SSC CHSL exam 2020. Take a free SSC CHSL […]<\/p>\n","protected":false},"author":53,"featured_media":44201,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[9,378],"tags":[2356,1625,358],"class_list":{"0":"post-44199","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ssc","8":"category-ssc-chsl","9":"tag-arithmetic","10":"tag-maths","11":"tag-ssc-chsl"},"better_featured_image":{"id":44201,"alt_text":"SSC CHSL Arithmetic Questions","caption":"SSC CHSL Arithmetic Questions","description":"SSC CHSL Arithmetic 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