{"id":43998,"date":"2021-01-07T11:17:58","date_gmt":"2021-01-07T05:47:58","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=43998"},"modified":"2021-01-07T11:23:34","modified_gmt":"2021-01-07T05:53:34","slug":"top-20-rrb-ntpc-time-and-work-questions","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/top-20-rrb-ntpc-time-and-work-questions\/","title":{"rendered":"Top-20 RRB NTPC Time And Work Questions"},"content":{"rendered":"

RRB NTPC Time And Work Questions:<\/strong><\/h1>\n

Download Top-20 Time and Work questions for RRB NTPC exam. Most important Time and Work questions based on asked questions in previous exam papers for RRB NTPC.<\/p>\n

Download Top -20 RRB NTPC Time And Work Questions <\/a><\/p>\n

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Question 1:\u00a0<\/b>A and B can complete a task in 20 days, B and C can complete it in 30 days while C and A can do the same task together in 24 days. How many days will each of B and C take to complete the task individually?<\/p>\n

a)\u00a050 and 54<\/p>\n

b)\u00a054 and 72<\/p>\n

c)\u00a048 and 80<\/p>\n

d)\u00a056 and 64<\/p>\n

Question 2:\u00a0<\/b>A and B can complete a task in 40 days, B and C can complete it in 30 days while C and A\u00a0can complete the same task together in 24 days. How many days will each of A, B and C take to complete the task individually?<\/p>\n

a)\u00a048, 96 and 32<\/p>\n

b)\u00a032, 48 and 96<\/p>\n

c)\u00a060, 120 and 40<\/p>\n

d)\u00a040, 120 and 60<\/p>\n

Question 3:\u00a0<\/b>A and B can complete a task together in 35 days. If A works alone and completes 5\/7th of the task and then leaves the rest for B to complete by herself, it will take a total of 90 days to complete the task. How many days would it take by A, the more efficient among the duo, to complete the entire work by herself?<\/p>\n

a)\u00a040<\/p>\n

b)\u00a045<\/p>\n

c)\u00a048<\/p>\n

d)\u00a042<\/p>\n

Question 4:\u00a0<\/b>A and B can do a piece of work together in 9 days while A alone can do it in 15 days. They start working together but B leaves 3 days before the completion of the work. For how many days did A and B work together?<\/p>\n

a)\u00a07.2<\/p>\n

b)\u00a07.5<\/p>\n

c)\u00a08.1<\/p>\n

d)\u00a08<\/p>\n

Question 5:\u00a0<\/b>A and B can do a piece of work together in 15 days while A alone can do it in 25 days. They start working together but B leaves 5 days before the completion of the work. For how many days did A and B work together?<\/p>\n

a)\u00a010<\/p>\n

b)\u00a013<\/p>\n

c)\u00a09<\/p>\n

d)\u00a012<\/p>\n

Question 6:\u00a0<\/b>A and B take part in a 100 m race. A runs at 5 km\/hr. A gives B a start of 8 m and still beats him by 8 seconds. Find the speed of B.<\/p>\n

a)\u00a04.14 km\/hr<\/p>\n

b)\u00a04.20 km\/hr<\/p>\n

c)\u00a05.15 km\/hr<\/p>\n

d)\u00a04.25 km\/hr<\/p>\n

Question 7:\u00a0<\/b>A and B together can complete a task in 12 days. However, if A works alone, completes
\nhalf the job and leaves and then B works alone and completes the rest of the work, it takes 25 days in all to complete the work. If B is more efficient than A, how many days would it have taken B to do the work by herself?<\/p>\n

a)\u00a018<\/p>\n

b)\u00a022<\/p>\n

c)\u00a020<\/p>\n

d)\u00a015<\/p>\n

Question 8:\u00a0<\/b>A and can complete a task in 12 days. However, A had to leave a few days before the
\ntask was completed and hence it took 16 days in all to complete the task. If A alone could complete the work in 21 days, how many days before the work getting over did A leave?<\/p>\n

a)\u00a07<\/p>\n

b)\u00a05<\/p>\n

c)\u00a09<\/p>\n

d)\u00a03<\/p>\n

Question 9:\u00a0<\/b>A ball is thrown upward in vacuum at 49 m\/sec. The time taken by the ball to reach the highest point is<\/p>\n

a)\u00a02.5 Seconds<\/p>\n

b)\u00a07.5 Seconds<\/p>\n

c)\u00a05 Seconds<\/p>\n

d)\u00a015 Seconds<\/p>\n

Question 10:\u00a0<\/b>A balloon is hovering at a height of 200 m above. A man in a boat on a lake observes it at an elevation of $45^\\circ$. 100 seconds later, he sees it at an angle of elevation of $30^\\circ$. What is the speed of the boat ?<\/p>\n

a)\u00a01.5 m\/s<\/p>\n

b)\u00a02.2 m\/s<\/p>\n

c)\u00a02 m\/s<\/p>\n

d)\u00a01.8 m\/s<\/p>\n

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Question 11:\u00a0<\/b>A clock is set to the right time at 4:00 AM on Thursday. If it gains 20 seconds in every 3 hours, then what is the time shown on the clock at 8:30 PM on Friday night?<\/p>\n

a)\u00a08 hours 30 minutes 30 seconds PM<\/p>\n

b)\u00a09 hours 34 minutes PM<\/p>\n

c)\u00a08 hours 34 minutes PM<\/p>\n

d)\u00a08 hours 34 minutes 30 seconds PM<\/p>\n

Question 12:\u00a0<\/b>A cyclist covers 500 m in 5 minutes. What distance (in km) would the cyclist cover in half an hour if he travels at the same speed ?<\/p>\n

a)\u00a03000<\/p>\n

b)\u00a03<\/p>\n

c)\u00a06<\/p>\n

d)\u00a030<\/p>\n

Question 13:\u00a0<\/b>A cyclist moving on a circular track of radius 100 meters completes one revolution in 2 minutes. What is the approximate speed of the cyclist?<\/p>\n

a)\u00a0200 m\/minute<\/p>\n

b)\u00a0314 m\/minute<\/p>\n

c)\u00a0300 m\/minute<\/p>\n

d)\u00a0900 m\/minute<\/p>\n

Question 14:\u00a0<\/b>A does a work in 10 days and B does the same work in 15 days. In how many days they together will complete the same work ?<\/p>\n

a)\u00a05 days<\/p>\n

b)\u00a06 days<\/p>\n

c)\u00a08 days<\/p>\n

d)\u00a010 days<\/p>\n

Question 15:\u00a0<\/b>A farmer travelled a distance of 61 km. in a 9 hours. He travelled partly on foot at the rate of 4 km. per hour and partly on bicycle at the rate of 9 km. per hour. The distance travelled on foot is:<\/p>\n

a)\u00a017 km.<\/p>\n

b)\u00a016 km.<\/p>\n

c)\u00a015 km.<\/p>\n

d)\u00a014 km.<\/p>\n

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Question 16:\u00a0<\/b>A flight covering a distance of 1200 kin could reduce the travel time by 30 minutes, due to an additive tailwind that increases the average speed by 120 km\/hr. What was the duration of the flight in hours?<\/p>\n

a)\u00a02.2 hours<\/p>\n

b)\u00a01.9 hours<\/p>\n

c)\u00a01.8 hours<\/p>\n

d)\u00a02 hours<\/p>\n

Question 17:\u00a0<\/b>A goods train runs at a speed of 72 km\/hr and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?<\/p>\n

a)\u00a0230 m<\/p>\n

b)\u00a0240 m<\/p>\n

c)\u00a0260 m<\/p>\n

d)\u00a0270 m<\/p>\n

Question 18:\u00a0<\/b>A hare spots a dog 100 m away and starts running away from it at 12 km\/h. One minute later,the dog gives a chase at 16 km\/h speed. At what distance from the spot where the hare took flight and the dog catch the hare?<\/p>\n

a)\u00a0900 m<\/p>\n

b)\u00a01000 m<\/p>\n

c)\u00a0950 m<\/p>\n

d)\u00a01100 m<\/p>\n

Question 19:\u00a0<\/b>A man can row his boat at speed of 4 km\/hr and he finds that the time taken rowing upstream is double to that taken downstream. Find the speed of the stream (in km\/hr).<\/p>\n

a)\u00a01.5<\/p>\n

b)\u00a01.3<\/p>\n

c)\u00a02<\/p>\n

d)\u00a01<\/p>\n

Question 20:\u00a0<\/b>A man completes a journey in 8 hours. He covers half the distance at 40 km\/hr and the rest at 60 km\/hr. the length of the journey is :<\/p>\n

a)\u00a0450 km<\/p>\n

b)\u00a0420 km<\/p>\n

c)\u00a0384 km<\/p>\n

d)\u00a0None of the above<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

(A+ B)’s 1 day’s work\u00a0 = $\\frac{1}{20}$<\/p>\n

(B + C)’s 1 day’s work =\u00a0$\\frac{1}{30}$<\/p>\n

(C + A)’s 1 day’s work =\u00a0$\\frac{1}{24}$<\/p>\n

On adding,<\/p>\n

2(A + B + C)’s 1 day’s work<\/p>\n

=\u00a0$\\frac{1}{20}$ +$\\frac{1}{30}$+$\\frac{1}{24}$<\/p>\n

\u00a0<\/span>
\n= $\\frac{6+4+5}{120}$= $\\frac{15}{120}$<\/p>\n

\u2234\u2234 (A + B + C)’s 1 day’s work<\/p>\n

=\u00a0$\\frac{15}{240}$<\/p>\n

\u2234\u2234 B’s 1 day’s work<\/p>\n

=$\\frac{15}{240}$\u00a0–\u00a0$\\frac{1}{24}$ \u00a0 =\u00a0$\\frac{5}{240}$ =\u00a0$\\frac{1}{48}$<\/p>\n

C’s 1 day’s work<\/p>\n

= -$\\frac{15}{240}$\u00a0– $\\frac{1}{20}$=
\n$\\frac{3}{240}$ =\u00a0$\\frac{1}{80}$<\/p>\n

so, shares =\u00a048 and 80<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Total work that can be completed by A and B in one day = $\\frac{1}{40}$
\nTotal work that can be completed by\u00a0A and B in one day = $\\frac{1}{30}$
\nTotal work that can be completed by\u00a0A and B in one day = $\\frac{1}{24}$<\/p>\n

Total number of days each can complete in one day = $\\frac{1}{40} +\u00a0\\frac{1}{30} + \\frac{1}{24}$<\/p>\n

3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Fraction of work completed by A is not mentioned.<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Let the total work be 75 units.<\/p>\n

($\\because$ LCM of 15 and 25 is 75.)<\/p>\n

Efficiency of A and B = 75\/15 = 5<\/p>\n

Efficiency of A = 75\/25 = 3<\/p>\n

B leaves 5 days before the completion of the work so A works 5 days extra so,<\/p>\n

5 days work of A = efficiency $\\times$ days = 3 $\\times$ 5 = 15<\/p>\n

Remaining work = 75 – 15 = 60 units<\/p>\n

60 units work done by A and B\u00a0so time taken by together = 60\/5 = 12 days<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

A’s speed$=(5\\times\\frac{5}{18})m\/\\sec=\\frac{25}{18}m\/\\sec.$<\/p>\n

Time taken by A to cover 100 m\u00a0$=(100\\times\\frac{18}{25})\\sec=72\\sec.$<\/p>\n

Time taken by B to cover 92 m = (72 + 8) = 80 sec.<\/p>\n

B’s speed\u00a0$=\\frac{92}{80}\\times\\frac{18}{5}\\ kmph=4.14kmph.$<\/p>\n

A is correct choice.<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let A took ‘A’ days to complete the task and B took ‘B’ days<\/p>\n

then Total time taken =\u00a0$\\frac{AB}{A+B}$=12 ———— Equation (i)<\/p>\n

However, A alone taken time = ‘A’ days will be\u00a0$\\frac{A}{2}$ days.<\/p>\n

Same for B alone taken time = ‘B’ days will be $\\frac{B}{2}$ days.<\/p>\n

Total Time =\u00a0$\\frac{A}{2}$ +\u00a0$\\frac{B}{2}$ = 25 days.<\/p>\n

A+B= 50 days ——————– Equation (ii)<\/p>\n

By (i) and (ii) equation AB = 600 —————– Equation (iii)<\/p>\n

A,B =20,30<\/p>\n

Because B is more efficient takes less days 80.<\/p>\n

A,B,C = 2,8,8<\/p>\n

8)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

initial velocity=u=49 m\/s<\/p>\n

final velocity=v=0 m\/s<\/p>\n

acceleration due to gravity=g=-9.8 $m\/s^{2}$<\/p>\n

we know, v=u + gt<\/p>\n

=>t=-u\/t<\/p>\n

t=5 s<\/p>\n

10)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Free RRB Preparation Videos<\/a><\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given that a cyclist covers a distance of 500 m in 5 minutes (300 sec) then speed of the cyclist is given by,<\/p>\n

s = $\\frac{500}{5 \\times 60}$<\/p>\n

s = $\\frac{5}{3}$<\/p>\n

Total distance the cyclist would cover in half an hour (1800 sec) if he travels at the same speed is given by,<\/p>\n

d =\u00a0$\\frac{5}{3} \\times 1800 $ m<\/p>\n

d = 3000 m (or) 3km<\/p>\n

Hence, option B is the correct answer.<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Speed of cyclist = distance covered by cyclist in one round\/time taken for one round<\/p>\n

distance covered in one round= 2\u03c0r= 628 m<\/p>\n

thus, speed of cyclist= 628\/2= 314 m\/minute<\/p>\n

14)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Given<\/p>\n

A does one work in = 10 days<\/p>\n

so in one day A completes $\\frac{1}{10}$ work<\/p>\n

similarly B does one work in 15 days<\/p>\n

so in one day B completes $\\frac{1}{15}$ work<\/p>\n

so if they work together than the time required by them is<\/p>\n

$\\frac{1}{10} + \\frac{1}{15}$<\/p>\n

= $\\frac{1}{6}$<\/p>\n

hence they complete one work together in 6 days<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

If t is the time travelled on foot, then 9-t is the time taken on the bicycle.<\/p>\n

The distance travelled on foot + the distance travelled on bicycle=total distance travelled<\/p>\n

thus, 4t + (9-t)9=61 , distance travelled=Speed x time<\/p>\n

On solving we get t=4<\/p>\n

So the distance travelled on foot=4×4=16 km<\/p>\n

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16)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

17)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Trains speed =$72\\ \\frac{km}{h}=\\frac{72000}{3600}=20\\ \\frac{m}{s}.$<\/p>\n

So, in 26 sec , it will cover =$26\\times\\ 20\\ m=520\\ m.$<\/p>\n

It covers platform’s length and train’s length in 26 secs.<\/p>\n

So, Trains length=\u00a0$\\left(520-250\\right)=270\\ m.$<\/p>\n

D is correct choice.<\/p>\n

18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Hare spots a dog at a distance of 100 m<\/p>\n

Distance covered by hare in 1 min, $ d =12 km\/hr \\times \\frac{1}{60} $<\/p>\n

$ d = \\frac{1}{5} km $<\/p>\n

= 200 m<\/p>\n

Now dog has to cover total 300 m (100 + 200)<\/p>\n

Time taken by dog to cover total 300 m ,<\/p>\n

Relative speed = 16-12 = 4 km\/hr<\/p>\n

$ t = \\frac{300 m}{4 km\/hr} $<\/p>\n

300 m = $ \\frac{3}{10} km $<\/p>\n

Solving , we get $ t= \\frac{3}{40} hr $<\/p>\n

Distance covered by hare = $ 12 \\times \\frac{3}{40} $<\/p>\n

d = $ \\frac{9}{10} km $<\/p>\n

= 900 m<\/p>\n

19)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let ‘2d’ be thee total distance covered by the man.<\/p>\n

$\\dfrac{d}{40}$ + $\\dfrac{d}{60}$ = 8<\/p>\n

$d = 24*8 = 192$ km<\/p>\n

Hence, the total distance covered by the man = 192*2 = 384 km<\/p>\n

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 <\/p>\n","protected":false},"excerpt":{"rendered":"

RRB NTPC Time And Work Questions: Download Top-20 Time and Work questions for RRB NTPC exam. Most important Time and Work questions based on asked questions in previous exam papers for RRB NTPC. Take a free RRB NTPC mock test Download RRB NTPC Previous Papers PDF Question 1:\u00a0A and B can complete a task in […]<\/p>\n","protected":false},"author":53,"featured_media":44002,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[31,3171,1603,1601],"tags":[495,1593,4187],"class_list":{"0":"post-43998","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-railways","8":"category-railways-en","9":"category-rrb-ntpc","10":"category-rrb-ntpc-je","11":"tag-railway","12":"tag-rrb-ntpc","13":"tag-time-and-work"},"better_featured_image":{"id":44002,"alt_text":"Top 20 RRB NTPC Time and Work Questions","caption":"Top-20 RRB NTPC Time and Work Questions ","description":"Top-20 RRB NTPC Time and Work Questions 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