{"id":43971,"date":"2021-01-08T09:19:43","date_gmt":"2021-01-08T03:49:43","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=43971"},"modified":"2021-01-08T09:19:43","modified_gmt":"2021-01-08T03:49:43","slug":"top-20-ssc-chsl-trigonometry-questions","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/top-20-ssc-chsl-trigonometry-questions\/","title":{"rendered":"Top-20 SSC CHSL Trigonometry Questions"},"content":{"rendered":"

SSC CHSL Trigonometry Questions:<\/strong><\/h1>\n

Download Top-20 Trigonometry questions for SSC CHSL exam 2020. Most important Trigonometry questions based on asked questions in previous exam papers for SSC CHSL.<\/p>\n

Download Top-20 SSC CHSL Trigonometry Questions<\/a><\/p>\n

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Question 1:\u00a0<\/b>What is the value of $(1 + cotA)^{2} + (1-cotA)^{2}$ ?<\/p>\n

a)\u00a0$2cosec^{2}A$<\/p>\n

b)\u00a0$2sec^{2}A$<\/p>\n

c)\u00a0$1-2cosec^{2}A$<\/p>\n

d)\u00a0$1-2sec^{2}A$<\/p>\n

Question 2:\u00a0<\/b>If cot 135\u00b0 = x, then the value of x is<\/p>\n

a)\u00a0-1\/\u221a3<\/p>\n

b)\u00a0-\u221a3<\/p>\n

c)\u00a0-1<\/p>\n

d)\u00a0-1\/2<\/p>\n

Question 3:\u00a0<\/b>If \u221a$(1 – cos^2A)\/cosA$ = x, then the value of x is<\/p>\n

a)\u00a0cotA<\/p>\n

b)\u00a0cosecA<\/p>\n

c)\u00a0tanA<\/p>\n

d)\u00a0secA<\/p>\n

Question 4:\u00a0<\/b>What is the value of \u221a[(1 – sinA)\/(1 + sinA)]?<\/p>\n

a)\u00a0cosA\/(1 – sinA)<\/p>\n

b)\u00a0cosecA\/(1 + sinA)<\/p>\n

c)\u00a0cosA\/(1 + sinA)<\/p>\n

d)\u00a0cosecA\/(1 – sinA)<\/p>\n

Question 5:\u00a0<\/b>If cosecA\/(cosecA – 1) + cosecA\/(cosecA + 1) = x, then x is<\/p>\n

a)\u00a0$2cosec^2A$<\/p>\n

b)\u00a0$2cosecA$<\/p>\n

c)\u00a0$2secA$<\/p>\n

d)\u00a0$2sec^2A$<\/p>\n

Question 6:\u00a0<\/b>If cot 30\u00b0 – cos 45\u00b0 = x, then x is<\/p>\n

a)\u00a0\u221a3+2<\/p>\n

b)\u00a0(\u221a6-1)\/\u221a2<\/p>\n

c)\u00a0(\u221a3-2\u221a2)\/\u221a6<\/p>\n

d)\u00a0(1+\u221a2)\/2<\/p>\n

Question 7:\u00a0<\/b>If tan2A = x, then x is<\/p>\n

a)\u00a0$2tanA\/(1 – tan^2A)$<\/p>\n

b)\u00a0$(1 – tan^2A)\/2tanA$<\/p>\n

c)\u00a0$2tanA\/(1 + tan^2A)$<\/p>\n

d)\u00a0$(tan^2A – 1)\/2tanA$<\/p>\n

Question 8:\u00a0<\/b>What is the value of sin 300\u00b0?<\/p>\n

a)\u00a0-1\/2<\/p>\n

b)\u00a02<\/p>\n

c)\u00a02\/\u221a3<\/p>\n

d)\u00a0-\u221a3\/2<\/p>\n

Question 9:\u00a0<\/b>If \u221a$(1 – cos^2A)$ = x, then the value of x is<\/p>\n

a)\u00a0cosecA<\/p>\n

b)\u00a0sinA<\/p>\n

c)\u00a0tanA<\/p>\n

d)\u00a0secA<\/p>\n

Question 10:\u00a0<\/b>If cosA\/(1 – sinA) = x, then the value of x is<\/p>\n

a)\u00a0secA – tanA<\/p>\n

b)\u00a0cosecA + tanA<\/p>\n

c)\u00a0secA + tanA<\/p>\n

d)\u00a0cosecA – tanA<\/p>\n

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Question 11:\u00a0<\/b> \u00ad <\/strong>If $\\sqrt{(sec^2A-1)}=x$, then the value of x is<\/p>\n

a)\u00a0cotA<\/p>\n

b)\u00a0tanA<\/p>\n

c)\u00a0cosecA<\/p>\n

d)\u00a0cosA<\/p>\n

Question 12:\u00a0<\/b>What is the value of $cos^2A\/(1 + sinA)$?<\/p>\n

a)\u00a01 + sinA<\/p>\n

b)\u00a01 -\u00ad sinA<\/p>\n

c)\u00a01 \u00ad- secA<\/p>\n

d)\u00a01 + secA<\/p>\n

Question 13:\u00a0<\/b>If $(cotA – cosecA)^2 = x$, then the value of x is<\/p>\n

a)\u00a0(1 – cosA)\/(1 + cosA)<\/p>\n

b)\u00a0(1 – sinA)\/(1 + sinA)<\/p>\n

c)\u00a0(1 – secA)\/(1 + secA)<\/p>\n

d)\u00a0(1 – cosecA)\/(1 + cosecA)<\/p>\n

Question 14:\u00a0<\/b>If cotA = x, then the value of x is<\/p>\n

a)\u00a0\u221a$(sec^2A + 1)$<\/p>\n

b)\u00a0\u221a$(cosec^2A + 1)$<\/p>\n

c)\u00a0\u221a$(sec^2A – 1)$<\/p>\n

d)\u00a0\u221a$(cosec^2A – 1)$<\/p>\n

Question 15:\u00a0<\/b>If cos 240\u00b0 = x, then value of x is<\/p>\n

a)\u00a0-1\/\u221a2<\/p>\n

b)\u00a0\u00ad\u221a3\/2<\/p>\n

c)\u00a01\/2<\/p>\n

d)\u00a0-1\/2<\/p>\n

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Question 16:\u00a0<\/b>If 1\/\u221a(1+$tan^{2}$A) = x, then value of x is<\/p>\n

a)\u00a0cosA<\/p>\n

b)\u00a0sinA<\/p>\n

c)\u00a0cosecA<\/p>\n

d)\u00a0secA<\/p>\n

Question 17:\u00a0<\/b>In which of the following quadrilaterals only one pair of opposite angles is supplementary?<\/p>\n

a)\u00a0Isosceles Trapezium<\/p>\n

b)\u00a0Parallelogram<\/p>\n

c)\u00a0Cyclic quadrilateral<\/p>\n

d)\u00a0Rectangle<\/p>\n

Question 18:\u00a0<\/b>What is the value of \u221a[(1 + sinA)\/(1 \u00ad- sinA)]?<\/p>\n

a)\u00a0secA \u00ad- tanA<\/p>\n

b)\u00a0cosecA + tanA<\/p>\n

c)\u00a0secA + tanA<\/p>\n

d)\u00a0cosecA \u00ad- tanA<\/p>\n

Question 19:\u00a0<\/b>If (1 + sinA)\/cosA + cosA\/(1 + sinA) = x, then the value of x is<\/p>\n

a)\u00a02cosecA<\/p>\n

b)\u00a02$cosec^{2}$A<\/p>\n

c)\u00a02$sec^{2}$A<\/p>\n

d)\u00a02secA<\/p>\n

Question 20:\u00a0<\/b>If tan 330\u00b0 = x, then the value of x is<\/p>\n

a)\u00a0$\\frac{-1}{\\sqrt{3}}$<\/p>\n

b)\u00a0${-\\sqrt{3}}$<\/p>\n

c)\u00a0$\\frac{-1}{2}$<\/p>\n

d)\u00a0$\\frac{-1}{\\sqrt{2}}$<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0$(1 + cotA)^{2} + (1-cotA)^{2}$<\/p>\n

= $(1+cot^2A+2cotA)+(1+cot^2A-2cotA)$<\/p>\n

= $2+2cot^2A=2(1+cot^2A)$<\/p>\n

$\\because$ $(cosec^2A-cot^2A=1)$<\/p>\n

= $2cosec^2A$<\/p>\n

=> Ans – (A)<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0cot 135\u00b0 = x<\/p>\n

= $cot(180-45)$<\/p>\n

= $-cot(45)$<\/p>\n

= $-1$<\/p>\n

=> Ans – (C)<\/p>\n

3)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0: $\\frac{\\sqrt{1-cos^2A}}{cosA}$<\/p>\n

$\\because (sin^2A+cos^2A=1)$<\/p>\n

= $\\frac{\\sqrt{sin^2A}}{cosA}$<\/p>\n

= $\\frac{sinA}{cosA} = tanA$<\/p>\n

=> Ans – (C)<\/p>\n

4)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\sqrt{[\\frac{(1 – sinA)}{(1 + sinA)}}]$<\/p>\n

Multiplying both numerator and denominator by $(\\sqrt{1+sinA})$<\/p>\n

=\u00a0$\\sqrt{[\\frac{(1 – sinA)}{(1 + sinA)}}]$ $\\times \\sqrt{\\frac{(1+sinA)}{(1+sinA)}}$<\/p>\n

= $\\sqrt{\\frac{1-sin^2A}{(1+sinA)^2}} = \\sqrt{\\frac{cos^2A}{(1+sinA)^2}}$<\/p>\n

= $\\frac{cosA}{1+sinA}$<\/p>\n

=> Ans – (C)<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0: $\\frac{cosecA}{cosecA-1}+\\frac{cosecA}{cosecA+1}$<\/p>\n

= $[(\\frac{1}{sinA})\\div(\\frac{1}{sinA}-1)]+[(\\frac{1}{sinA})\\div(\\frac{1}{sinA}+1)]$<\/p>\n

= $[(\\frac{1}{sinA})\\div(\\frac{1-sinA}{sinA})]+[(\\frac{1}{sinA})\\div(\\frac{1+sinA}{sinA})]$<\/p>\n

= $[(\\frac{1}{sinA}) \\times (\\frac{sinA}{1-sinA})]+[(\\frac{1}{sinA}) \\times (\\frac{sinA}{1+sinA})]$<\/p>\n

= $(\\frac{1}{1-sinA})+(\\frac{1}{1+sinA})$<\/p>\n

= $\\frac{(1+sinA)+(1-sinA)}{(1+sinA)(1-sinA)} = \\frac{2}{1-sin^2A}$<\/p>\n

= $\\frac{2}{cos^2A} = 2sec^2A$<\/p>\n

=> Ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0cot 30\u00b0 – cos 45\u00b0 = x<\/p>\n

= $\\sqrt{3} – \\frac{1}{\\sqrt{2}}$<\/p>\n

= $\\frac{\\sqrt{6}-1}{\\sqrt{2}}$<\/p>\n

=> Ans – (B)<\/p>\n

7)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0: $tan(2A)$<\/p>\n

$\\because tan(A+B)=\\frac{tanA+tanB}{1-tanAtanB}$<\/p>\n

Replacing B by A<\/p>\n

=> $tan(A+A)=\\frac{tanA+tanA}{1-tanAtanA}$<\/p>\n

=> $tan(2A)=\\frac{2tanA}{1-tan^2A}$<\/p>\n

=> Ans – (A)<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0:\u00a0sin 300\u00b0<\/p>\n

= $sin(360-60)$<\/p>\n

= $-sin(60)$<\/p>\n

= $\\frac{-\\sqrt{3}}{2}$<\/p>\n

=> Ans – (D)<\/p>\n

9)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0: $\\sqrt{1-cos^2A}$<\/p>\n

$\\because (sin^2A+cos^2A=1)$<\/p>\n

= $\\sqrt{sin^2A}=sinA$<\/p>\n

=> Ans – (B)<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0cosA\/(1 – sinA) = x<\/p>\n

Multiplying both numerator and denominator by $(1+sinA)$<\/p>\n

= $\\frac{cosA}{1-sinA} \\times \\frac{(1+sinA)}{(1+sinA)}$<\/p>\n

= $\\frac{cosA(1+sinA)}{1-sin^2A} = \\frac{cosA(1+sinA)}{cos^2A}$<\/p>\n

= $\\frac{1+sinA}{cosA} = (\\frac{1}{cosA}+\\frac{sinA}{cosA})$<\/p>\n

= $secA+tanA$<\/p>\n

=> Ans – (C)<\/p>\n

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11)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\sqrt{(sec^2A-1)}=x$<\/p>\n

$\\because (sec^2A-tan^2A=1)$<\/p>\n

= $\\sqrt{tan^2A} = tanA$<\/p>\n

=> Ans – (B)<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression\u00a0:\u00a0$cos^2A\/(1 + sinA)$<\/p>\n

Multiplying both numerator and denominator by $(1-sinA)$<\/p>\n

= $\\frac{cos^2A}{1+sinA} \\times \\frac{(1-sinA)}{(1-sinA)}$<\/p>\n

= $\\frac{cos^2A(1-sinA)}{1-sin^2A} = \\frac{cos^2A(1-sinA)}{cos^2A}$<\/p>\n

= $1-sinA$<\/p>\n

=> Ans – (B)<\/p>\n

13)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0$(cotA – cosecA)^2 = x$<\/p>\n

= $(\\frac{cosA}{sinA}-\\frac{1}{sinA})^2$<\/p>\n

= $(\\frac{cosA-1}{sinA})^2$<\/p>\n

= $\\frac{(1-cosA)^2}{sin^2A} = \\frac{(1-cosA)^2}{1-cos^2A}$<\/p>\n

= $\\frac{(1-cosA)^2}{(1-cosA)(1+cosA)}$<\/p>\n

= $\\frac{1-cosA}{1+cosA}$<\/p>\n

=> Ans – (A)<\/p>\n

14)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

We know that, $cosec^2A-cot^2A=1$<\/p>\n

=> $cot^2A=cosec^2A-1$<\/p>\n

=> $cotA=\\sqrt{cosec^2A-1}$<\/p>\n

=> Ans – (D)<\/p>\n

15)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0:\u00a0cos 240\u00b0 = x<\/p>\n

= $cos(180+60)$<\/p>\n

= $-cos(60)$<\/p>\n

= $\\frac{-1}{2}$<\/p>\n

=> Ans – (D)<\/p>\n

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16)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a01\/\u221a(1+$tan^{2}$A) = x<\/p>\n

$\\because (sec^2A-tan^2A=1)$<\/p>\n

= $\\frac{1}{\\sqrt{sec^2A}}$<\/p>\n

= $\\frac{1}{secA} = cosA$<\/p>\n

=> Ans – (A)<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

In rectangle, all angles are 90\u00b0 and in a parallelogram, adjacent angles are supplementary while in a cyclic quadrilateral\u00a0only one pair of opposite angles is supplementary.<\/p>\n

=> Ans – (C)<\/p>\n

18)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Expression\u00a0:\u00a0$\\sqrt{[\\frac{(1 + sinA)}{(1 – sinA)}}]$<\/p>\n

Multiplying both numerator and denominator by $(\\sqrt{1+sinA})$<\/p>\n

=\u00a0$\\sqrt{[\\frac{(1 + sinA)}{(1 – sinA)}}]$ $\\times \\sqrt{\\frac{(1+sinA)}{(1+sinA)}}$<\/p>\n

= $\\sqrt{\\frac{(1+sinA)^2}{1-sin^2A}} = \\sqrt{\\frac{(1+sinA)^2}{cos^2A}}$<\/p>\n

= $\\frac{1+sinA}{cosA} = (\\frac{1}{cosA}+\\frac{sinA}{cosA})$<\/p>\n

= $secA+tanA$<\/p>\n

=> Ans – (C)<\/p>\n

19)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Expression\u00a0: $\\frac{(1+sinA)}{cosA}+\\frac{cosA}{(1+sinA)}$<\/p>\n

=\u00a0$\\frac{(1+sinA)^2+(cosA)^2}{cosA(1+sinA)}$<\/p>\n

= $\\frac{(1+2sinA+sin^2A)+cos^2A}{cosA(1+sinA)}$<\/p>\n

= $\\frac{1+2sinA+1}{cosA(1+sinA)}$ \u00a0 \u00a0$[\\because sin^2A+cos^2A=1]$<\/p>\n

= $\\frac{2+2sinA}{cosA(1+sinA)} = \\frac{2(1+sinA)}{cosA(1+sinA)}$<\/p>\n

= $\\frac{2}{cosA} = 2secA$<\/p>\n

=> Ans – (D)<\/p>\n

20)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Expression\u00a0:\u00a0tan 330\u00b0 = x<\/p>\n

= $tan(360-30)$<\/p>\n

= $-tan(30)$<\/p>\n

= $\\frac{-1}{\\sqrt{3}}$<\/p>\n

=> Ans – (A)<\/p>\n

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Download SSC Preparation App<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"

SSC CHSL Trigonometry Questions: Download Top-20 Trigonometry questions for SSC CHSL exam 2020. Most important Trigonometry questions based on asked questions in previous exam papers for SSC CHSL. Take a free SSC CHSL Tier-1 mock test Download SSC CHSL Previous Papers PDF Question 1:\u00a0What is the value of $(1 + cotA)^{2} + (1-cotA)^{2}$ ? a)\u00a0$2cosec^{2}A$ […]<\/p>\n","protected":false},"author":53,"featured_media":43974,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[9,378],"tags":[358,4349],"class_list":{"0":"post-43971","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-ssc","8":"category-ssc-chsl","9":"tag-ssc-chsl","10":"tag-trigonometry"},"better_featured_image":{"id":43974,"alt_text":"Top 20 SSC CHSL Trigonometry Questions","caption":"Top-20 SSC CHSL Trigonometry Questions ","description":"Top-20 SSC CHSL Trigonometry Questions 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