{"id":43150,"date":"2020-10-15T12:36:59","date_gmt":"2020-10-15T07:06:59","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=43150"},"modified":"2020-10-15T12:36:59","modified_gmt":"2020-10-15T07:06:59","slug":"trigonometry-questions-for-rrb-ntpc-set-3-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/trigonometry-questions-for-rrb-ntpc-set-3-pdf\/","title":{"rendered":"Trigonometry Questions for RRB NTPC Set-3 PDF"},"content":{"rendered":"

Trigonometry Questions for RRB NTPC Set-3 PDF<\/strong><\/span><\/h2>\n

Download RRB NTPC Top-10 Trigonometry Questions Set-3 PDF. Questions based on asked questions in previous exam papers very important for the Railway NTPC exam.<\/p>\n

Download Trigonometry Questions for RRB NTPC Set-3 PDF<\/a><\/p>\n

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Download RRB NTPC Previous Papers PDF<\/a><\/p>\n\n

Question 1:\u00a0<\/b>If $\\sec \\theta + \\tan \\theta = 2, $then $\\sec \\theta – \\tan \\theta = ?$<\/p>\n

a)\u00a00.5<\/p>\n

b)\u00a01.5<\/p>\n

c)\u00a01<\/p>\n

d)\u00a00.75<\/p>\n

Question 2:\u00a0<\/b>If $\\sin A = \\cos B$, where $A$ and $B$ are acute, then find $(A + B)$.<\/p>\n

a)\u00a0$60^\\circ$<\/p>\n

b)\u00a0$50^\\circ$<\/p>\n

c)\u00a0$90^\\circ$<\/p>\n

d)\u00a0$45^\\circ$<\/p>\n

Question 3:\u00a0<\/b>If A and B are complementary angles, then find the value of $\\cos A \\cos B – \\sin A \\sin B$.<\/p>\n

a)\u00a01<\/p>\n

b)\u00a00<\/p>\n

c)\u00a0$\\frac{1}{2}$<\/p>\n

d)\u00a0-1<\/p>\n

Question 4:\u00a0<\/b>If $(1 + \\tan A) (1 + \\tan B) = 2$, then find $A + B$.<\/p>\n

a)\u00a0$90^\\circ$<\/p>\n

b)\u00a0$180^\\circ$<\/p>\n

c)\u00a0$0^\\circ$<\/p>\n

d)\u00a0$45^\\circ$<\/p>\n

Question 5:\u00a0<\/b>If A=$30^\\circ$ then find the value of $cos^{2}A+cos^{2}(60+A)+cos^{2}(60-A)$<\/p>\n

a)\u00a0$\\frac{3}{2}$<\/p>\n

b)\u00a0$\\frac{\\sqrt{3}}{2}$<\/p>\n

c)\u00a0$\\frac{-3}{2}$<\/p>\n

d)\u00a01<\/p>\n

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Question 6:\u00a0<\/b>If and b are supplementary angles find the value of
\n$\\frac{\\tan A + \\tan B}{1 – \\tan A \\tan B}$<\/p>\n

a)\u00a00<\/p>\n

b)\u00a01<\/p>\n

c)\u00a0-1<\/p>\n

d)\u00a0$\\frac{1}{2}$<\/p>\n

Question 7:\u00a0<\/b>simplify $\\frac{cot (90^\\circ-\\theta) sin(180^\\circ-\\theta) sec(360^\\circ-\\theta)}{tan(180^\\circ+\\theta) sec(-\\theta) cos(90^\\circ+\\theta)}$<\/p>\n

a)\u00a02<\/p>\n

b)\u00a0-1<\/p>\n

c)\u00a01<\/p>\n

d)\u00a0-2<\/p>\n

Question 8:\u00a0<\/b>In the second quadrant, sin $\\theta$ varies from:<\/p>\n

a)\u00a01 to -1<\/p>\n

b)\u00a01 to 0<\/p>\n

c)\u00a00 to -1<\/p>\n

d)\u00a0-1 to 1<\/p>\n

Question 9:\u00a0<\/b>$\u00a0If \\sin\\theta = \\cos\\theta, and \\theta $ is acute, the value of\u00a0 $\u00a02\\sin^{2} \\theta – 3\\cos^{2} \\theta is : $<\/p>\n

a)\u00a0$\u00a0-\\frac{1}{2} $<\/p>\n

b)\u00a01<\/p>\n

c)\u00a0-1<\/p>\n

d)\u00a0$ \\frac{1}{2}$<\/p>\n

Question 10:\u00a0<\/b>If $\\cosec \\theta + \\cot \\theta = 2,$ then $\\cot \\theta = ?$<\/p>\n

a)\u00a00<\/p>\n

b)\u00a00.5<\/p>\n

c)\u00a01<\/p>\n

d)\u00a00.75<\/p>\n

RRB NTPC Previous Papers [Download PDF]<\/a><\/p>\n

Download General Science Notes PDF<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

The correct option is A.<\/p>\n

We know that, $sec^{2}\\theta- \\tan^{2}\\theta = 1$<\/p>\n

$\\Rightarrow$ ($sec\\theta+ tan\\theta$)($sec\\theta – tan\\theta$) = 1<\/p>\n

$\\Rightarrow$ \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 2 $\\times$ ( $sec\\theta – tan\\theta$) = 1<\/p>\n

$\\Rightarrow$. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0$sec\\theta – tan\\theta$ = 0.5<\/p>\n

2)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Given, Sin A = Cos B, it can be written as<\/p>\n

Sin A = sin(90 – B)<\/p>\n

A = 90 – B<\/p>\n

A + B = 90.<\/p>\n

C is correct choice.<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

If A and B are complementary angles then<\/p>\n

A+B = 90<\/p>\n

$\\cos A \\cos B – \\sin A \\sin B$.<\/p>\n

we know that<\/p>\n

$cos(A+B)=\\cos A \\cos B – \\sin A \\sin B$.<\/p>\n

$\u00a0$cos(A+B)<\/p>\n

put value A+B=90<\/p>\n

$cos90=0$<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$(1 + \\tan A) (1 + \\tan B) = 2$<\/p>\n

$ 1 + \\tan B + \\tan A + \\tan A \\tan B = 2 $<\/p>\n

$ \\tan A + \\tan B + \\tan A \\tan B = 1 $<\/p>\n

$ \\tan A + \\tan B = 1 –\u00a0\\tan A \\tan B\u00a0$<\/p>\n

$ \\frac{\u00a0\\tan A + \\tan B}{1 –\u00a0\\tan A \\tan B} = 1 $<\/p>\n

$ \\frac{\u00a0\\tan x + \\tan y}{1 –\u00a0\\tan x \\tan y} = \\tan (x+y) $<\/p>\n

$ \\frac{\u00a0\\tan A + \\tan B}{1 –\u00a0\\tan A \\tan B} = \\tan(A+B) = 1 $<\/p>\n

$ \\tan (A+B) = \\tan 45^\\circ $<\/p>\n

therefore,$\u00a0 A+B = 45^\\circ $<\/p>\n

5)\u00a0Answer\u00a0(A)<\/strong><\/p>\n\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

7)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\frac{cot (90^\\circ-\\theta) sin(180^\\circ-\\theta) sec(360^\\circ-\\theta)}{tan(180^\\circ+\\theta) sec(-\\theta) cos(90^\\circ+\\theta)}$<\/p>\n

$\\frac{cot (90^\\circ-\\theta)$ = tan(\\theta)<\/p>\n

$sin(180^\\circ-\\theta)$<\/p>\n

$sec(360^\\circ-\\theta)$<\/p>\n

$tan(180^\\circ+\\theta)$<\/p>\n

$sec(-\\theta)$<\/p>\n

$cos(90^\\circ+\\theta)$<\/p>\n

8)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

In the second quadrant, sin $\\theta$ varies from 1 to 0.<\/p>\n

B is correct choice.<\/p>\n

9)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

$\\sin\\theta = \\cos\\theta when \\theta=45\\degree$<\/p>\n

So ,\u00a0$ 2\\sin^{2} \\theta – 3\\cos^{2} \\theta$<\/p>\n

=$\\frac{2}{2} – \\frac{3}{2}$<\/p>\n

=$\\frac{-1}{2}$<\/p>\n

So, the answer would be option b)$\\frac{-1}{2}$.<\/p>\n

10)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

 <\/p>\n

DOWNLOAD APP FOR RRB FREE MOCKS<\/a><\/p>\n\n

We hope this Top-10 Trigonometry Questions pdf for RRB NTPC exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Trigonometry Questions for RRB NTPC Set-3 PDF Download RRB NTPC Top-10 Trigonometry Questions Set-3 PDF. Questions based on asked questions in previous exam papers very important for the Railway NTPC exam. Download RRB NTPC Previous Papers PDF Question 1:\u00a0If $\\sec \\theta + \\tan \\theta = 2, $then $\\sec \\theta – \\tan \\theta = ?$ a)\u00a00.5 […]<\/p>\n","protected":false},"author":42,"featured_media":43160,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[3167,125,3171,31,1701,1679,1897,1605,1603,1601,1673],"tags":[4117,492,1635,1593,3658],"class_list":{"0":"post-43150","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-downloads-en","8":"category-featured","9":"category-railways-en","10":"category-railways","11":"category-rpf-si-and-constable","12":"category-rrb-group-d","13":"category-rrb-group-d-2","14":"category-rrb-je","15":"category-rrb-ntpc","16":"category-rrb-ntpc-je","17":"category-rrb-para-medical-categories","18":"tag-railway-exams","19":"tag-rrb-group-d","20":"tag-rrb-je","21":"tag-rrb-ntpc","22":"tag-trigonometry-questions"},"better_featured_image":{"id":43160,"alt_text":"Trigonometry Questions for RRB NTPC Set-3 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