{"id":43097,"date":"2020-10-09T19:35:45","date_gmt":"2020-10-09T14:05:45","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=43097"},"modified":"2020-10-09T19:35:45","modified_gmt":"2020-10-09T14:05:45","slug":"reasoning-questions-for-ssc-cgl-tier-2-pdf","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/reasoning-questions-for-ssc-cgl-tier-2-pdf\/","title":{"rendered":"Reasoning Questions for SSC CGL Tier – 2 PDF"},"content":{"rendered":"

Reasoning Questions for SSC CGL Tier – 2 PDF<\/strong><\/span><\/h3>\n

Download SSC CGL Tier 2 Reasoning Questions PDF. Top 20 Reasoning questions based on previous exam papers very important for the SSC exam.<\/p>\n

Download Reasoning Questions for SSC CGL Tier – 2 PDF<\/a><\/p>\n

Get 10 SSC CGL Tier-2 Mocks for Rs. 149<\/a><\/p>\n

Take SSC CGL Tier-2 Mock Tests<\/a><\/p>\n

Download SSC CGL Tier-2 Previous Papers PDF<\/a><\/p>\n

Question 1:\u00a0<\/b>Which of the following interchanges in signs and numbers will make the given equation correct?
\n8 x 9 + 2 = 74<\/p>\n

a)\u00a0x and =, 2 and 9<\/p>\n

b)\u00a0x and +, 8 and 2<\/p>\n

c)\u00a0+ and x, 8 and 9<\/p>\n

d)\u00a0+ and =, 74 and 2<\/p>\n

Question 2:\u00a0<\/b>Five students P, Q, R, S and T are sitting on a bench. Q is to the left of P and right of T. S is at the extreme right end and R is to the immediate\u00a0left of S. Who is sitting third from the left?<\/p>\n

a)\u00a0P<\/p>\n

b)\u00a0Q<\/p>\n

c)\u00a0R<\/p>\n

d)\u00a0T<\/p>\n

Question 3:\u00a0<\/b>Ankit scored 32, 45 and 49 marks in Physics, English and Philosophy respectively. The maximum marks in each subject is 50. Determine his overall percentage for the three subjects.<\/p>\n

a)\u00a058<\/p>\n

b)\u00a050<\/p>\n

c)\u00a042<\/p>\n

d)\u00a084<\/p>\n

Question 4:\u00a0<\/b>If 52*14= 33, 44*8= 26 and 86*14= 50, then what will 43*15 be?<\/p>\n

a)\u00a043<\/p>\n

b)\u00a058<\/p>\n

c)\u00a026<\/p>\n

d)\u00a029<\/p>\n

Question 5:\u00a0<\/b>B is older than C but not as old as D. E is not as old as B. Who is the oldest of all?<\/p>\n

a)\u00a0B<\/p>\n

b)\u00a0E<\/p>\n

c)\u00a0C<\/p>\n

d)\u00a0D<\/p>\n

Take SSC CGL Tier-2 Mock Tests<\/a><\/p>\n

Question 6:\u00a0<\/b>Five planes, A, B, P, Q and R were saluting on Independence Day in such a way that R was second to the left of Q but to the immediate right of A. There was one plane between B and P. B was not at any of the ends. P and Q were neighbours. Who was at the left end?<\/p>\n

a)\u00a0A<\/p>\n

b)\u00a0B<\/p>\n

c)\u00a0R<\/p>\n

d)\u00a0Q<\/p>\n

Question 7:\u00a0<\/b>In a company all Mondays and Sundays are offs. If a month starts with a Monday and has 31 days then how many offs will be there in that month?<\/p>\n

a)\u00a07<\/p>\n

b)\u00a08<\/p>\n

c)\u00a09<\/p>\n

d)\u00a05<\/p>\n

Question 8:\u00a0<\/b>If day before yesterday was Sunday, then which day of the week will the sixth day from today be?<\/p>\n

a)\u00a0Wednesday<\/p>\n

b)\u00a0Tuesday<\/p>\n

c)\u00a0Monday<\/p>\n

d)\u00a0Thursday<\/p>\n

Question 9:\u00a0<\/b>Rajan and Manu went to a market. Rajan bought 3 erasers and 5 pens for Rs 105 and Manu bought 4 erasers and 6 pens for Rs 130. What is the price of one eraser?<\/p>\n

a)\u00a0Rs 25<\/p>\n

b)\u00a0Rs 20<\/p>\n

c)\u00a0Rs 10<\/p>\n

d)\u00a0Rs 19<\/p>\n

Question 10:\u00a0<\/b>Ravi had five subjects in his final examination. The maximum marks in each subject are 100. If his percentage in four subjects is 80, and he scores 65 marks in the fifth subject, determine his overall percentage for the five subjects.<\/p>\n

a)\u00a078<\/p>\n

b)\u00a079<\/p>\n

c)\u00a077<\/p>\n

d)\u00a076<\/p>\n

Download SSC CGL Tier-2 Previous Papers PDF<\/a><\/p>\n

Take SSC CGL Tier-2 Mock Tests<\/a><\/p>\n

Question 11:\u00a0<\/b>Amit’s age is four times the age of Babli. Babli’s age is three times the age of Priya. If the present age of Priya is 5 years, what is the present age (in years) of Amit?<\/p>\n

a)\u00a065<\/p>\n

b)\u00a045<\/p>\n

c)\u00a055<\/p>\n

d)\u00a060<\/p>\n

Question 12:\u00a0<\/b>The average temperature of a town in the \ufb01rst six days of a month was 410C and the sum of the temperatures of the \ufb01rst \ufb01ve days of the same month was 2010C. What was the temperature on the sixth day of the month?<\/p>\n

a)\u00a0400C<\/p>\n

b)\u00a0450C<\/p>\n

c)\u00a0460C<\/p>\n

d)\u00a0500C<\/p>\n

Question 13:\u00a0<\/b>There are five students – P, Q, R, S and T having different heights in a class. P’s height is more than only one student. Q’s height is more than S and P but not more than R. S’s height is more than P. R is not the smallest. Who is having the maximum height in the class?<\/p>\n

a)\u00a0Q<\/p>\n

b)\u00a0R<\/p>\n

c)\u00a0S<\/p>\n

d)\u00a0T<\/p>\n

Question 14:\u00a0<\/b>There are 45 trees in a row. The lemon tree is 20th from right end. What is the rank of lemon tree from left end?<\/p>\n

a)\u00a026<\/p>\n

b)\u00a024<\/p>\n

c)\u00a025<\/p>\n

d)\u00a027<\/p>\n

Question 15:\u00a0<\/b>In a row of books a book of English is 16th from left end of row. A book of Mathematics is 12th from the right end. If the Mathematics book is 6th to the right of the English book, then how many total books are in the row?<\/p>\n

a)\u00a033<\/p>\n

b)\u00a032<\/p>\n

c)\u00a034<\/p>\n

d)\u00a031<\/p>\n

Download SSC CGL General Science Notes PDF<\/a><\/p>\n

Question 16:\u00a0<\/b>In the following question, by using which mathematical operators will the expression become correct?
\n30 ? 6 ? 4 ? 5 ? 4<\/p>\n

a)\u00a0+, =, x and –<\/p>\n

b)\u00a0-, =, x and +<\/p>\n

c)\u00a0=, x, + and –<\/p>\n

d)\u00a0-, +, = and x<\/p>\n

Question 17:\u00a0<\/b>If 6 @ 4 @ 7 = 101 and 2 @ 5 @ 11 = 150, then what is the value of A in A @ 8 @ 9 = 289?<\/p>\n

a)\u00a05<\/p>\n

b)\u00a08<\/p>\n

c)\u00a012<\/p>\n

d)\u00a017<\/p>\n

Question 18:\u00a0<\/b>Among four books, Book1 is twice as heavy as Book 2. Book 3’s weight is half of Book 2’s weight. Book 4 is 60 grams more as compared to Book 2 but 60 grams less as compared Book 1. Which book is heaviest?<\/p>\n

a)\u00a0Book 1<\/p>\n

b)\u00a0Book 2<\/p>\n

c)\u00a0Book 3<\/p>\n

d)\u00a0Book 4<\/p>\n

Question 19:\u00a0<\/b>In the given figure , how many bottles are not brown<\/p>\n

<\/figure>\n

a)\u00a058<\/p>\n

b)\u00a057<\/p>\n

c)\u00a032<\/p>\n

d)\u00a027<\/p>\n

Question 20:\u00a0<\/b>In a row of people Manu is 7th from bottom end of row. Shrey is 10 ranks above Manu. If Shrey is 8th from top end, then how many people are there in this row?<\/p>\n

a)\u00a025<\/p>\n

b)\u00a026<\/p>\n

c)\u00a024<\/p>\n

d)\u00a023<\/p>\n

18000+ Questions – Free SSC Study Material<\/a><\/p>\n

Free SSC Preparation (Videos Youtube)<\/a><\/p>\n

Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression :\u00a08 x 9 + 2 = 74<\/p>\n

(A) :\u00a0x and =, 2 and 9<\/p>\n

$\\equiv8=2+9\\times74$<\/p>\n

R.H.S. $=666+2=668\\neq$ L.H.S.<\/p>\n

(B) :\u00a0x and +, 8 and 2<\/p>\n

$\\equiv2+9\\times8=74$<\/p>\n

L.H.S. $=2+72=74=$ R.H.S.<\/p>\n

=> Ans – (B)<\/p>\n

2)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

S is at the extreme right end and R is to the left of S.<\/p>\n

=> R sits second from right end.<\/p>\n

Q is to the left of P and right of T.<\/p>\n

=> T sits at extreme left end.<\/p>\n

Thus, arrangement\u00a0:<\/p>\n

<\/figure>\n

$\\therefore$\u00a0P<\/strong>\u00a0is sitting third from the left.<\/p>\n

=> Ans – (A)<\/p>\n

3)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Total marks scored by Ankit\u00a0in Physics, English and Philosophy respectively = $32+45+49=126$<\/p>\n

Total aggregate marks of the three subjects = $3\\times50=150$<\/p>\n

$\\therefore$ Required percentage = $\\frac{126}{150}\\times100$<\/p>\n

= $\\frac{126}{3}\\times2=84\\%$<\/p>\n

=> Ans – (D)<\/p>\n

4)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The pattern followed is that for the numbers, $a*b=c$, we have = $c=\\frac{(a+b)}{2}$<\/p>\n

Eg\u00a0:-\u00a052*14= 33 $\\equiv\\frac{(52+14)}{2}=\\frac{66}{2}=33$<\/p>\n

and 86*14= 50\u00a0$\\equiv\\frac{(86+14)}{2}=\\frac{100}{2}=50$<\/p>\n

Similarly,\u00a043*15\u00a0$\\equiv\\frac{(43+15)}{2}=\\frac{58}{2}=29$<\/p>\n

=> Ans – (D)<\/p>\n

5)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

B is older than C but not as old as D, => D > B > C.<\/p>\n

E is not as old as B, => B > E<\/p>\n

Thus, combining above equations, we get\u00a0:\u00a0D > B > E, C<\/strong><\/p>\n

Thus, D is the oldest of all.<\/p>\n

=> Ans – (D)<\/p>\n

6)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

R was second to the left of Q but to the immediate right of A, => A R _ Q<\/p>\n

There was one plane between B and P, => the last plane must be to the immediate right of Q.<\/p>\n

Also, B was not at any of the ends, => B was between R and Q.<\/p>\n

Arrangement\u00a0:<\/p>\n

<\/figure>\n

$\\therefore$\u00a0A<\/strong>\u00a0was at the left end.<\/p>\n

=> Ans – (A)<\/p>\n

7)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

It is given that\u00a0all Mondays and Sundays are offs.<\/p>\n

If a month starts with a Monday and has 31 days, then number of Mondays = 5<\/p>\n

But number of Sundays = 4<\/p>\n

Thus, total off days = 4+5 = 9<\/p>\n

=> Ans – (C)<\/p>\n

8)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

If day before yesterday was Sunday, then\u00a0today is = Tuesday<\/p>\n

Now, 6th day from today = Tuesday (+6) = Monday<\/p>\n

=> Ans – (C)<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let price of 1 eraser = Rs. $x$ and price of 1 pen = Rs.\u00a0$y$<\/p>\n

According to ques, => $3x+5y=105$ —————(i)<\/p>\n

and $4x+6y=130$<\/p>\n

$\\equiv2x+3y=65$ ————(ii)<\/p>\n

Now, multiplying equation (i) by 2 and equation (ii) by 3 and subtracting them\u00a0: $2(i)-3(ii)$<\/p>\n

=> $10y-9y=210-195$<\/p>\n

=> $y=15$<\/p>\n

Substituting it in equation (ii), we get\u00a0: $2x+3(15)=65$<\/p>\n

=> $2x=65-45=20$<\/p>\n

=> $x=\\frac{20}{2}=10$<\/p>\n

Thus, price of 1 eraser is Rs. 10<\/p>\n

=> Ans – (C)<\/p>\n

10)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Maximum marks in each subject = 100<\/p>\n

Percentage marks in 4 subjects = 80%<\/p>\n

=> Total marks scored in 4 subjects = $80\\times4=320$<\/p>\n

Marks in 5th subject = 65<\/p>\n

=> Overall percentage for the five subjects = $\\frac{(320+65)}{500}\\times100$<\/p>\n

= $\\frac{385}{5}=77\\%$<\/p>\n

=> Ans – (C)<\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

Priya’s present age = 5 years<\/p>\n

=> Babli’s present age = $3\\times5=15$ years<\/p>\n

$\\therefore$ Amit’s present age = $4\\times15=60$ years<\/p>\n

=> Ans – (D)<\/p>\n

12)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Average temperature of a town in the \ufb01rst six days\u00a0 = $410C$<\/p>\n

=> Sum of temperatures in 6 days = $6\\times410=2460C$<\/p>\n

Sum of the temperatures of the \ufb01rst \ufb01ve days of the same month = $2010C$<\/p>\n

$\\therefore$ Temperature on the sixth day of the month = $2460-2010=450C$<\/p>\n

=> Ans – (B)<\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Q’s height is more than S and P but not more than R and\u00a0S’s height is more than P,<\/p>\n

=> R > Q > S\u00a0>\u00a0P<\/p>\n

P’s height is more than only one student, => T is the shortest.<\/p>\n

$\\therefore$\u00a0R > Q > S > P > T<\/strong><\/p>\n

Thus, R is the tallest in the class.<\/p>\n

=> Ans – (B)<\/p>\n

14)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Total number of trees = 45<\/p>\n

Position of lemon tree from right end = 20th<\/p>\n

=> Rank of lemon tree from left end = $(45+1)-20$<\/p>\n

=\u00a0$46-20=26$<\/p>\n

=> Ans – (A)<\/p>\n

15)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Position of English book from left end = 16th<\/p>\n

=> Position of Mathematics book from left end = 16 + 6 = 22nd<\/p>\n

Also,\u00a0Position of Mathematics book from\u00a0right end = 12th<\/p>\n

Thus, total books in the row = (22+12) – 1 = 34-1 = 33<\/p>\n

=> Ans – (A)<\/p>\n

16)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Expression :\u00a030 ? 6 ? 4 ? 5 ? 4<\/p>\n

(A) : $30+6=4\\times5-4$<\/p>\n

L.H.S. = $36$<\/p>\n

R.H.S. = $20-4=16\\neq$ L.H.S.<\/p>\n

(B) : $30-6=4\\times5+4$<\/p>\n

L.H.S. = $24$<\/p>\n

R.H.S. = $20+4=24=$ L.H.S.<\/p>\n

=> Ans – (B)<\/p>\n

17)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

The pattern followed is that sum of squares of the number is written on the right.<\/p>\n

Eg = $6^2+4^2+7^2=36+16+49=101$<\/p>\n

and\u00a0$2^2+5^2+11^2=4+25+121=150$<\/p>\n

Similarly,\u00a0$A^2+8^2+9^2=289$<\/p>\n

=> $A^2+64+81=289$<\/p>\n

=> $A^2=289-145=144$<\/p>\n

=> $A=\\sqrt{144}=12$<\/p>\n

=> Ans – (C)<\/p>\n

18)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Let weight of Book 2 = $2x$ kg<\/p>\n

=> Weight of Book 1 = $4x$ kg<\/p>\n

and weight of book 3 = $x$ kg<\/p>\n

Thus, weight of book 4 = $2x+60=4x-60$<\/p>\n

=> $4x-2x=60+60$<\/p>\n

=> $2x=120$<\/p>\n

=> $x=\\frac{120}{2}=60$<\/p>\n

Thus, respective weights of Book 1,2,3 and 4 = $240,120,60,180$ kg<\/p>\n

$\\therefore$ Book 1 is the heaviest.<\/p>\n

=> Ans – (A)<\/p>\n

19)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

<\/figure>\n

Bottles that are not brown are represented by blue colour = 31 + 26 + 1 = 58<\/p>\n

=> Ans – (A)<\/p>\n

20)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Manu’s position from bottom end = 7th<\/p>\n

=> Shreya’s position from bottom end = 7 + 10 = 17th<\/p>\n

Also, Shreya’s position from top end = 8th<\/p>\n

$\\therefore$ Total number of people = (17+8) – 1 = 24<\/p>\n

=> Ans – (C)<\/p>\n

Free SSC Online Coaching<\/a><\/p>\n

DOWNLOAD APP FOR SSC FREE MOCKS<\/a><\/p>\n

We hope this Reasoning Questions pdf for SSC CGL Tier 2 exam will be highly useful for your Preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Reasoning Questions for SSC CGL Tier – 2 PDF Download SSC CGL Tier 2 Reasoning Questions PDF. Top 20 Reasoning questions based on previous exam papers very important for the SSC exam. Take SSC CGL Tier-2 Mock Tests Download SSC CGL Tier-2 Previous Papers PDF Question 1:\u00a0Which of the following interchanges in signs and numbers 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