{"id":42995,"date":"2020-10-01T18:41:46","date_gmt":"2020-10-01T13:11:46","guid":{"rendered":"https:\/\/cracku.in\/blog\/?p=42995"},"modified":"2020-10-01T18:41:46","modified_gmt":"2020-10-01T13:11:46","slug":"arithmetic-questions-for-ibps-clerk-prelims","status":"publish","type":"post","link":"https:\/\/cracku.in\/blog\/arithmetic-questions-for-ibps-clerk-prelims\/","title":{"rendered":"Arithmetic Questions for IBPS Clerk Prelims"},"content":{"rendered":"

Arithmetic Questions for IBPS Clerk Prelims<\/strong><\/span><\/h2>\n

Download Top-15 Banking Exams Arithmetic questions PDF. Banking Exams Arithmetic questions based on asked questions in previous exam papers very important for the Banking \u00a0exams.<\/p>\n

Download Arithmetic Questions for IBPS Clerk Prelims<\/a><\/p>\n

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Question 1:\u00a0<\/b>11.11% of 90 + 8.33% of 120 =?<\/p>\n

a)\u00a020<\/p>\n

b)\u00a030<\/p>\n

c)\u00a040<\/p>\n

d)\u00a050<\/p>\n

e)\u00a060<\/p>\n

Question 2:\u00a0<\/b>What is the value of (x) in the following equation ?
\n$ \\frac { x ^ {1.2}}{98} = \\frac {28}{x^{1.8}}$<\/p>\n

a)\u00a018<\/p>\n

b)\u00a012<\/p>\n

c)\u00a016<\/p>\n

d)\u00a014<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

What should come in place of the question mark (?) in the following question ?<\/p>\n

Question 3:\u00a0<\/b>$(7921\\div178)-5.5=\\sqrt{?}$<\/p>\n

a)\u00a01512<\/p>\n

b)\u00a01521<\/p>\n

c)\u00a01251<\/p>\n

d)\u00a01531<\/p>\n

e)\u00a0None of these<\/p>\n

Instructions<\/b><\/p>\n

What will come in the place of question mark(?) in the given questions?<\/p>\n

Question 4:\u00a0<\/b>$(3\\frac{6}{17}\\div2\\frac{7}{34}-1\\frac{9}{25})=(?)^2$<\/p>\n

a)\u00a0$ \\frac{2}{5}$<\/p>\n

b)\u00a0$\\frac{1}{3}$<\/p>\n

c)\u00a0$\\frac{4}{5}$<\/p>\n

d)\u00a0$\\frac{1}{5}$<\/p>\n

e)\u00a0$\\frac{3}{5}$<\/p>\n

Instructions<\/b><\/p>\n

What value should come in the place of question mark (?) in the following questions?<\/p>\n

Question 5:\u00a0<\/b>$\\frac{17}{24}\\div\\frac{68}{24}\\div\\frac{380}{95}=(?)^{2}$<\/p>\n

a)\u00a04<\/p>\n

b)\u00a08<\/p>\n

c)\u00a06<\/p>\n

d)\u00a09<\/p>\n

e)\u00a0None of these<\/p>\n

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Instructions<\/b><\/p>\n

What \u2018\u2019approximate\u2019\u2019 value should come in the place of question mark (?) in the following questions? (You are not expected to calculate the exact value )<\/p>\n

Question 6:\u00a0<\/b>$\\sqrt[3]{80000}$=?<\/p>\n

a)\u00a050<\/p>\n

b)\u00a049<\/p>\n

c)\u00a042<\/p>\n

d)\u00a038<\/p>\n

e)\u00a040<\/p>\n

Instructions<\/b><\/p>\n

In each of these questions two equations numbered I & II are given. You have to solve both the equations and give answer.<\/p>\n

Question 7:\u00a0<\/b>I. $4a^{2}-20a+21=0$
\nII. $2b^{2}-5b+3=0$<\/p>\n

a)\u00a0if $a < b$<\/p>\n

b)\u00a0if $a > b$<\/p>\n

c)\u00a0if relationship between $a$ & $b$ cannot be established<\/p>\n

d)\u00a0if $a\\geq b$<\/p>\n

e)\u00a0if $a\\leq b$<\/p>\n

Instructions<\/b><\/p>\n

What will come in place of question mark (?) in the following questions ?<\/p>\n

Question 8:\u00a0<\/b>$784\\div 16 \\div7=?$<\/p>\n

a)\u00a049<\/p>\n

b)\u00a014<\/p>\n

c)\u00a021<\/p>\n

d)\u00a07<\/p>\n

e)\u00a0None of these<\/p>\n

Question 9:\u00a0<\/b>What will come in place of both question mark (?) in the following equation ?
\n$\\frac {76\\times 32 \\div ? + 16}{6^{2} \\div 9 \\times 4 – ?} = 40$<\/p>\n

a)\u00a016<\/p>\n

b)\u00a04<\/p>\n

c)\u00a08<\/p>\n

d)\u00a012<\/p>\n

e)\u00a06<\/p>\n

Question 10:\u00a0<\/b>$\\frac{14}{19}\\times\\frac{57}{70}\\times\\frac{20}{21}=?$<\/p>\n

a)\u00a0$\\frac{2}{7}$<\/p>\n

b)\u00a0$\\frac{4}{7}$<\/p>\n

c)\u00a0$\\frac{2}{9}$<\/p>\n

d)\u00a0$\\frac{3}{7}$<\/p>\n

e)\u00a0None of these<\/p>\n

Take a free mock test for IBPS-Clerk<\/a><\/p>\n

IBPS Clerk previous year papers<\/a><\/p>\n

Instructions<\/b><\/p>\n

What will come in place of the question mark (?) in the following questions?<\/p>\n

Question 11:\u00a0<\/b>56835 – 12683 + 38934 = ?<\/p>\n

a)\u00a083085<\/p>\n

b)\u00a083083<\/p>\n

c)\u00a083088<\/p>\n

d)\u00a083086<\/p>\n

e)\u00a0None of these<\/p>\n

Question 12:\u00a0<\/b>What will come in place of both the question marks (?) in the following question ? $\\frac{(?)^{1.3}}{45}=\\frac{75}{(?)^{1.7}}$<\/p>\n

a)\u00a025<\/p>\n

b)\u00a0-15<\/p>\n

c)\u00a0-25<\/p>\n

d)\u00a017<\/p>\n

e)\u00a0None of these<\/p>\n

Question 13:\u00a0<\/b>$8080 \\div 80 \\div 8 = ?$<\/p>\n

a)\u00a0880<\/p>\n

b)\u00a012.625<\/p>\n

c)\u00a0808<\/p>\n

d)\u00a016.225<\/p>\n

e)\u00a0None of these<\/p>\n

Question 14:\u00a0<\/b>(14 $\\times $ 24) + (27 $\\times $12) = ?<\/p>\n

a)\u00a0650<\/p>\n

b)\u00a0665<\/p>\n

c)\u00a0660<\/p>\n

d)\u00a0655<\/p>\n

e)\u00a0None of these<\/p>\n

Question 15:\u00a0<\/b>The product of two consecutive even numbers is 7568. What is 150% of the sum of the two numbers?<\/p>\n

a)\u00a0204<\/p>\n

b)\u00a0261<\/p>\n

c)\u00a0304<\/p>\n

d)\u00a0198<\/p>\n

e)\u00a0None of these<\/p>\n

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Answers & Solutions:<\/strong><\/span><\/p>\n

1)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

10+10 = 20 (11.11% = 1\/9 and 8.33% = 1\/12)<\/p>\n

2)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

The question can be reframed as,<\/p>\n

$x^{1.2}\\times x^{1.8}$ = 98*28 = 14*7*7*4= 7*7*7*8<\/p>\n

x^3=7*7*7*8<\/p>\n

Hence, x = 7*2 = 14<\/p>\n

3)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let unknown be x,<\/p>\n

$(7921\\div178)-5.5=\\sqrt{x}$<\/p>\n

Hence, x=[(7921\/178)-5.5]^2=39^2=1521<\/p>\n

4)\u00a0Answer\u00a0(A)<\/strong><\/p>\n

Given equation can be solved as follows:<\/p>\n

$\\frac{57}{17} \\times \\frac{34}{75} – \\frac{34}{25}$ = $\\frac{4}{25}$<\/p>\n

Hence, answer will be A<\/p>\n

5)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

As we can see that equation can be written as\u00a0$(\\frac{17}{24}\\times \\frac{24}{68})\\times\\frac{95}{380}$<\/p>\n

Hence, answer will be $\\frac{1}{4}$<\/p>\n

6)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

We need to find the approximate value of $\\sqrt[3]{80000}$<\/p>\n

We know that $2^3 = 8$ and $10^3 = 1000$<\/p>\n

Let the value of $\\sqrt[3]{80000} = X$
\nSo, $X = 2 \\times 10 \\times \\sqrt[3]{10}$<\/p>\n

The $\\sqrt[3]{10}$ is approximately equal to 2.1<\/p>\n

Hence, the approximate value equals $20*2.1 = 42$<\/p>\n

The closest option is option (c)<\/p>\n

7)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

$4a^2-20a+21 = 0$
\n$(2a-3)(2a-7) = 0$
\n$a = \\frac{3}{2}, \\frac{7}{2}$<\/p>\n

$2b^2-5b+3 = 0$
\n$(2b-3)(b-1) = 0$
\n$b = 1, \\frac{3}{2}$<\/p>\n

$\\therefore a\\geq b$<\/p>\n

8)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

784 = 7 x 7 x 16
\nLet x be the unknown quantity, then<\/p>\n

x = $\\frac{784}{16\\times7} = 7$<\/p>\n

9)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

Let the value of the number which replaces the question mark be equal to $X$<\/p>\n

$\\frac {76\\times 32 \\div X + 16}{6^{2} \\div 9 \\times 4 – X} = 40$
\nSo, $ 76 \\times 32 \\div X +16 = 40 \\times (16 – X)$
\nOr, $ 2432 \\div X + 16 = 640 – 40 \\times X$
\nDividing by 8, we get $304 \\div X + 5 \\times X = 78$
\nOr, $ 5X^2 – 78 \\times X + 304 = 0$<\/p>\n

Hence, $X=8$ and the correct answer is option (c)<\/p>\n

10)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\frac{14}{19}\\times\\frac{57}{70}\\times\\frac{20}{21}$<\/p>\n

$\\frac{2}{1}\\times\\frac{1}{7}\\times\\frac{2}{1}$<\/p>\n

$\\frac{4}{7}$<\/p>\n

11)\u00a0Answer\u00a0(D)<\/strong><\/p>\n

This question is trying to check the BODMAS rule<\/p>\n

56835 – 12683 + 38934 = (56835 + 38934) – 12683 = 83086<\/span><\/p>\n

12)\u00a0Answer\u00a0(E)<\/strong><\/p>\n

Let ? = x
\nAccording to given equation
\n$\\frac{(x)^{1.3}}{45}=\\frac{75}{(x)^{1.7}}$
\n$ x^{3} $ = 45 $ \\times$ 75
\n<\/span>$ x^{3} $ = 15 $ \\times$ 15 $ \\times$ 15<\/span>
\nx = 15
\n<\/span><\/p>\n

13)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

$\\frac{8080}{80}$ =101<\/p>\n

101\u00f78 need not be calculated.<\/span><\/p>\n

We know that 8\u00d712=96 and 8\u00d713=104. Hence the answer must lie between 12 and 13.<\/span><\/span><\/p>\n

Hence the correct answer is Option B.<\/span><\/span><\/p>\n

14)\u00a0Answer\u00a0(C)<\/strong><\/p>\n

(14$\\times$24) + (27$\\times$12)<\/p>\n

= 336 + 324<\/p>\n

= 660<\/p>\n

15)\u00a0Answer\u00a0(B)<\/strong><\/p>\n

Let even numbers be ‘2n’ and ‘2n+2’.
\nAccording to question,
\n$2n\\times(2n+2)=7568$.
\n$4n(n+1)=7568$.
\n$n(n+1)=1892$.
\n$n=43$.
\nHence, numbers are 86 and 88 respectively.
\nSum of numbers=86+88.
\n=174.
\n150% of sum of numbers=$1.5\\times174$.
\n$=261$.
\nHence, Option B is correct.<\/p>\n

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We hope this Arithmetic questions for IBPS Clerk\u00a0 will be highly useful for your preparation.<\/p>\n","protected":false},"excerpt":{"rendered":"

Arithmetic Questions for IBPS Clerk Prelims Download Top-15 Banking Exams Arithmetic questions PDF. Banking Exams Arithmetic questions based on asked questions in previous exam papers very important for the Banking \u00a0exams. Download IBPS Clerk Previous Papers PDF Take a IBPS Clerk free mock test Question 1:\u00a011.11% of 90 + 8.33% of 120 =? a)\u00a020 b)\u00a030 […]<\/p>\n","protected":false},"author":42,"featured_media":42997,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"om_disable_all_campaigns":false,"_mi_skip_tracking":false,"footnotes":""},"categories":[8,3167,125,2999,229,228,2067,2071,2069,3264,3266,255],"tags":[2356,66,50,4171,48],"class_list":{"0":"post-42995","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-banking","8":"category-downloads-en","9":"category-featured","10":"category-ibps-en","11":"category-ibpsclerk","12":"category-ibpspo","13":"category-ibps-rrb-clerk","14":"category-ibps-rrb-clerk-en","15":"category-ibps-rrb-po","16":"category-ibps-so-en","17":"category-ibps-so-en-banking","18":"category-ibps-specialist-officer-so","19":"tag-arithmetic","20":"tag-ibps","21":"tag-ibps-clerk","22":"tag-ibps-clerk-prelims","23":"tag-ibps-po"},"better_featured_image":{"id":42997,"alt_text":"Arithmetic Questions for IBPS 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